skema mrsm2015 - cikgu adura's blog 2€¦ · heat released when 1 mole of lead(ii) sulphate...
TRANSCRIPT
3
SECTION A
Question
No 1 Mark Scheme
Sub
Mark ΣM
(a)
Answer :
Analgesic
Sample answer:
Paracetamol // Aspirin
1
1
2
(b)
Sample answer :
1. To kill/inhibit all bacteria // to slow down/retard the growth of
bacteria 2. Bacteria can become resistant to the antibiotic // To avoid
become ill again
1
1
2
(c)
(i)
Sample answer :
Peria,Bitter gourd (Momordica charantia) //
Daun hempedu bumi (Andrographis paniculata) //
Daun misai kucing (Orthosiphon aristatus) //
Kacang panjang //
Akar petawali
(a : any reasonable answer)
1
1
(ii) Sample answer:
Lower cost // Easily available // Biodegradable // Less side effect
1
1
(d) Aspartame // Stevia // Honey // Maple syrup // Brown sugar 1 1
(e) (i) Answer :
Preservative
1
1
(ii)
Sample answer :
Increase cancer risk / can cause colon cancer / leukemia / nose
and throat cancer / can cause nausea / dizziness / carcinogenic
1
1
TOTAL
9
SKEMA MRSM2015
https://cikguadura.wordpress.com/
4
Question
No 2 Mark Scheme
Sub
Mark ΣM
(a) Answer :
Group 18 // Noble gases // Inert gases // Group VIII
1
1
(b)
Answer :
Helium r : He
Explanation
Sample answer :
Stable // not easily burnt // lighter // unreactive
1
1 2
(c)
(i) Answer :
2.8.1 / 2,8,1 r: 2:8:1
1
6
(ii)
Answer :
1. Nuclei attraction towards valence electron / Force of
attraction between nucleus/proton and valence electron
in atom Z is weaker
2. Ability for atom Z to release/lose one/valence electron is
easier
1
1
(iii)
Answer :
1. Ionic compound (r : ionic bond)
2. ZY (r : YZ)
(Accept actual symbol for Z/K and Y/Cl )
1
1
(iv) R, Q, Y, X, T, Z 1
TOTAL 9
5
Question No
3 Mark Scheme
Sub
Mark ΣM
(a)
(i) Answer:
Alkene 1
2
(ii)
Answer:
a: CH3CH=CHCH3
1
(b)
Answer :
C4H8 + 6 O2 4 CO2 + 4 H2O
1. Correct formula of reactants and products
2. Balanced equation
1
1 2
(c) Answer:
Phosphoric acid // 300 oC // 60 atm
1 1
(d)
(i) Answer :
Brown solution becomes colourless / decolourised
1
4
(ii) Answer :
2,3-dibromobutane
1
(iii)
Answer :
1. Bubble / pass through / flow the gas /compound P into
bromine water in a test tube/suitable container
// add bromine water into the test tube containing gas P
2. Shake
1
1
(e) Answer:
Butyl ethanoate
1 1
TOTAL
10
6
Question
No 4 Mark Scheme
Sub
Mark ΣM
(a)
Answer :
Acid V : hydrochloric acid // HCl
Alkali T: sodium hydroxide // NaOH
1
1 2
(b)
(i) Answer :
Neutralisation
1
2
(ii)
Answer :
HCl + NaOH NaCl + H2O
1. Correct formula reactants and products
1
(c)
Answer :
1. no. of mol of acid V = // 0.005 mol
2. From equation,
1 mol of acid V react with 1 mol alkali T
0.005 mol of acid V react with 0.005 mol alkali T
3. :. the concentration of alkali T = mol dm-3 //
= 0.2 mol dm-3
(ecf : no. of mol of acid V for P2 only )
OR
1. =
0.1 x 50 = Mb x 25
2. Mb = 0.2 mol dm-3 *(2 marks only for this method)
1
1
1
3
(d)
Answer :
