strength and failure criteria
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Composite Strength and Failure Criteria
Micromechanics of failure in a unidirectional ply
In the fibre direction (‘1’), we assume equal strain in fibre and matrix. The applied stress is shared:
1 = f Vf + m Vm
Failure of the composite depends on whether the fibre or the matrix reaches its failure strain first.
Failure in longitudinal tension
ffT1 V
Failure in longitudinal compression
• Failure is difficult to model, as it may be associated with different modes of failure, including fibre buckling and matrix shear.
• Composite strength depends not only on fibre properties, but also on the ability of the matrix to support the fibres.
• Measurement of compressive strength is particularly difficult - results depend heavily on method and specimen geometry.
Failure in longitudinal compression
Shear failure mode
Microbuckling
f
mfffC1 E
EV1V2
Failure in transverse tension
High stress/strain concentrations occur around fibre, leading to interface failure. Individual microcracks eventually coalesce...
Failure in transverse compression
May be due to one or more of:
• compressive failure/crushing of matrix
• compressive failure/crushing of fibre
• matrix shear
• fibre/matrix debonding
Failure by in-plane shear
Due to stress concentration at fibre-matrix interface:
Five numbers are needed to characterise the strength of a composite lamina:
1T* longitudinal tensile strength
1C* longitudinal compressive strength
2T* transverse tensile strength
2C* transverse compressive strength
* in-plane shear strength‘1’ and ‘2’ denote the principal material directions; * indicates a failure value of stress.
Typical composite strengths (MPa)
UD CFRP UD GRP woven GRP SiC/Al
1T* 2280 1080 367 1462
1C* 1440 620 549 2990
2T* 57 39 367 86
2C* 228 128 549 285
* 71 89 97 113
The use of Failure Criteria
• It is clear that the mode of failure and hence the apparent strength of a lamina depends on the direction of the applied load, as well as the properties of the material.
• Failure criteria seek to predict the apparent strength of a composite and its failure mode in terms of the basic strength data for the lamina.
• It is usually necessary to calculate the stresses in the material axes (1-2) before criteria can be applied.
Maximum stress failure criterion
Failure will occur when any one of the stress components in the principal material axes (1, 2, 12) exceeds the corresponding strength in that direction.
*1212
2*
2
2*
22
1*
1
1*
11
)0(
)0(
)0(
)0(
C
T
C
T
Formally, failure occurs if:
Maximum stress failure criterion
All stresses are independent. If the lamina experiences biaxial stresses, the failure envelope is a rectangle - the existence of stresses in one direction doesn’t make the lamina weaker when stresses are added in the other...
Maximum stress failure envelope
1
2
2T*
1T*
2C*
1C*
Orientation dependence of strength
The maximum stress criterion can be used to show how apparent strength and failure mode depend on orientation:
2
1
12
x
cossin
sin
cos
12
22
21
x
x
x
Orientation dependence of strength
At failure, the applied stress (x) must be large enough for one of the principal stresses (1, 2 or 12) to have reached its failure value.
Observed failure will occur when the minimum such stress is applied:
cossin
sin
cos
min*12
2*2
2*1
*x
Orientation dependence of strength
Off-axis tensile strength (E-glass/epoxy)
0
250
500
750
1000
1250
1500
0 10 20 30 40 50 60 70 80 90
reinforcement angle
stre
ng
th (
MP
a)
long tension
in-plane shear
trans tension
2*1 cos
2*2 sin
cossin*12
Daniel & Ishai (1994)
Maximum stress failure criterion
• Indicates likely failure mode.
• Requires separate comparison of resolved stresses with failure stresses.
• Allows for no interaction in situations of non-uniaxial stresses.
Maximum strain failure criterion
Failure occurs when at least one of the strain components (in the principal material axes) exceeds the ultimate strain.
*1212
2*
2
2*
22
1*
1
1*
11
)0(
)0(
)0(
)0(
C
T
C
T
Maximum strain failure criterion
The criterion allows for interaction of stresses through Poisson’s effect.
For a lamina subjected to stresses 1, 2, 12, the failure criterion is:
*1212
2*
2
2*
21212
1*
1
1*
12121
0,
0,
0,
0,
C
T
C
T
Maximum strain failure envelope
For biaxial stresses (12 = 0), the failure envelope is a parallelogram:
1
2
Maximum strain failure envelope
In the positive quadrant, the maximum stress criterion is more conservative than maximum strain.
1
2
The longitudinal tensile stress 1 produces a compressive strain 2. This allows a higher value of 2 before the failure strain is reached.
max strain
max stress
Tsai-Hill Failure Criterion
• This is one example of many criteria which attempt to take account of interactions in a multi-axial stress state.
• Based on von Mises yield criterion, ‘failure’ occurs if:
12
*12
12
2
*2
22*
1
21
2
*1
1
Tsai-Hill Failure Criterion• A single calculation is required to determine failure.• The appropriate failure stress is used, depending on
whether is +ve or -ve.• The mode of failure is not given (although inspect the
size of each term).• A stress reserve factor (R) can be calculated by setting
2
2
*12
12
2
*2
22*
1
21
2
*1
1 1
R
Orientation dependence of strength
The Tsai-Hill criterion can be used to show how apparent strength depends on orientation:
2
1
12
x
cossin
sin
cos
12
22
21
x
x
x
UD E-glass/epoxy Orientation dependence of strength
0
200
400
600
800
1000
1200
0 10 20 30 40 50 60 70 80 90
angle (o)
app
aren
t st
ren
gth
(M
Pa)
long tension
trans tension
shear
Tsai-Hill
Tsai-Hill Failure Envelope
• For all ‘quadratic’ failure criteria, the biaxial envelope is elliptical.
• The size of the ellipse depends on the value of the shear stress:
1
2
12 = 0
12 > 0
Comparison of failure theories
• Different theories are reasonably close under positive stresses.
• Big differences occur when compressive stresses are present.
A conservative approach is to consider all available theories: