trac nghiem sinh

8/3/2019 Trac Nghiem Sinh

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CU HI TRC NGHIM KIM TRA HC K IIMn: Sinh hc Lp 9

Cu 1: Pht biu no sau y l khng ng vi chc nng ca di truyn y hc t vn? (chng V/ bi30/ mc 1)

A. Chn on. C. Cho li khuyn quan n cc bnh v tt di truyn.B. Cung cp thng tin. D. iu tr cc tt, bnh di truyn.

p n: DCu 2: Nhng ngi c quan h huyt thng trong vng my i th khng c kt hn vi nhau?(chng V/ bi 30/ mc 1)

A. 3 i . C. 5 i.B. 4 i . D. 6 i.

p n: ACu 3: la tui no sau y ph n khng nn sinh con? (chng V/ bi 30/ mc 1)

A. 24. B. 28. C. 34. D. Trn 35.p n: DCu 4: Nguyn nhn ch yu gy ra nhim mi trng, lm tng s ngi mc bnh, tt di truyn l do:(chng V/ bi 30/ mc 3)

A. Khi thi ra t cc khu cng nghip.B. S tn ph cc khu rng phng h do con ngi gy ra.C. Cc cht phng x v ha cht c trong t nhin hoc do con ngi to ra.D. Ngun ly lan cc dch bnh.

p n: CCu 5: Bnh bch tng do mt gen ln quy nh. Mt cp v chng c mu da bnh thng v u c kiugen d hp th t l phn trm con ca h mc bnh bch tng l: (chng V/ bi 30/ mc 3)

A. 25%. B. 50%. C. 75%. D. 100%.p n: ACu 6: Ngnh di truyn y hc c chc nng chn on, cung cp thng tin v cho li khuyn lin quann cc bnh v tt di truyn c gi l g? (chng V/ bi 30/ mc 1)

A. Di truyn hc sc khe.B. Di truyn hc hn nhn v k hoch ha gia nh..C. Di truyn y hc t vn.D. Di truyn hc tng lai nhn loi.

p n: CCu 7: Nhng trng hp no sau y khngphi l nguyn nhn gy ra cc bnh, tt di truyn ngi?(chng V/ bi 30/ mc 1)

A. Do kt hn gn trong phm vi 3 iB. Ngi ph n trn 35 tui cn sinh C. Do n ung thiu chtD. Sng mi trng b nhim nng do phng x, ha cht

p n: CCu 8: Ti sao ph n khng nn sinh con tui ngoi 35? (chng V/ bi 30/ mc 2)

A. Ph n sinh con ngoi tui 35 th a con d mc bnh, tt di truynB. Khi con ln b m gi khng sc lc u t cho con pht trin ttC. Chm sc con nh ngi ng tui khng ph hp v th lc v sc chu ngD. Ph n sinh con ngoi tui 35 th 100% con sinh ra mc bnh , tt di truyn

p n: ACu 9: Hy chn cu sai trong cc cu sau: Ti sao khng nn kt hn gn? (chng V/ bi 30/ mc 1)

A. V lm suy thoi ni gingB. V lm cc t bin ln c hi d biu hin ra kiu hnh .C. V vi phm Lut Hn nhn gia nh


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2D. V d gy ra chng v sinh n

p n: DCu 10: iu no sau y l khng ng cho c s di truyn ca lut hn nhn gia nh? (chng V/ bi30/ mc 2)

A. Nn sinh con tui 20 24 m bo hc tp v cng tc tt v gim thiu t l tr s sinhmc bnh ao

B. Nu ngi c quan h huyt thng trong vng 3 i ly nhau th kh nng d tt con ci hc tng

ln r rt v dn n suy thoi ni gingC. Do t l nam / n tui 18 35 l 1 : 1 nn mi ngi ch c ly mt v (hay mt chng)D. Nu mt nam ly nhiu v hay mt n ly nhiu chng s dn n mt cn bng trong x hi

p n: ACu 11: Di truyn y hc t vn c chc nng g? (chng V/ bi 30/ mc 1)

A. Gip y hc chn on, pht hin bnh di truyn, tm ra nguyn nhn, t ra cch phng vcha bnh.

B. Gip y hc khc phc nhng hu qu ca cc bnh, tt di truynC. Chn on, cung cp thng tin v cho li khuyn lin quan n bnh v tt di truynD. M phng t vn v Lut Hn nhn v gia nh

p n: C

Cu 12: Chn t ph hp trong s nhng t cho sn in vo ch trng trong cu: Di truyn hc ch r hu qu ca vic kt hn gn lm cho cc t bin c hi c biu hin trn c th nghp. (chng V/ bi 30/ mc 2)

A. Ln B. Tri C. Chm D. Nhanhp n: ACu 13: Cng ngh t bo l ngnh k thut v: (chng VI / bi 31/ mc 2)

A. Quy trnh ng dng di truyn hc vo trong t bo.B. Quy trnh sn xut to ra c quan hon chnh.C. Quy trnh nui cy t bo hoc m to ra c quan hoc c th hon chnh.D. Duy tr sn xut cy trng hon chnh.

p n: C

Cu 14: Trong cng on ca cng ngh t bo, ngi ta tch t bo hoc m t c th ri mang nui cytrong mi trng nhn to to: (chng VI / bi 31/ mc 1)

A. C th hon chnh. C. C quan hon chnh.B. M so. D. M hon chnh.

p n: BCu 15: c cy trng trong mt thi gian ngn p ng yu cu sn xut, ngi ta tch b phn noca cy nui cy trn mi trng dinh dng t trong ng nghim? (chng VI/ bi 31/mc 1)

A. M. C. M phn sinh.B. T bo r. D. M so v t bo r.

p n: CCu 16: Trong cng ngh t bo, ngi ta dng tc nhn no kch thch m so phn ha thnh c quan

hoc c th hon chnh? (chng VI / bi 31/ mc 1)A. Tia t ngoi. C. Xung in.B. Tia X. D. Hoocmn sinh trng.

p n: DCu 17: Hy chn cu sai trong cc cu: ngha ca vic ng dng nhn ging v tnh trong ng nghim cy trng l g? (chng VI / bi 31/ mc 2)

A. Gip nhn nhanh ging cy trng p ng yu cu ca sn xutB. Gip to ra ging c nhiu u im nh sch nm bnh, ng u v c tnh ca ging gc C. Gip to ra nhiu bin d ttD. Gip bo tn mt s ngun gen thc vt qu him c nguy c tuyt chng

p n: C


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3Cu 18: Nhn bn v tnh ng vt c nhng trin vng nh th no? (chng VI /bi 31/ mc 3)

A. Nhn nhanh ngun gen ng vt qu him c nguy c b tuyt chng v nhn nhanh ging vtnui nhm p ng nhu cu sn xut

B. To ra ging vt nui mi c nhiu c tnh quC. To ra c quan ni tng t cc t bo ng vt c chuyn gen ngiD. To ra ging c nng sut cao, min dch tt

p n: A

Cu 19: tng nhanh s lng c th p ng yu cu sn xut, ngi ta p dng phng php no?(chng VI / bi 31/ mc 2)

A. Vi nhn ging C. Gy t bin dng t bo xmaB. Sinh sn hu tnh D. Gy t bin gen

p n: ACu 20: Trong ng dng di truyn hc, cu li l sn phm ca phng php: (chng VI / bi 31/ mc 3)

A. Gy t bin gen C. Nhn bn v tnhB. Gy t bin dng t bo xma D. Sinh sn hu tnh

p n: CCu 21: nhn c m non, c quan hoc c th hon chnh hon ton ging vi c th gc, ngi ta

phi thc hin : (chng VI / bi 31/ mc 1)Cng ngh t bo C. Cng ngh sinh hcCng ngh gen D. K thut genp n: ACu 22: Ngi ta tch m phn sinh (t nh sinh trng hoc t t bo l non) nui cy trong mi trngno to ra m so? (chng VI / bi 31/ mc 1)A. Mi trng t nhinB. Mi trng dinh dng c trong ng nghimC. Kt hp mi trng nhn to v t nhinD. Mi trng dinh dng trong vn mp n: B

Cu 23: Hy chn phng n sai: Phng php vi nhn ging cy trng v nhn bn v tnh ng vtc nhiu u vit hn so vi nhn ging v tnh bng cch: gim, chit, ghp. (chng VI / bi 31/ mc 2)A. t tn ging C. To ra nhiu bin d ttB. Sch mm bnh D. Nhn nhanh ngun gen qu himp n: CCu 24: Trong 8 thng t mt c khoai ty thu c 2000 triu mm ging trng cho 40 ha. y lkt qu ng dng ca lnh vc cng ngh no? .(chng VI / bi 31/ mc 3)

A. Cng ngh chuyn genB. Cng ngh t boC. Cng ngh chuyn nhn v chuyn phiD. Cng ngh sinh hc x l mi trng

p n: BCu 25: Trong k thut cy gen, ADN ti t hp c hnh thnh bi: (chngVI / bi 32/ mc 2)A. Phn t ADN ca t bo nhn l plasmitB. Mt on ADN ca t bo cho vi mt on ADN ca t bo nhn l plasmitC. Mt on mang gen ca t bo cho vi ADN ca th truynD. Mt on ADN mang gen ca t bo cho vi ADN ti t hp

p n: CCu 26: K thut gen l g? (chngVI / bi 32/ mc 1)

A. K thut gen l k thut to ra mt gen mi.B. K thut gen l cc thao tc sa cha mt gen h hng.C. K thut gen l cc thao tc chuyn mt gen t t bo nhn sang t bo khc.


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4D. K thut gen l cc thao tc tc ng ln ADN, chuyn mt on ADN mang mt gen hoc mt

cm gen t t bo ca loi cho sang t bo ca loi nhn nh th truynp n: DCu 27: Cng ngh gen l g? (chngVI / bi 32/ mc 1)

A. Cng ngh gen l ngnh k thut v quy trnh ng dng k thut genB. Cng ngh gen l ngnh k thut v quy trnh to cc ADN ti t hpC. Cng ngh gen l ngnh k thut v quy trnh to ra cc sinh vt bin i gen

D. Cng ngh gen l ngnh khoa hc nghin cu v cu trc v hot ng ca cc genp n: ACu 28: Nhng thnh tu no di y khng phi l kt qu ng dng ca cng ngh gen? (chngVI /bi 32/ mc 2 )

A. To chng vi sinh vt miB. To cy trng bin i genC. To c quan ni tng ca ngi t cc t bo ng vtD. To ra cc c th ng vt bin i gen.

p n: CCu 29: Ngnh cng ngh s dng cc t bo sng v qu trnh sinh hc to ra cc sn phm sinh hccn thit cho con ngi l ngnh :(chngVI / bi 32/ mc 2)

A. Cng ngh enzim / prtin C. Cng ngh t bo thc vt v ng vtB. Cng ngh gen D. Cng ngh sinh hc

p n: DCu 30: Ngnh cng ngh no l cng ngh cao v mang tnh quyt nh s thnh cng ca cuc cch mngsinh hc? (chngVI / bi 32/ mc 2)

A. Cng ngh gen C. Cng ngh chuyn nhn v phiB. Cng ngh enzim / prtin D. Cng ngh sinh hc x l mi trng

p n: ACu 31: Ngnh cng ngh no sn xut ra cc ch phm vi sinh dng trong chn nui, trng trt v boqun thc phm? (chngVI / bi 32/ mc 3)

A. Cng ngh enzim / prtin C. Cng ngh t bo thc vt v ng vt

B. Cng ngh gen D. Cng ngh ln menp n: DCu 32: Ngnh cng ngh no sn xut ra cc loi axt amin, cc cht cm ng sinh hc v thuc phthin cht c? (chngVI / bi 32/ mc 3)

A. Cng ngh enzim / prtin C. Cng ngh sinh hc y dcB. Cng ngh sinh hc x l mi trng D. Cng ngh t bo thc vt v ng vt

p n: ACu 33: Trong cc khu sau: Trnh t no l ng vi k thut cy gen? (chngVI / bi 32/ mc 2)

I. To ADN ti t hpII. Chuyn ADN ti t hp vo t bo nhn, to iu kin cho gen ghp biu hinIII. Tch ADN NST ca t bo cho v tch phn t ADN dng lm th truyn t vi khun hoc vi rt

A. I, II, III B. III, II, I C. III, I, II D. II, III, Ip n: CCu 34: Hoocmn no sau y c dng tr bnh i tho ng ngi? (chngVI / bi 32/ mc 1)

A. Glucagn B. Arnalin C. Tirxin D. Insulinp n: DCu 35: Trong cc lnh vc sau y:

I. To cc chng vi sinh vt miII. To ging cy trng bin i genIII. To ng vt bin i gen


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5Trong sn xut v i sng, cng ngh gen c ng dng cc lnh vc no? (chngVI / bi 32/ mc 1)

A. I B. II, III C. I, III D. I, II, IIIp n: DCu 36: Mc ch ca vic s dng k thut gen l : (chngVI / bi 32/ mc 2)

A. L s dng nhng kiu gen tt, n nh lm gingB. sn xut ra cc sn phm hng ha trn quy m cng nghip.

C. L tp trung cc gen tri c li vo nhng c th dng lm gingD. L tp trung nhng gen l vo mt c th to ging mi

p n: BCu 37: Ti sao cng ngh sinh hc ang c u tin pht trin? (chngVI / bi 32/ mc 3)

A. V gi tr sn lng ca mt s sn phm cng ngh sinh hc ang c v tr cao trn th trng thgii

B. V cng ngh sinh hc d thc hin hn cc cng ngh khc.C. V thc hin cng ngh sinh hc t tn kmD. V thc hin cng ngh sinh hc n gin , d lm.

p n: ACu 38: Trong ng dng k thut gen. Sn phm no sau y to ra qua ng dng lnh vc to ra cc

chng vi sinh vt mi: (chngVI / bi 32/ mc 3)A. Hoocmn insulin cha bnh i tho ng ngiB. To ging la giu vitamin AC. Sa b c mi sa ngi v d tiu ha, dng nui tr trong vng 6 thng tuiD. C trch c trng lng cao

p n: ACu 39: Tia no sau y c kh nng xuyn su qua cc m? (chngVI / bi 33/ mc 1)

A. Tia hng ngoi, tia X, tia t ngoi.B. Tia X, tia gamma, tia anpha, tia btaC. Tia X, tia t ngoi, tia gammaD. Tia t ngoi, tia anpha, tia bta

p n: BCu 40: Tia no sau y khng c kh nng xuyn su qua cc m? (chngVI / bi 33/ mc 1)A. Tia X B. Tia gamma C. Tia t ngoi D. Tia anpha

p n: CCu 41: Trong chn ging thc vt loi tia no sau y c dng x l ht ny mm, bu nhy, htphn, m nui cy ? (chngVI / bi 33/ mc 3)

A. Tia X, tia gamma, tia anpha, tia btaB. Tia X, tia t ngoi, tia gamma, tia anphaC. Tia hng ngoi, tia X, tia t ngoi, tia gammaD. Tia t ngoi, tia gamma, tia anpha, tia bta

p n: A

Cu 42: Trong chn ging bng cch gy t bin nhn to, loi tia no c dng x l vi sinh vt,bo t v ht phn? (chngVI / bi 33/ mc 1)A. Tia hng ngoi B. Tia X C. Tia t ngoi D. Tia bta

p n: CCu 43: Bin php no sau y khng c thc hin khi x l t bin bng cc tc nhn ha hc?(chngVI / bi 33/ mc 2)

A. Que cun bng tm ha cht t vo nh sinh trng ca thn v cnhB. Tim dung dch ha cht vo bu nhyC. Ngm ht kh, ht ny mm vo dung dch ha cht c nng thch hp trong mt thi gian hp

lD. Ngm thn v cnh vo dung dch ha cht c nng thch hp trong mt thi gian hp l


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6p n: DCu 44: Trong chn ging vi sinh vt, to ra nhng loi vcxin phng bnh cho ngi v gia sc,ngi ta chn: (chngVI / bi 33/ mc 2)

A. Cc th t bin to ra cc cht c hot tnh caoB. Cc th t bin sinh trng mnhC. Cc th t bin gim sc sng (yu so vi dng ban u)D. Cc th t bin rt ngn thi gian sinh trng

p n: CCu 45: tng sinh khi nm men v vi khun, trong chn ging vi sinh vt, ngi ta chn:(chngVI / bi 33/ mc 3)

A. Cc th t bin gim sc sng so vi dng ban uB. Cc th t bin rt ngn thi gian sinh trngC. Cc th t bin to ra cc cht c hot tnh caoD. Cc th t bin sinh trng mnh

p n: DCu 46: Tc nhn no di y thng c dng to th a bi? (chngVI / bi 33/ mc 1)

A. Etyl mtan sunphnat (EMS) C. CnsixinB. Nitrz mtyl ur (NMU) D. Nitrz tyl ur (NEU)

p n: CCu 47: Ti sao cnsixin c th to ra th a bi? (chngVI / bi 33/ mc 3)

A. Cnsixin cn tr s hnh thnh thoi phn bo lm cho ton b nhim sc th khng phn li .B. Cnsixin kch thch s nhn i ca cc nhim sc th v to ra t bo a biC. Cnsixin kch thch s hp nht ca 2 t bo lng bi v to ra t bo a biD. Cnsixin gy t mt s si thoi phn bo lm cho mt s cp nhim sc th khng phn li v to

ra t bo a bip n: ACu 48: Ngi ta to c chng nm Pnixilin c hot tnh cao hn 200 ln so vi dng ban u , nhchn lc cc th t bin theo hng no di y? (chngVI / bi 33/ mc 3)

A. Chn cc th t bin to ra cht c hot tnh sinh hc cao

B. Chn cc th t bin rt ngn thi gian sinh trngC. Cc th t bin b gim sc sngD. Cc th t bin sinh trng mnh

p n: ACu 49: t bin no sau y khng c con ngi s dng trong chn ging cy trng? (chngVI/bi 33/ mc 1)

A. t bin c thi gian sinh trng rt ngn, cho nng sut v cht lng sn phm caoB. t bin c kh nng khng c nhiu loi su bnhC. t bin c kh nng chng chu tt vi cc iu kin bt li ca mi trngD. t bin c sc sng gim

p n: D

Cu 50: Trong cc tc nhn vt l tc nhn no khng s dng gy t bin nhn to? (chngVI/ bi 33/mc 1)A. Cc tia phng x C. Tia hng ngoiB. Tia t ngoi D. Sc nhit

p n: CCu 51: Sc nhit l g? (chngVI/ bi 33/ mc 1)

A. L nhit mi trng tng ln mt cch t ngtB. L nhit mi trng gim i mt cch t ngtC. L s tng hoc gim nhit mi trng mt cch t ngtD. L s thay i nhit ca mi trng khng ng k

p n: C


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7Cu 52: Ngi ta c th s dng tc nhn ha hc gy t bin nhn to vt nui bng cch :(chngVI / bi 33/ mc 3)

A. Dng ha cht vi nng thch hp tc ng ln cc t bo ganB. Dng ha cht vi nng thch hp tc ng ln cc t bo noC. Dng ha cht vi nng thch hp tc ng ln cc t bo muD. Dng ha cht vi nng thch hp tc ng ln tinh hon v bung trng

p n: D

Cu 53: i vi vt nui, phng php chn ging t bin ch c s dng hn ch vi mt s nhmng vt bc thp, kh p dng vi nhm ng vt bc cao l v: (chngVI/ bi 33/ mc 3 )

A. Do c quan sinh sn nm su trong c th, d cht sinh vt khi x l bng tc nhn l ha hcB. Do khng c tc nhn gy t bin i vi ng vt bc caoC. Do rt tn kmD. Do ng vt bc cao c sc sng mnh lit nn khng b nh hng ca cc tc nhn gy t bin

p n: ACu 54: Nguyn nhn ca hin tng thoi ha ging cy giao phn l: (Chng VI/ bi 34 /mc 1)

A. Do giao phn xy ra ngu nhin gia cc loi thc vtB. Do lai khc thC. Do t th phn bt buc

D. Do lai gia cc dng thun c kiu gen khc nhaup n: CCu 55: T th phn l hin tng th phn xy ra gia: ( Chng VI/ bi 34 /mc 1)

A. Hoa c v hoa ci ca cc cy khc nhauB. Hoa c v hoa ci ca cc cy khc nhau v mang kiu gen khc nhauC. Hoa c v hoa ci trn cng mt cyD. Hoa c v hoa ci ca cc cy khc nhau nhng mang kiu gen ging nhau

p n: CCu 56: Nguyn nhn ca hin tng thoi ha ging ng vt l: ( Chng VI/ bi 34 /mc 1)

A. Do giao phi xy ra ngu nhin gia cc loi ng vtB. Do giao phi gn

C. Do lai gia cc dng thun c kiu gen khc nhauD. Do lai phn tchp n: BCu 57: Giao phi cn huyt l: ( Chng VI/ bi 34 /mc 1)

A. Giao phi gia cc c th khc b mB. Lai gia cc cy c cng kiu genC. Giao phi gia cc c th c kiu gen khc nhauD. Giao phi gia cc c th c cng b m hoc giao phi gia con ci vi b hoc m chng

p n: DCu 58: Khi t th phn bt buc cy giao phn, th h sau thng xut hin hin tng: ( Chng VI/bi 34 /mc 1)

A. C kh nng chng chu tt vi iu kin ca mi trngB. Cho nng sut cao hn th h trcC. Sinh trng v pht trin chm, bc l nhng tnh trng xuD. Sinh trng v pht trin nhanh, bc l nhng tnh trng tt

p n: CCu 59: Biu hin ca hin tng thoi ha ging l: ( Chng VI/ bi 34 /mc 1)

A. Con lai c sc sng cao hn b mB. Con lai sinh trng mnh hn b mC. Nng sut thu hoch lun tng lnD. Con lai c sc sng km dn

p n: D


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8Cu 60: Trong chn ging cy trng, ngi ta khng dng phng php t th phn :( Chng VI/ bi34 /mc 1)

A. Duy tr mt s tnh trng mong munB. To dng thunC. To u th laiD. Chun b cho vic to u th lai

p n: C

Cu 61: Giao phi gn v t th phn qua nhiu th h c th dn n hin tng thoi ha ging l do:( Chng VI/ bi 34 /mc 2)

A. To ra cc cp gen ln ng hp gy hiB. Tp trung nhng gen tri c hi cho th h sauC. Xut hin hin tng t bin gen v t bin nhim sc thD. To ra cc gen ln c hi b gen tri t ch

p n: ACu 62: Qua cc th h t th phn bt buc cy giao phn hoc giao phi gn ng vt th :( Chng VI/ bi 34 /mc 2)

