some statements weaker than wor
TRANSCRIPT
Some statements weaker than WOR
Liuzhen Wujoint work with Ralf Schindler and Liang Yu
Institute of MathematicsChinese Academy of Sciences
October 22, 2016
Liuzhen Wu (AMSS) Some statements weaker than WOR October 22, 2016 1 / 21
Axiom of Choice Background
The statement of Axiom of Choice
Throughout this talk, we assume ZF, the Zermelo-Frankel set theory, as theground theory. Axiom of Choice has numerous equivalent forms in literature, all ofwhich can be treated as ”the” statement of Axiom of Choice.
Definition (Axiom of Choice)
The Axiom of Choice is refer to one of the following statements:
1 For any set X of nonempty sets, there exists a choice function f defined on X .
2 (Well-ordering Principle WO) Every set can be well-ordered.
3 (Zorn’s lemma) Every non-empty partially ordered set in which every chain(i.e. totally ordered subset) has an upper bound contains at least onemaximal element.
Liuzhen Wu (AMSS) Some statements weaker than WOR October 22, 2016 2 / 21
Axiom of Choice Background
Consequences of Axiom of Choice: holy side
Followings are some consequences of AC:
1 Boolean prime ideal Theorem.
2 Tychonoff’s theorem in topology
3 Hahn-Banach Theorem.
4 Any consequence of Zorn’s Lemma appeared in Algebra textbook.
5 Any “correct” statements need AC while you are not aware of.
Liuzhen Wu (AMSS) Some statements weaker than WOR October 22, 2016 3 / 21
Axiom of Choice Background
Consequences of Axiom of Choice: evil side
Followings are some consequences of AC:
1 Existence of nonmeasurable set.
2 Banach-Tarski Paradox.
3 Any “wrong” statements follow from AC and you know it.
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Axiom of Choice Background
Typical construction base on AC
The construction of Vitali subset V of [0, 1]:
For reals in [0, 1], sayx ∼ y
whenever x − y is rational. ∼ is an equivalence relation on [0, 1].
[X ]: the equivalence class of x .
By AC, we can choose one element out of each equivalence class. Thus there is aset V ⊂ [0, 1], with the property that for each x , there exists a unique y ∈ V anda unique rational number r such that x = y + r .
V is not Lebesgue measurable.
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Axiom of Choice Background
The consistency of AC
Theorem (Godel)
Con(ZF )→ Con(ZF + AC )
By the inner model method.
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Axiom of Choice Background
The independency of AC
Theorem (Cohen)
Con(ZF )→ Con(ZF + ¬AC )
By the forcing and symmetric model method.
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Axiom of Choice Background
AC is true
The reasons:
The good consequences are true. The bad consequences are forgivable.
AC is a powerful tools.
(For set theorists)AC holds in any canonical inner model of ZF up to now.
A simple explanation of the last item:Such inner models are “constructible”. In these models we “construct” ACmanually.
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Axiom of Choice Background
AC is false
The reasons:
The bad consequences are too annoying to be true.
There should be correct ways to obtain good consequences of AC.
(For set theorists) ¬AC holds in some canonical model of ZF .
or
ZF is false.
Remark: No set theorist judges the validity of ¬AC by forcing models.
Liuzhen Wu (AMSS) Some statements weaker than WOR October 22, 2016 9 / 21
Axiom of Choice Background
AC is false
The reasons:
The bad consequences are too annoying to be true.
There should be correct ways to obtain good consequences of AC.
(For set theorists) ¬AC holds in some canonical model of ZF .
or
ZF is false.
Remark: No set theorist judges the validity of ¬AC by forcing models.
Liuzhen Wu (AMSS) Some statements weaker than WOR October 22, 2016 9 / 21
Axiom of Choice Background
Some canonical models without AC
1 Any models of ZF + AD.
2 Chang’s model under many measurable cardinals.
3 L[Vλ+1] under j : L[Vλ+1]→ L[Vλ+1].
A common phenomenons: They all need large cardinals. This is not bycoincidence. Indeed, the recent advance in inner model theory suggests if thecurrent inner model program ultimately fails, then probably the right inner modelabsorbs all large cardinals need to be compatible with ¬AC .
Liuzhen Wu (AMSS) Some statements weaker than WOR October 22, 2016 10 / 21
Axiom of Choice Background
A few words about AD
Definition (Axiom of Determinacy)
Every two-player game of perfect information of length ω, in which the playersplay naturals, is determined.
Theorem (Mycielski-Swierczkowski)
AD implies any subset of reals are Lebesgue measurable.
Corollary
AD implies ¬AC .
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Axiom of Choice Statements weaker than Axiom of Choice
Statements weaker than Axiom of Choice
Now we see it is reasonable to separate consequences of AC from AC.
