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Advances in Theoretical and Applied Mechanics, Vol. 7, 2014, no. 2, 91 - 111
HIKARI Ltd, www.m-hikari.com
http://dx.doi.org/10.12988/atam.2014.4816
Solution for the Motion of a Symmetric Euler
Gyroscope for Arbitrary Initial Values of the Euler
Angles using Eру Kinematic
Differential Poisson Equations
P. K. Plotnikov
Yu. Gagarin State Technical University of Saratov.77 Politechnicheskaya
Street 410054 Saratov, Russia
Copyright © 2014 P. K. Plotnikov. This is an open access article distributed under the Creative
Commons Attribution License, which permits unrestricted use, distribution, and reproduction in
any medium, provided the original work is properly cited.
Abstraсt
It is proved that the regular precession in symmetric Euler gyroscope (SEG) is not
the unique type of motion, it corresponds only to well-known initial Euler angles
slaving between them. For any other initial angles arise movement different from
the regular precession. The paper solved analytically, as a result of integration of
the differential kinematic equations Poisson with periodic coefficients, the
problem of motion of the SEG with arbitrary initial Euler angles. Periodic
coefficients – are SEG angular velocity, found as a solution independent from
angles of its dynamical equations. Derived from the general formulas obtained for
private, agreed initial Euler angles formulas for regular precession, coinciding
with the well-known. For some changed in relation to them the initial angle are
received formulas for irregular precession. In addition to the solutions of the Euler
angles obtained the solutions in Euler - Krylov angles. The analytical results are
supported by the mathematical modeling. In particular, we find conditions
("whack") when the irregular SEG precession at the Euler-Krylov angles occurs
in the direction of the rotational impulse and the sign of the angular velocity of
proper rotation is reversed. In Euler angles of the motion of irregular precession
92 P. K. Plotnikov
at a «strong» and «weak» impact are qualitatively the same. In relation to the
case of regular precession the changes are significant: the angles of precession and
nutation are oscillatory, and the angular velocity and the angle of proper rotation
change their sign to the opposite.
Keyword: symmetric Euler gyroscope, precession, Euler angles, Poisson
equations, rotation, mathematical modeling, nutation, Euler-Krylov angles,
angular velocity, impact, drift
Statement of the problem. Solution of the problem of the inertial motion of a
symmetric Euler gyroscope (SEG) is well known and is described in many works,
in particular, in [1,2,5]. This movement is a regular precession, nutation
characterized by a constant angle between the axis of angular momentum,
combined with the axis inertial basis, and the axis of own rotation of the SEG. In
this case the angular velocity of precession and nutation are constant.
These properties have been used in [4] in the preparation of the experiment on
tests of general relativity using SEG and telescope on the satellite when deciding
on the choice of the relations between the principal moments of inertia, ensuring a
very small angular velocity of precession. In the experiment [7-8] angular velocity
drifts amounted magnitude less than 10-11 deg / h, which provided the Einstein
theory true with an error of less than 1%.
Note that the solution of the problem of regular precession became possible
under the following restrictions on the initial Euler angles [5, formulas (2.39),
(2.41)]: G
Crconstconst 0
000 cos;0;
where G - the angular momentum; r - the component of the angular velocity SEG
on proper rotation axis; C- SEG principal moment of inertia around the same axis.
In contrast to [1, 2, 5], the problem is solved in two stages. The first stage of the
problem is to determine the angular velocity of the gyroscope, what is achieved by
integrating of the dynamic equations of motion of the SEG, around the equatorial
axis which is acted rotary pulse (shock). Initial Euler angles - zero, because one of
the axes of the inertial system is directed along the vector of the angular
momentum of the SEG and the other axis at the initial time were combined with
the other two axes of the inertial coordinate system. The angular SEG momentum
its size and direktion are changed as the result of shock. At the same stage for zero
initial conditions are determined by the current Euler angles after integration of
kinematic Poisson equations whose coefficients are found by the angular velocity
of the SEG. Formulas for the Euler angles found in the first stage, show the
irregular precession. In the second phase are taken in consideration nonzero initial
Euler angles. By using the matrix method of addition of turns are taken the
formulas for the resulting Euler angles of rotation, as well as the Euler-Krylov. As
a special case, for known, mutually initial conditions (see. Previous paragraph) are
Solution for the motion of a symmetric Euler gyroscope 93
the expressions for the regular precession. Of these same formulas for irregular
precession angles for some other arbitrary initial angles are received too.