A. T l th ng hp v th d hp khng iB. T l th ng hp gim v th d hp tng

C. T l th ng hp tng v th d hp gimD. T l th ng hp tng v th d hp khng i

p n: CCu 63: T th phn bt buc v giao phi gn gy ra hin tng thoi ha nhng vn c s dngtrong chn ging v : ( Chng VI/ bi 34 /mc 2)

A. cng c v duy tr mt s tnh trng mong mun, to dng thunB. Tao ra ging mi gp phn pht trin chn nui v trng trtC. L mt bin php quan trng khng th thiu trong chn nui, trng trtD. To ra nhiu bin d v t hp t bin mi

p n: ACu 64: c im no sau y khngphi l mc ch ca vic ng dng t th phn v giao phi

gn vo chn ging v sn xut: ( Chng VI/ bi 34 /mc 2)A. To ra dng thun dng lm gingB. Tp hp cc c tnh qu vo chn ging v sn xutC. Cng c v duy tr mt s tnh trng mong munD. Pht hin v loi b nhng gen xu ra khi qun th

p n: BCu 65: Ti sao mt s loi thc vt t th phn nghim ngt v ng vt thng xuyn giao phi

gn khng b thoi ha?( Chng VI/ bi 34 /mc 2)A. V chng c nhng gen c bit c kh nng km hm tc hi ca nhng cp gen ln gy

hiB. V hin ti chng ang mang nhng cp gen ng hp khng gy hi cho chng

C. V chng c nhng gen gy hi lm mt kh nng hnh thnh hp tD. V chng l nhng loi sinh vt c bit khng chu s chi phi ca cc qui lut di truynp n: BCu 66: Trng hp no sau y hin tng thoi ha ging xy ra? ( Chng VI/ bi 34 /mc 3)

A. C chua t th phn lin tc qua nhiu th hB. u H Lan t th phn lin tc qua nhiu th hC. Ng t th phn lin tc qua nhiu th hD. Chim b cu thng xuyn giao phi gn

p n: C


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9Cu 67: Nu th h xut pht P c kiu gen 100% Aa , tri qua 3 th h t th phn th t l ng

hp th h con th 3 (F3) l: ( Chng VI/ bi 34 /mc 3)A. 87,5% B. 75% C. 25% D. 18,75%

p n: ACu 68: Nu th h xut pht P c kiu gen 100% Aa, phi tri qua 2 th h t th phn th t l ca

th d hp cn li th h con lai F2 l: ( Chng VI/ bi 34 /mc 3)A. 12,5% B. 25% C. 50% D. 75%

p n: BCu 69 : u th lai biu hin r nht khi thc hin php lai gia: (chng VI / bi 35 / mc 1)

A. Cc c th khc loiB. Cc dng thun c kiu gen khc nhauC. Cc c th c sinh ra t mt cp b mD. Hoa c v hoa ci trn cng mt cy

p n: BCu 70: Khi thc hin lai gia cc dng thun mang kiu gen khc nhau th u th lai th hin r nht th h con lai:( Chng VI/ bi 35 /mc 1)

A. Th 1 B. Th 2 C. Th 3 D. Mi th hp n: A

Cu 71: Lai kinh t l: (chng VI / bi 35 / mc 1)A. Cho vt nui giao phi cn huyt qua mt, hai th h ri dng con lai lm sn phmB. Lai gia 2 loi khc nhau ri dng con lai lm gingC. Lai gia 2 dng thun khc nhau ri dng con lai lm gingD. Lai gia 2 dng thun khc nhau ri dng con lai lm sn phm

p n: DCu 72: Trong chn nui, ngi ta s dng phng php ch yu no to u th lai?(chng VI / bi35 / mc 1)

A. Giao phi gn B. Cho F1 lai vi cy PC Lai khc dng D. Lai kinh t

p n: D

Cu 73: to u th lai cy trng ngi ta dng phng php ch yu no sau y? (chng VI / bi35 / mc 1)A. T th phn B. Cho cy F1 lai vi cy PC. Lai khc dng D. Lai phn tch

p n: CCu 74: u th lai biu hin nh th no qua cc th h : (chng VI / bi 35 / mc 1)

A. Biu hin cao nht th h P, sau gim dn qua cc th h .B. Biu hin cao nht th h F1, sau gim dn qua cc th h .C. Biu hin cao nht th h F2, sau gim dn qua cc th h.D. Biu hin cao nht th h F1, sau tng dn qua cc th h .

p n: B

Cu 75: to u th lai, khu quan trng u tin l: (chng VI / bi 35 / mc 1)A. Lai khc dng B. Lai kinh tC. Lai phn tch D. To ra cc dng thun

p n: DCu 76: Ngy nay, nh k thut gi tinh ng lnh, th tinh nhn to v k thut kch thch nhiu

trng rng mt lc th tinh, vic to con lai kinh t c nhiu thun li i vi cc vt nuino sau y? (chng VI / bi 35 / mc 1)A. B v ln B. G v lnC. Vt v c D. B v vt

p n: A


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10Cu 77 : Mun duy tr u th lai trong trng trt phi dng phng php no? (chng VI / bi 35 / mc2)

A. Cho con lai F1 lai hu tnh vi nhauB. Nhn ging v tnh bng gim, chit, ghpC. Lai kinh t gia 2 dng thun khc nhauD. Cho F1 lai vi P

p n: B

Cu 78: u th lai biu hin r nht con lai ca php lai no sau y?(chng VI / bi 35 / mc 2)A. P: AABbDD X AABbDDB. P: AaBBDD X AabbddC. P: AAbbDD X aaBBddD. P: aabbdd X aabbdd

p n: CCu 79: Ti sao nc ta hin nay ph bin l dng con ci thuc ging trong nc, con c cao

sn thuc ging nhp ni lai kinh t? (chng VI / bi 35 / mc 2)A. V mun to c con lai F1 cn c nhiu con ci hn con c, nn gim kinh ph ta

ch nhp con cB. V nh vy to c nhiu con lai F1 hn

C. V nh vy con lai s c kh nng thch nghi vi iu kin kh hu, chn nui ging m v sctng sn ging b

D. V nh vy s gim kinh ph v con lai c sc tng sn ging bp n: CCu 80: Php lai no di y gi l lai kinh t? (chng VI / bi 35 / mc 3 )

A. Lai ng Vit Nam vi ng MhicB. Lai la Vit Nam vi la Trung QucC. Lai c chua hng Vit Nam vi c chua Ba Lan trngD. Lai b vng Thanh Ha vi b Hn sten H Lan

p n: DCu 81: Ti sao khi lai 2 dng thun, u th lai biu hin r nht F1? ( Chng VI/ bi 35 /mc 3)

A. V hu ht cc cp gen c th lai F1 u trng thi d hpB. V hu ht cc cp gen c th lai F1 u trng thi ng hp triC. V hu ht cc cp gen c th lai F1 u trng thi ng hp lnD. V hu ht cc cp gen c th lai F1 u trng thi ng hp tri v ng hp ln

p n: ACu 82: Ti sao u th lai biu hin r nht F1, cn sau gim dn qua cc th h? (chng VI / bi 35/ mc 3)

A. V cc th h sau, t l cc t hp ng hp tri gim dn v khng c biu hinB. V cc th h sau, t l cc t hp ng hp tri biu hin cc c tnh xuC. V cc th h sau, t l d hp gim dn, ng hp ln tng dn v biu hin cc c tnh xuD. V cc th h sau, t l d hp gim dn, ng hp tri tng dn v biu hin cc c tnh xu

p n: CCu 83: Trong chn nui, ngi ta gi li con c tt lm ging cho n ca n l ng hay sai , ti sao?(chng VI / bi 35 / mc 3)

A. ng, v con ging c chn lcB. ng, v to c dng thun chng nhm gi c vn gen ttC. Sai, v y l giao phi gn c th gy thoi ha ging.D. Sai, v trong n c t con nn khng chn c con ging tt

p n: CCu 84: Vai tr ca chn lc trong chn ging l: ( chng VI / bi 36 / mc 3)

A. Lm nng cao nng sut v cht lng ca vt nui, cy trngB. To ra ging mi gp phn pht trin chn nui, trng trt


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11C. Phc hi cc ging thoi ha, to ra ging mi hoc ci to ging cD. L mt bin php quan trng u tin khng th thiu trong sn xut nng nghip

p n: CCu 85: u im ca phng php chn lc hng lot l: ( chng VI / bi 36 / mc 1)

A. ng dng c hiu qu trn tt c cc i tng vt nui, cy trngB. Nhanh to ra kt qu v kt qu lun n nhC. n gin, d lm, t tn km, c th p dng rng ri

D. Ch p dng mt ln trn mi i tng sinh vtp n: CCu 86: Kt qu ca chn lc hng lot l: ( chng VI / bi 36 / mc 1)

A. Kt qu nhanh thi gian u, nng sc sn xut n mc no ri dng liB. Kt qu lun cao v n nhC. Kt qu nhanh xut hin v n nhD. Kt qu chm xut hin v n nh

p n: ACu 87: Nhc im ca phng php chn lc hng lot l: ( chng VI / bi 36 / mc 1)

A. Ch da vo kiu hnh, thiu kim tra kiu genB. Khng c hiu qu khi p dng trn vt nui

C. Khng c hiu qu trn cy t th phnD. i hi phi theo di cng phu v cht ch

p n: ACu 88: u im ca phng php chn lc c th l: ( chng VI / bi 36 / mc 1)

A. n gin, d tin hnh v t tn kmB. C th p dng rng riC. Ch cn tin hnh mt ln to ra hiu quD. Kt hp c nh gi kiu hnh vi kim tra kiu gen

p n: DCu 89: Nhc im ca phng php chn lc c th l: ( chng VI / bi 36 / mc 1)

A. ng dng khng c hiu qu trn cy trng

B. ng dng c hiu qu trn cy trng nhng khng c hiu qu trn vt nuiC. Hiu qu thu c thp hn so vi chn lc hng lotD. Cng phu, tn km nn kh p dng rng ri

p n: DCu 90: Chn lc hng lot l g? ( chng VI / bi 36 / mc 1)

A. Da trn kiu hnh chn ra mt nhm c th ph hp nht vi mc tiu chn lc lm gingB. Da trn kiu hnh chn mt s t c th tt em kim tra kiu gen chn nhng c th ph

hp vi mc tiu chon lc lm gingC. Da trn kiu gen chn ra mt nhm c th ph hp nht vi mc tiu chn lc lm gingD. Pht hin v loi b cc c th c kiu gen v kiu hnh khng ph hp

p n: A

Cu 91: Chn lc c th l g? ( chng VI / bi 36 / mc 1)A. Da trn kiu hnh chn ra mt nhm c th ph hp nht vi mc tiu chn lc lm gingB. Chn ly mt s t c th tt, nhn ln ring r thnh tng dng , kim tra kiu gen ca mi c

th, chn c th ph hp nht vi mc tiu chn lc lm gingC. Chn ly mt s t c th tt, nhn ln ring r thnh tng dng , khng kim tra kiu gen ca

mi c th, chn c th ph hp nht vi mc tiu chn lc lm gingD. Chn ly mt s t c th tt, trn ln ln cc ht ging vi nhau ri gieo trng v sau

p n: BCu 92: Di y l cc bc c bn trong chn ging la ca mt s nng dn:

