1. A productivity test was conducted on a well. The test results indicate that the well is capable of producing at a stabilized flow rate of 110 STB/day and a bottom-hole flowing pressure of 900 psi. After shutting the well for 24 hours, the bottom-hole pressure reached a static value of 1300 psi.

Calculate: Productivity index AOF Oil flow rate at a bottom-hole flowing pressure of 600 psi Wellbore flowing pressure required to produce 250 STB/day

A. = 1.0 0.2 0.8 = 1.0 0.2 0.8 = 0.862 0.8 (0.69)2 = 0.862 0.38088= 0.48112Qmax = = 228.63319 STB/dayPI = ( JP ) = = = 0.316

B.AOF (Absolute open flow ) adalah keadaan choke dibuka full yang berarti kemampuan rate maksimum ( Qmax ) dari perhitungan 1A maka didapat Qmax = 228.63319 STB/day.

C. = 1.0 0.2 0.8 = 1.0 0.2 0.8 = 0.908 0.8 (0.212)2 = 0.908 0.170= 0.738

Qmax = 149.05149 STB/day

D. = 1.0 0.2 0.8 = 1.0 0.2 0.8 = 0.862 0.8 (0.69)2 = 0.862 0.38088Qmax= Qmax = 519.62088 STB/day

2. A well is producing from a saturated reservoir with an average reservoir pressure of 2500 psig. Stabilized production test data indicated that the stabilized rate and wellbore pressure are 350 STB/day and 2000 psig, respectively.

Calculate: Oil flow rate at pwf1850 psig Calculate oil flow rate assuming constant J Construct the IPR by using Vogels method and the constant productivity index approach

A. = 1.0 0.2 0.8 = 1.0 0.2 0.8 = 0.852 0.8 (0.74)2 = 0.852 0.438 = 350 x 0.414 = 144.90 STB/day

B. = 1.0 0.2 0.8 = 1.0 0.2 0.8 = 0.872 0.8 (0.8)2 = 0.872 0.512= 350 x 0.36= 126 STB/dayQmax with assuming J constantQmax= = = = 1388.88 STB/day

Pwfq0

25000

2000126

1850144.9

01388.88

3. An oil well is producing from an undersaturated reservoir that is characterized by a bubble-point pressure of 2130 psig. The current average reservoir pressure is 3000 psig. Available flow test data show that the well produced 250 STB/day at a stabilized pwf2500 psig. Construct the IPR data.

Pwfq

30000

2500896.7

1500357.14

0250

4. The well described in Example 3 was retested and the following results obtained:Pwf = 1700 psig, Qo = 630.7 STB/dayGenerate the IPR data using the new test data.

Pwfq

30000

17001000

1000744.637

0630.7

5. Construct IPR of a vertical well in an undersaturated oil reservoir using the generalized Vogel equation. The following data are given:

= = = = = 2995.6 STB/day

Qmax = 4477.058 STB/day

Pwfq

56510

30004,477

10003188.157

02995.6

6. Construct IPR of two wells in an undersaturated oil reservoir using the generalized Vogel equation. The following data are given:

Well A

Well B

qo at Pb

Well A Well BPwfq

50000

4000914.634

3000506.756

2000378.78

1000323.27

0300

Pwfq

50000

40002743.9

30001520.27

20001136.36

1000969.828

0900

7. Using the data given in number-2, predict the IPR where the average reservoir pressure declines from 2500 psig to 2200 psig.

Pwfq

22000

20002034.88

1000467.91

0350

8. The information given number 2 is repeated here for convenience: Current average pressure = 2500 psig Stabilized oil flow rate = 350 STB/day Stabilized wellbore pressure = 2000 psigGenerate the current IPR data and predict future IPR when the reservoirpressure declines from 2500 to 2000 psig by using Wiggins method.

Pwfq

25000

2000350

0749.478

9. A well is producing from a saturated oil reservoir that exists at its saturation pressure of 4000 psig. The well is flowing at a stabilized rate of 600 STB/day and a pwf of 3200 psig. Material balance calculations provide the following current and future predictions for oil saturation andPVT properties.

Generate the future IPR for the well at 3000 psig by using Standingsmethod.

Relation J to J*

Prepare table for future IPR by assuming values of Pwf and calculating corresponding rate :

PwfPwf/Prq0

300010

25000.83322.865

20000.66578.931

15000.5779.331