the kinematic equations

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The Kinematic Equations IB PHYSICS | MOTION

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Page 1: The Kinematic Equations

The Kinematic EquationsIB PHYSICS | MOTION

Page 2: The Kinematic Equations

Motion Variables

Displacement Initial Velocity Final Velocity Acceleration Time

Whenever we are describing the motion of an accelerating object, there are five variables that we need to take into account

Note: The variables used in IB Physics vary slightly from other nomenclature standards

s tu v a

Page 3: The Kinematic Equations

Calculating Acceleration

π‘Žπ‘π‘π‘’π‘™π‘’π‘Ÿπ‘Žπ‘‘π‘–π‘œπ‘› =π‘“π‘–π‘›π‘Žπ‘™ π‘£π‘’π‘™π‘œπ‘π‘–π‘‘π‘¦ βˆ’ π‘–π‘›π‘–π‘‘π‘–π‘Žπ‘™ π‘£π‘’π‘™π‘œπ‘π‘–π‘‘π‘¦

π‘β„Žπ‘Žπ‘›π‘”π‘’ 𝑖𝑛 π‘‘π‘–π‘šπ‘’

Sym

bo

lsU

nit

s

=

= a v - ut

ms-2 ms-1 ms-1

s-

Page 4: The Kinematic Equations

Think about this unit…

m/s/sm/s2

m s-2

π‘Ž =𝑣 βˆ’ 𝑒

𝑑

Page 5: The Kinematic Equations

Try This | 1

What is the acceleration of a car that accelerates from 15 m s-1 to 35 m s-1 in 10 seconds?

𝑒

𝑣

π‘Ž

𝑑

π‘Ž =𝑣 βˆ’ 𝑒

𝑑

π‘Ž = πŸπ¦π¬βˆ’πŸ

15 ms-1

35 ms-1

10 s

?

=35 βˆ’ 15

10

Page 6: The Kinematic Equations

Try This | 2

Find the average acceleration of a northbound train that slows down from 12 m s-1 to a complete stop in 8 sec *Tip: You can get a negative value!

𝑒

𝑣

π‘Ž

𝑑

π‘Ž =𝑣 βˆ’ 𝑒

𝑑

π‘Ž = βˆ’πŸ. πŸ“ π¦π¬βˆ’πŸ

12 ms-1

0 ms-1

8 s

?

=0 βˆ’ 12

8

Page 7: The Kinematic Equations

Solve for v

π‘Ž =𝑣 βˆ’ 𝑒

𝑑

𝑣 = 𝑒 + π‘Žπ‘‘

Page 8: The Kinematic Equations

Physics Data Booklet

Page 9: The Kinematic Equations

How far have I gone?V

elo

city

(m

s-1

)

Time (s)

20

40

60

80

100

2 4 6 8 101 3 5 7 9 11 12

120

10 s

80 m s-1

𝑠 = 𝑣𝑑 = 80 m sβˆ’1 10 s = 800 m

π‘Žπ‘Ÿπ‘’π‘Ž π‘’π‘›π‘‘π‘’π‘Ÿ π‘”π‘Ÿπ‘Žπ‘β„Ž = 80 m sβˆ’1 10 s = 800 m

Page 10: The Kinematic Equations

Use the graphs to tell you MORE!Sl

op

eA

rea Un

der C

urve

Displacement vs Time

Velocity vs Time

Slo

pe

Velocity vs Time

Velocity

Acceleration

Displacement

Page 11: The Kinematic Equations

How far have I gone?V

elo

city

(m

s-1

)

Time (s)

20

40

60

80

100

2 4 6 8 101 3 5 7 9 11 12

120 π‘Žπ‘Ÿπ‘’π‘Ž π‘’π‘›π‘‘π‘’π‘Ÿ π‘”π‘Ÿπ‘Žπ‘β„Ž = 60 m sβˆ’1 8 s = 480 m

π΄π‘£π‘’π‘Ÿπ‘Žπ‘”π‘’ π‘‰π‘’π‘™π‘œπ‘π‘–π‘‘π‘¦ =𝑣 + 𝑒

2

𝑠 =𝑣 + 𝑒

2Γ— 𝑑

Page 12: The Kinematic Equations

Physics Data Booklet

Page 13: The Kinematic Equations

What if I don’t know v?

𝑣 = 𝑒 + π‘Žπ‘‘π‘  = 𝑣+𝑒 𝑑2

𝑠 = 𝑒+π‘Žπ‘‘+𝑒 𝑑2

𝑠 = 2𝑒𝑑+π‘Žπ‘‘2

2𝑠 = 𝑒𝑑+

12π‘Žπ‘‘2

= 2𝑒+π‘Žπ‘‘ 𝑑2

Page 14: The Kinematic Equations

Physics Data Booklet

Page 15: The Kinematic Equations

One more equation

𝑣2 = 𝑒2 + 2π‘Žπ‘ 

Page 16: The Kinematic Equations

Equations

𝑣 = 𝑒 + π‘Žπ‘‘

𝑠 = 𝑒𝑑 + 12π‘Žπ‘‘2

𝑣2 = 𝑒2 + 2π‘Žπ‘ 

𝑠 = 𝑣+𝑒 𝑑2

m m s-1 m s-1 m s-2 s

𝑒 𝑣 π‘Ž 𝑑

𝑠 𝑒 π‘Ž 𝑑

𝑠 𝑒 𝑣 π‘Ž

𝑠 𝑒 𝑣 𝑑

Page 17: The Kinematic Equations

Try This | 3

𝑠

𝑒

𝑣

π‘Ž

𝑑

You speed up with a uniform acceleration from 0 m/s to 30 m/s in 5 seconds. How far have you gone?

𝑠 = 30+0 (5)2

0 m s-1

30 m s-1

5 s

?

------

= πŸ•πŸ“π¦

Page 18: The Kinematic Equations

Try This | 4

𝑠

𝑒

𝑣

π‘Ž

𝑑

If a plane on a runway is accelerating at 4.8 m s-2 for 15 seconds before taking off, how long should the runway be?

𝑠 = 𝑒𝑑 + 12π‘Žπ‘‘2

= (0)(15) + 12(4.8)(15)2

𝑠 = 540 m

0 m s-1

------

15 s

?

4.8 m s-2

Page 19: The Kinematic Equations

Try This | 5

𝑠

𝑒

𝑣

π‘Ž

𝑑

A driver slams on the brakes and skids for 3 seconds before coming to a stop. You go and measure that the skid marks show a deceleration over 9 m. What was the initial speed of the car?

𝑠 = 𝑣+𝑒 𝑑2

𝑒 = 2π‘ π‘‘βˆ’ 𝑣

𝑒 = 6 m sβˆ’1

?

0 m s-1

3 s

9 m

-----= 2(9)(3)

βˆ’ 0

Page 20: The Kinematic Equations

Lesson Takeaways

❑ I can identify the 5 primary variables of motion

❑ I can identify the proper kinematic equation to use for a

problem that is presented

❑ I can rearrange to solve for the unknown variable

❑ I can calculate for an unknown