- Gieo trng ging khi u- Chn nhng cy u t lm ging cho v sau


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12- Ht ca mi cy c gieo trng ring thnh tng dng- So snh nng sut, cht lng ca cc dng vi nhau, so snh vi ging khi u v ging i

chng chn ra dng tt nhtCc thao tc nu trn l ca phng php chn lc no di y?(chng VI / bi 36 / mc 2)A. Chn lc c th B. Chn lc hng lot mt lnC. Chn lc hng lot hai ln D. Chn lc hng lot nhiu ln

p n: A

Cu 93: Di y l cc bc c bn trong chn ging la ca mt s nng dn:- Gieo trng ging khi u- Chn nhng cy u t v ht thu hoch chung lm ging cho v sau- Gieo trng cc ht ging c chn- So snh nng sut v cht lng ca ging c chn vi ging khi u v ging i chngCc thao tc nu trn l ca phng php chn lc no di y?(chng VI / bi 36 / mc 2)A.Chn lc c th B. Chn lc hng lot mt lnC.Chn lc hng lot hai ln D. Chn lc hng lot nhiu ln

p n: BCu 94: Trong chn ging vt nui, phng php chn lc no c hiu qu nht? ( chng VI / bi 36 /mc 2)

A. Chn lc hng lot mt lnB. Chn lc hng lot nhiu lnC. Chn lc c th, kim tra c ging qua i conD. Chn lc hng lot nhiu ln, chn lc c th

p n: CCu 95: Trong thc t chn ging, ngi ta thng p dng cc phng php chn lc c bn no sauy? ( chng VI / bi 36 / mc 2)

A. Chn lc t nhin, chn lc c th B. Chn lc c th, chn lc hng lotC. Chn lc nhn to, chn lc hng lot D. Chn lc nhn to, chn lc c th

p n: BCu 96: Trong chn lc hng lot, ngi ta da vo c im no chn cc tnh trng p ng

mc tiu chn ging? (chng VI / bi 36/ mc 2)A. Kiu hnh chn t mt c thB. Kiu hnh v kiu gen chn t mt c thC. Kiu gen chn t mt nhm c thD. Kiu hnh chn t trong mt nhm c th

p n: DCu 97: Nng dn duy tr cht lng ging la bng cch chn cc cy tt c bng v ht tt thu hochchung lm ging cho v sau. l phng php chn lc no?( chng VI / bi 36 / mc 2)

A. Chn lc nhn to B. Chn lc t nhinC. Chn lc c th D. Chn lc hng lot

p n: DCu 98: Trong chn nui vt trng, ngi ta chn trong n nhng con ci c c im: ( chng VI /bi 36 / mc 3)

A. u to, c ngn, pha sau ca thn nB. u nh, c di, pha sau ca thn nC. Chn thp, n nhiu, tng trng nhanhD. C di, u to, chn nh, thn ngn

p n: BCu 99: ging la A thun chng c to ra t lu , mi bt u gim ng u v chiu cao

v thi gian sinh trng. Hi cn p dng phng php chn lc no khi phc li 2 cim tt ca ging la trn? ( chng VI /bi 36 / mc 3)


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13A. Chn lc hng lot mt lnB. Chn lc hng lot nhiu lnC. Chn lc hng lot nhiu ln v chn lc c thD. Chn lc c th

p n: ACu 100: ging la B thun chng c to ra t lu, c sai khc r rt gia cc c th v ng

u v chiu cao v thi gian sinh trng. Hi cn p dng phng php chn lc no khi

phc li 2 c im tt ca ging la trn? ( chng VI /bi 36 / mc 3)A. Chn lc hng lot mt ln B. Chn lc hng lot nhiu lnC. Chn lc c th D. Chn lc hng lot mt ln v chn lc c th

p n: BCu 101: Hot ng no sau y khng c chn lc hng lot?( chng VI / bi 36 / mc 3)

A. C s nh gi kiu hnh i conB. C th tin hnh chn lc mt ln hay nhiu lnC. Con chu ca cc c th chn gi li c nhn ln theo tng dng ring rD. Thc hin i vi cy t th phn v cy giao phn

p n: CCu 102: Di y l cc bc c bn trong chn ging ci c: ( chng VI / bi 36 / mc 3)

- Gieo trng ging khi u (v 1)- Chn ht ca nhng cy u t lm ging cho v 2- Gieo trng cc ht ging c chn v 1- Chn ht ca nhng cy u t lm ging cho v 3- Gieo trng cc ht ging c chn v 2- So snh nng sut v cht lng ca ging c chn v 2 vi ging khi u v ging i

chngCc phng php nu trn l ca phng php chn lc no di y?A. Chn lc c th B. Chn lc hng lot 1 lnC. Chn lc hng lot 2 ln D. Chn lc hng lot 3 ln

p n: C

Cu 103: Trong qu trnh to cc ging la nh ti nguyn t bin, tm thm t bin, cc nh khoas dng phng php: ( chng VI / bi 36 / mc 3)A. Chn lc c th B. Chn lc hng lot 1 lnC. Chn lc hng lot 2 ln D. Chn lc hng lot nhiu ln

p n: ACu 104: Nc ta rt ngn thi gian to ra ging mi v to nhng c tnh qu m phng php chnging truyn thng cha lm c l nh?( chng VI / bi 37 / mc 1)

A. Vn dng cc quy lut bin d.B. S dng cc k thut phn t v t bo.C. Vn dng cc quy lut di truyn - bin d, s dng cc k thut phn t v t bo.D. S dng cc phng php chn lc.

p n: CCu 105: Thnh tu ni bt nht trong chn ging cy trng nc ta l lnh vc no? ( chng VI /bi 37 / mc 1)

A. Chn ging la, lc, c chua.B. Chn ging ng, ma, u tng.C. Chn ging la, ng, u tng.D. Chn ging u tng, lc, c chua.

p n: CCu 106: Gy t bin nhn to trong chn ging cy trng gm cc phng php no?( chng VI / bi37 / mc 2)


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14A. To bin d t hp, chn lc c th v x l t bin, chn ging bng chn dng t bo xmac bin d.B. Phi hp gia lai hu tnh v x l t bin, gy t bin nhn to ri chn lc hng lot toging mi, chn ging bng t bin xma.C. Gy t bin nhn to ri chn c th to ging mi, phi hp gia lai hu tnh v x l tbin, chn ging bng chn dng t bo xma c bin d hoc t bin xma.D. Gy t bin nhn to ri chn c th to ging mi, phi hp gia lai hu tnh to bin d t

hp vi chn lc c th.p n: CCu 107: Cc phng php c s dng trong chn ging vt nui l:( chng VI / bi 37 / mc 1)

A. To ging mi, ci to ging a phng.B. To ging u th lai (ging lai F1), nui thch nghi cc ging nhp ni.C. To ging mi, ci to ging a phng, to ging u th lai (ging lai F1), nui thch nghi ccging nhp ni, ng dng cng ngh sinh hc trong cng tc ging.D. To ging mi, to u th lai, ng dng cng ngh sinh hc trong cng tc ging.

p n: CCu 108: Trong chn ging vt nui, ch yu ngi ta dng phng php no to ngun bin d ?( chng VI / bi 37 / mc 1)

A. Gy t bin nhn to.B. Giao phi cn huyt.C. Lai ging.D. S dng hoocmn sinh dc.

p n: CCu 109: Con lai kinh t c to ra gia b vng Thanh Ho v b Hn sten H Lan, chu c kh hunng, cho 1000 kg sa/con/nm. y l thnh tu chn ging vt nui thuc lnh vc no?( chng VI /bi 37 / mc 1)

A. Cng ngh cy chuyn phi.B. Nui thch nghi.C. To ging u th lai (ging lai F1).

D. To ging mi.p n: CCu 110: Nhim v ca khoa hc chn ging l:( chng VI / bi 37 / mc 3)

A. Ci tin cc ging cy trng, vt nui hin c.B. Ci tin cc ging vt nui, cy trng v vi sinh vt hin c.C. Ci tin cc ging hin c, to ra cc ging mi c nng sut cao.D. To ra cc ging mi c nng sut, sn lng cao, p ng vi yu cu ca con ngi.

p n: CCu 111: Trong chn ging vt nui, qu trnh to ging mi i hi thi gian rt di v kinh ph rt lnnn ngi ta thng dng cc phng php no sau y:( chng VI / bi 37 / mc 2)

A. Nui thch nghi v chn lc c th.

B. To ging u th lai v chn lc c th.C. Ci tin ging a phng, nui thch nghi hoc to ging u th lai.D. ng dng cng ngh sinh hc trong cng tc ging.

p n: CCu 112: Ging du tam bi (3n) c to ra t ging du t bi (4n) vi ging du lng bi (2n) nhphng php:( chng VI / bi 37 / mc 2)

A. Gy t bin nhn to.B. Lai hu tnh v x l t bin.C. To ging a bi th.D. To ging u th lai.

p n: C


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15Cu 113: Trong chn ging cy trng, phng php no sau y c xem l c bn?( chng VI / bi 37/ mc 3)

A. Gy t bin nhn to.B. Nhn ging v tnh.C. Lai hu tnh.D. T th phn.

p n: C

Cu 114: Cng ngh cy chuyn phi b c ng dng vo thc tin:( chng VI / bi 37 / mc 2)A. Gip tng nhanh n b sa hoc b tht.B. Gim thi gian to ging b.C. Gip tng nhanh n b sa hoc b tht, gim thi gian to ging b.D. Xc nh sm kiu gen cho sn lng sa cao, gip chn nhanh b lm ging.

p n: CCu 115: Ging ln B - 81 c to ra t ging i bch v ging -81 nh phng php:( chng VI/ bi 37 / mc 2)

A. To ging u th lai.B. Nui thch nghi cc ging nhp ni.C. Lai khc ging to ging mi.

D. Lai kinh t.p n: CCu 116: Ging to o vng c to ra bng cch:( chng VI / bi 37 / mc 3)

A. Chiu x tia X vo ht ging to Gia Lc.B. Chn lc t th t bin t nhin.C. X l t bin nh sinh trng cy non ca ging to Gia Lc.D. Chn lc c th t ging to Gia Lc.

p n: CCu 117: Ging la DT17 c to ra t ging la DT10 c nng sut cao vi ging la OM80 c ht godi, trong, cho cm do nh phng php:( chng VI / bi 37 / mc 3)

A. Gy t bin nhn to.

B. To ging u th lai.C. Lai hu tnh to bin d t hp.D. To ging a bi th.

p n: CCu 118: Th no l mi trng sng ca sinh vt?( chng I / bi 41 / mc 1)

A. L ni tm kim thc n, nc ung ca sinh vt.B. L ni ca sinh vt.C. L ni sinh sng ca sinh vt, bao gm tt c nhng g bao quanh chng.D. L ni kim n, lm t ca sinh vt .

p n: CCu 119: Nhn t sinh thi l :( chng I / bi 41 / mc 1)

A. Cc yu t v sinh hoc hu sinh ca mi trng.B. Tt c cc yu t ca mi trng.C. Nhng yu t ca mi trng tc ng ti sinh vt.D. Cc yu t ca mi trng nh hng gin tip ln c th sinh vt.

p n: CCu 120: Cc nhn t sinh thi c chia thnh nhng nhm no sau y?( chng I / bi 41 / mc 1)

A. Nhm nhn t v sinh v nhn t con ngi.B. Nhm nhn t nh sng, nhit , m v nhm cc sinh vt khc.C. Nhm nhn t sinh thi v sinh , nhm nhn t sinh thi hu sinh v nhm nhn t con ngi.D. Nhm nhn t con ngi v nhm cc sinh vt khc.

p n: C


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16

Cu 121: Sinh vt sinh trng v pht trin thun li nht v tr no trong gii hn sinh thi?( chng I /bi 41 / mc 1)

