1. SQL Basics Some common queries

2. SELECT USE AdventureWorks GO SELECT ContactID, Title, FirstName, LastName FROM Person.Contact Comment: Person is the Schema and Contact is the Table

3. SELECT ALL USE AdventureWorks GO SELECT * FROM Person.Contact Comment: Good practise to explicity reference only necessary columns

4. FILTER USE AdventureWorks GO SELECT Title, FirstName, LastName FROM Person.Contact WHERE Title = 'Ms.'

5. AND USE AdventureWorks GO SELECT Title , FirstName, LastName FROM Person .Contact WHERE Title = 'Ms.' AND LastName = 'Antrim'

6. OR USE AdventureWorks GO SELECT Title , FirstName, LastName FROM Person .Contact WHERE Title = 'Ms.' OR LastName = 'Antrim'

7. NOT USE AdventureWorks GO SELECT Title, FirstName, LastName FROM Person.Contact WHERE NOT Title = 'Ms.'

8. WITHOUT PARENTHESIS USE AdventureWorks GO SELECT Title , FirstName, LastName FROM Person .Contact WHERE Title = 'Ms.' AND FirstName = 'Catherine' OR LastName = 'Adams'

9. With Parentheses SELECT ContactID, Title, FirstName, MiddleName, LastName FROM Person.Contact WHERE (Title = 'Ms.' AND FirstName = 'Catherine') OR LastName = 'Adams'

10. BETWEEN USE AdventureWorks GO SELECT SalesOrderID, ShipDate FROM Sales.SalesOrderHeader WHERE ShipDate BETWEEN '7/28/2002' AND '7/29/2002'

11. Less Than USE AdventureWorks GO SELECT ProductID , Name , StandardCost FROM Production .Product WHERE StandardCost < 110.0000

12. IS NULL USE AdventureWorks GO SELECT ProductID , Name , Weight FROM Production .Product WHERE Weight IS NULL

13. IN USE AdventureWorks GO SELECT ProductID , Name , Color FROM Production .Product WHERE Color IN ( 'Silver' , 'Black' , 'Red' )

14. LIKE USE AdventureWorks GO SELECT ProductID , Name FROM Production .Product WHERE Name LIKE 'B%'

15. Escape USE AdventureWorks GO SELECT ProductID , Name FROM Production .Product WHERE Name LIKE '%/_%' ESCAPE '/'

16. ORDER BY USE AdventureWorks GO SELECT p .Name, h.EndDate, h.ListPrice FROM Production .Product p INNER JOIN Production.ProductListPriceHistory h ON p .ProductID = h.ProductID ORDER BY p .Name, h.EndDate

17. ORDER - DESC USE AdventureWorks GO SELECT p .Name, h.EndDate, h.ListPrice FROM Production .Product p INNER JOIN Production.ProductListPriceHistory h ON p .ProductID = h.ProductID ORDER BY p .Name DESC , h.EndDate DESC Comment: Although queries sometimes appear to return data properly without an ORDER BY clause, the natural ordering of results is determined by the physical key column order in the clustered index

18. ORDER BY Unselected Column USE AdventureWorks GO SELECT p .Name FROM Production .Product p

19. TOP USE AdventureWorks GO SELECT TOP 10 v .Name, v.CreditRating FROM Purchasing .Vendor v ORDER BY v .CreditRating DESC , v.Name

20. Variables USE AdventureWorks GO DECLARE @Percentage float SET @Percentage = 1 SELECT TOP (@Percentage) PERCENT Name FROM Production .Product ORDER BY Name

21. GROUP BY USE AdventureWorks GO SELECT OrderDate , SUM (TotalDue) TotalDueByOrderDate FROM Sales .SalesOrderHeader WHERE OrderDate BETWEEN '7/1/2001' AND '7/31/2001' GROUP BY OrderDate

22. GROUP BY ALL USE AdventureWorks GO SELECT OrderDate , SUM (TotalDue) TotalDueByOrderDate FROM Sales .SalesOrderHeader WHERE OrderDate BETWEEN '7/1/2001' AND '7/31/2001' GROUP BY ALL OrderDate

