standard form ax + by = c slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none...

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Standard Standard Form Form Ax + By = C Ax + By = C Slope Slope y- y- intercept intercept x- x- intercep intercep t t 3x – 4y = 3x – 4y = 24 24 1/2 1/2 3 3 2x – 5y = –10 2x – 5y = –10 none none 7 7 3/ 3/ 4 4 6 6 8 8 x + 2y = x + 2y = 6 6 6 6 2/ 2/ 5 5 2 2 5 5 x = – 7 x = – 7 undefine undefine d d

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y – y 1 = m (x – x 1 ) m = slope x 1 = x-coordinate of point on line y 1 = y-coordinate of point on line To convert to Slope-intercept Form: DDistribute the slope. MMove y 1 to right side of the equal sign.

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Page 1: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

Standard FormStandard FormAx + By = CAx + By = C

SlopeSlope y-intercepty-intercept x-interceptx-intercept

3x – 4y = 243x – 4y = 24

––1/21/2 3 3

2x – 5y = –102x – 5y = –10

nonenone – – 77

3/43/4 – – 66 88

x + 2y = 6x + 2y = 6 66

2/52/5 22 – – 55

x = – 7 x = – 7 undefinedundefined

Page 2: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined
Page 3: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

y – y1 = m (x – x1)m = slope

x1 = x-coordinate of point on liney1 = y-coordinate of point on line

To convert to Slope-intercept Form: Distribute the slope. Move y1 to right side of the equal sign.

Page 4: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

ExampleExample 05/04/2305/04/23

Give an equation in Standard Formfor the line that has a slope of passes through the point (8, –2). Find the x-int and y-int.

)( 11 xxmyy Slope = – 2 and (8, –2) ))8()(

23()2( xy

12232 xy

Point-Slope Form →

Substitute your given values →

Distribute →

)8(232 xy

23

Continue →

Page 5: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

Continued Continued 05/04/2305/04/23

Multiply by – 2 →

Standard Form →

Continued from the previous slide →

1423

yxPut into Standard Form →

1423

xySolve for y →

12232 xy

]1423[2 yx

2823 yxx-int = 28/3y-int = –14

Page 6: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

ExampleExample 05/04/2305/04/23

Give an equation in Standard Formfor the line that passes through thepoints (3, 5) and (6, – 1)

3651slope

)( 11 xxmyy Slope = – 2 Pick one of the given points. Let’s pick (3, 5)

))3()(2()5( xy

625 xy112 xy112 yx

Point-Slope Form →Substitute your given values →

Distribute →Solve for y →

Put into Standard Form →

)3(25 xy

Page 7: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

Example ContinuedExample Continued 05/04/2305/04/23

Give an equation in Standard Formfor the line that passes through thepoints (3, 5) and (6, – 1)

3651slope

)( 11 xxmyy Slope = – 2 Pick one of the given points. Let’s pick (6, –1)

))6()(2()1( xy

1221 xy112 xy112 yx

Point-Slope Form →Substitute your given values →

Distribute →Solve for y →

Put into Standard Form →

)6(21 xy

Page 8: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

Example Example 05/04/2305/04/23

Give an equation in Standard Formfor the line that has an x-int 3 and y-int 7.

3007slope

)( 11 xxmyy

Slope = – 7/3 Pick one of the given points. Let’s pick (3, 0)

))3()(37()0( xy

737

xy

737

yx

Point-Slope Form →Substitute your given values →

Distribute →

Put into Standard Form →

)3(37

xy

The ordered pairs are (3, 0) and (0, 7).

Continued→

Page 9: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

Continued Continued 05/04/2305/04/23

]737[3 yxMultiply by 3 →

2137 yxStandard Form →

737

yxContinued from the previous slide →

Page 10: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

Example Example 05/04/2305/04/23

Last week, Mr. Baxter sold $20,000 worth of newspaper advertisements and earned $800. The week before, he sold $26,000 worth of advertisements and earned $860. Assume the relationship between Mr. Baxter’s weekly earnings and the value of the advertisements he sells is linear.

a)Write the data above as two ordered pairs in the form (s, e).

b) Find the slope of the line given these ordered pairs.

c) Write an equation for the line in slope-intercept form given the data.

(20,000, 800) and (26,000, 860)

Slope = .01

Continued→

Page 11: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

Example Example 05/04/2305/04/23

Last week, Mr. Baxter sold $20,000 worth of newspaper advertisements and earned $800. The week before, he sold $26,000 worth of advertisements and earned $860. Assume the relationship between Mr. Baxter’s weekly earnings and the value of the advertisements he sells is linear. Ordered Pairs (20,000, 800) and (26,000, 860)Slope = .01c) Write an equation for the line in slope-intercept form given the data.

Slope = .01 and (20,000, 800) )( 11 xxmyy )20000(01.800 xy

20001.800 xy60001. xy

Page 12: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

You cannot find 1 equation for a piecewise function.

You can find an equation for each part. Use the endpoints of each part to find

the slope of that segment. Use the slope and one of the points to

write an equation in point-slope form. Convert to slope intercept form. Write an inequality to define that

piece.

Page 13: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

Use the endpoints of each part to find slope.

Write an equation in point-slope form.

Convert to slope- intercept form.

Write an inequality.

30103

)1(33 xy

103

xxy

Page 14: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

Use the endpoints of each part to find slope.

Write an equation in point-slope form.

Convert to slope- intercept form.

Write an inequality.

41

1534

)5(414 xy

51411

41

x

xy

Page 15: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

Use the endpoints of each part to find slope

write an equation in point-slope form

Convert to slope intercept

Write an inequality

45640

)6(40 xy

65244

xxy

Page 16: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

30;3 xxy

51;411

41

xxy

65;244 xxy

Page 17: Standard Form Ax + By = C Slopey-interceptx-intercept 3x – 4y = 24 –1/23 2x – 5y = –10 none – 7 3/4 – 6 8 x + 2y = 6 6 2/52 – 5 x = – 7 undefined

Lesson Master 3-5. Pages 165-166 #’s 2, 5, 7-9, 13, 14, 16.

Quiz on Sections 3-4 and 3-5 on Tuesday, November 25th!!!