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1 PETE 411 Well Drilling Lesson 14 Jet Bit Nozzle Size Selection

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    PETE 411Well Drilling

    Lesson 14

    Jet Bit Nozzle Size Selection

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    14. Jet Bit Nozzle Size Selection

    Nozzle Size Selection

    for Optimum Bit Hydraulics:

    Max. Nozzle Velocity

    Max. Bit Hydraulic Horsepower

    Max. Jet Impact Force

    Graphical Analysis

    Surge Pressure due to Pipe Movement

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    3

    Read:Applied Drilling Engineering, to p.162

    Quiz A

    Thu rsday, Oct. 10, 7 - 9 p .m . Rm . 101

    Closed Book1 Equation sheet allowed, 8 1/2x 11 (both sides)

    HW #7:

    On the Web - due 10-09-02

    { Quiz A_2001 is on the web }

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    Jet Bit Nozzle Size Selection

    Proper bottom-hole cleaning

    will eliminate excessive regrinding of drilled

    solids, and

    will result in improved penetration rates

    Bottom-hole cleaning efficiency is achieved through proper selection of bit

    nozzle sizes

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    5

    Jet Bit Nozzle Size Selection

    - Optimization -

    Through nozzle size selection,

    optimization may be based on

    maximizing one of the following: Bit Nozzle Velocity

    Bit Hydraulic Horsepower

    Jet impact force

    There is no general agreement on which ofthese three parameters should be maximized.

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    Maximum Nozzle Velocity

    Nozzle velocity may be maximized consistent with

    the following two constraints:

    1.The annular fluid velocity needs to be high

    enough tolift the drill cuttingsout of the hole.

    - This requirement sets the minimum

    fluid circulation rate.

    2.The surface pump pressure must stay within themaximum allowable pressurerating of the

    pump and the surface equipment.

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    Maximum Nozzle Velocity

    From Eq. (4.31)

    i.e.

    so the bit pressure drop should be maximized in

    order to obtain the maximum nozzle velocity

    4

    bdn

    10*074.8

    PCv

    bn Pv

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    Maximum Nozzle Velocity

    This (maximization) will be achieved when

    the surface pressure is maximized and the

    frictional pressure loss everywhere is

    minimized, i.e., when the flow rate isminimized.

    pressure.surfaceallowablemaximumtheand

    ratencirculatiominimumtheatsatisfied,areabove2&1whenmaximizedisvn

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    Maximum Bit Hydraulic Horsepower

    The hydraulic horsepower at the bit is

    maximized when is maximized.q)p( bit

    dpumpbit ppp

    where may be called the parasiticpressure

    loss in the system (friction).dp

    bitdpump ppp

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    Maximum Bit Hydraulic Horsepower

    .turbulentisflowtheif

    cqpppppp75.1

    dpadcadcdpsd

    In general, wheremd cqp 2m0

    The parasiticpressure loss in the system,

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    Maximum Bit Hydraulic Horsepower

    0)1(pwhen0

    17141714

    pump

    1

    mHbit

    m

    pumpbitHbit

    qmcdq

    dP

    cqqpqpP

    dpumpbit ppp m

    d cqp

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    Maximum Bit Hydraulic Horsepower

    whenmaximumis

    11pwhen.,.

    )1(pwhen.,.

    d

    pump

    Hbit

    pump

    d

    P

    pm

    ei

    pmei

    pumpd p

    m

    p

    1

    1

    0)1(ppump m

    qmc

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    Maximum Bit Hydraulic Horsepower

    - Examples -

    In turbulent flow, m = 1.75

    pumpbit

    pump

    pumpd

    pof%64p

    pof36%

    %100*p175.1

    1p

    pd p1m

    1p

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    In laminar flow, for Newtonian fluids, m = 1

    pumpb

    pump

    pumpd

    pof%50p

    pof50%

    %100*p11

    1p

    Maximum Bit Hydraulic Horsepower

    Examples - contd

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    Maximum Bit Hydraulic Horsepower

