solutions
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Solutions. Colligative Properties of Solutions. Objectives. Describe the colligative properties of a solution. Calculate freezing point depression and boiling point elevation for solutions. Colligative Properties. - PowerPoint PPT PresentationTRANSCRIPT
Solutions
Colligative Properties of
Solutions
Objectives1. Describe the colligative properties of a
solution.2. Calculate freezing point depression and
boiling point elevation for solutions
Colligative Properties
• A property that depends on the concentration of solute particles but not on the identity of the solute.
Vapor Pressure Lowering
• As the concentration of a solute increases, the concentration of the solvent particles at the surface of a liquid decreases. This causes the vapor pressure to be lower.
• A 1.0 m solution of glucose (C6H12O6) lowers the vapor pressure to the same extent as a 1.0 m solution of sucrose (C12H22O11)
Freezing Point Depression
Freezing Point Depression (Δtf): the difference between the freezing point of a pure solvent and a solution of a solute in the same solvent.
Δtf = Kfm
Kf = molal freezing point constant in oC/mm = molality
Sample Problem1. What is the freezing point depression of water in a
solution of 17.1 g of sucrose (C12H22O11) and 200. g of water? What is the actual freezing point of water. Water has a Molal F.P. constant of -1.86 oC/m.
Sample Problem2. A water solution containing an unknown quantity of
a non-electrolyte solute is found to have a freezing point of -0.23 oC. What is the molal concentration of the solution?
Sample Problems1. Determine the freezing point of a water solution of fructose
(C6H12O6) made by dissolving 58.0 g of fructose in 185 g of water.-3.24oC
2. Calculate the molality of a solution of 39.2 g of urea, H2NCONH2, in 485 g of pure acetic acid. Determine the freezing point of this solution.For acetic acid: Normal f.p. = 16.6oCKf = -3.90 oC/m1.35 m, 11.3 oC
Sample Problems1. What is the expected change in the freezing point of
water in a solution of 62.5 g of barium nitrate, Ba(NO3)2, in 1.00 kg of water.
Sample Problems1. What is the expected freezing point depression for a
solution that contains 2.0 mol of magnesium sulfate dissolved in 1.0 kg of water?-7.4oC
2. A water solution contains 42.9 g of calcium nitrate dissolved in 500. g of water. Calculate the freezing point of the solution.-2.92oC
Boiling Point Elevation
Boiling Point Elevation (Δtb): the difference between the boiling point of a pure solvent and a solution of a solute in the same solvent.
Δtb = Kbm
Kf = molal boiling point constant in oC/mm = molality
Sample ProblemA solution contains 50.0 g of sucrose, C12H22O11, a non-
electrolyte, dissolved in 500.0 g of water. What is the boiling point elevation?
Sample Problems1. What is the boiling point of a solution of 25.0 g of
2-butoxyethanol, HOCH2CH2OC4H9, in 68.7 g of ether? (For ether, ∆tb= 2.02oC/m)40.8oC
2. What mass of glycerol, CH2OHCHOHCH2OH, must be dissolved in 1.00 x 103 g of water in order to have a boiling point of 104.5oC?810g
3. What is the expected boiling point of a 1.70 m solution of sodium sulfate in water?102.6oC