thermodynamics overall (brief)

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1412 Lecture notes – Chapter 15 - Thermodynamics Thermodynamics  First Law of Thermodynamics = energy is neither created nor destroyed Enthalpy: H +H, endothermic feels cold because heat is converted into chemical energy lower energy reactants higher energy products   H, exothermic feels hot because chemical energy is converted into heat higher energy reactants lower energy products H rxn = Σ(n×H f ) prod  Σ(n×H f ) react  CaCO 3 (s)  CaO(s) + CO 2 (g)  H rxn = _____________ 2C 2 H 2 (g) + 5O 2 (g)  4CO 2 (g) + 2H 2 O(g) H rxn = _____________ How much heat is produced by the decomposition of 2 moles of CaCO 3 ? How much heat is produced by the combustion of 5 grams of C 2 H 2 ? Entropy: S Change in entropy ( S) is a measure of change in disorder for a reaction. Less disordered reactants more disordered products + S More disordered reactants less disordered products  S Second Law of Thermodynamics = the universe favors disorder. Third Law of Thermodynamics = at zero Kelvin, entropy (S) is equal to zero. S rxn = Σ(n×S f ) prod  Σ(n×S f ) react 2C 2 H 2 (g) + 5O 2 (g)  4CO 2 (g) + 2H 2 O(g) S rxn = _____________ Some values taken from appendix K Substance H f 0 (kJ/mol) S f 0 (J/mol) G f 0 (kJ/mol)  CaCO 3 (s) –1207 92.9 –1129 CaO(s) –635.5 40 –604.2 CO 2 (g) –393.5 213.6 –394.4 C 2 H 2 (g) 226.7 200.8 209.2 O 2 (g) 0 205.0 0 H 2 O(g) –241.8 188.7 –228.6

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Page 1: Thermodynamics Overall (Brief)

8/3/2019 Thermodynamics Overall (Brief)

http://slidepdf.com/reader/full/thermodynamics-overall-brief 1/2

1412 Lecture notes – Chapter 15 - Thermodynamics

Thermodynamics 

• First Law of Thermodynamics = energy is neither created nor destroyed

Enthalpy: ∆H

• +∆H, endothermicfeels cold because heat is converted into chemical energy

lower energy reactants higher energy products

•  – ∆H, exothermicfeels hot because chemical energy is converted into heathigher energy reactants lower energy products

• ∆Hrxn = Σ(n×∆Hf)prod – Σ(n×∆Hf)react 

• CaCO3(s)  CaO(s) + CO2(g)  ∆Hrxn = _____________ 

• 2C2H2(g) + 5O2(g)  4CO2(g) + 2H2O(g) ∆Hrxn = _____________ 

• How much heat is produced by the decomposition of 2 moles of CaCO3?

• How much heat is produced by the combustion of 5 grams of C2H2?

Entropy: ∆S

• Change in entropy (∆S) is a measure of change in disorder for a reaction.

• Less disordered reactants more disordered products +∆S

• More disordered reactants less disordered products – ∆S

• Second Law of Thermodynamics = the universe favors disorder.

• Third Law of Thermodynamics = at zero Kelvin, entropy (S) is equal to zero.

• ∆Srxn = Σ(n×∆Sf)prod – Σ(n×∆Sf)react 

• 2C2H2(g) + 5O2(g)  4CO2(g) + 2H2O(g) ∆Srxn = _____________ 

Some values taken from appendix K

Substance ∆Hf0

(kJ/mol) ∆Sf0

(J/mol) ∆Gf0

(kJ/mol) CaCO3(s) –1207 92.9 –1129

CaO(s) –635.5 40 –604.2

CO2(g) –393.5 213.6 –394.4

C2H2(g) 226.7 200.8 209.2

O2(g) 0 205.0 0

H2O(g) –241.8 188.7 –228.6

Page 2: Thermodynamics Overall (Brief)

8/3/2019 Thermodynamics Overall (Brief)

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1412 Lecture notes – Chapter 15 - Thermodynamics

Spontaneity - Will a reaction occur?

• Exothermic reactions (-∆H) are favored over endothermic reactions because the total potentialenergy is lowered.

• Increasing disorder (+∆S) is favored over decreasing disorder.

Gibbs Free Energy: ∆G 

• Gibbs free energy (∆G) tells whether a reaction (as written) is spontaneous.

• ∆Grxn = Σ(n×∆Gf)prod – Σ(n×∆Gf)react 

• ∆Grxn = ∆Hrxn – T∆Srxn temperature must be in Kelvin 

• ∆Grxn < 0 means reaction is spontaneous (product favored)

• ∆Grxn > 0 means reverse reaction is spontaneous (reactant favored)

• ∆Grxn = 0 means forward and reverse are equally favored (equilibrium)

• 2C2H2(g) + 5O2(g)  4CO2(g) + 2H2O(g) ∆Grxn = _____________ 

Hess’s Law

• C2H4 + H2O C2H5OH ∆H = ___________ 

Also given:

C2H5OH + 3O2  2CO2 + 3H2O ∆H = -1367 kJ/mol

C2H4 + 3O2  2CO2 + 2H2O ∆H = -1411 kJ/mol

Internal Energy and Work

• ∆E = q + w w = -P∆V = -∆nRT R = 8.314 J/mol·K ∆H = qp 

•  –w = work done by the system, +w = work done on the system

• H2O( ℓ  ) H2O(g)  ∆Hvap = 40.7 kJ/mol ∆E = ______________ 

Practice Problems: 11, 14, 30, 34, 36, 88c-f, 92, 94, 95, 96, 108