    In general, the hydraulic horsepower is notoptimized at all times

    It is usually more convenient to select apump liner size that will be suitable for

    the entire well

    Note that at no time should the flow rate beallowed to drop below the minimum

    required for proper cuttings removal

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    Maximum Jet Impact Force

    The jet impact force is given by Eq. 4.37:

    )(c0.01823

    01823.0

    d dpump

    bitdj

    ppq

    pqcF

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    Maximum Jet Impact Force

    But parasitic pressure drop,

    2201823.0

    m

    dpdj

    m

    d

    qcqpcF

    cqp

    )(c0.01823d dpumpj ppqF

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    Maximum Jet Impact Force

    Upon differentiating, setting the first derivative

    to zero, and solving the resulting quadratic

    equation, it may be seen that the impact

    forceis maximized when,

    pd p2m

    2p

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    Maximum Jet

    Impact Force

    - Examples -

    pb

    pd

    pof%47pand

    pof%53p1.75,mif,

    Thus

    pb

    pd

    pof33%pand

    pof%67p1.00mif,

    Also

    pd p2m

    2p

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    Nozzle Size Selection

    - Graphical Approach -

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    1. Show opt. hydraulic path

    2. Plot pdvs q

    3. From Plot, determineoptimum q and pd

    4. Calculate5. CalculateTotal Nozzle Area:

    (TFA)

    6. Calculate Nozzle Diameter

    dpumpbit ppp

    optbd

    opt

    opttpC

    qA

    )(

    10*311.8)(

    2

    25

    With 3 nozzles:3

    A4d

    tot

    N

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    Example 4.31

    Determine the proper pump operatingconditions and bit nozzle sizes for max.

    jet impact force for the next bit run.

    Current nozzle sizes: 3 EA 12/32

    Mud Density = 9.6 lbm.gal

    At 485 gal/min, Ppump = 2,800 psi

    At 247 gal/min, Ppump= 900 psi

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    Example 4.31 - given data:

    Max pump HP (Mech.) = 1,250 hp

    Pump Efficiency = 0.91

    Max pump pressure = 3,000 psig

    Minimum flow rateto lift cuttings = 225 gal/min

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    Example 4.31 - 1(a), 485 gpm

    Calculate pressure drop through bit nozzles:

    22

    2510*311.8

    :)34.4.(td

    bAc

    qpEq

    psi9061,894-2,800losspressureparasitic

    psi1,894

    32

    12

    4

    3(0.95)

    )485)(6.9)(8.311(10p

    22

    2

    2-5

    b

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    Example 4.31 - 1(b), 247 gpm

    psipb 491

    32

    12

    43)95.0(

    )247)(6.9)(10(311.82

    2

    2

    25

    psi409491-900losspressureparasitic

    Plot these two

    points in Fig. 4.36

    (q1, p1) = (485, 906)

    (q2, p2) = (247, 409)

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    Example 4.31 - contd

    2. For optimum hydraulics:

    gal/min650

    000,3

    )91.0)(250,1(714,1714,1q

    max

    max

    P

    EPHp

    1,Interval)a(

    gal/min225q

    psi875,1

    )000,3(22.1

    2

    2

    2p

    min

    maxd

    P

    m2,Interval(b)

    3,Interval(c)

    32

    1

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    Example 4.31

    3. From graph, optimum point is at

    )(

    10*311.8)(

    2

    25

    optbd

    opt

    opttpC

    qA

    )700,1(*)95.0(

    )650(*6.9*10*8.311

    2

    2-5

    indoptN

    nds2

    opt 3214in0.47A

    psippsigal

    q b 700,1300,1p,min

    650 d

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    psippsigal

    q b 700,1300,1p,min

    650 d

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    Example 4.32

    It is desired to estimate the proper pump

    operating conditions and bit nozzle sizes formaximum bit horsepower at 1,000-ft

    increments for an interval of the well

    between surface casing at 4,000 ftandintermediate casing at 9,000 ft. The well

    plan calls for the following conditions:

    Well Planning

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    Example 4.32

    Pump: 3,423 psi maximum surface pressure

    1,600 hp maximum input

    0.85 pump efficiency

    Drillstring: 4.5-in., 16.6-lbm/ft drillpipe

    (3.826-in. I.D.)