A. Gn im gy cht di.B. Gn im gy cht trn.C. im cc thunD. trung im ca im gy cht di v im gy cht trn.

p n: CCu 122: Gii hn sinh thi l g?( chng I / bi 41 / mc 1)

A. L khong thun li ca mt nhn t sinh thi m bo c th sinh vt sinh trng v pht trintt.

B. L gii hn chu ng ca c th sinh vt i vi cc nhn t sinh thi khc nhau.C. L gii hn chu ng ca c th sinh vt i vi mt nhn t sinh thi nht nh.D. L khong tc ng c li nht ca nhn t sinh thi i vi c th sinh vt.

p n: CCu 123: Cc nhn t sinh thi no sau y l nhn t sinh thi v sinh?( chng I / bi 41 / mc 1)

A. nh sng, nhit , m, thc vt.B. Nc bin, sng, h, ao, c, nh sng, nhit , dc.

C. Kh hu, th nhng, nc, a hnh.D. Cc thnh phn c gii v tnh cht l, ho ca t; nhit , m, ng vt.

p n: CCu 124: C th sinh vt c coi l mi trng sng khi: ( chng I / bi 41 / mc 3)

A. Chng l ni ca cc sinh vt khc.B. Cc sinh vt khc c th n ly cht dinh dng t c th chng.C. C th chng l ni , ni ly thc n, nc ung ca cc sinh vt khc.D. C th chng l ni sinh sn ca cc sinh vt khc.

p n: CCu 125: V sao nhn t con ngi c tch ra thnh mt nhm nhn t sinh thi ring? ( chng I / bi41 / mc 1)

A. V con ngi c t duy, c lao ng.B. V con ngi tin ho nht so vi cc loi ng vt khc.C. V hot ng ca con ngi khc vi cc sinh vt khc, con ngi c tr tu nn va khai thc ti

nguyn thin nhin li va ci to thin nhin.D. V con ngi c kh nng lm ch thin nhin.

p n: CCu 126: Nhng loi c gii hn sinh thi rng i vi nhiu nhn t sinh thi, th chng c vng phn bnh th no? ( chng I / bi 41 / mc 3)

A. C vng phn b hp.B. C vng phn b hn ch.C. C vng phn b rng.

D. C vng phn b hp hoc hn ch.p n: CCu 127: Khi no cc yu t t, nc, khng kh, sinh vt ng vai tr ca mt mi trng?( chng I /bi 41 / mc 3)

A. Khi ni c iu kin thun li v ni cho sinh vt.B. L ni sinh vt c th kim c thc n.C. Khi l ni sinh sng ca sinh vt.D. Khi ni khng c nh hng g n i sng ca sinh vt.

p n: CCu 128: Khi no cc yu t ca mi trng nh t, nc, khng kh, sinh vt ng vai tr ca mt nhnt sinh thi?( chng I / bi 41 / mc 3)


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17A. Khi cc yu t ca mi trng khng nh hng ln i sng sinh vt.B. Khi sinh vt c nh hng trc tip n mi trng.C. Khi cc yu t ca mi trng tc ng ln i sng sinh vt.D. Khi sinh vt c nh hng gin tip n mi trng.

p n: CCu 129: C chp c gii hn chu ng v nhit l: 20C n 440C, im cc thun l 280C. C r phic gii hn chu ng v nhit l: 50C n 420C, im cc thun l 300C. Nhn nh no sau y l

ng?( chng I / bi 41 / mc 3)A. Vng phn b c chp hp hn c r phi v c im cc thun thp hn.B. Vng phn b c r phi rng hn c chp v c gii hn di cao hn.C. C chp c vng phn b rng hn c r phi v c gii hn chu nhit rng hn.D. C chp c vng phn b rng hn c r phi v c gii hn di thp hn.

p n: CCu 130: Khi chuyn nhng sinh vt ang sng trong bng rm ra sng ni c cng chiu sng caohn th kh nng sng ca chng nh th no?( chng I / bi 42 / mc 1)

A. Vn sinh trng v pht trin bnh thng.B. Kh nng sng b gim sau khng pht trin bnh thng.C. Kh nng sng b gim, nhiu khi b cht.

D. Khng th sng c.p n: CCu 131: nh sng nh hng ti i sng thc vt nh th no? ( chng I / bi 42 / mc 1) ( Mc 2)

A. Lm thay i hnh thi bn ngoi ca thn, l v kh nng quang hp ca thc vt.B. Lm thay i cc qu trnh sinh l quang hp, h hp.C. Lm thay i nhng c im hnh thi v hot ng sinh l ca thc vt.D. Lm thay i c im hnh thi ca thn, l v kh nng ht nc ca r.

p n: CCu 132: Hin tng ta cnh t nhin l g?( chng I / bi 42 / mc 1)

A. L hin tng cy mc trong rng c tn l hp, t cnh.B. Cy trng ta bt cc cnh pha di.

C. L cnh ch tp trung phn ngn cy, cc cnh cy pha di sm b rng.D. L hin tng cy mc trong rng c thn cao, mc thng.p n: CCu 133: Cy a sng thng sng ni no?( chng I / bi 42 / mc 1)

A. Ni nhiu nh sng tn x.B. Ni c cng chiu sng trung bnh.C. Ni quang ng.D. Ni kh hn.

p n: CCu 134: Cy a bng thng sng ni no?( chng I / bi 42 / mc 1)

A. Ni t nh sng tn x.

B. Ni c m cao.C. Ni t nh sng v nh sng tn x chim ch yu.D. Ni t nh sng tn x hoc di tn cy khc.

p n: CCu 135: Theo kh nng thch nghi vi cc iu kin chiu sng khc nhau ca ng vt, ngi ta chiang vt thnh cc nhm no sau y?( chng I / bi 42 / mc 1)

A. Nhm ng vt a sng, nhm ng vt a kh.B. Nhm ng vt a sng, nhm ng vt a bng.C. Nhm ng vt a sng, nhm ng vt a ti.D. Nhm ng vt a sng, nhm ng vt a m.

p n: C


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18Cu 136: Cy thng mc ring r ni quang ng thng c tn rng hn cy thng mc xen nhau trongrng v:( chng I / bi 42 / mc 2)

A. nh sng mt tri tp trung chiu vo cnh cy pha trn.B. Cy c nhiu cht dinh dng.C. nh sng mt tri chiu c n cc pha ca cy.D. Cy c nhiu cht dinh dng v phn ngn ca cy nhn nhiu nh sng.

p n: C

Cu 137: Vai tr quan trng nht ca nh sng i vi ng vt l:( chng I / bi 42 / mc 2)A. Kim mi.B. Nhn bit cc vt.C. nh hng di chuyn trong khng gian.D. Sinh sn.

p n: CCu 138: Nu nh sng tc ng vo cy xanh t mt pha nht nh, sau mt thi gian cy mc nh thno?( chng I / bi 42 / mc 2)

A. Cy vn mc thng.B. Cy lun quay v pha mt tri.C. Ngn cy s mc cong v pha c ngun sng.

D. Ngn cy r xung.p n: CCu 139: L cy a sng c c im hnh thi nh th no? ( chng I / bi 42 / mc 3)

A. Phin l rng, mu xanh sm.B. Phin l dy, rng, mu xanh nht.C. Phin l hp, dy, mu xanh nht.D. Phin l hp, mng, mu xanh sm.

p n: CCu 140: L cy a bng c c im hnh thi nh th no?( chng I / bi 42 / mc 3)

A. Phin l hp, mng, mu xanh nht.B. Phin l hp, dy, mu xanh sm.

C. Phin l rng, mng, mu xanh sm.D. Phin l di, mng, mu xanh nht.p n: CCu 141: Vo bui tra v u gi chiu, t th nm phi nng ca thn ln bng ui di nh th no?( chng I / bi 42 / mc 3)

A. Lun phin thay i t th phi nng theo hng nht nh.B. T th nm phi nng khng ph thuc vo cng chiu sng ca mt tri.C. Phi nng nm theo hng trnh bt nh nng chiu vo c th.D. Phi nng theo hng b mt c th hp thu nhiu nng lng nh sng mt tri.

p n: CCu 142: Nhp iu chiu sng ngy v m nh hng ti hot ng ca nhiu loi ng vt nh th

no?( chng I / bi 42 / mc 1) ( Mc 3)A. Ch hot ng vo lc trc mt tri mc v lc hong hn.B. Ch yu hot ng vo ban ngy.C. C loi a hot ng vo ban ngy, c loi a hot ng vo ban m, c loi hot ng vo lc

hong hn hay bnh minh.D. Ch yu hot ng lc hong hn hoc khi tri ti.

p n: CCu 143: V sao nhng cy ba rng thng mc nghing v tn cy lch v pha c nhiu nh sng?( chng I / bi 42 / mc 3)

A. Do tc ng ca gi t mt pha.B. Do cy nhn c nhiu nh sng.


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19C. Cy nhn nh sng khng u t cc pha.D. Do s lng cy trong rng tng, ln t cy ba rng.

p n: CCu 144: ng dng s thch nghi ca cy trng i vi nhn t nh sng, ngi ta trng xen cc loi cytheo trnh t sau:( chng I / bi 42 / mc 3)

A. Cy a bng trng trc, cy a sng trng sau.B. Trng ng thi nhiu loi cy.

C. Cy a sng trng trc, cy a bng trng sau.D. Tu theo ma m trng cy a sng hoc cy a bng trc.

p n: CCu 145: Nhng cy g cao, sng chen chc, tn l hp phn b ch yu :( chng I / bi 42 / mc 3)

A. Tho nguyn.B. Rng n i.C. Rng ma nhit i.D. Hoang mc.

p n: CCu 146: Tng Cutin dy trn b mt l ca cc cy xanh sng vng nhit i c tc dng g? (ChngI/ Bi 43/ Mc1 )

A. Hn ch s thot hi nc khi nhit khng kh ln cao.B. Hn ch nh hng c hi ca tia cc tm vi cc t bo l.C. To ra lp cch nhit bo v l cy.D. Tng s thot hi nc khi nhit khng kh ln cao.

p n: ACu 147: V ma ng gi lnh, cc cy xanh vng n i thng rng nhiu l c tc dng g?(Chng I/ Bi 43/ Mc 1)

A. Tng din tch tip xc vi khng kh lnh v gim s thot hi nc.B. Lm gim din tch tip xc vi khng kh lnh.C. Gim din tch tip xc vi khng kh lnh v gim s thot hi nc.D. Hn s thot hi nc.

p n: CCu 148: Vi cc cy xanh sng vng nhit i, chi cy c cc vy mng bao bc, thn v r cy ccc lp bn dy. Nhng c im ny c tc dng g? (Chng I/ Bi 43/ Mc 1)

A. Hn ch s thot hi nc khi nhit khng kh cao.B. To ra lp cch nhit bo v cy.C. Hn ch nh hng c hi ca tia cc tm vi cc t bo l.D. Gim din tch tip xc vi khng kh lnh.

p n: BCu 149: Qu trnh quang hp ca cy ch c th din ra bnh thng nhit mi trng no?(Chng I/ bi 43/mc 2)

A. 00- 400. B. 100- 400.

C. 200

- 300

. D. 250

-350

.p n: CCu 150: nhit qu cao (cao hn 400C) hay qu thp (00C) cc hot ng sng ca hu ht cc loicy xanh din ra nh th no? (Chng I/ bi 43/mc 2)

A. Cc ht dip lc c hnh thnh nhiu.B. Quang hp tng h hp tng.C. Quang hp gim. h hp tng.D. Quang hp gim thiu v ngng tr, h hp ngng tr.

