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Over Lesson 1–3 A.A B.B C.C D.D 5-Minute Check 1 A.3(x 2 ) B.3x + x 2 C.3(x + x 2 ) D.3 + x + x 2 Which algebraic expression represents the verbal expression three times the sum of a number and its square?

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Splash Screen Lesson Menu Five-Minute Check (over Lesson 13) Then/Now New Vocabulary Key Concept: Absolute Value Example 1:Evaluate an Expression with Absolute Value Example 2:Solve an Absolute Value Equation Example 3:No Solution Example 4:One Solution Over Lesson 13 A.A B.B C.C D.D 5-Minute Check 1 A.3(x 2 ) B.3x + x 2 C.3(x + x 2 ) D.3 + x + x 2 Which algebraic expression represents the verbal expression three times the sum of a number and its square? Over Lesson 13 A.A B.B C.C D.D 5-Minute Check 2 A.5 (4n 3 ) B.4n 3 5 C.4n D.n 3 5 Which algebraic expression represents the verbal expression five less than the product of the cube of a number and 4? Over Lesson 13 A.A B.B C.C D.D 5-Minute Check 3 A (65) = 65 B.23 + n = 65 C.23 = 2n + 65 D.2n + 23 = 65 Which equation represents the verbal expression the sum of 23 and twice a number is 65? Over Lesson 13 A.A B.B C.C D.D 5-Minute Check 4 A.1 B.0.5 C.0 D.1 Solve the equation 12f 4 = 7 + f. Over Lesson 13 A.A B.B C.C D.D 5-Minute Check 5 A.2 B.1 C.0 D.1 Solve the equation 10y + 1 = 3(2y 5). Over Lesson 13 A.B. C.D. A.A B.B C.C D.D 5-Minute Check 6 Then/Now You solved equations using properties of equality. (Lesson 13) Evaluate expressions involving absolute values. Solve absolute value equations. Vocabulary absolute value empty set extraneous solution Concept Example 1 Evaluate an Expression with Absolute Value Answer: 4.7 Replace x with 4. Multiply 2 and 4 first. Subtract 8 from 6. Add. A.A B.B C.C D.D Example 1 A.18.3 B.1.7 C.1.7 D.13.7 Example 2 Solve an Absolute Value Equation Case 1a=b y + 3=8 y + 3 3=8 3 y=5y=5 Answer: The solutions are 5 and 11. Thus, the solution set is 11, 5 . Check|y + 3|=8 Case 2a=b y + 3=8 y + 3 3=8 3 y=11 |y + 3|=8 ? |5 + 3|=8 ? |8|=8 8=88=8 ? |11 + 3|=8 ? |8|=8 8=88=8 A.A B.B C.C D.D Example 2 A.{5} B.{10, 5} C.{5, 10} D.{5} What is the solution to |2x + 5| = 15? Example 3 No Solution Solve |6 4t| + 5 = 0. This sentence is never true. Answer: The solution set is . |6 4t| + 5=0Original equation |6 4t|=5Subtract 5 from each side. A. B. C. D. A.A B.B C.C D.D Example 3 Example 4 One Solution Case 1a=b 8 + y=2y 3 8=y 3 11=y Example 4 One Solution Check: Answer: A. B. C. D. A.A B.B C.C D.D Example 4 End of the Lesson