sees 503 - 5.1 flood routing - middle east technical …users.metu.edu.tr/bertug/sees503/sees 503 -...
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CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 1/19
Assist. Prof. Dr. Bertuğ AkıntuğDepartment of Civil EngineeringMiddle East Technical University
Northern Cyprus Campus
SEES 503SEES 503SUSTAINABLE WATER SUSTAINABLE WATER
RESOURCERESOURCEFLOOD ROUTINGFLOOD ROUTING
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 2/19
FLOOD ROUTINGFLOOD ROUTING
Overview
IntroductionStorage EquationReservoir RoutingRouting in Natural Channels
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 3/19
FLOOD ROUTINGFLOOD ROUTING
Introduction
Flood routing is a procedure through which the temporal variation of discharge at a point on a stream channel or on a reservoir may be determined by consideration of similar data from a point upstream.
Flood routing is a process, which shows how a flood wave is reduced in magnitude, and lengthened in time by the storage in a reach or reservoir between the two points.
Change in flood hydrograph due to storage
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 4/19
FLOOD ROUTINGFLOOD ROUTING
Overview
IntroductionStorage EquationReservoir RoutingRouting in Natural Channels
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 5/19
FLOOD ROUTINGFLOOD ROUTING
Storage (Continuity) Equation
Q
∑ ∆−=∆ tQIS )(
Change in flood hydrograph due to storage
dtdSQI =−or
I : inflowQ: outflowdS/dt: change in storage
I
tSS
tSQI
∆−
=∆∆
=− 12
: the average inflow(I1+I2)/2 during ∆t.
: the average outflow(Q1+Q2)/2 during ∆t.
S1 and S2 : storage at the beginning and at the end of ∆t.
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 6/19
FLOOD ROUTINGFLOOD ROUTING
Storage (Continuity) Equation
Although the storage equation is correct and simple, the movement of a flood wave in a river channel or in a reservoir is a condition of unsteady flow.Therefore following assumptions and approximations are required.
The stream should be divided into parts (reaches) where channel characteristics are constant or assumed to be constant.There should be a stream gauge at each end of the reach.The time interval, ∆t, should be as large as possible so as to have less number of computation steps, but at the same time it should be small enough to observe the passage of the flood peak.
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 7/19
FLOOD ROUTINGFLOOD ROUTING
Storage (Continuity) Equation
Assumptions and approximations are required. (con’t)If there are tributaries entering the reach whose discharges are small compared to the inflow, they may be ignored.
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 8/19
FLOOD ROUTINGFLOOD ROUTING
Overview
IntroductionStorage EquationReservoir RoutingRouting in Natural Channels
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 9/19
FLOOD ROUTINGFLOOD ROUTING
Reservoir Routing
Reservoir routing provides methods for evaluating the effects of a reservoir on a flood wave passing through it.For the design and planning of hydraulic structures, it applies to the determination of the location and the capacity of reservoir, of the size of outlets or spillways, etc.
Change in flood hydrograph due to storage in the reservoir
In reservoir routing, it is assumed that the water surface in the reservoir is horizontal at all times and the relationship between the storage and discharge is constant.
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 10/19
FLOOD ROUTINGFLOOD ROUTING
Reservoir Routing
22
11
2122)( QtSQ
tSII +
∆=
−∆
++
Known Unknown
Known Obtained
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 11/19
FLOOD ROUTINGFLOOD ROUTING
Reservoir Routing
22
11
2122)( QtSQ
tSII +
∆=
−∆
++
Unknown
If not known Q0=I0
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 12/19
FLOOD ROUTINGFLOOD ROUTING
Reservoir Routing
22
11
2122)( QtSQ
tSII +
∆=
−∆
++
If Qn > In : to complete the outflow hydrograph after the end of the inflow hydrograph, the values of inflow are taken to be constant and equal to the last inflow value In and routing process is continued till an outflow value equal to or closer to In value is obtained. This way the lengthening on the base time can be determined.
If not known Q0=I0
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 13/19
FLOOD ROUTINGFLOOD ROUTING
Overview
IntroductionStorage EquationReservoir RoutingRouting in Natural Channels
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 14/19
FLOOD ROUTINGFLOOD ROUTING
Routing in Natural Channels
In natural channels, storage is not only a function of outflow but also inflow.
Storage in natural channels
Wedge storage may be positive or negative depending upon whether the food in coming toward the reach (+) or going away from the reach (-).
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 15/19
FLOOD ROUTINGFLOOD ROUTING
Routing in Natural Channels
(gain to storage during rising) > (loss from storage during falling)The routing procedure in the channels is obtained by expressing storage as a function of both outflow and inflow.
Change in flood hydrograph due to storage in the channel
Outflow vs storage
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 16/19
FLOOD ROUTINGFLOOD ROUTING
Determination of x by trial and error
Routing in Natural Channels
Muskingum Method is generally used in the channel routing procedure.
K: travel time of the center of mass of flood wave from the upstream end of the reach to the downstream end.
x: dimensionless constant. It indicates the effective weights of inflow and outflow.
)( QIKxKQS −+=
( )QxxIKS )1( −+=
TRIAL & ERROR METHODAssume x plot S vs [xI+(1-x)Q]The correct x is the one that gives closest to the straight line. K: slope of this line.
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 17/19
FLOOD ROUTINGFLOOD ROUTING
Routing in Natural Channels
Muskingum Method
( )111 )1( QxxIKS −+= ( )222 )1( QxxIKS −+=
22
11
2122)( QtSQ
tSII +
∆=
−∆
++
( ) ( )2
221
1121
)1(2)1(2)( Qt
QxxIKQt
QxxIKII +∆
−+=
−
∆−+
++
CVE 376 Engineering Hydrology, 2e © 2005 METU Press. 18/19
FLOOD ROUTINGFLOOD ROUTING
Rearranging above equation for inflow and outflow terms
Routing in Natural Channels
Muskingum Method
1122)1(222)1(2 Qt
txKItKxtI
tKxtQ
ttxK
∆∆−−
+∆+∆
+∆−∆
=∆
∆+−
( ) ( )2
221
1121
)1(2)1(2)( Qt
QxxIKQt
QxxIKII +∆
−+=
−
∆−+
++
1122 )1(2)1(2
)1(22
)1(22 Q
txKtxKI
txKKxtI
txKKxtQ
∆+−∆−−
+∆+−
+∆+
∆+−−∆
=
1211202 QCICICQ ++= 1210 =++ CCC