shaly sand equations

5
Shaly sand equations: Laminated shaly s and - forward calculation of re Poupon (1954) equation: Input Parameters: Type into the yellow fields the parameters. Rw = 0.05 Ohm m 0. m = n = deri!ed parameter: F = Rsh = 5 Ohm m Calculation:  "r#hie Poupon !aria$le input: V-shale 0.05 0.10 0.0 1.00 1.5 1.%0 1.%5 1.4& 0.95 1.%9 1.44 1.49 1.' 0.90 1.54 1.'0 1.'' 1.&9 0.5 1.&% 1.&9 1.5 1.99 0.0 1.95 .01 .0 . 0.&5 . .9 .%5 .50 0.&0 .55 .' .' .% 0.'5 .9' %.0 %.0 %. 0.'0 %.4& %.5% %.5 %.&0 0.55 4.1% 4.1& 4.1 4. 0.50 5.00 5.00 5.00 5.00 0.45 '.1& '.10 '.0% 5.90 0.40 &.1 &.'0 &.40 &.0 0.%5 10.0 9.&0 9.4 .45 0.%0 1%.9 1.&' 1 1.&9 10.5 0.5 0.00 1&.%9 15.% 1.50 0.0 %1.5 4.&5 0.49 15.4 0.15 55.5' %'.90 &.' 1.% 0.10 15.00 5'. %'.&' 1.55 0.05 500.00 4.0% 45.& 4.04 0.01 1500.00 99.5 49. 4.9' φ  = S w R t 1  R t = 1V sh  R w ( φ m S w n ) + V sh  R sh

Upload: ryodi-hananda

Post on 07-Jul-2018

220 views

Category:

Documents


0 download

TRANSCRIPT

Page 1: Shaly Sand Equations

8/18/2019 Shaly Sand Equations

http://slidepdf.com/reader/full/shaly-sand-equations 1/5

Page 2: Shaly Sand Equations

8/18/2019 Shaly Sand Equations

http://slidepdf.com/reader/full/shaly-sand-equations 2/5

sistivity

5

0.401.&91.95

.1%

.%4

.5

. '%.1&

%.54%.9'4.445.005.'4'.%&. 0

.19.09

10.011.0111.&91 .%1 .49

0.01 0.10 1.00

1.00

10.00

100.00

1000.00

10000.00

00.050.10

0. 00.40

w

* t

Vsh

Page 3: Shaly Sand Equations

8/18/2019 Shaly Sand Equations

http://slidepdf.com/reader/full/shaly-sand-equations 3/5

Shaly sand equations: Estimate of Sw from resistivity and shale conten

Equations:

Poupon+ 1954 ,ndonesia + 19&1

Input: Material parameter Type into the yellow fields the parameters

10.00 Ohm m

0.05 Ohm m

&.00 Ohm m

0. 0m = .00 deri!ed parameter: F =

n = .00

Calculation:

-aria$le Poupon ,ndonesia imandouVsh Sw Sw Sw

0.00 0.%54 0.%54 0.%540.05 0.%% 0.%4' 0.%490.10 0.%11 0.%% 0.%450.15 0. 9 0.% 9 0.%400. 0 0. '& 0.% 0.%%'0. 5 0. 45 0.%14 0.%%0.%0 0. 4 0.%0& 0.%0.%5 0. 0 0.%00 0.% 40.40 0.1&9 0. 94 0.% 00.45 0.15& 0. 0.%1'0.50 0.1%4 0. % 0.%1

R t=

R w

=

R sh =

Φ =

R o =

0.00 0.05 0.10 0.150.000

0.050

0.100

0.150

0. 00

0. 50

0.%00

0.%50

0.400

0.450

0.500

) w

.

S w = [ R w⋅( 1 R t

− V sh R sh )⋅

1φ m⋅

11 − V sh ]

1

n S w = {V sh(

1

−Vsh

2⋅

Page 4: Shaly Sand Equations

8/18/2019 Shaly Sand Equations

http://slidepdf.com/reader/full/shaly-sand-equations 4/5

imandou + 19'%

5

1. 5

0. 0 0. 5 0.%0 0.%5 0.40 0.45 0.50

Poupon,ndonesia

imandou

-/shale

S W = 1

2⋅ RW

φ m⋅

[√4 ⋅ φ

m

R W ⋅ ρ t

+

(V sh R sh )

2

− V sh R sh ]S w = {V sh

(1

−Vsh

2⋅√ R t

R sh+√ Rt

R0 }−

2

n

Page 5: Shaly Sand Equations

8/18/2019 Shaly Sand Equations

http://slidepdf.com/reader/full/shaly-sand-equations 5/5

(V sh R sh )

2

− V sh R sh ]