1. Heat the solution until saturated and cool.
2. Filter and dry the crystal
1
1
2
(e) Answer :
Sodium ethanoate /Sodium acetate/ CH3COONa / NaCH3COO
1 1
TOTAL
10
7
Question
No 5 Mark Scheme
Sub
Mark ΣM
(a) Answer:
Heat released when 1 mole of lead(II) sulphate is formed
1
1
(b)
Sample answer :
Exothermic reaction //
The heat of precipitation for 1 mol of lead(II) sulphate is -50.4 kJ //
The heat released when 1 mol of lead(II) sulphate formed is 50.4 kJ
// Total energy content of the reactants/lead(II) nitrate and sodium
sulphate is higher than total energy content of the products/lead(II)
sulphate and sodium nitrate //
1 mol of lead(II) nitrate react with 1 mol of sodium sulphate to
produce 1 mol lead(II) sulphate and 1 mol sodium nitrate and
released 50.4 kJ
(Any one)
1
1
(c)
(i) Answer :
Heat change = (50)(4.2)(14) J // 2940 J // 2.940 kJ
1
4
(ii)
Answer:
1. Number of moles of Cu(NO3)2 = // 0.025 mol
2. 0.025 mol of Cu release 2940 J
.: 1 mol of Cu release 2940J x 1 = 117600 J
0.025
3. Heat of displacement, ∆H = - 117.6 kJ mol-1
(ecf : No of mole for P2)
1
1
1
(d)
Answer:
1. Sulphuric acid is a diprotic acid while hydrochloric acid is a
monoprotic acid // 1 mol of sulphuric acid produce 2 mol of H+
ions while 1 mol of hydrochloric acid produce 1 mol of H+ ions
2. Concentration of hydrogen ions in Experiment II/sulphuric acid
is doubled /twice/two times
3. Number of mole of water formed is double/twice/two times
1
1
1
3
(e)
Answer:
1. Functional diagram
2. Correct label
1
1
2
TOTAL 11
8
Question
No 6 Mark Scheme
Sub
Mark ΣM
(a) Answer :
Electrical to chemical energy
1
1
(b)
(i)
Answer :
Brown solid deposited
r: electrode become thicker
1
3
(ii) Answer :
Cu2+ + 2e Cu
1
(iii) Answer:
+2 to 0 1
(c)
Answer :
1. Oxygen gas r : O2
2. Insert/put/place the glowing wooden splinter into the test
tube/boiling tube.
3. The glowing wooden splinter relights/rekindles/reignites
*P1 must be correct in order to get P2 and P3
1
1
1
3
(d) Answer:
1. Blue to light blue // intensity of the blue colour
decreases
2. The concentration of Cu2+ ions /the number of Cu2+ ions
per unit volume decreased
1
1
2
(e)
Answer:
1. Copper(II) ion // Cu2+
2. Copper atom release electrons /ionise/oxidise to form Cu2+
1
1
2
TOTAL 11
9
Scheme Answer
Question
No 7 Mark Scheme Sub
Mark ΣM
(a) Answer :
1. Diffusion ( r : diffuse)
2. Potassium manganate(VII) consists of tiny and
discrete particles/ions
3. The particles/ions move in between / diffuse between
the space of agar / gel
4. from higher concentration to lower concentration
adp : particles / ions
1
1
1
1
4
(b) (i) Answer:
1. Correct symbol ; J / Li
2. Correct proton number and nucleon number 73 J
1
1
2
(ii) Answer :
1. Atom J has 3 proton and 3 electrons
2. The number of positive charges is equal to the number of
negative charges
3. Ion J+ have 3 protons and 2 electrons // Atom J lose one
electron to form ion J+1
4. The number of positive charge is more than the number of
negative charge by one unit
1
1
1
1
4
(c) (i) Answer:
1. Melting point and boiling point for MgO is higher
than CO2
2. The ions are held together by strong electrostatic
force
3. More heat energy is needed to overcome the force.
4. Molecule CO2 are held together by weak
intermoleculer force / Van der Waals force
5. Less heat energy needed to overcome the force
1
1
1
1
1
5
(ii) Answer:
1. MgO can conduct electricity in molten state or
aqueous solution
2. but CO2 cannot conduct electricity at any state.