1. About the problem of influence of initial conditions of the
kinematic equations on the character of motions of a
symmetric Euler gyroscope
In this section the following task is set: to define exactly the range of values of
initial Euler angles for Euler kinematic equations symmetric gyroscope (SEG) at
which they become identities- after the substituting them their analytical solutions
given in [1], as well as the range of solutions of dynamic equations given in [5].
As these solutions describe the regular precession, then the question is, at what
initial conditions, it is observed, and on what conditions it is not.
Dynamic equations for symmetric Euler gyroscope form [1, p. 126]
.;0;0
;0
;0
0 constrrdt
dr
dt
drC
rpCAdt
dqA
qrACdt
dpA
(А.1)
Kinematic Euler equations [1, p. 115]
.cos
;sincossin
;cossinsin
r
q
p
(А.2)
Solutions of these equations, obtained in [1, § 37]:
.cos;
;;cos
;;
00101
0
0
0
nrntn
constG
Cr
G
Cr
AGnnt
(А.3)
Here Gr ,0 ; 2
0
222222 rCqApAG - constants.
94 P. K. Plotnikov
Equations (A.2), solved with respect to [5, p. 46]:
.cossin
;sincos
;sin
cossin
qpctgrdt
d
qpdt
d
qp
dt
d
(А.4)
According to solutions of equations (A.1) and the notation of [5, p. 88], we have:
.tan;sin;
;;;
;;cos;sin
30
10
0
10
0
1
2
30
22
10
22
300102101
C
A
G
An
nHGCAG
rrtqtp
(А.5)
Substituting (A5) in (A4), and using (A3) for the third equation in (A.4):
;coscossin
;coscossinsin
cos
0100100
0
00
10000
ttA
G
tg
ttttr
A
Gr
.coscos 01010010
10
G
A
A
G (А.6)
Equality (A.6) is an identity in
00 ; ,...3,2,12 mm , (А.7)
I.e. the angle should be zero. For the equation (A.2) of (A.4) we have
;sincoscossin0 0010 tttt
.sinsin0 010010 tt (А.8)
Equality (A8) becomes an identity at angles 0 =0; ,...3,2,1 mm .
For the angle nt0 of the first equation in (A.4) we have
.
sincossin
AGqp
n
(А.9)
Solution for the motion of a symmetric Euler gyroscope 95
Considering (A3) and (A5), we obtain:
;coscossin 0100100 ttA
G
01010010
10 coscos
G
A
A
G,
I.e. we obtain again correlations (A.7). This means that equation (A9) becomes an
identity when 0 ; tn1 ; for any values 0 . From (A9), it also follows that
the variation of the angle 0 of the initial value 0 , i.e. 00 the
equality (A.9) will not turn into an identity.
From these calculations, we conclude that the regular precession of a gyroscope in
symmetric Euler gyroscope is only possible under the following initial values of
the angles:
.cos;0; 0000 G
Crconstconst (А.10)
In any other initial values of the Euler angles the equations (A.4) will be identical
with other solutions which do not coincide with the functions of (A3).
The actuality of the article is confirmed by publications [4,7,8].
2. Solution of Problem using the Poisson equation for arbitrary
initial Euler angles
Given in [9] the solutions of the Poisson equations for zero initial angles as
matriciant (7) [9] containing the periodic final relations, and the results of the
mathematic simulation listed in the annex to this article, also prove the result that
- in different from (A.10) of the initial values of the angle there is an irregular
precession. There are also analytical solutions for
,cos;0; 0000 G
Crconst
also for 000 ;0; ,
that in the first variant of the initial angles describe regular, and in the second
version irregular precession.
Above we show that the regular precession of SEG, which is characterized by
(A.5), occurs only when the initial values of the angles are described by (A.10).
With any other initial values of these angles occurs irregular precession. In
particular, for zero initial angles of the problem is solved in [9, 10] analytically:
matriciant is found for differential Poisson kinematic equations, i.e. the
transforming matrix with formulas for making the identity matrix of the direction
96 P. K. Plotnikov
cosines of the initial angles. In the same article are given formulas for determining
Euler-Krylov angles for the indicatid matriciant.
Below we give the analytical solution of the same problem for arbitrary initial
Euler angles. Following [5], we present the scheme of the Euler angles of rotation
with the image of freewheeling framework gimbal of FIG. 1. As in [9], with the
body gyroscope we associate the moving coordinate system Oxyz (corresponding
coordinate system O1'2'3 'in [5]), as well as the inertial coordinate systems: the
first Oξηζ, with which the system coordinate Oxyz at the initial time coincides,
and second Oξnηnζn in respect to which the coordinate system Oξηζ is developed
to initial angles Ψo, Θo, Φo.