p n: DCu 151: c im cu to ca ng vt vng lnh c ngha gip chng gi nhit cho c th chng rtl: (Chng I/ bi 43/mc 1)


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20A. C chi di hn.B. C th c lng dy v di hn ( th c lng).C. Chn c mng rng.D. m tht di chn dy.

p n: BCu 15 2: ng vt hng nhit th nhit c th nh th no? (Chng I/ bi 43/mc 1)

A. Nhit c th khng ph thuc vo nhit mi trng.

B. Nhit c th ph thuc vo nhit mi trng.C. Nhit c th thay i ngc vi nhit mi trng.D. Nhit c th tng hay gim theo nhit mi trng.

p n: ACu 15 3: ng vt bin nhit th nhit c th nh th no? (Chng I/ bi 43/mc 1)

A. Nhit c th khng ph thuc vo nhit mi trng.B. Nhit c th ph thuc vo nhit mi trng.C. Nhit c th thay i khng theo s tng hay gim nhit mi trng.D. Nhit c th thay i ngc vi nhit mi trng.

p n: BCu 15 4:Nhng cy sng ni kh hn thng c nhng c im thch nghi no?(Chng I/ bi 43/

mc 2)A. L bin thnh gai, l c phin mng.B. L v thn cy tiu gim.C. C th mng nc, bn l rngD. Hoc c th mng nc hoc l tiu gim hoc l bin thnh gai.

p n: DCu 15 5: Phin l ca cy a m, a sng khc vi cy a m, chu bng im no? (Chng I/ bi43/mc 3 )

A. Phin l mng, bn l rng, m giu km pht trin, mu xanh sm.B. Phin l to, mu xanh sm, m giu km pht trin.C. Phin l hp, mu xanh nht, m giu pht trin.

D. Phin l nh, mng, l kh c hai mt l, m giu t pht trin.p n: CCu 156: Phin l ca cy a m, chu bng khc vi cy a m, a sng im no? (Chng I/ bi43/mc 3)

A. Phin l hp, mu xanh nht, m giu pht trin.B. Phin l dy, c nhiu t bo kch thc ln cha nc.C. Phin l hp, l c lp lng cch nhit.D. Phin l mng, rng bn, m giu t pht trin.

p n: DCu 157:Nhm sinh vt no sau y c kh nng chu ng cao vi s thay i nhit ca mi trng?( Chng 1/ bi 43/ mc 2)

A. Nhm sinh vt hng nhit.B. Nhm sinh vt bin nhit.C. Nhm sinh vt nc.D. Nhm sinh vt cn.

p n: ACu 158:Nhn t nhit nh hng nh th no ln i sng thc vt? ( Chng 1/ bi 43/ mc 2)

A. n s bin dng ca cy c r th vng ngp nc .B. n cu to ca rC. n s di ra ca thnD. n hnh thi, cu to, hot ng sinh l v s phn b ca thc vt.

p n: D


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21Cu 159: Gii thch no v hin tng cy sa mc c l bin thnh gai l ng: (Chng 1/ bi 43/ mc2)

A. Cy sa mc c l bin thnh gai gip cho chng chng chu vi gi bo.B. Cy sa mc c l bin thnh gai gip cho chng bo v c khi con ngi ph hoi.C. Cy sa mc c l bin thnh gai gip cho chng gim s thot hi nc trong iu kin khhn ca sa mc.D. Cy sa mc c l bin thnh gai gip cy hn ch tc ng ca nh sng.

p n: CCu 160:Nhm sinh vt no di y c xp vo nhm ng vt hng nhit? ( Chng 1/ bi 43/ mc3)

A. C su, th, ch, di. B. B cu, c r phi, c chp, ch si.C. C r phi, c chp, ch, c su. D. B cu, ch si, th, di.

p n: DCu 161:Nhm sinh vt no di y c xp vo nhm ng vt bin nhit? ( Chng 1/ bi 43/ mc3)

A. C r phi, c chp, ch, c su. B. C su, th, ch, di.C. B cu, mo, th, di. D. B cu, c r phi, c chp, mo.

p n: A

Cu 162:Nhm sinh vt no di y c xp vo nhm thc vt chu hn?( Chng 1/ bi 43/ mc 3)A. Cy rau mc, cy xng rng, cy phi lao.B. Cy thuc bng, cy thng, cy rau b.C. Cy xng rng, cy thuc bng, cy thng, cy phi lao.D. Cy xng rng, cy phi lao, cy rau b, cy rau mc.

p n: CCu 163:Nhm sinh vt no sau y ton l ng vt a kh? ( Chng 1/ bi 43/ mc 3)

A. ch, c sn, lc . B. c sn, giun t, thn ln.C. Giun t, ch, c sn. D. Lc , thn ln, k nhng.

p n: D

Cu 164:Nhm sinh vt no sau y ton l ng vt a m? ( Chng 1/ bi 43/ mc 3)A. ch, c sn, giun t. B. ch, lc , giun t.C. Lc , thn ln, k . D. c sn, thn ln, giun t.

p n: ACu 165: Quan h gia hai loi sinh vt trong c hai bn cng c li l mi quan h? ( Chng 1/ bi44/ mc 1)

A. Hi sinh. B. Cng sinh.C. K sinh. D Cnh tranh.

p n: BCu 166: Quan h gia hai loi sinh vt, trong mt bn c li cn bn kia khng c li v cng khngc hi l mi quan h? ( Chng 1/ bi 44/ mc 1)

A. K sinh. B. Cnh tranh.C. Hi sinh. D. Cng sinh.p n: CCu 167: Cc sinh vt khc loi tranh ginh nhau thc n, ni v cc iu kin sng khc ca mitrng l c im ca mi quan h khc loi no sau y? ( Chng 1/ bi 44/ mc 1)

A. Cng sinh. B. Hi sinh.C. Cnh tranh. D. K sinh.

p n: CCu 168: Sinh vt sng nh trn c th ca sinh vt khc, ly cht dinh dng v mu t c th vt ch lc im ca mi quan h khc loi no sau y? ( Chng 1/ bi 44/ mc1)

A. Sinh vt n sinh vt khc. B. Hi sinh.


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22C. Cnh tranh. D. K sinh.

p n: DCu 169: Cc sinh vt cng loi c quan h vi nhau nh th no? ( Chng 1/ bi 44/ mc 1)

A. Cng sinh v cnh tranh. B. Hi sinh v cnh tranh.C. H tr v cnh tranh. D. K sinh, na k sinh.

p n: CCu 170: ng vt n tht con mi, ng vt n thc vt v thc vt bt su b thuc quan h khc loi

no sau y? ( Chng 1/ bi 44/ mc 1)A. Cng sinh. B. Sinh vt n sinh vt khc.C. Cnh tranh. D. K sinh.

p n: BCu 171: Quan h gia cc c th trong hin tng t ta thc vt l mi quan h g? (Chng 1/ bi44/ mc 3)

A. Cnh tranh . B. Sinh vt n sinh vt khc.C. Hi sinh. D. Cng sinh.

p n: ACu 172: Rn v bt sng bm trn da tru, b. Rn, bt vi tru, b c mi quan h theo kiu no diy? ( Chng 1/ bi 44/ mc 1)

A. Hi sinh. B. K sinh.C. Sinh vt n sinh vt khc. D. Cnh tranh.

p n: BCu 173: a y sng bm trn cnh cy. Gia a y v cy c mi quan h theo kiu no di y?( Chng 1/ bi 44/ mc 2)

A. Hi sinh. B. Cng sinh.C. K sinh. D. Na k sinh.

p n: ACu 174: Khi c gi bo, thc vt sng thnh nhm c li g so vi sng ring r? ( Chng 1/ bi 44/mc 2)

A. Lm tng thm sc thi ca gi.

B. Lm tng thm s xi mn ca t.C. Lm cho tc gi thi dng li, cy khng b .D. Gim bt sc thi ca gi, hn ch s ca cy.

p n: DCu 175: Cc c th cng loi sng vi nhau thnh mt nhm trong cng mt khu vc c th cnh tranhnhau gay gt, dn ti mt s c th c th tch ra khi nhm trong hon cnh no di y? ( Chng 1/bi 44/ mc 2)

A. Khi mi trng cn kit ngun thc n, ni qu cht chi.B. Khi gp k th xm ln lnh a.C. Khi c gi bo.D. Khi c dch bnh.

p n: ACu 176: iu kin no di y ph hp vi quan h h tr? ( Chng 1/ bi 44/ mc 2)A. S lng c th cao. B. Mi trng sng m p.C. Kh nng sinh sn gim. D. Din tch ch hp l, ngun sng y .

p n: DCu 177: Con h v con th trong rng c th c mi quan h trc tip no sau y: ( Chng 1/ bi 44/mc 1)

A. Cnh tranh v thc n v ni . B. Cng sinh.C. Vt n tht v con mi. D. K sinh.

p n: C


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23Cu 178: C di thng mc ln vi la trn cnh ng lm cho nng sut la b gim i, gia c di vla c mi quan h theo kiu no di y: ( Chng 1/ bi 44/ mc 2)

A. Cng sinh. B. Hi sinh.C. Cnh tranh. D. K sinh.

p n: CCu 179: Quan h no sau y l quan h cng sinh? ( Chng 1/ bi 44/ mc 2)

A. Vi khun trong nt sn r cy h u. B. a y bm trn cnh cy.

C. Giun a sng trong rut ngi. D. Cy np m bt cn trng.p n: ACu 180: C p bm vo ra bin hoc c ln, nh c ra v c ln a i xa. C p, ra bin v cln c mi quan h no di y? ( Chng 1/ bi 44/ mc 3)

A. Cng sinh. B. K sinh.C. Na k sinh. D. Hi sinh.

p n: DCu 181: Trong qun th, t l gii tnh cho ta bit iu g? ( Chng II/ bi 47/ mc 1)

A. Tim nng sinh sn ca loi. B. Gii tnh no c sinh ra nhiu hnC. Gii tnh no c tui th cao hn D. Gii tnh no c tui th thp hn

p n: A

Cu 182:Pht biu no sau y l khng ng vi thp tui dng pht trin?( Chng II/ bi 47/ mc 1)A. y thp rng B. s lng c th trong qun th n nhC. S lng c th trong qun th tng mnh D. T l sinh cao

p n: BCu 183: Vo cc thng ma ma trong nm, s lng mui tng nhiu. y l dng bin ng s lng:( Chng II/ bi 47/ mc 1)

A. Theo chu k ngy m B. Theo chu k nhiu nmC. Theo chu k ma D. Khng theo chu k

p n: CCu 184: Mt ca qun th ng vt tng khi no? ( Chng II/ bi 47/ mc 2)

A. Khi iu kin sng thay i t ngt nh lt li, chy rng, dch bnh, B. Khi khu vc sng ca qun th m rng.C. Khi c s tch n ca mt s c th trong qun th.D. Khi ngun thc n trong qun th di do.

p n: DCu 185: T l gii tnh trong qun th thay i ch yu theo: ( Chng II/ bi 47/ mc 2)

A. La tui ca c th v s t vong khng ng u gia c th c v ci.B. Ngun thc n ca qun th.C. Khu vc sinh sng.D. Cng chiu sng.

p n: A

Cu 186: C ch iu ha mt qun th ph thuc vo: ( Chng II/ bi 47/ mc 3)A. S thng nht mi tng quan gia t l sinh sn v t l t vong.B. Kh nng sinh sn ca cc c th trong qun th.C. Tui th ca cc c th trong qun th.D. Mi tng quan gia t l s lng c v ci trong qun th.