3. MgO in solid cannot conduct electricity becouse ion
held together/do not have free moving ion
4. MgO in molten and aqueous solution consists of ion
that move freely/mobile
5. CO2 consists of neutral molecule / Do not have ions
1
1
1
1
1
5
TOTAL 20
10
Question
No 8 Mark Scheme Sub
Mark ΣM
(a) Answer:
1. Smaller size has larger total surface area
2. Absorb more heat
3. Time taken to cook is shorter
1
1
1
3
(b) (i) Answer:
1. Average rate of reaction experiment I
= 40 / 90 = 0.44 cm3 s-1
2. Average rate of reaction experiment II
= 40 / 150 = 0.27 cm3 s-1
1
1
2
(ii) Answer :
1. Label the axis and unit
2. Correct position of the three curves and labeled
3. Volume marked at 40 cm3 and time taken shown correctly
for all experiments
1
1
1
3
(iii) Answer :
Zn + 2 H+ Zn2+ + H2
1. Correct formula of the reactants and products
2. Balanced equation
1
1
2
(iv) Answer :
Experiment I and II
1. Rate of reaction of Experiment I is higher
2. Copper(II) sulphate solution acts as catalyst
3. provide an alternative path with lower activation energy
4. More colliding particles able to achieve the activation
energy
5. The frequency of effective collision between zinc atom
and hydrogen ions is higher
*adp : higher
Experiment II and III
1. Rate of reaction in experiment II is higher
2. The concentration of hydrochloric acid in experiment II is
higher
3. The number of hydrogen ions per unit volume is higher
4. The frequency of collision between zinc atom and
hydrogen ions is higher
5. The frequency of effective collision between particles is
higher
1
1
1
1
1
1
1
1
1
1
10
TOTAL 20
Volume /cm3
Time /s
11
Question
No 9 Mark Scheme
Sub
Mark ΣM
(a) Answer:
1. Reinforced concrete is made up of concrete and steel/
steel bars/ steel wires / polymer fibres
2. Concrete is strong but brittle/ weak in tension
3. And steel is strong in tension
4. Combination of concrete and steel produced a tough and
more tensile strength material
1
1
1
1
4
(b) Answer :
1. SO2 causes respiratory problem in humans
2. Sulphur dioxide dissolves in rainwater to form acid rain.
3. Lakes and rivers become acidic
4. Fish and other aquatic organisms die
5. pH of the soil decreases
6. Salts are leached out of the top soil./ roots of trees are
destroyed / plants die of malnutrition and diseases
*P3,4,5 & 6 are given marks if P2 is mentioned.
1
1
1
1
1
1
6
(c) Answer:
Apparatus : 1 kg weight, ruler, retort stand and clamp , steel
ball bearing , thread
Materials : copper block, bronze block, // copper block,
brass block , cellophane tape
(a: If materials and apparatus are listed together)
Procedure
1. Steel ball bearing is taped onto a copper block
2. A [1-2] kg weight is hung at a height of 50 cm above the
steel ball bearing.
3. The weight is allowed to drop onto the steel ball bearing
4. The diameter of the dent made by the ball bearing on the
copper block is measured.
5. Step 2-4 are repeated three times
6. The experiment is repeated using bronze block/ brass
block
Tabulation of data
Metal block Diameter of dent (mm)
1 2 3 Average
Copper
Bronze /brass
1. Label heading for type of metal block(MV)
2. Label heading for diameter of the dent with unit (RV)
(If values are given, must be consistent with observation)
Observation
The diameter of the dent on the bronze /alloy block is smaller
than copper/pure metal block
1
1
1
1
1
1
1
1
1
1
1
11
Max
10
TOTAL 20 https://cikguadura.wordpress.com/
12
Question
No 10 Mark Scheme
Sub
Mark ΣM
(a) Answer:
In reaction I,
1. Iron(II) ion acts as a reducing agent/reductant
2. Iron(II) ion releases electron to form iron(III) ion//
Oxidation number of iron increase from +2 to +3//
Iron(II) ion is oxidized to form iron(III) ion //
Iron(II) ion reduced Br2 to bromide ion
In reaction II,
3. Iron(II) ion acts as an oxidising agent/oxidant
4. Iron(II) ion receive electron to form iron atom //
Oxidation number of iron decrease from +2 to 0//
Iron(II) ion is reduced to form iron atom //
Iron(II) ion oxidized zinc to zinc ion
1
1
1
1
4
(b) Answer :
1. N, carbon, M
Experiment I
2. M can reduce carbon dioxide to carbon// M can react
with carbon dioxide
3. M is more reactive than carbon
Experiment II
4. Carbon can reduce N oxide to N// carbon can react
with N oxide
5. Carbon is more reactive than N
6. Metal M is magnesium/ aluminium (r: Zinc)
7. Metal N is copper
1
1
1
1
1
1
1
7
Max
6
(c) Sample Answer:
1. Example of oxidising agent: bromine water/chlorine
water/ acidified potassium manganate(VII) / acidified
potassium dichromate(VI).
