solve a variety of word problems with perimeter. module 7 lesson 23

12
SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

Upload: gregory-campbell

Post on 17-Jan-2016

250 views

Category:

Documents


0 download

TRANSCRIPT

Page 1: SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER.

MODULE 7 LESSON 23

Page 2: SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

MULTIPLY BY 5 SPRINT

2 minutes

End

Page 3: SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

PROBLEM SOLVING STEPS

1. Read & Model the problem• Read the problem• What can you draw?• What conclusions can you make using the drawing?

2. Write & Solve an equation• Use numbers to show your thinking and conclusions

3. Write a statement explaining your answer• Use words to explain your answer and how it relates to the

problem4. Assess the reasonableness of your solution

• Ask yourself questions to make sure your answer makes sense:• The question asks for …• My answer matches the question because …• The units I used make sense because …• My answer is the right size (not too big or small) because …

Page 4: SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

PROBLEM 1

Gale makes a miniature stop sign, a regular octagon, with a perimeter of 48 centimeters for the town he built with blocks. What is the length of each side of the stop sign?

P = 48 cm

48 ÷8 = 6 cm

Each side of the stop sign is 6 cm long.

Page 5: SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

PROBLEM 3

Travis bends wire to make rectangles. Each rectangle measures 34 inches by 12 inches. What is the total length of wire Travis needs to make two rectangles?

34 in

12 in

(2 x 12) + (2 x 34)= (24) + (68) = 92

inches

Page 6: SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

PROBLEM 2

Travis bends wire to make rectangles. Each rectangle measures 34 inches by 12 inches. What is the total length of wire Travis needs to make two rectangles?

34 in

12 in

(2 x 12) + (2 x 34)= (24) + (68) = 92

inches

92 + 92 = 184 inches

Travis needs 184 inches of wire to make

two rectangles.

Page 7: SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

PROBLEM 3

The perimeter of a rectangular bedroom is 32 feet. The width of the room is 8 feet. White is the length of the room?

??

8 ft

32 ÷ 2 = 16 ft

The length of the bedroom is 8 feet.

8 + ____ = 16 ft8

Page 8: SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

PROBLEM 4

Raj uses 6-inch square tiles to make a rectangle. What is the perimeter of the rectangle in inches?

P = 16 tiles16 x 6 = 96 inches

The perimeter of the

rectangle is 96 inches.

6 inches

Page 9: SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

PROBLEM 5

Mischa makes a 4 foot by 6 foot rectangular banner. She puts ribbon around the outside edges. The ribbon costs $2 per foot. What is the total cost of the ribbon? 4 ft

6 ft

(2 x 4) + (2 x 6)4 + 4 + 6 + 6

= 20 ft

The cost of the ribbon is $40.

20 x $2 = $40

Page 10: SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

PROBLEM 6

Colton buys a roll of wire fencing that is 120 yards long. He uses it to fence in his 18 yard by 24 yard rectangular garden. Will Colton have enough wire fencing left over to fence in a 6 yard by 8 yard play space for his pet rabbit?

Garden

18 yd

24 yd

(2 x 18) + (2 x 24)= (36) + (48)= 84 yards

Colton has 36 yards left.

120 – 84 = 36

Page 11: SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

PROBLEM 6

Colton buys a roll of wire fencing that is 120 yards long. He uses it to fence in his 18 yard by 24 yard rectangular garden. Will Colton have enough wire fencing left over to fence in a 6 yard by 8 yard play space for his pet rabbit?

Rabbit Pen

6 yd

8 yd

(2 x 6) + (2 x 8)= (12) + (16)= 28 yards

Colton has enough wire fence to make the rabbit pen because there are 36 yards left, and he only

needs 28 yards.

28 < 36

Page 12: SOLVE A VARIETY OF WORD PROBLEMS WITH PERIMETER. MODULE 7 LESSON 23

And …We’re Done!