p n: ACu 187: a s ng vt, t l c/ci giai on trng hoc con non mi n thng l: ( Chng II/bi 47/ mc )

A. 50/50 B. 70/30 C. 75/25 D. 40/60p n: ACu 188: Tp hp c th no di y l qun th sinh vt? ( Chng II/ bi 47/ mc 2)


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24A. Tp hp cc c th giun t, giun trn, cn trng, chut chi ang sng trn mt cnh ng.B. Tp hp cc c th c chp, c m, c r phi ang sng chung trong mt ao.C. Tp hp cc cy c hoa cng mc trong mt cnh rng.D. Tp hp cc cy ng ( bp) trn mt cnh ng.

p n: DCu 189: Mt qun th chim s c s lng c th cc nhm tui nh sau:- Nhm tui trc sinh sn: 53 con / ha

- Nhm tui sinh sn: 29 con/ ha- Nhm tui sau sinh sn: 17 con/ haBiu thp tui ca qun th ny ang dng no? ( Chng II/ bi 47/ mc 3)

A. Va dng n nh va dng pht trin. B. Dng pht trin.C. Dng gim st. D. Dng n nh.

p n: BCu 190: Mt qun th chut ng c s lng c th cc nhm tui nh sau:- Nhm tui trc sinh sn 44 con/ ha.- Nhm tui sinh sn: 43 con / ha- Nhm tui sau sinh sn: 21 con / haBiu thp tui ca qun th ny ang dng no? ( Chng II/ bi 47/ mc 3)

A. Dng n nh B. Dng pht trinC. Dng gim st D. Va dng n nh va dng pht trin

p n: A.Cu 191: Mt qun th hu c s lng c th cc nhm tui nh sau:- Nhm tui trc sinh sn: 25 con / ha- Nhm tui sinh sn: 45 con / ha- Nhm tui sau sinh sn: 15 con / haBiu thp tui ca qun th ny ang dng no? ( Chng II/ bi 47/ mc 3)

A. Dng pht trin. B. Dng n nh.C. Va dng n nh va dng pht trin. D. Dng gim st.

p n: D

Cu 192: Tp hp no sau y l qun th sinh vt t nhin? ( Chng II/ bi 47/ mc 3)A. By kh mt sng trong rng. B. n c sng sngC. n chim sng trong rng. D. n ch nui trong nh.

p n: ACu 193: V d no sau y khng phi l qun th sinh vt? ( Chng II/ bi 47/ mc 2)

A. Cc c th chim cnh ct sng b bin Nam cc.B. Cc c th chut ng sng trn mt ng la.C. Cc c th rn h mang sng ba hn o cch xa nhau.D. Rng cy thng nha phn b ti vng ng bcVit Nam.

p n: CCu 194: Qun th ngi c c trng no sau y khc so vi qun th sinh vt?( Chng II. / bi s

48 /Mc 1)A. T l gii tnh B. Thnh phn nhm tuiC. Mt D. c trng kinh t x hi.

p n: D.Cu 19 5: Qun th ngi c 3 dng thp tuinh hnh sau :(Chng II. / bi s 48 / Mc 2)

Dng thp dn s gi l:A. Dng a, b B. Dng b, cC. Dng a, c D. Dng c

p n: D.


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25Cu 196: Qun th ngi c nhng nhm tui no sau y?(Chng II. / bi s 48 / Mc 1)

A. Nhm tui trc sinh sn, nhm tui sinh sn v lao ng, nhm tui ht kh nng lao ngnng nhcB. Nhm tui sinh sn v lao ng, nhm tui sau lao ng, nhm tui khng cn kh nng sinhsnC. Nhm tui lao ng, nhm tui sinh sn , nhm tui ht kh nng lao ng nng nhcD. Nhm tui trc lao ng , nhm tui lao ng, nhm tui sau lao ng

p n A.Cu 197: Tng dn s nhanh c th dn n tnh trng no sau y:(Chng II/ bi s 48 / Mc 1)

A. Thiu ni , nhim mi trng, nhng lm cho kinh t pht trin mnh nh hng tt nngi lao ngB. Lc lng lao ng tng , lm d tha sc lao ng dn n nng sut lao ng gimC. Lc lng lao ng tng , khai thc trit ngun ti nguyn lm nng sut lao ng cngtng.D. Thiu ni , ngun thc n, nc ung , nhim mi trng, tn ph rng v cc ti nguynkhc.

p n D.Cu 198: c im ca hnh thp dn s tr l g?(Chng II. / bi s 48 / Mc 2)

A. y rng, cnh thp xin nhiu v nh thp nhn, biu hin t l t vong cao, tui th trungbnh thpB. y khng rng , cnh thp xin nhiu v nh thp khng nhn, biu hin t l t vong cao,tui th trung bnh thp.C. y rng, cnh thp hi xin v nh thp khng nhn, biu hin t l t vong cao, tui thtrung bnh thpD.y rng, cnh thp hi xin v nh thp khng nhn, biu hin t l t vong trung bnh , tuith trung bnh kh cao

p n: A.Cu 199: Thp dn s gi c c im l: (Chng II. / bi s 48/ Mc 2)

A. y hp, nh khng nhn, cnh thp gn nh thng ng, biu hin t l sinh v t l t vong

u thp, tui th trung bnh cao.B. y trung bnh , nh khng nhn, cnh thp gn nh thng ng, biu hin t l sinh v t l tvong u thp, tui th trung bnh cao.C. y rng , nh khng nhn, cnh thp gn nh thng ng, biu hin t l sinh v t l t vongu thp, tui th trung bnh cao.D. y rng , nh nhn, cnh thp xin nhiu, biu hin t l sinh v t l t vong u thp, tuith trung bnh cao

p n:A.Cu 200: qun th ngi , quy nh nhm tui trc sinh sn l: (Chng II / bi s 48/ Mc 1)

A. T 15 n di 20 tui B. T s sinh n di 15 tuiC. T s sinh n di 25 tui D. T s sinh n di 20 tui

p n:BCu 201: Nu mt nc c s tr em di 15 tui chim trn 30% dn s, s lng ngi gi chim di10%, tui th trung bnh thp th c xp vo loi nc c :(Chng II. / bi s 48 /Mc 3)

A. Thp dn s tng i n nh B. Thp dn s gim stC. Thp dn s n nh D. Thp dn s pht trin

p n : DCu 202: Thp dn s th hin :(Chng II / bi s 48 /Mc 3 )

A. c trng dn s ca mi ncB. Thnh phn dn s ca mi ncC. Nhm tui dn s ca mi ncD. T l nam/ n ca mi nc


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26p n : A.Cu 203: Mc ch ca vic thc hin Php lnh dn s Vit Nam l : (Chng II / bi s 48 / Mc 1)

A.Bo m cht lng cuc sng ca mi c nhn, gia nh v ton x hiB. Bo v mi trng khng kh trong lnhC. Bo v ti nguyn khong sn ca quc giaD. Nng cao dn tr cho ngi c thu nhp thp

p n : A.

Cu 204: Rng ma nhit i l:( Chng II/ bi 49/ Mc 2)A. Mt qun th sinh vt B. Mt qun x sinh vtC. Mt qun x ng vt D. Mt qun x thc vt

p n: B.Cu 205: Qun x sinh vt c nhng du hiu in hnh no? ( Chng II/ bi 49/ Mc 1.)

A. S lng cc loi trong qun x.B. Thnh phn loi trong qun xC. S lng cc c th ca tng loi trong qun xD. S lng v thnh phn loi trong qun x

p n: D.Cu 206: S lng cc loi trong qun x th hin ch s no sau y: ( Chng II/ bi 49/ Mc 1.)

A. nhiu, a dng, tp trungB. a dng, thng gp, tp trungC. thng gp, nhiu, tp trungD. a dng, thng gp, nhiu

p n: D.Cu 207 : Ch s th hin mc phong ph v s lng loi trong qun x l :(Chng II/ bi 49/ Mc1.)

A. a dng B. nhiuC. thng gp D. tp trung

p n: A.Cu 208 : Ch s th hin mt c th ca tng loi trong qun x l: ( Chng II/ bi 49/ Mc 1.)

A. a dng B. nhiu,C. thng gp D. tp trungp n: B.Cu 209: Ch s th hin t l % s a im bt gp mt loi trong tng s a im quan st qun xl: ( Chng II/ bi 49/ Mc 1.)

A. a dng B. nhiuC. thng gp D. tp trung

p n: C.Cu 210: Tp hp no sau y khng phi l qun x sinh vt?( Chng II/ bi 49/ Mc 2)

A. Mt khu rng B. Mt h t nhinC. Mt n chut ng D. Mt ao c

p n : C.Cu 211 : S lng c th trong qun x lun c khng ch mc nht nh ph hp vi kh nngca mi trng. Hin tng ny gi l:( Chng II/ bi 49/ Mc 1.)

A. S cn bng sinh hc trong qun x B. S pht trin ca qun xC. S gim st ca qun x D. S bt bin ca qun x

p n: A.Cu 212: Hin tng s lng c th ca mt qun th b s lng c th ca qun th khc trong qunx km hm l hin tng no sau y:( Chng II/ bi 49/ Mc 3)

A. Khng ch sinh hc B Cnh tranh gia cc loiC. H tr gia cc loi D. Hi sinh gia cc loi

p n: A.


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27Cu 213 : Hin tng khng ch sinh hc trong qun x dn n h qu no sau y?( Chng II/ bi49/ Mc 3)

A. m bo cn bng sinh thi B. Lm cho qun x khng pht trin cC. Lm mt cn bng sinh thi D. m bo kh nng tn ti ca qun x

p n: A.Cu 214: Tp hp cc sinh vt no sau y c coi l mt qun x?( Chng II/ bi 49/ Mc 3)

A. i c Vnh Phc B. n hi u bin

C. By si trong rng D. Tm, c trong h t nhinp n: D.Cu 215: Trong mi quan h gia cc thnh phn trong qun x ,th quan h ng vai tr quan trngnht l :Mc 2)

A. Quan h v ni . B. Quan h dinh dngC. Quan h h tr. D. Quan h i ch

p n: BCu 216: Trong mt qun x sinh vt, loi u th l:( Chng II/ bi 49/ Mc 1 )

A. Loi ch c mt qun x hoc c nhiu hn hn cc loi khcB. Loi c s lng c th ci ng nhtC. Loi ng vai tr quan trng ( s lng ln)

D. Loi c t l c/ ci n nh nhtp n: CCu 217: Trong mt qun x sinh vt, loi c trng l:( Chng II/ bi 49/ Mc 1 )

A. Loi ch c mt qun x hoc c nhiu hn hn cc loi khcB. Loi c s lng c th ci ng nhtC. Loi ng vai tr quan trng ( s lng ln)D. Loi c t l c/ ci n nh nht

p n A.Cu 218: Hin tng khng ch sinh hc c th xy ra gia cc qun th no sau y:

( Chng II/ bi 49/ Mc 3)A. Qun th ch ng v qun th chim s

B. Qun th chim s v qun th chim cho moC. Qun th g v qun th chu chuD. Qun th c chp v qun th c r

p n: C.Cu 219:Mt h sinh thi hon chnh bao gm nhng thnh phn ch yu no sau y:

( Chng II/ bi 50/ Mc 1)A. Thnh phn v sinh, thnh phn hu c, thnh phn v cB. Thnh phn ng vt, thnh phn thc vt, thnh phn vi sinh vtC. Sinh vt sn xut, sinh vt tiu th, sinh vt phn giiD. Thnh phn v sinh, sinh vt sn xut, sinh vt tiu th, sinh vt phn gii

p n:D.

