solved by m. bilal azam · 2021. 1. 2. · b. 0.1 m/s c. 2.5 q 16, when two surfaces are in...
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Solved by M. Bilal Azam
Bilal Sohaib
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Bilal Sohaib
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Bilal Sohaib
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Bilal Sohaib
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Solved by M. Bilal Azam
Bilal Sohaib
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Bilal Sohaib
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Bilal Sohaib
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Bilal Sohaib
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Bilal Sohaib
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Bilal Sohaib
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Solved by M. Bilal Azam
Bilal Sohaib
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Bilal Sohaib
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Bilal Sohaib
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Bilal Sohaib
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Bilal Sohaib
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Sum vertical vectors 5-2 = 3m Horizontal vector = 4m Resultant = sqrt[3^2+4^2] = 5m
Solved by M. Bilal Azam
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According to Law of Conservation of Energy (KE)f-(KE)i=W ½mvf2-½mvi2=ηmgd vf=√(2ηgd) vf=√(2×0.05×9.8×20) = 4.4 ms-1
Solved by M. Bilal Azam
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h′=12 mm n1=1.5 n2=1 h=? Since Apparent depth/Actual depth=h′/h=n2/n1 h=h′×n1/n2=(12)(1.5)/1 h=18 mm
Solved by M. Bilal Azam
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There are insufficient parameters given to solve this problem.
Solved by M. Bilal Azam
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V=1/3(πr²h) V=1/3(π2²h) By differentiating w.r.t. h, we get dV/dh=4π/3=4.2 cm³/cm
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Solved by M. Bilal Azam
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