ser way chapter 5
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Chapter 5
Energy
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Some Energy
ConsiderationsEnergy can be transformed from oneform to another
The total amount of energy in the Universenever changesEssential to the study of physics, chemistry,biology, geology, astronomy
Can be used in place of Newton’s lawsto solve certain problems more simply
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WorkProvides a link between force andenergyThe work, W , done by a constantforce on an object is defined as theproduct of the component of theforce along the direction ofdisplacement and the magnitudeof the displacement
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WorkW = F x
This equation
applies when theforce is in thesame direction asthe displacement
are inthe same directionand F x
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Work GeneralW = (F cos ) x
F is the magnitude
of the forceΔ x is themagnitude of theobject’s
displacement is the anglebetween
and F x
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Work, cont.This gives no information about
The time it took for the displacementto occurThe velocity or acceleration of theobject
Work is a scalar quantity
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Units of WorkSI
Newton • meter = Joule N • m = J J = kg • m 2 / s 2
US Customary
foot • pound ft • lb
no special name
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More About WorkThe work done by a force is zerowhen the force is perpendicular tothe displacement
cos 90° = 0
If there are multiple forces actingon an object, the total work doneis the algebraic sum of the amountof work done by each force
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More About Work, cont.Work can be positive or negative
Positive if the force and thedisplacement are in the samedirectionNegative if the force and the
displacement are in the oppositedirection
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When Work is ZeroDisplacement ishorizontal
Force is verticalcos 90° = 0
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Work Can Be Positive or
NegativeWork is positivewhen lifting theboxWork would benegative iflowering the box
The force wouldstill be upward,but thedisplacementwould be
downward
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Work, FinalWork doesn’t happen by itself Work is done by something in theenvironment, on the object ofinterestThe forces are constant
Varying force will be discussed later
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Work and Dissipative
ForcesWork can be done by frictionThe energy lost to friction by an object
goes into heating both the object andits environmentSome energy may be converted into sound
For now, the phrase “Work done by
friction” will denote the effect of thefriction processes on mechanical energyalone
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Kinetic EnergyEnergy associated with the motionof an object Scalar quantity with the sameunits as workWork is related to kinetic energy
2mv21KE
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Work-Kinetic Energy
TheoremWhen work is done by a net force on anobject and the only change in the object
is its speed, the work done is equal tothe change in the object’s kineticenergy
Speed will increase if work is positiveSpeed will decrease if work is negative
net f i W KE KE KE
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Section 2 Energy Chapter 5
Sample Problem
Work-Kinetic Energy Theorem On a frozen pond, a person kicks a 10.0 kg sled,giving it an initial speed of 2.2 m/s. How far does the
sled move if the coefficient of kinetic friction betweenthe sled and the ice is 0.10?
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Section 2 Energy Chapter 5
Sample Problem, continued
Work-Kinetic Energy Theorem1. Define
Given: m = 10.0 kgv i = 2.2 m/sv f = 0 m/s
µk = 0.10Unknown: d = ?
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Section 2 Energy Chapter 5
Sample Problem, continued
Work-Kinetic Energy Theorem2. Plan
Choose an equation or situation: This problem can besolved using the definition of work and the work-kineticenergy theorem.
W net = F net d cos The net work done on the sled is provided by the forceof kinetic friction.
W net = F k d cos = µk mgd cos
S i 2 E
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Section 2 Energy Chapter 5
Sample Problem, continued
Work-Kinetic Energy Theorem2. Plan, continued
The force of kinetic friction is in the direction opposite d,
= 180°. Because the sled comes to rest, the finalkinetic energy is zero.W net = ∆ KE = KE f - KE i = – (1/2) mv i 2
Use the work-kinetic energy theorem, and solve for d .