FIG. 1
Scheme of turns of introduced coordinate systems 1 and represented by Ishlinskii
A.Y. [3], relations (1)
xyzАА
ННН
111
1
000
0
~ xyz
АННН
(1)
,0
1AAA
Solution for the motion of a symmetric Euler gyroscope 97
where Ψo, Θo, Φo, Ao - initial angles of rotation SEG and the corresponding SЕG
to them transforming matrix (direction cosine matrix); Ψ1, Θ1, Φ1, A1 - angles of
rotation corresponding matriciant A1 when Ao = E (E - the identity matrix); Ψ, Θ,
Φ, A - resulting rotation angles and the corresponding matrix transforms.
As in [9], we find an analytical solution for the matrix A1; [1] we use the notation
U = A1. In this article the finding of angular velocities p, q, r is treated as a
solution of the dynamical equations SEG, who had the initial angular velocity r(o)
= R, where the impact into the axis of the gyroscope body in the form of rotational
momentum Mo about Ox (hereinafter denoted Mo = Hx - the angular momentum
of the impact) was applied.
Dynamic Euler equations for gyroscopes with dynamic symmetry axis, including
gyro ball (C = A) are as follows:
,;0
;0
;0
A
AOr
dt
dr
pdt
dq
tIdt
d
A
Mq
dt
dp
(2)
p, q, r - the components of the angular velocity vector of the gyroscope
rotation in the related with it axes; I (t) - the identity function; Mo - angular
momentum, given to the gyroscope as the result of the impact.
For the initial conditions
t = 0; p (0) = 0; q (0) = 0; r (0) = R (3)
solving of system of differential equations (2) with initial conditions (3)
are as follows respectively [5,9]:
.;;sin;cos 0
A
MaRrtaqtap (4)
In particular, for ball gyro
.;0; Rrqap (5)
Converting of coordinate system Oxyz from the initial position Oξηζ
characterized by the formulas:
,; 11 AAAAAxyzT
(6)
where AAA ,, - coordinate transformation matrix of simple turns. On
the other hand, this matrix may be determined by integrating of the kinematic
equation matrix Poisson
98 P. K. Plotnikov
;; 111
EtAAtPdt
dA (7)
.
0
0
0
;1
33
1
32
1
31
1
23
1
22
1
21
1
13
1
12
1
11
1
pq
pr
qr
tP
aaa
aaa
aaa
A (8)
Matrix of the direction of cosines of the Euler angles to FIG. 1 with a combination
of coordinate systems and:
.
cossinsinsincos
sinsincoscossincossincossinsincoscos
cossinsincoscoscossinsinsincoscoscos
11111
111111111111
11111111111
1
A (9)
Matrix of the direction of cosines of the Euler - Krylov angles (2) analogous to
the matrix [3], has the form:
.
coscoscossinsin
cossinsinsincoscoscossinsinsincossin
sinsincossincossincoscossinsincoscos
kA (10)
FIG. 2
Solution for the motion of a symmetric Euler gyroscope 99
Tensor of angular velocities for gyroscopes with dynamic symmetry axis
has the form:
0cossin
cos0
sin0
tata
taR
taR
tP (11)
i.e. it satisfies to the condition:
2
;tPtP .
Because of this condition, the system (8) is driven by Lyapunov [6]. Indeed, the
substitution
1)( АtФZ (12)
system (8), (11) is reduced to the matrix equivalence of differential equations with
constant coefficients
BZdt
dZ , (13)
3;2;1,;;;
00
0
00
;
100
0cossin
0sincos
)( 11
1
jiRRZZ
a
aR
R
Btt
tt
tФ ij
. (14)
Equivalence of equations (8) and (13) is confirmed by the implementation of
identity ВtФtPФtФ )()()( 11 .