Procedure
2. Clamp a U-tube to a retort stand.
3. Pour dilute sulphuric acid into the U-tube
4. Carefully add potassium iodide solution to one of the
arms of the U-tube
5. Carefully add bromine water to the other arm of the
U-tube.
6. Dip a carbon electrode in each of the solution.
7. Connect the electrodes to a galvanometer
Confirmatory test
8. Using a clean glass tube or dropper, draw out 1 cm3
of potassium iodide solution into a test tube. Add a
few drops of starch solution into the test tube.
Observations
9. At potassium iodide/negative terminal brown solution
1
1
1
1
1
1
1
1
1
13
is formed that change starch solution to blue black
10. Bromine water change from brown to colorless //
chlorine water change from pale yellow to colourless
// acidified potassium manganate(VII) change from
purple to colourless //acidified potassium
dichromate(VI) change from orange to green
11. Deflection of needle of galvanometer
1
1
11
Max
10
TOTAL 20
END OF MARKING SCHEME
4541/3
3
1(a) KK0503 – Measuring and using number
Question Mark Scheme Mark
1(a) Able to record all the time taken at five different temperatures
correctly with one decimal place.
Answers:
Temperature / 0C 25.0 30.0 40.0 50.0 60.0
Time /s 95.0 80.0 60.0 47.0 40.0
3
Able to record the time taken correctly with no or two decimal
places // Able to record the time taken in at least 3 experiments with
one decimal place correctly.
2
Able to record the time taken in two experiments correctly. 1
No response given OR wrong response 0
1(b) KK0506 – Communicating
Question Mark Scheme Mark
1(b) Able to construct a table correctly with the following aspects :
(i) Three column with correct quantities and units ;Temperature/ 0C ,
Time taken / s , 1/time / s-1
(ii) Correct all reading of time taken with one decimal place
(iii) Correct all reading of 1/ time to 3 decimal places.
Suggested answer:
Temperature / 0C
25.0 30.0 40.0 50.0 60.0
Time /s 95.0 80.0 60.0 47.0 40.0
/ s-1
0.011 0.013 0.017 0.021 0.025
3
Able to construct a table correctly with 2 following aspects
#If any of the time taken in 1(a) is wrong but transferred correctly in
the table
2
Able to construct a table correctly with 1 following aspect 1
No response given OR wrong response 0
SKEMA MRSM2015https://cikguadura.wordpress.com/
4541/3
4
1(c)(i) KK0506 – Communicating
Question Mark Scheme Mark
1(c)(i)
Able to plot the graph with the following criteria :
(i) Both axes with correct labels and units
Y- axis : Temperature/ 0C [#Scale not necessary begin from 0]
X-axis : 1/ time / s-1 [#Scale must begin from 0]
(ii) Correct scale and all points are transferred correctly.
# size of the graph at least half of graph paper
#adp data from 1(a)
(iii)Best fit line
3
Able to plot the graph with the following criteria :
(i) reverse position of axes
(ii) 2 points are transferred correctly
(iii)Line
2
Able to give an idea to plot the graph
(i) Label at least one axis without unit
(ii) Line
1
No response or wrong response
0
4541/3
5
1(c)(ii) KK0506 – Communicating
Question Mark Scheme Mark
1(c)(ii)
Able to state the relationship between temperature and the rate
of reaction correctly
Sample answer
When the temperature increases, the rate of reaction increases//
The rate of reaction increases when temperature increases.//
When the temperature is higher, the rate of reaction is higher
3
Able to state the relationship between the rate of reaction and
temperature less correctly
Sample answer
The rate of reaction increases //
Rate of reaction is directly proportional to temperature//
The higher the rate , the higher the temperature
2
Able to give an idea of rate of reaction
Sample answer
The rate of reaction changes // increase
1
No response or wrong response
Sample answer
Temperature increases
0
4541/3
6
1(c)(iii)KK0505 – Predicting
Question Mark Scheme Mark
1(c)(iii)
Able to predict the time taken to collect 30 cm3 of hydrogen gas
at 45.0 0C correctly with the following aspects :
(i) Show on the graph (extrapolate )
(ii) Show the calculation step
(iii) Time taken with correct unit and one decimal place
Answer
1/ time = 0.019 s-1 [value in range 0.018 0.020 s-1]
.: time = 52.6 s [ value in range 50.0 -55.6 s ]
3
Able to predict the time taken to collect 30 cm3 of hydrogen gas
at 45.0 0C with correct unit
Answer
Value in range: 0.016 ˂ 1/t ˂ 0.018 s-1 and 0.020 ˂ 1/t ˂ 0.022 s-1 ,
55.6 ˂ t ˂ 62.5 s and 45.5 ˂ t ˂ 50.0 s
2
Able to give an idea in prediction
Any value other than Score 3 and Score 2 // more than 48.0 s // less
than 60.0 s
1
No response or wrong response
0
4541/3
7
1 (d) KK0509 – Defining operationally
Question Mark Scheme Mark
1(d)
Able to describe the following criteria :
(i) What should be done :
(ii) What should be observed
Sample answer
Time taken to collect hydrogen gas when hydrochloric acid is
reacted with zinc powder //
When hydrochloric acid is reacted zinc powder, time taken to collect
gas is recorded.