2
2
1 – cos2
–2 cos
i k
i
k
mv mgd
v d
g
S i 2 E
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Section 2 Energy Chapter 5
Sample Problem, continued
Work-Kinetic Energy Theorem3. Calculate
Substitute values into the equation:
2
2
(–2.2 m/s)2(0.10)(9.81 m/s )(cos180 )
2.5 m
d
d
S i 2 E
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Section 2 Energy Chapter 5
Sample Problem, continued
Work-Kinetic Energy Theorem4. Evaluate
According to Newton’s second law, the accelerationof the sled is about -1 m/s 2 and the time it takes thesled to stop is about 2 s. Thus, the distance the sledtraveled in the given amount of time should be lessthan the distance it would have traveled in the
absence of friction.2.5 m < (2.2 m/s)(2 s) = 4.4 m
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Work and Kinetic EnergyAn object’s kineticenergy can also bethought of as theamount of work themoving object coulddo in coming to rest
The moving hammer
has kinetic energyand can do work onthe nail
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Types of ForcesThere are two general kinds offorces
ConservativeWork and energy associated with theforce can be recovered
NonconservativeThe forces are generally dissipative andwork done against it cannot easily berecovered
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Conservative ForcesA force is conservative if the work itdoes on an object moving between two
points is independent of the path theobjects take between the pointsThe work depends only upon the initial andfinal positions of the object
Any conservative force can have a potentialenergy function associated with it
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More About Conservative
ForcesExamples of conservative forcesinclude:
GravitySpring forceElectromagnetic forces
Potential energy is another way oflooking at the work done byconservative forces
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Nonconservative ForcesA force is nonconservative if thework it does on an object depends
on the path taken by the objectbetween its final and startingpoints.Examples of nonconservativeforces
Kinetic friction, air drag, propulsiveforces
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Friction Depends on the
PathThe blue path isshorter than thered pathThe work requiredis less on the bluepath than on thered pathFriction dependson the path andso is a non-conservative force
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Potential EnergyPotential energy is associated withthe position of the object withinsome system
Potential energy is a property of thesystem, not the object
A system is a collection of objectsinteracting via forces or processesthat are internal to the system
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Work and Potential EnergyFor every conservative force apotential energy function can befoundEvaluating the difference of thefunction at any two points in an
object’s path gives the negative ofthe work done by the forcebetween those two points
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Gravitational Potential
EnergyGravitational Potential Energy isthe energy associated with therelative position of an object inspace near the Earth’s surface
Objects interact with the earth
through the gravitational forceActually the potential energy is forthe earth-object system
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Work and Gravitational
Potential EnergyPE = mgy
Units of PotentialEnergy are thesame as those ofWork and KineticEnergy
f igravity PEPEW
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Work-Energy Theorem,
ExtendedThe work-energy theorem can beextended to include potential energy:
If other conservative forces are present,potential energy functions can be
developed for them and their change inthat potential energy added to the rightside of the equation
( ) ( )nc f i f i W KE KE PE PE
Section 3 Conservation of
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Section 3 Conservation of Energy Chapter 5
Sample Problem
Conservation of Mechanical EnergyStarting from rest, a child zooms down a frictionlessslide from an initial height of 3.00 m. What is her
speed at the bottom of the slide? Assume she has amass of 25.0 kg.
Section 3 Conservation of
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Section 3 Conservation of Energy Chapter 5
Sample Problem, continued
Conservation of Mechanical Energy1. DefineGiven:
h = h i = 3.00 mm = 25.0 kgv i = 0.0 m/sh
f = 0 m
Unknown: v f = ?
Section 3 Conservation of
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Section 3 Conservation of Energy Chapter 5
Sample Problem, continued
Conservation of Mechanical Energy2. Plan
Choose an equation or situation: The slide isfrictionless, so mechanical energy is conserved.Kinetic energy and gravitational potential energy arethe only forms of energy present.
21 2
KE mv
PE mgh
Section 3 Conservation of
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Section 3 Conservation of Energy Chapter 5
Sample Problem, continued
Conservation of Mechanical Energy2. Plan, continued
The zero level chosen for gravitational potentialenergy is the bottom of the slide. Because the childends at the zero level, the final gravitational potentialenergy is zero.
PE g,f = 0
Section 3 Conservation of
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Section 3 Conservation of Energy Chapter 5
Sample Problem, continued
Conservation of Mechanical Energy2. Plan, continued
The initial gravitational potential energy at the top of
the slide isPE g,i = mgh i = mgh
Because the child starts at rest, the initial kineticenergy at the top is zero.