Solution of a linear homogeneous differential equation (13) is a formula Cauchy
001 ZNtNtZ , (15)
where N (t) - the fundamental matrix of solutions; Z (0) - matrix of the initial
values of the direction cosines, and on the condition Z (0) = E. After finding the
fundamental matrix and a number of transformation the solution (15) takes the
form:
100 P. K. Plotnikov
.;
;
cossincos1
sincossin
cos1sincos
1
2
1
22
2
2
1
2
2
2
1
1
2
11
2
2
2
2
1
A
CRRRan
n
Rnt
n
ant
n
ant
n
aR
ntn
antnt
n
R
ntn
aRnt
n
R
n
ant
n
R
Z
(16)
From (12) it follows that, so that ZtФА )(11 a solution of equation (8) for a
gyroscope with dynamic symmetry axis is the matrix (matriciant)
2
2
1
2
2
2
1
2
1
2
11
1
2
2
2
2
1
2
11
1
2
2
2
2
1
1
coscos1cos1
cossin
sincos1
coscos
sinsin
cossin
cossin
sinsin
coscos1
cossin
sincos
sinsin
coscos
n
Rnt
n
ant
n
aRnt
n
aR
tntn
a
tntn
aR
ntt
nttn
R
tntn
R
n
ant
n
Rt
tntn
a
tntn
aR
ntt
nttn
R
tntn
R
n
ant
n
Rt
A
. (17)
Matrix 1A in totality with Ao=E is the solution of the first step of the problem [9]
- irregular precession. For initial Euler matrix 0A is so:
.
cossinsinsincos
sinsincoscossincossincossinsincoscos
cossinsincoscoscossinsinsincoscoscos
00000
000000000000
000000000000
0
A
(18)
Formulas to determine the Euler angles (Solution of the 2 step of problem) are so:
3
1
0
1
1
1
3
1
0
3
1
2
11
233
1
0
3
1
3333
1
0
1
1
3
3
1
0
2
1
3
31
32 ;cos;
k
kk
k
kk
k
kk
k
kk
k
kk
aa
aa
a
atgaaa
aa
aa
a
atg . (19)
Solution for the motion of a symmetric Euler gyroscope 101
Poisson equations correspond to the following kinematic Euler equations:
.;;;
;sin
;cos
;cossin
;cossin
;sin
cossin
0000000
ttttt
Rr
taq
tap
ctgpqr
qp
pq
; (20)
3. Application of the obtained formulas to the case of regular
precession
Let us use initial values appropriate to this type of precession
CR
Aatg 000 ;0 the matrix Ao:
.
cos0sin
010
sin0cos
00
00
0
A (21)
With this in mind, we obtain:
;
cossinsincos
cossinsincos
cossinsincos
cos0sin
010
sin0cos
0
1
330
1
31
1
320
1
330
1
31
0
1
230
1
21
1
220
1
230
1
21
0
1
130
1
11
1
120
1
130
1
11
00
00
1
33
1
32
1
31
1
23
1
22
1
21
1
13
1
12
1
11
aaaaa
aaaaa
aaaaa
aaa
aaa
aaa
A
(22)
0
1
330
1
31
1
32
31
32
sincos
aa
a
a
atg . (23)
After transformations we receive
;
cossincos1cos
sin
2
2
1
2
2
02
1
0
n
Rnt
n
ant
n
aR
ntn
a
tg (24)
;sin;cos 00H
Aa
H
CR (25)
102 P. K. Plotnikov
nA
Ht
A
Hnttgnttg ;; (26)
- decision coincided with a classic.
Determine the value of the nutation angle Θ:
.cossincos 0
1
330
1
3133 aaa
After calculations
.coscos 0H
RC (27)
Decision on Θ by (27) also coincided with the classical solution for regular
precession. Consider the solution to the angle of proper rotation Φ.
0
1
130
1
11
0
1
230
1
21
11
23
cossin
cossin
aa
aa
a
atg . (28)
.*,*
*
t
ttgtg (29)
The formulas coincide with the formulas of the classical solution, but with zero
initial precession angles and proper rotation.
4. Lets examine now an option for solving the problem of
irregular precession
For initial angles CR
Aatg 000 ;0 differing from the angles (25),
generating regular precession, by sign nutation angle only. After the
transformation formulas for determining the Euler angles for JEG have the form:
tntt
tntttg
nttg
nt
nttg
coscos2sin2cos2cossin
cossin2sinsin2cossin
coscossin22coscos
cos
cos2coscos2
sin
000
000*
00
2
0
2
00*
00
2
*
(30)
Solution for the motion of a symmetric Euler gyroscope 103
Expression (30) suggests that only by changing the sign of the initial nutation
angle - at constant initial two other corners in the Euler gyroscope having
irregular motion of precession.