3
Able to describe the either criterion (i) or (ii)
Sample answer
Time taken to collect hydrogen gas //
hydrochloric acid is reacted with zinc powder//
The speed at which reactants are converted to products//
Rate of reaction = change in selected quantity
time taken
2
Able to give an idea for the rate of reaction
Sample answer
Time taken // Volume of hydrogen gas collected
1
No response or wrong response
0
4541/3
8
1 (e) KK0507 – Space time relationship
Question Mark Scheme Mark
1(e)
Able to explain correctly with the following aspects.
(i) Zinc strip has bigger size
(ii) Smaller total surface area
(iii)The rate of reaction is lower
Sample answer
P1. Zinc strip has bigger size.
P2. Smaller total surface area of zinc that exposed
P3. The rate of reaction decreases/lower // Reaction is slow
3
Able to give 2 aspects correctly
2
Able to give one aspect correctly or an idea
Sample answer
Big size // Smaller total surface area // Rate of reaction is low
1
No response or wrong response
0
4541/3
9
2 (a) KK0510 – Controlling variables
Question Mark Scheme Mark
2 (a)
Able to state the three variables correctly
Sample answer
Manipulated variable
Type of metal // Copper , zinc and silver
Responding variable
Displacement reaction// displacement silver // solid formed // grey
solid formed
Fixed variable
Silver nitrate solution // Volume/concentration of silver nitrate
solution // Type of solution
3
Able to state any two variables correctly
2
Able to state any one variable correctly
1
No response or wrong response
0
4541/3
10
2 (b) KK05011- Hypothesizing
Question Mark Scheme Mark
2 (b)
Able to state the relationship between the manipulated variable
and the responding variable and state the direction correctly
Sample answer
A more electropositive metal can displace silver from silver nitrate
solution //
More electropositive metal will displaced less electropositive metal
from its salt solution //
Zinc and copper can displace silver from silver nitrate solution//
A metal higher in position in Electrochemical Series will displace a
metal lower in position in Electrochemical Series from its solution
3
Able to state the relationship between the manipulated variable
and the responding variable without stating the direction//
* RV → MV
Sample answer
A more electropositive metal can displace silver //
More electropositive metal will displaced less electropositive metal //
Zinc / copper can displace silver from silver nitrate solution//
*Metal will be displaced from its salt solution by a more
electropositive metal
2
Able to state the idea of hypothesis
Sample answer
Metal will be displaced // Silver is displaced // Silver ion is displaced
1
No response or wrong response
0
4541/3
11
2(c) KK0508 – Interpreting data
Question Mark Scheme Mark
2(c)
Able to arrange the three metals correctly.
Answer
Silver , Copper , Zinc // Ag , Cu , Zn
# Skor 1 : If fully stated in reverse
3
Able to arrange any two metals in sequence correctly.
Sample answers
Zinc , Silver , Copper // Zn , Ag , Cu
Copper , Zinc , Silver // Cu , Zn , Ag
2
Able to arrange the three metals in reverses sequence.
Answer
Zinc , Copper , Silver // Zn , Cu , Ag
1
No response or wrong response
0
4541/3
12
2(d)KK0502 – Classification
Question Mark Scheme Mark
2(d)
Able to classify all the six metals correctly
Sample answer
Metal which are more
electropositive than lead
Metal which are less
electropositive than lead
Magnesium // Mg
Zinc // Zn
Aluminium // Al
Iron // Fe
Copper // Cu
Silver // Ag
#Score 1 : If classification is reverse
3
Able to classify at least 5 metals correctly
2
Able to classify at least 3 metals correctly
1
No response or wrong response
0
4541/3
13
Question 3– Experimenting
Question Mark Scheme Mark
3(a)
Able to give the problem statement correctly
Sample answer
Is detergent more / less effective in cleansing action in sea water
compared to soap? //
Is soap more / less effective in cleansing action in sea water
compared to detergent? //
Is detergent more effective as cleansing agent in sea water compared
to soap?
3
Able to give the problem statement
Sample answer
Which one is more effective in sea water, detergent or soap?//
To investigate the effectiveness of soap and detergent in sea water //
Does detergent and soap show different effectiveness in sea water? //
Detergent has more ability to removes stain compared to soap
2
Able to give an idea of the problem statement
Sample answer
Detergent is more effective // Soap is more effective // Detergent
cleans better
1
No response or wrong response
0
4541/3
14
Question Mark Scheme Mark
3(b)
Able to state all the three variables correctly
Sample answer
Manipulated variable
Detergent and soap // Type of cleansing agent
Responding variable
Effectiveness of cleansing // Absence / presence of oily stains //
Formation of scum // Ability to remove stain
Fixed variable
Sea water // Size of oily stains
3
Able to state any two variables correctly
2
Able to state any one variable correctly
1
No response or wrong response
0
4541/3
15
Question Mark Scheme Mark
3(c)
Able to state the hypothesis correctly
Sample answer
Detergent is more effective in cleansing action in sea water while
soap is less effective //
When detergent is used, the oily stains is removed while when soap
is used , the oily stains remains//
When detergent is used ,no scum is formed while when soap is used ,
scum is formed.
3
Able to state the hypothesis
Sample answer
Detergent is more effective in cleansing action in sea water //
When detergent is used, the oily stains is removed//
When detergent is used ,no scum is formed while when soap is used ,
scum is formed//
Detergent is more effective in cleansing action in sea water than
soap//
Effectiveness of cleaning action is higher in sea water when used
detergent compared to soap//
The oily stains is removed when detergent is used while the oily
stains remains when soap is used//
No scum will formed when detergent is used while scum will
formed when soap is used//
Effectiveness of detergent and soap in sea water are different
2
Able to give an idea of the hypothesis
Sample answer
Different cleansing agent have different effectiveness in sea water//
No scum formed in detergent //
Scum will formed in soap //
Effectiveness of detergent and soap in sea water are different
1
No response or wrong response
0
4541/3
16
Question Mark Scheme Mark
3(d)
Able to list the materials and apparatus completely
Sample answer
Materials
1. Soap
2. Detergent
3. Sea water
4. Cloth with oily stains // Dirty cloth
Apparatus
1. Measuring cylinder
2. Beaker
3. Stirrer / glass rod
3
Able to list the materials and apparatus
Sample answer
Materials
1. Soap solution
2. Detergent
3. Sea water
4. Cloth with oily stains // Dirty cloth
Apparatus
1. Measuring cylinder
2. Any suitable container
2
Able to give an idea of materials and apparatus
Sample answer
Materials
1. Soap solution / 2. Detergent
3. Sea water
4. Cloth with oily stains // Dirty cloth
Apparatus
1.[Any suitable container]
1
No response or wrong response
0
4541/3
17
Question Mark Scheme Mark
3(e) Able to list all the steps of procedure correctly
Sample answer
√1
1. Measure [20-100]cm3 of sea water by using measuring cylinder
and pour into a beaker.
√2
2. Add [10-50] cm3 of soap solution
√3
3. Put a piece of cloth with oily stain into the beaker
√4
4. Shake / Stir the mixture
√5
5. Record the observations after 10 minutes
√6
6. Repeat steps 1 to 5 using detergent to replace soap solution
3
Able to state the steps 1 , 2 , 3 , 5 and 6 less correctly
Sample answer
√1
1. Measure sea water by using measuring cylinder and pour into a
beaker
√2
2. Add soap solution
√3
3. Put a piece of cloth with oily stain into the beaker
√5
5. Record the observations
√6
6. Repeat the experiment
2
Able to state steps 1 , 2 and 3
1
No response or wrong response
0
4541/3
18
Question Mark Scheme Mark
3(f)
Able to construct a table that consists of :
1. Headings for manipulated and responding variables
2. List of cleansing agent : detergent and soap
Sample answer
Cleansing agent Observation
Soap
Detergent
2
Able to construct a table that consists of :
1. Headings for manipulated or responding variables
Sample answer
Type of cleansing agent Observation
Observation
Type of cleansing agent
1
No response or wrong response
0
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