stats survey project

17
AP Statistics Survey Project Desiree Acevedo, Frank Palomarez, Paul Ortiz Mr. Eastvedt Period 4 June 4, 2011

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Page 1: Stats survey project

AP Statistics Survey ProjectDesiree Acevedo, Frank Palomarez, Paul

OrtizMr. Eastvedt

Period 4June 4, 2011

Page 2: Stats survey project

Survey QuestionsO Q1 - What grade are you in?O Q2 - How old are you?O Q3 - Are you male or female?O Q4 - How many siblings do you have?O Q5 - How many people live in your

house?O Q6 - How many days of the week do you

typically get homework?O Q7 - How many pairs of jeans do you

own?

Page 3: Stats survey project

Questions continued …. O Q8 - Which do you prefer to watch:

College Football or Professional FootballO Q9 - What type of phone do you prefer:

Touch screen or Full KeyboardO Q10 - Which do you prefer: Fast Food or

Home-made FoodO Q11 - Would you rather play videogames

or physical sports?

Page 4: Stats survey project

Confidence Intervals for Means

Question 1: Grade level of participants

x= 9.93 s= 1.095 n= 84 df= 83 9.93 ± (T*)×(1.095/√84)

= (9.70, 10.16)O This confidence interval means that we

are 95% confident that the true mean grade level of survey participants is between 9.70 and 10.16

Page 5: Stats survey project

Confidence Intervals for Means

Question 2: Age of participants

x= 15.27 s= 1.19 n= 84 df= 83 15.27 ± (T*)×(1.19/√84)

= (15.02, 15.53)

O This confidence interval means that we are 95% confident that the true mean age of survey participants is between 15.02 and 15.53

Page 6: Stats survey project

Confidence Intervals for Means

Question 4: Number of siblings participants have

x= 2.63 s= 1.63 n= 84 df= 83 2.63 ± (T*)×(1.63/√84)

= (2.28, 2.98)O This confidence interval means that

we are 95% confident that the true mean of number siblings of survey participants is between 2.28 and 2.98

Page 7: Stats survey project

Confidence Intervals for Means

Question 5: Number of people in participant’s householdx= 5.71 s= 2.39 n= 84 df= 83

5.71 ± (T*)×(2.39/√84)

= (5.20, 6.23)O This confidence interval means that we

are 95% confident that the true mean of people in the household of survey participants is between 5.20 and 6.23

Page 8: Stats survey project

Confidence Intervals for Means

Question 6: Day of week participants typically receive homeworkx= 4.44 s= 1.13 n= 73 df= 72

4.44 ± (T*)×(1.13/√73)

= (4.17, 4.70)O This confidence interval means that

we are 95% confident that the true mean of days per week survey participants receive homework is between

Page 9: Stats survey project

Confidence Intervals for Means

Question 7: Pairs of jeans participants own

x= 10.91 s= 12.87 n= 67 df= 66

10.91 ± (T*)×(12.87/√67)

= (7.77, 14.05)O This confidence interval means that

we are 95% confident that the true mean age of survey participants is between 7.77 and 14.05

Page 10: Stats survey project

Confidence Intervals for Proportions

Question 3: Gender (p=female q=male) p= .548 q= .452 z*= 1.960

n= 84 .548 ± 1.960√((.548×.452)/84)

= (.442, .654)

O This means that we are 95% confident that the true proportion of affirmative participants (females) is between .442 and .654

Page 11: Stats survey project

Confidence Intervals for Proportions

Question 8: Watching NFL vs. NCAA Football (p = prefer NFL ; q = prefer NCAA)

p= .868 q= .132 z*= 1.960 n= 76 .868 ± 1.960√((.868×.132)/76)

= (.792, .944)O This means that we are 95% confident that

the true proportion of affirmative participants (prefer watching NFL) is between .792 and .944

Page 12: Stats survey project

Confidence Intervals for Proportions

Question 9: Touch screen vs. Full Keyboard(p= Full keyboard q= Touch screen)

p= .561 q= .439 Z*= 1.960 n= 82 .561 ± 1.960√((.561×.439)/82)

= (.454, .668)O This means that we are 95% confident

that the true proportion of affirmative participants (prefer a full keyboard cell phone) is between .454 and .668

Page 13: Stats survey project

Confidence Intervals for Proportions

Question 10: Fast food vs. Home-made (p= Fast Food q= Home-made)

p= .296 q= .701 Z*= 1.960 n= 81 .296 ± 1.960√((.296×.701)/81)

= (.197, .396)

O This means that we are 95% confident that the true proportion of affirmative participants (prefer fast food) is between .197 and .396

Page 14: Stats survey project

Confidence Intervals for Proportions

Question 11: Videogames vs. Physical sports

(p= Videogames q= Sports)p= .266 q= .742 Z*= 1.960 n= 79

.266 ± 1.960√((.266×.742)/79)

= (.168, .364)O This means that we are 95% confident

that the true proportion of affirmative participants (prefer playing videogames) is between .168 and .364

Page 15: Stats survey project

Hypothesis Test: Question 6How many days of the week do you typically

get homework?“ … researchers say that American students have just the right

amount of homework.”

1. Ho: x=4.44 Ha: x≠4.44

2. Assumptions/Conditions:*Randomness-our sample was randomly selected*10%-our sample is less than 10% of the student

population*Distribution-we can assume that the sample is

randomly distributed3. We will conduct a 1 sample T-test4. p-value= .6125. With such a high p-value we cannot reject the null hypothesis. This means that we can assume that the average student receives homework about four to five days a week.

Page 17: Stats survey project

Males vs. Females: Question 11Would you rather play videogames or physical

sports?1. Ho: proportion of males > proportion of females (prefer playing video games) Ha: proportion of males < proportion of females (prefer playing video games)2. Assumptions/Conditions:

*Randomness-our sample was randomly selected*10%-our sample is less than 10% of the student

population*Distribution-we can assume that the sample is randomly

distributed3. We will conduct a 2-proportion Z-test4. females = .256 males = .286

p-value = .3225. With a high p-value we cannot reject the null hypothesis. This means that we can assume that the average teenage male prefers to play video games over physical sports than the average teenage female.