23. HAVING USE AdventureWorks GO SELECT s .Name, COUNT (w.WorkOrderID) Cnt FROM Production .ScrapReason s INNER JOIN Production.WorkOrder w ON s .ScrapReasonID = w.ScrapReasonID GROUP BY s .Name HAVING COUNT (*)>50

24. DISTINCT USE AdventureWorks GO SELECT DISTINCT HireDate FROM HumanResources .Employee

25. AVG USE AdventureWorks GO SELECT AVG (ListPrice) FROM Production .Product

26. AVG and DISTINCT USE AdventureWorks GO SELECT AVG ( DISTINCT ListPrice ) FROM Production .Product

27. Column ALIASES USE AdventureWorks GO SELECT Color AS 'Grouped Color' , AVG ( DISTINCT ListPrice ) AS 'Average Distinct List Price' , AVG (ListPrice) 'Average List Price' FROM Production .Product GROUP BY Color

28. INFORMATION SCHEMA USE AdventureWorks GO SELECT column_name + ' IS NULL AND ' FROM INFORMATION_SCHEMA.columns WHERE table_name = 'Employee' ORDER BY ORDINAL_POSITION

29. String concatenation USE AdventureWorks GO SELECT 'The ' + p.name + ' is only ' + CONVERT ( varchar (25),p.ListPrice) + '!' FROM Production .Product p WHERE p .ListPrice between 100 AND 120 ORDER BY p .ListPrice

30. Comma Delimited List USE AdventureWorks GO DECLARE @Shifts varchar (20) SET @Shifts = '' SELECT @Shifts = @Shifts + s.Name + ',' FROM HumanResources .Shift s ORDER BY s .EndTime SELECT @Shifts

31. SELECT INTO USE AdventureWorks GO SELECT CustomerID , Name , SalesPersonID, Demographics INTO Store_Archive FROM Sales .Store Comment: This creates a table called Store_Archive

32. Create a schema with SELECT USE AdventureWorks GO SELECT CustomerID , Name , SalesPersonID, Demographics INTO Store_Archive2 FROM Sales .Store WHERE 1 =0

33. Puzzle I've got The Customers table : T1 .. has two columns : ID(int) , IsDeleted(bit) I want in a one sql query to return : NumberOfAllCustomers -- NumberOfDeletedCustomers -- NumberOfExistingCustomers

34. Prepare data for puzzle USE tempdb ; IF OBJECT_ID ( 'dbo.T1' ) IS NOT NULL DROP TABLE dbo .T1; CREATE TABLE dbo .t1 ( ID INT NOT NULL, IsDeleted bit ); INSERT INTO dbo .T1(ID, IsDeleted) VALUES (1,0); INSERT INTO dbo .T1(ID, IsDeleted) VALUES (2,1); INSERT INTO dbo .T1(ID, IsDeleted) VALUES (3,0); INSERT INTO dbo .T1(ID, IsDeleted) VALUES (4,1); INSERT INTO dbo .T1(ID, IsDeleted) VALUES (5,0); GO

35. Check expected answers SELECT Count (ID) AS NumberOfAllExistingCustomers FROM T1 SELECT Count (ID) AS NumberOfDeletedCustomers FROM T1 WHERE IsDeleted = 1 SELECT Count (ID) AS NumberOfExistingCustomers FROM T1 WHERE IsDeleted = 0

36. Answer One SELECT COUNT (*) AS NumberOfAllCustomers , SUM ( CASE IsDeleted WHEN 1 THEN 1 END ) AS NumberOfDeletedCustomers , SUM ( CASE IsDeleted WHEN 0 THEN 1 END ) AS NumberOfExistingCustomers FROM T1 GO

37. Answer Two select numberOfAllCustomers , numberOfDeletedCustomers, numberOfAllCustomers - numberOfDeletedCustomers AS NumberOfExistingCustomers from ( select ( select count (id) from t1 ) numberOfAllCustomers, ( select count (id) from t1 where isdeleted = cast (1 as bit )) numberOfDeletedCustomers ) t;