student lecture 31 quadric surfaces
DESCRIPTION
.TRANSCRIPT
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LECTURE 31
QUADRIC SURFACES
When a standard quadric surface
x2
a2 y
2
b2 z
2
c2= 1
is rotated in space mixed terms xy, xz and yz appear in the equation. It is possible to expressthe resulting quadratic form in matrix form xTAx = 1 where A is a symmetric matrix. Ananalysis of the eigenvectors and eigenvalues of A will reveal both the structure and the principalaxes of the surface.
Consider the curve 2x24xy+5y2 = 54. The presence of the mixed term xy indicatesthat this is a standard object (ellipse or hyperbola) which has been tilted to some degreeso that its major and minor axes no longer point in the x and y directions. To under-stand the curve we need to apply a specific transformation which untilts the curve intostandard form. Our first step is to rewrite the quadratic form in terms of matrices.
Claim: 2x2 4xy + 5y2 = 54 is equivalent to ( x y )(
2 22 5
)(x
y
)= 54
Proof:
This gets us over into the arena of matrices where the theory of eigenvalues andeigenvectors may be brought into play! Observe that by its nature of construction, thematrix A will be symmetric and thus its eigenvectors will be naturally orthogonal to eachother. We now undertake a complete eigen-analysis of A.
1
-
2
-
So the eigenvalues of A are 1 and 6 with associated unit eigenvectors
25
15
and
1
5
25
respectively. Observe that the eigenvectors are indeed orthogonal.These di-
rections X =
25
15
and Y =
1
5
25
actually form the principal axes of the
curve. That
is the curve sits properly on the eigenvectors of A. We will prove this formally in the nextlecture. Furthermore in the {X, Y } system the equation of the curve is 1X2 + 6Y 2 = 54.(Note the use of the eigenvalues). We can now identify the curve as an ellipse whoseclosest point to the origin is 3 units in the Y direction. Thus the closest points to the
origin are
3
5
65
in the {x, y} system. The transformation which interrelates the
two coordinate systems is
(x
y
)= P
(X
Y
)where P is the usual matrix of eigenvectors
25
15
15
25
. Sketch:
In summary:The quadratic form xTAx where A is a symmetric matrix has principal axes given by
the orthogonal eigenvectors of A and the associated quadratic curves and quadric surfacesmay be transform into standard objects with the eigenvalues as coefficients.
3
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Example 1 Express the equation of the surface
x2 + 2y2 + 2z2 + 4xy 4xz + 6yz = 30
in terms of its principal axes X , Y and Z and hence determine the nature of the surface.
Find an orthogonal matrix P implementing the transformation through
xy
z
= P
XY
Z
.
Deduce the shortest distance from the surface to the origin and the
xy
z
coordinates
of these closest point(s).
The equation may be written as(x y z
) 1 2 22 2 32 3 2
xy
z
= 30
Now the matrix A =
1 2 22 2 32 3 2
has eigenvalues -3, 3 and 5 with associated eigen-
vectors
11
1
, 21
1
and
01
1
. Observe the orthogonality of the eigenvectors!
4
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P =
13
26
0
13
16
12
13
16
12
, 3X2 + 3Y 2 + 5Z2 = 30
Hyperboloid of one sheet with closest distance to the origin of6 at
03
3
We will start the next lecture with a formal proof of these algorithms and results.
31You can now do Q 91 and 92
5
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