KE i = 0 Therefore, the final kinetic energy is as follows:
212f f
KE mv
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Reference Levels for
Gravitational Potential EnergyA location where the gravitationalpotential energy is zero must be chosenfor each problem
The choice is arbitrary since the change inthe potential energy is the importantquantityChoose a convenient location for the zeroreference height
Often the Earth’s surface May be some other point suggested by theproblem
Once the position is chosen, it must remainfixed for the entire problem
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Reference Levels, contAt location A, thedesk may be theconvenient referencelevelAt location B, thefloor could be usedAt location C, theground would be themost logicalreference levelThe choice isarbitrary, though
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Conservation of
Mechanical EnergyConservation in generalTo say a physical quantity is conserved is tosay that the numerical value of the quantity
remains constant throughout any physicalprocess although the quantities may changeform
In Conservation of Energy, the totalmechanical energy remains constant
In any isolated system of objects interactingonly through conservative forces, the totalmechanical energy of the system remainsconstant.
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Conservation of Energy,
cont.Total mechanical energy is thesum of the kinetic and potential
energies in the system
Other types of potential energyfunctions can be added to modify thisequation
f f ii
f i
PEKEPEKE
EE
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Problem Solving with
Conservation of EnergyDefine the system
Verify that only conservative forces are presentSelect the location of zero gravitationalpotential energy, where y = 0
Do not change this location while solving theproblem
Identify two points the object of interestmoves between
One point should be where information is givenThe other point should be where you want to find outsomething
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Problem Solving, contApply the conservation of energyequation to the system
Immediately substitute zero values, then dothe algebra before substituting the othervalues
Solve for the unknown
Typically a speed or a positionSubstitute known valuesCalculate result
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Work-Energy With
Nonconservative ForcesIf nonconservative forces arepresent, then the full Work-Energy
Theorem must be used instead ofthe equation for Conservation ofEnergy
Often techniques from previouschapters will need to be employed
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Potential Energy Stored in
a SpringInvolves the spring constant , kHooke’s Law gives the force
F = - k xF is the restoring forceF is in the opposite direction of x
k depends on how the spring wasformed, the material it is made from,thickness of the wire, etc.
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Potential Energy in a
SpringElastic Potential Energy
Related to the work required to
compress a spring from itsequilibrium position to some final,arbitrary, position x 2
s kx21
PE
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Spring Potential Energy,
ExampleA) The spring is inequilibrium, neitherstretched orcompressedB) The spring iscompressed, storingpotential energyC) The block isreleased and thepotential energy istransformed tokinetic energy of theblock
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Work-Energy Theorem
Including a SpringWnc = (KE f – KE i) + (PE gf – PE gi) +(PE sf – PE si)
PEg is the gravitational potentialenergyPE s is the elastic potential energy
associated with a springPE will now be used to denote thetotal potential energy of the system
Section 2 Energy Ch 5
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Chapter 5
Sample Problem
Potential Energy A 70.0 kg stuntman is attached to a bungee cord withan unstretched length of 15.0 m. He jumps off a
bridge spanning a river from a height of 50.0 m.When he finally stops, the cord has a stretchedlength of 44.0 m. Treat the stuntman as a point mass,and disregard the weight of the bungee cord.
Assuming the spring constant of the bungee cord is71.8 N/m, what is the total potential energy relative tothe water when the man stops falling?
Section 2 Energy Ch 5
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Chapter 5
Sample Problem, continued
Potential Energy1. DefineGiven: m = 70.0 kg
k = 71.8 N/mg = 9.81 m/s 2 h = 50.0 m – 44.0 m = 6.0 m
x = 44.0 m – 15.0 m = 29.0 mPE = 0 J at river level
Unknown: PE tot = ?
Section 2 Energy Ch t 5
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Chapter 5
Sample Problem, continued
Potential Energy2. PlanChoose an equation or situation: The zero level for
gravitational potential energy is chosen to be at thesurface of the water. The total potential energy is thesum of the gravitational and elastic potential energy.
212
tot g elastic
g
elastic
PE PE PE
PE mgh
PE kx
Section 2 Energy Ch t 5
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Chapter 5
Sample Problem, continued
Potential Energy3. CalculateSubstitute the values into the equations and solve:
2 3
2 4
3 4
4
(70.0 kg)(9.81 m/s )(6.0 m) = 4.1 10 J1
(71.8 N/m)(29.0 m) 3.02 10 J2
4.1 10 J + 3.02 10 J
3.43 10 J
g
elastic
tot
tot
PE
PE
PE
PE
Section 2 Energy Ch t 5
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Chapter 5
Sample Problem, continued
Potential Energy4. Evaluate
One way to evaluate the answer is to make an
order-of-magnitude estimate. The gravitationalpotential energy is on the order of 10 2 kg 10m/s 2 10 m = 10 4 J. The elastic potential energyis on the order of 1 10 2 N/m 10 2 m 2 = 10 4 J.
Thus, the total potential energy should be on theorder of 2 10 4 J. This number is close to theactual answer.
Section 3 Conservation of Ch t 5
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Energy Chapter 5
Conservation of Mechanical Energy3. Calculate
Substitute values into the equations:
PE g,i = (25.0 kg)(9.81 m/s2)(3.00 m) = 736 J
KE f = (1/2)(25.0 kg) v f 2 Now use the calculated quantities to evaluate thefinal velocity.
ME i = ME f PE i + KE i = PE f + KE f 736 J + 0 J = 0 J + (0.500)(25.0 kg) v f 2 v f = 7.67 m/s
Sample Problem, continued
Section 3 Conservation of EChapter 5
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Energy Chapter 5
Sample Problem, continued
Conservation of Mechanical Energy4. Evaluate
The expression for the square of the final speed can
be written as follows:
Notice that the masses cancel, so the final speeddoes not depend on the mass of the child. This
result makes sense because the acceleration of anobject due to gravity does not depend on the massof the object.
v f 2
2 mghm
2 gh
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Conservation of EnergyIncluding a Spring
The PE of the spring is added toboth sides of the conservation of
energy equation The same problem-solvingstrategies apply
f sgisg )PEPEKE()PEPEKE(
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Nonconservative Forceswith Energy Considerations
When nonconservative forces arepresent, the total mechanical energy of
the system is not constantThe work done by all nonconservativeforces acting on parts of a systemequals the change in the mechanical
energy of the system
nc W Energy
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Nonconservative Forcesand Energy
In equation form:
The energy can either cross a boundary
or the energy is transformed into aform of non-mechanical energy such asthermal energy
( )( ) ( )
nc f i i f
nc f f i i
W KE KE PE PE or
W KE PE KE PE
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Transferring EnergyBy Work
By applying a forceProduces a displacement of the system
HeatThe process of transferring heat bycollisions between atoms or moleculesFor example, when a spoon rests in a cup ofcoffee, the spoon becomes hot becausesome of the KE of the molecules in thecoffee is transferred to the molecules of thespoon as internal energy
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Transferring EnergyMechanical Waves
A disturbance propagates through amediumExamples include sound, water, seismic
Electrical transmissionTransfer by means of electrical current
This is how energy enters any electricaldevice
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Transferring EnergyElectromagnetic radiation
Any form of electromagnetic waves
Light, microwaves, radio wavesFor example
Cooking something in your microwaveovenLight energy traveling from the Sun tothe Earth
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Notes About Conservationof Energy
We can neither create nor destroyenergy
Another way of saying energy isconservedIf the total energy of the system doesnot remain constant, the energy must
have crossed the boundary by somemechanismApplies to areas other than physics
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PowerOften also interested in the rate atwhich the energy transfer takes placePower is defined as this rate of energytransfer
SI units are Watts (W)
W Fv
t
2
2
J kg mW
s s
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Power, cont.US Customary units are generally hp
Need a conversion factor
Can define units of work or energy in terms
of units of power:kilowatt hours (kWh) are often used in electricbillsThis is a unit of energy, not power
W746slbft550hp1
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Center of MassThe point in the body at which allthe mass may be considered to be
concentratedWhen using mechanical energy, thechange in potential energy is relatedto the change in height of the centerof mass
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Work Done by VaryingForces
The work done bya variable force
acting on anobject thatundergoes adisplacement is
equal to the areaunder the graphof F x versus x
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Spring ExampleSpring is slowlystretched from 0
to xmax W = ½kx²
applied s= - = kxF F
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Spring Example, cont.The work is alsoequal to the areaunder the curveIn this case, the
“curve” is atriangle
A = ½ B h givesW = ½ k(x max ) 2 and W = PE