Theorem (Halpern, LoS and Ryll-Nardzewski, Feferman)
The followings does not implies Axiom of Choice:
1 Boolean Prime Ideal Theorem.
2 Hahn-Banach Theorem.
3 The existence of non-measurable set.
Theorem (Kelley, Blass-Halpern)
The followings are equivalent to Axiom of Choice:
1 Tychonoff’s Theorem.
2 The existence of Hamel Base for any vector space.
Liuzhen Wu (AMSS) Some statements weaker than WOR October 22, 2016 12 / 21
Axiom of Choice Statements weaker than Axiom of Choice
A folklore open problem for decades
What happen when we only deals with the mathematical object actually appearsin the mathematics studies? Or, is it true that nice local consequences of AC doesnot necessarily entail corresponding local version of AC?
Question
Does the existence of Hamel Base for R over Q implies WOR, the existence ofwell-ordering of reals?
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Hamel Base for R/Q and AC
Theorem (Schindler-Wu-Yu)
Con(ZFC )→ Con(ZF + there is a Hamel Base for R/Q + ¬WOR).
R/Q is the Q-vector space with domain R, equipped with the usual + and ×operation.
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Hamel Base for R/Q and AC The proof
Framework
1. Start from Cohen-Halpern-Levy model N = HOD(O)L[G ] over L.
2. Working in N, we construct a forcing PH whose generic filter is a RN/Q HamelBase. Let GH be the corresponded generic set and FH be the correspondedmaximal antichain.
3. In N[GP ], define NP = HOD({FP} ∪ RN[GP ])N[GP ].
4. We show that NP and N have the same reals and there is no well ordering ofreals in NP .
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Hamel Base for R/Q and AC The proof
Cohen-Halpern-Levy model over L
Cohen-Halpern-Levy model is the simplified version of Cohen’s first ¬AC -model.It is defined as
N = HOD(g)L[G ].
Notation:G is the Add(ω, ω)-generic filter over L.Add(ω, ω): the forcing add ω many Cohen reals.g : the set of Cohen reals add by G .HOD: the class of hereditary ordinal definable sets.
Theorem (Cohen,Feferman, Halpern-Levy)
In N, the following is true:
1 ZF + ¬WOR holds.
2 Boolean Prime Ideal Theorem.
3 Every locally countable Σ12-equivalence relation has a transversal. In
particular, there is a nonmeasurable set.
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Hamel Base for R/Q and AC The proof
Decomposition of reals of N
Fact
Any reals in N is in some L[gi0 , . . . , gin ] for some gi0 , . . . , gin in g .
In N, the reals admits the following decomposition: R =⋃
I∈ω<ω1
WI , where
WI = RL[gI ] \⋃
J(I WJ .
Lemma
The decomposition defined above lifts to a direct sum system {V I}I∈ω<ω1
for R/Q.
Liuzhen Wu (AMSS) Some statements weaker than WOR October 22, 2016 17 / 21
Hamel Base for R/Q and AC The proof
The forcing PH
p ∈ PH if p : ω → RN is a total function so that
1 For any I ∈ ω<ω1 , ran(p) ∩WI is linear independent over span(⋃
J(I WJ) i.e,all linear combination of ran(p) ∩WI is not in U|I |,
2 (Termspace Preparation) For any gI , p � gI ∈ L[gI ], where p � gI is a functionfrom ω defined as:
(p � gI )(n) =
{p(n) : p(n) ∈ L[gI ]0 : Otherwise.
p ≤ q if ran(p) ⊇ ran(q).
Liuzhen Wu (AMSS) Some statements weaker than WOR October 22, 2016 18 / 21
Hamel Base for R/Q and AC The proof
The forcing PH
Lemma
PH has the followings property:
1 PH does not add any new reals.
2 PH does not add a well-ordering of R.
3 PH adds a Hamel-Base for R/Q.
The proof relies on the following lemma:
Lemma (Homogeneity of PH under Add(ω, ω))
For any condition (p, b) ∈ Add(ω, ω) ∗ PH , φ a sentence in the forcing languagewith its parameters being names for ordinals, gI for some I , and for R and FH .Assume that p ∈ Add(ω,O) and p forces that b ∈ L[gI ]. Now if there is some(q, c) < p with q � Add(ω, I ) = p and q c � I = I decides φ, then (p, b) decidesφ.
The proof uses the termspace and Prikry type forcing argument.
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Hamel Base for R/Q and AC The proof
Generalizations
Theorem (Wu-Yu)
In Cohen’s model, for any locally countable Σ21-binary relation R, there is a
maximal discrete set for R.
Theorem (Wu-Yu)
For any ZF provable Π12-preorder P,
Con(ZFC )→ Con(ZF + there is a maximal antichain of P + ¬WOR)
Theorem (Wu-Yu)
Assume Con(ZF+AD), then there is a ZF + ¬AC model in which for any ZFprovable second order definable, locally countable binary relation R, there is amaximal discrete set for R.
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Question
Question
Can we separate the following statements
1 There exists a Hamel base for R/Q.
2 There exists a Luzin set.
3 There exists a Siepinski Set.
Thank you for your attention!
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