    600 ft of 7.5-in.-O.D. x 2.75-in.-

    I.D. drill collars

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    Example 4.32

    Surface Equipment: Equivalent to 340

    ft. of drillpipe

    Hole Size: 9.857 in. washed out to 10.05 in.

    10.05-in.-I.D. casing

    Minimum Annular Velocity: 120 ft/min

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    Mud Program

    Mud Plastic YieldDepth Density Viscosity Point(ft) (lbm/gal) (cp) (lbf/100 sq ft)

    5,000 9.5 15 5

    6,000 9.5 15 5

    7,000 9.5 15 58,000 12.0 25 9

    9,000 13.0 30 12

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    Solution

    The path of optimum hydraulics is asfollows:

    Interval 1

    gal/min.681

    423,3

    )85.0)(600,1(714,1

    p

    EP714,1q

    max

    Hp

    max

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    Solution

    Interval 2Since measured pump pressure data are not

    available and a simplified solution technique

    is desired, a theoretical m value of 1.75 isused. For maximum bit horsepower,

    psia1,245

    423,3175.1

    1

    1

    1max

    pmpd

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    Solution

    Interval 3

    For a minimum annular velocity of

    120 ft/min opposite the drillpipe,

    gal/min395

    60

    1205.405.10448.222

    min

    q

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    Table

    The frictional pressure loss in othersections is computed following a

    procedure similar to that outlined above for

    the sections of drillpipe. The entireprocedure then can be repeated to

    determine the total parasitic losses at

    depths of 6,000, 7,000, 8,000 and 9,000 ft.The results of these computations are

    summarized in the following table:

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    Table

    5,000 38 490 320 20 20 888

    6,000 38 601 320 20 25 1,0047,000 38 713 320 20 29 1,120

    8,000 51 1,116 433 28 75* 1,703

    9,000 57 1,407 482 27* 111* 2,084

    * Laminar flow pattern indicated byHedstrom number criteria.

    ddpadcadcdps ppppppDepth

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    Table

    The proper pump operating conditions

    and nozzle areas, are as follows:

    5,000 600 1,245 2,178 0.380

    6,000 570 1,245 2,178 0.361

    7,000 533 1,245 2,178 0.338

    8,000 420 1,245 2,178 0.299

    9,000 395 1,370 2,053 0.302

    in.)(sq(psi)(psi)(gal/min))ft(

    (5)Ap(4)p(3)Rate(2)FlowDepth)l( tbd

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    Table

    The first three columns were read directlyfrom Fig. 4.37. (depth, flow rate and pd)

    Col. 4 (pb) was obtained by subtractingshown in Col.3 from the maximum pump

    pressure of 3,423 psi.

    Col.5 (Atot) was obtained using Eq. 4.85

    dp

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    Surge Pressure due to Pipe Movement

    When a string of pipe isbeing lowered into the

    wellbore, drilling fluid is

    being displaced and forcedout of the wellbore.

    The pressure required to

    force the displaced fluid outof the wellbore is called the

    surge pressure.

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    Surge Pressure due to Pipe Movement

    An excessively high surge pressure canresult in breakdownof a formation.

    When pipe is being withdrawn a similar

    reduction is pressure is experienced. Thisis called a swab pressure, and may be

    high enough to suck fluids into the wellbore,

    resulting in a kick.

    swabsurge PP ,vfixedFor pipe

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    Figure 4.40B

    - Velocity profile for laminar flow pattern when closed