survey of the universe tom burbine tburbine@mtholyoke

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Survey of the Universe Tom Burbine [email protected]

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Survey of the Universe Tom Burbine [email protected]. Prospective Astronomy Majors Lunch. Monday, March 4 th 12:15-1:10pm Kendade 303. Meet the faculty, learn about the Mars Rover, and enjoy a delicious lunch. HW# 3. Due March 6. Characteristics of waves. - PowerPoint PPT Presentation

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Page 1: Survey of the Universe Tom Burbine tburbine@mtholyoke

Survey of the Universe

Tom [email protected]

Page 2: Survey of the Universe Tom Burbine tburbine@mtholyoke

Prospective Astronomy Majors Lunch

Meet the faculty, learn about the Mars Rover, and enjoy a delicious lunch.

Monday, March 4th

12:15-1:10pmKendade 303

Page 3: Survey of the Universe Tom Burbine tburbine@mtholyoke

HW# 3

• Due March 6

Page 4: Survey of the Universe Tom Burbine tburbine@mtholyoke

Characteristics of waves• velocity = wavelength x frequency• Wavelength = distance• Frequency = cycles per second = hertz

Page 5: Survey of the Universe Tom Burbine tburbine@mtholyoke

For light

• c = wavelength x frequency• In a vacuum, speed of light stays the same• So if wavelength goes up• Frequency does down• f = frequency• λ = wavelength• c = λ x f

Page 6: Survey of the Universe Tom Burbine tburbine@mtholyoke

Calculations

• c = λ x f• So if the wavelength is 1 x 10-12 m• 3 x 108 m/s = 1 x 10-12 m * f• f = 3 x 108 m/s/1 x 10-12 m • f = 3 x 1020 s-1 = 3 x 1020 Hz

Page 7: Survey of the Universe Tom Burbine tburbine@mtholyoke

Calculations

• c = λ x f• So if the frequency is 1 x 1015 Hz• 3 x 108 m/s = λ * 1 x 1015 Hz • λ = 3 x 108 m/s/1 x 1015 Hz • λ = 3 x 10-7 m

Page 8: Survey of the Universe Tom Burbine tburbine@mtholyoke

Energy of light

• Energy is directly proportional to the frequency• E = h * f• h = Planck’s constant = 6.626 x 10-34 J*s• since f = c/λ• Energy is inversely proportional to the wavelength• E = hc/λ

Page 9: Survey of the Universe Tom Burbine tburbine@mtholyoke

Calculations

• What is the energy of a radio wave with a frequency of 1 x 107 Hz?

• E = h * f• h = Planck’s constant = 6.626 x 10-34 J*s• E = 6.626 x 10-34 J*s * 1 x 107

• E = 6.626 x 10-27 J

Page 10: Survey of the Universe Tom Burbine tburbine@mtholyoke

Calculations

• What is the energy of a gamma ray photon with wavelength of 1 x 10-15 m

• E = hc/λ• h = Planck’s constant = 6.626 x 10-34 J*s• E = 6.626 x 10-34 J*s * 3 x 108 m/s / 1 x 10-15 m• E = 1.99 x 10-10 J

Page 11: Survey of the Universe Tom Burbine tburbine@mtholyoke
Page 12: Survey of the Universe Tom Burbine tburbine@mtholyoke

Higher the frequency, Higher the energy of the photonHigher the wavelength, Lower the energy of the photon

redviolet

VIBGYOR

Page 13: Survey of the Universe Tom Burbine tburbine@mtholyoke

ROYGBIV

• ROYGBIV • Red – long wavelength• Violet – short wavelength

Page 14: Survey of the Universe Tom Burbine tburbine@mtholyoke

http://www.arpansa.gov.au/images/basics/emr.jpg

Page 15: Survey of the Universe Tom Burbine tburbine@mtholyoke

Any Questions?