5. Mathematical modeling
FIG. 3 - 8 shows the results of mathematical modeling of the kinematic Euler
equations, which confirm the analytical obtained results FIG. 3 and 4 are graphs
modeling of processes of change of the Euler angles and Euler-Krylov,
respectively, for the initial angles
,0;)0(;)0( 0000000 (М.1)
ie corresponding to the conditions (20) regular precession in Euler angles. The
relationship of the Euler angles and Euler-Krylov set by the equality of the
corresponding elements of the matrices (9) and (10). Options SEG
radRC
aAsradR
AC
sradRsradassmsCssmsA
,308.0arctan;/,1057.11
;/,1570;/,10;,2.0;,1.0
0
3
322
(М.2)
Graphics fig.3 depict the change of the Euler angles of the regular
precession, which is not possible for the charts fig.4 for Euler – Krylov angles .
On it in the angles and observed harmonic oscillations with a frequency of
several more 500Hz, and in the angle - it rise- FIG. 4.
104 P. K. Plotnikov
FIG.3
Solution for the motion of a symmetric Euler gyroscope 105
FIG. 4
With applying of more strong rotational impulse around the axis Ox, when
Rs
a 1,4000 and other conditions for FIG. 3 and 4 the character constant of
movement is not changed (so the graphics are not shown), but we have the Euler
angles: .7.15)01.0(,905.0,50)01.0( 0 radconstradrad махмах
For Euler- Krylov angles FIG.6 and the amplitudes of fluctuations on , are
equal 0.5 rad, frequency about 530 Hz. Angle - increasing frequency oscillations
superimposed 530Hz. Also at constant simulation parameters SEG movements on
(M.1), (M.2) (Figures 3 and 4), but by changing of signs of initial nutation angles
on the back, ,308.000 rad we got pictures of movements 5 and 6. In Euler
angles FIG. 5 the movement became irregular nature of precession, namely by
and the oscillation frequencies above 500Hz bit of different amplitude with
offset approximately 0.3 rad centers hesitation. In angle the sign of velosity in
relation FIG.3 is reversed, and the angle became progressive. According to the
Euler-Krylov angles qualitatively analogical character.
106 P. K. Plotnikov
FIG.5
Solution for the motion of a symmetric Euler gyroscope 107
Фиг. 6
108 P. K. Plotnikov
FIG.7
Solution for the motion of a symmetric Euler gyroscope 109
FIG.8
Figures 7 and 8 shows the results of modeling SEG parameters by motion
corresponding to 5 and 6, with the only difference the angular velocity is provided
by equal Rs
a 1,4000 . As a result, the character of movements by the Euler
110 P. K. Plotnikov
angles (Fig. 7) has not changed qualitatively, quantitatively the centers of
fluctuations parted on the angles and to 0.45rad, the oscillations frequency
increased to 820 Hz. The angle is still increasing, with the superimposed
oscillations. At the same time, the movement in the Euler - Krylov angles changed
gardinally (FIG. 8). The angle became monotonically in crease in the direction
of the rotational impulse that is new. The angle still is oscillatory with a
frequency around 820 Hz displaced center of oscillation and angle the changed
the sign on the inverse of FIG.6.
Observation on the results of mathematical modeling: the movements
corresponding to the regular precession as in Euler angles so in the Euler-Krylov
angles qualitatively from the size of the angular velocity caused by the influence
of the rotational impulse is independent. Irregular movement of precession
depend cardinally from when the angle becomes monotonically increasing in the
direction of the momentum of impulse action and angle of proper rotation
changes the sign of its monotonous rotation.
Conclusion
1. It is Proved that the regular precession in the SEG is possible only if the
initial Euler angles are defined by the well-known formulas:
GCr
constconst 0000 cos;0; .
For any other initial angles the regular precession is impossible.
2. An analytical solution for the motion of the SEG by integrating of the
differential kinematic Poisson equations is found. The formulas for determining of
Euler angles and Euler – Krylov angles are done.
3. The derived formulas and the mathematical modeling confirmed that at other
initial angles different from angles indieated in the output the precession will be
different from the regular.
4. It is shown On the basis of analytical solutions and the results of mathematical
modeling, that movements corresponding to the regular precession as in Euler
angles – so it is shown, in the Euler-Krylov angles qualitatively from the angular
velocity caused by the influence of the rotational momentum are independent. At
the same time, the motion of irregular precession crucially depend from a: when
one angle velocity is beg (a>R) – the angle becomes monotonically increasing
in the direction of the momentum (with superimposed vibrational), and the angle
of of proper rotation changes the sign of its monotonic rotation (also with a
superimposed vibrational) on the reverse.
Solution for the motion of a symmetric Euler gyroscope 111
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Received: August 24, 2014; Published: October 22, 2014