three moment theorem sam zou 3/6/2018 · three moment theorem sam zou 3/6/2018 span a = 24ft span b...

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Three Moment Theorem Sam Zou 3/6/2018 SPAN A = 24ft SPAN B = 9ft Span C =10ft Uniform load on span A, w1=3klf Uniform load on span C, w2=6klf Point load on span b, P=104k Distance to point load P from R2, D=6ft 1. Use three Moment Theorem to solve internal moments 2. Solve Support reaction R1, R2, R3 Make free body diagram of span A and B. - Make free body diagram of span A - Make free body diagram of span B - Make free body diagram of span C - Double Check ΣM@R2 =R1 (A)-W1(A/2)+|M2|=0 ΣFv =R1 -W1+V1=0 ΣFv =R2 -P+V2=0 ΣF =R1+R2+R3-W1-P-W2=0 ΣM@R3 =R2 (9)-P(3)-1.7(9)-|M2|+|M3|=0 ΣM@R3 =R4 (C)-W2(C/2)-|M3|=0 ΣM@R4 =R3 (C)-W2(C/2)+|M3|-V2(C)=0 =R3 (10)-60(5)+77.9-14.16(10)=0 R3 =95.3 =R4 (10)-60X(5)-77.9=0 R4 =22.2k =R2 (9)-104(3)-1.7(9)-184.2+77.9=0 =R1 (24)-24x3x(24/2)+184.28=0 R1 = 28.3 k R2 = 90.16k V1=1.7k V2=14.16k =M1=0 =WL2/24=1728 2M2(24+9)+M3(9)=6(1728+416) M2(9)+2M3(9+10)=6(520+250) =4PL2/81 =416 Make free body diagram of span B and C. =M2 =M3 M2=-184.28 k-ft M3=-77.9 k-ft L1 = A L2 = B =M2 =5PL2/81=520 =WL2/24 =250 =M3 =M4 =0 L1 = B L2 = C R1 R2 R3 R4 V1 V2 V1 V2 M2 M2 M3 M3

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Three Moment TheoremSam Zou3/6/2018

SPAN A = 24ftSPAN B = 9ftSpan C =10ftUniform load on span A, w1=3klfUniform load on span C, w2=6klfPoint load on span b, P=104kDistance to point load P from R2, D=6ft

1. Use three Moment Theorem to solve internal moments

2. Solve Support reaction R1, R2, R3

Make free body diagram of span A and B.

- Make free body diagram of span A

- Make free body diagram of span B

- Make free body diagram of span C

- Double Check

ΣM@R2 =R1 (A)-W1(A/2)+|M2|=0

ΣFv =R1 -W1+V1=0

ΣFv =R2 -P+V2=0

ΣF =R1+R2+R3-W1-P-W2=0

ΣM@R3 =R2 (9)-P(3)-1.7(9)-|M2|+|M3|=0

ΣM@R3 =R4 (C)-W2(C/2)-|M3|=0

ΣM@R4 =R3 (C)-W2(C/2)+|M3|-V2(C)=0 =R3 (10)-60(5)+77.9-14.16(10)=0 R3 =95.3

=R4 (10)-60X(5)-77.9=0 R4 =22.2k

=R2 (9)-104(3)-1.7(9)-184.2+77.9=0

=R1 (24)-24x3x(24/2)+184.28=0R1 = 28.3 k

R2 = 90.16k

V1=1.7k

V2=14.16k

=M1=0

=WL2/24=17282M2(24+9)+M3(9)=6(1728+416)

M2(9)+2M3(9+10)=6(520+250)

=4PL2/81 =416

Make free body diagram of span B and C.

=M2 =M3

M2=-184.28 k-ft

M3=-77.9 k-ft

L1 = A L2 = B

=M2

=5PL2/81=520 =WL2/24 =250

=M3 =M4 =0 L1 = B L2 = C

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R3 R4

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