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    PETE 405Well Dri l l ing

    Lesson 3

    Th e Rig - Dr i ll ing Equ ipm en t

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    Contents

    Rig PumpsSolids Control Equipment

    Air DrillingThe Rotary SystemThe Swivel

    The Well Control SystemThe Well Monitoring SystemOffshore Drilling

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    A s s ign men t s :

    READ: A DE Ch. 1, to p .30

    HW #1: A DE 1.1, 1.2, 1.3

    NOTE: A ns w ers in bo ok are no talway s c o rrec t ...

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    Schematicof Rig

    CirculatingSystem for

    liquid

    drillingfluid

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    Exam p le 1.3

    Compute the pump factor in units ofbarrels per stroke for a double-actingduplex pump having:

    6.5-inch liners (d L) 2.5 inch rods (d r ) 18-inch strokes (LS ) and a volumetric efficiency of 90%. (E V)

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    Solu t ion :

    The pump factor for a duplex pump canbe determined using Equation 1.10

    stroke

    d d E L F r LV S p

    /in991,1

    5.25.629.0182

    22

    3

    22

    22

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    Recall :

    There are 231 in. 3 in a U. S. gallon and42 U.S. gallons in a U.S. barrel. Thusconverting to the desired field unitsyields:

    1,991 in. 3/stroke * gal/231 in. 3 * bbl/42 gal.= 0.2052 bbl/stroke.

    Thus: Pump Factor = 0.2052 bbl/stroke

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    Pump Factor = 3 * /4 d L2 LS E V / (231 * 42)

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    Example :

    Pump Factor for Triplex Pump

    3

    3

    2

    VS

    2

    L

    inbbl

    422311

    strokein0.90126

    43

    ELd4

    3

    bbl/stroke0.09442Factor Pump

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    Example : Pump Rate

    = Pump Factor * Strokes/min

    = 0.09442

    = 7.554 bbl/min

    = 317.3 gal/min

    min

    stks

    80stk

    bbl

    Pump Rate = 317 gal/min

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    Pumps of the future

    Source: drilling contractor, sept/oct 2002

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    Pumps of the future

    BENTECs SOFT PUMP SYSTEM (SPS)

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    Hydrocyclone

    desander desilter

    * No moving parts* Low cost* Pressure drop* Diameter

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    15Decanting Centrifuge Use?

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    l

    l

    Use?

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    Fig. 1.33 Schematic

    of RotarySystem

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    Fig. 1.34 Cutaway

    View ofSwivel

    ROTATING * Seals* Bearings

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    Fig. 1.38

    Cutaway View andDimensions forExample Tool Joint

    PINBOX

    TJShoulder

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    Fig. 1.39 Stabilizer

    * Keeps pipe in center of hole

    * Aids in drilling straight hole

    * Prolongs bit life

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    Fig. 1.41 Kick Detection During

    Drilling Operations

    1

    2

    3

    KICK

    GAIN IN PIT VOLUME EQUALTO KICK VOLUME

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    Fig. 1.46 RemoteControl

    Panel for

    operatingBlowout

    PreventersCHOKE

    What to do if KICK occurs?

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    23Fig. 1.44 Annular Blowout Preventer

    DPTJDCOH

    Press

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    Ram Blowout Preventer

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    25Ram Blowout Preventer -contd

    SHEAR / BLIND

    RAM ASSEMBLY

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    26Fig. 1.48 Rotating Blowout Preventer

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    Fig. 1.51 High-

    PressureCirculating

    System forWell

    Control

    Operations

    Keep BHP const.

    Kick

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    Fig. 1.56 Subsurface

    Well

    MonitoringSystem

    MWD

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    29Fig. 1.57 Spread Mooring Systems

    OFFSHORE DRILLING

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    Fig. 1.58

    Schematic ofEquipmentfor Marine

    Drilling

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    Fig. 1.59 Operation of aHeave Compensator

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    Fig. 1.60 Subsea

    BOPStack

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    Fig. 1.63 Subsea Equipment

    Installation Procedure

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    Ty pic al Casin g Str ing s

    Water Level

    Depth Seafloor Below ML

    Conductor pile 36 30 200

    Conductor Casing 26 20 1000

    Surface Casing 17 1/2 13 3/8 4000

    Hole Csg. Depth

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    Som e Typ ical Cas ing Str ing s

    Depth Below ML

    Conductor pile 36 30 200

    Conductor Casing 26 20 1000

    Surface Casing 17 1/2 13 3/8 4000

    Hole Csg. Depth

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    Example Hole and String Sizes (in)

    Structural casing

    Conductor string

    Surface pipe

    Intermediate String

    Production Liner

    Hole Size30 20

    13 3/8

    9 5/8

    7

    Pipe Size 36 26

    17 1/2

    12 1/4

    8 3/4

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    37Capacity = Area * Length

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    What is the capacity of 10,000 ft of 5OD, 19.50 lb/ft drillpipe?

    Capacity = Area * Length

    Area = /4 d 2 = /4 * 4.276 2 = 14.36 in 2

    Length = 10,000 ft = 120,000 in

    Capacity = 14.36 *120,000 in 3 /(231*42 in 3 /bbl)

    Capacity = 177.6 bbls

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    What is the displacement of 10,000 ftof 5 OD, 19.50 lb/ft drillpipe?

    Capacity = Area * Length

    Area = /4 (od 2 - id 2 ) = /4 * (5 2 - 4.276 2)

    = 5.275 in 2

    Length = 10,000 ft = 120,000 in

    Displ. = 5.276 * 120,000 in3

    /(231 * 42 in3

    /bbl)

    Displacement = ? bbls