Cu 220: Thnh phn v sinh ca h sinh thi bao gm nhng yu t no sau y:( Chng II/ bi 50/ Mc 2)A.Cc cht v c: nc, kh cacbonic, kh oxi...., cc loi vi rt, vi khun...B. Cc cht mn, b, cc loi ru, a y.C. Cc nhn t kh hu nh: nhit , nh sng, m...cc loi nm, mc.D.Nc, kh cacbonic, kh oxi, nhit , nh sng, m.

p n: D.Cu 221:Dng nng lng trong chui thc n, nng lng khi u trong sinh gii c ly t u?( Chng II/ bi 50/ Mc )

A. T mi trng khng kh B. T ncC. T cht dinh dng trong t D. T nng lng mt tri


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28p n: D.Cu 222: Trong chui thc n sau:Cy c B ra ch Rn Vi sinh vtTh rn l : ( Chng II/ bi 50/ Mc 2)

A. Sinh vt sn xut B. Sinh vt tiu th cp 1C. Sinh vt tiu th cp 2 D. Sinh vt tiu th cp 3

p n D.

Cu 223: Cho chui thc n n gin cn ch trng sau:Cy g (...........) Chut Rn Vi sinh vtLoi no sau y in vo ch trng l hp l nht ( Chng II/ bi 50/ Mc 2)

A. Mo B. Su n l cyC. B nga D. ch

p n B.Cu 224: Trong chui thc n, sinh vt sn xut l loi sinh vt no sau y?( Chng II/ bi 50/ Mc 1)

A. Nm v vi khun B. Thc vtC. ng vt n thc vt D. Cc ng vt k sinh

p n B.Cu 225: Sinh vt tiu th gm nhng i tng no sau y?( Chng II/ bi 50/ Mc 2)

A. ng vt n thc vt , ng vt n tht bc 1 . ng vt n tht bc 2B. ng vt n tht bc 1, ng vt n tht bc 2, thc vtC. ng vt n tht bc 2, ng vt n thc vt, thc vtD. Thc vt , ng vt n tht bc 2 , ng vt n thc vt

p n:A.Cu 226: Sinh vt n tht l :( Chng II/ bi 50/ Mc 1)

A. Con b B. Con cuC. Con th D. Cy np m

p n : D.Cu 227: Nm sinh vt l : Trn, c, chu chu, g rng v vi khun c th c quan h dinh dng theos no di y?( Chng II/ bi 50/ Mc 3)

A. C chu chu trn g rng vi khunB. C trn chu chu vi khun g rngC C chu chu g rng trn vi khunD. C chu chu vi khun g rng trn

p n :CCu 228:Li thc n l :( Chng II/ bi 50/ Mc 1)

A. Gm mt chui thc nB. Gm nhiu loi sinh vt c quan h dinh dng vi nhauC. Gm cc chui thc n c nhiu mt xch chungD. Gm t nht l 1 chui thc n tr ln

p n C.Cu 229:Sinh vt no l mt xch cui cng trong chui thc n hon chnh ?( Chng II/ bi 50/ Mc1)

A. Vi sinh vt phn gii B. ng vt n thc vtC. ng vt n tht D. Thc vt

p n A.Cu 230:Cc hnh thc khai thc thin nhin ca con ngi thi nguyn thu l (chng 3/ bi 53/ mc 1)

A. Hi qu , sn bt th.B. Bt c, hi qu.C. Sn bt th, hi lm cy rng.D. Sn bt ng vt v hi lm cy rng.


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29p n: DCu 231: Tc ng ln nht ca con ngi ti mi trng t nhin l (chng 3/ bi 53 / mc 3 )

A. Ph hu thm thc vt, gy ra nhiu hu qu xu .B. Ci to t nhin lm mt cn bng sinh thi.C. Gy nhim mi trng.D. Lm gim lng nc gy kh hn.

p n : A

Cu 232:Nguyn nhn gy chy nhiu khu rng thi nguyn thu l do ( chng 3 / bi 53 / mc 2)A. Con ngi dng la ly nh sngB. Con ngi dng la nu nng thc n .C. Con ngi dng la si m .D. Con ngi t la dn th d vo cc h su bt .

p n : D.Cu 233: x hi nng nghip do con ngi hot ng trng trt v chn nui :(chng 3/ bi 53/mc 1 )

A. Cht ph v t rng ly t canh tc.B. Cht ph rng ly t chn th gia sc .C. Cht ph v t rng ly t canh tc , chn th gia sc .

D. t rng ly t trng trt .p n : CCu 234: Sn bt ng vt hoang d qu mc dn n hu qu ( chng 3/ bi 53/ mc 1 )

A. Mt cn bng sinh thi .B. Mt nhiu loi sinh vt .C. Mt ni ca sinh vt .D. Mt cn bng sinh thi v mt nhiu loi sinh vt .

p n : DCu 235: x hi nng nghip, hot ng nng nghip em li li ch l ( chng 3/ bi 53/ mc 1)

A. Hnh thnh cc h sinh thi trng trt .B. Tch lu thm nhiu ging vt nui .

C. Tch lu thm nhiu ging cy trng, vt nui .D. Tch lu thm nhiu ging cy trng, vt nui v hnh thnh cc h sinh thi trng trtp n : DCu 236: x hi nng nghip hot ng cy xi t canh tc lm thay i t v nc tng mt nn( chng 3 /bi 53 / mc 2 )

A. t b kh cn . B. t gim mu m .C. Xi mn t . D. t kh cn v suy gim mu m.

p n : D.Cu 237: Nn nng nghip hnh thnh , con ngi phi sng nh c ,dn n nhiu vng rng b chuyni thnh ( chng 3 / bi 53 / mc 3)

A. Khu dn c B. Khu sn xut nng nghip .

C. Khu chn th vt nui. D. Khu dn c v khu sn sut nng nghip .p n : D.Cu 238: Tc ng xu ca con ngi i vi mi trng t nhin ( chng 3 / bi 53 / mc 1 )

A. Cht ph rng ba bi , khai thc ti nguyn thin nhin .B. Khai thc ti nguyn thin nhin , Sn bt ng vt hoang d .C. Sn bt ng vt hoang d, cht ph rng ba bi .D. Cht ph rng ba bi, sn bt ng vt hoang d, khai thc ti nguyn thin nhin .

p n : D.Cu 239: Suy gim a dng ca sinh hc l nguyn nhn gy nn ( chng 3 / bi 53 / mc 3)

A. Mt cn bng sinh thi . B. Lm suy gim h sinh thi rng .C. Lm suy gim ti nguyn sinh vt . D. Lm c ch hot ng ca cc vi sinh vt .


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30p n : ACu 240: x hi cng nghip xut hin nhiu vng trng trt ln l do ( chng 3 / bi 53 / mc 3 )

A. Nn nng nghip c gii ho . B. Cng nghip khai khong pht trin .C. Ch to ra my hi nc . D. Nn ho cht pht trin .

p n : A.Cu 241 : Hu qu gy nn cho mi trng t nhin do con ngi sn bt ng vt qu mc l ( chng3 / bi 53 / mc 2 )

A. ng vt mt ni c tr .B. Mi trng b nhim .C. Nhiu loi c nguy c b tit chng , mt cn bng sinh thi .D. Nhiu loi tr v trng thi cn bng .

p n : C.Cu 242: Th k XVIII c coi l im mc ca ( chng 3 / bi 53/ mc 3)

A. S pht trin ca nn nng nghip . B. Thi i vn minh cng nghip .C. S pht trin th . D. Nn nng nghip c gii ho .

p n : BCu 243: Hot ng no sau y ca con ngi khng nh hng n mi trng ( chng 3 / bi 53/mc 1 )

A. Hi lm . B. Sn bn qu mc .C. Chin tranh . D. Hi lm, sn bn, chin tranh .

p n : A.Cu 244: Th no l nhim mi trng ? ( chng 3 / bi 54 / mc 1 )

A. L hin tng mi trng t nhin b bn .B. L hin tng mi trng t nhin b bn . Cc tnh cht vt l thay i .C. L hin tng mi trng t nhin b bn . Cc tnh cht vt l , ho hc , sinh hc thay i .D. L hin tng mi trng t nhin b bn .Cc tnh cht vt l , ho hc , sinh hc b thay igy tc hi cho con ngi v cc sinh vt khc .

p n : DCu 245: Nguyn nhn dn n nhim mi trng l g ? ( chng 3 / bi 54 / mc 1 ) )

A. Do hot ng ca con ngi gy ra .B. Do 1 s hot ng ca t nhin ( ni la , l lt ..)C. Do con ngi thi rc ra sng .D. Do hot ng ca con ngi gy ra v do 1 s hot ng ca t nhin.

p n : DCu 246: Nguyn nhn gy nhim kh thi ch yu do qu trnh t chy ( chng 3 / bi 54 / mc 1 )

A. G , than . B. Kh t , ci .C. Kh t , g . D. G , ci , than , kh t .

p n : D.Cu 247: Mt s hot ng gy nhim khng kh nh ( chng 3/ bi 54 / mc 1)

A. Chy rng , cc phng tin vn ti .

B. Chy rng , un nu trong gia nh .C. Phng tin vn ti , sn xut cng nghip .D. Chy rng , phng tin vn ti , un nu trong gia nh , sn xut cng nghip .

p n : D.Cu 248:Nguyn nhn nhim khng kh l do ( chng 3 /bi 54 / mc 1 )

A. Sn bt ba bi , v t chc .B. Cc cht thi t thc vt phn hu .C. n rng ly t canh tc .D. Cc cht thi do t chy nhin liu : g , ci , than , du m .

p n : D


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31Cu 249 : Nng lng nguyn t v cht phng x c kh nng gy t bin ngi , gy ra mt s bnh( chng 3 / bi 54 / mc 1 )

A. Bnh di truyn . B. Bnh ung th .C. bnh lao . D. Bnh di truyn v bnh ung th.

p n : D.Cu 250:Ngun nhim phng x ch yu l t cht thi ca ( chng 3 / bi 54 / mc 1 )

A. Cng trng khai thc cht phng x .

B . Nh my in nguyn t .C. Th v kh ht nhn .D. Cng trng khai thc cht phng x, nh my in nguyn t, vic th v kh ht nhn .

p n : DCu 251 : Ngun gc gy nhim sinh hc ch yu do cc cht thi nh ( chng 3 /bi 54 /mc 1 )

A. Phn , rc , nc thi sinh hot .B. Nc thi sinh hot , nc thi t cc bnh vin .C. Xc cht ca cc sinh vt , nc thi t cc bnh vin .D. Phn , rc , nc thi sinh hot , xc cht sinh vt , nc thi t cc bnh vin .

p n : D.Cu 252: Khc phc nhim ho cht bo v thc vt gm cc bin php no ? ( chng 3/bi54/ mc 3)

A. Bin php sinh hc v bin php canh tc .B. Bin php canh tc , bn phn .C. Bn phn , bin php sinh hc .D. Bin php sinh hc , bin php canh tc , bn phn hp l .

p n : D.Cu 253: Trng st rt pht trin u trong c th ngi ? ( chng 3/ bi 54 / mc 2)

A. Trong gan . B. Trong hng cu .C. Trong bch cu . D. Trong gan v hng cu .

p n : D.C u 254:Ngi n gi c ( tht c sng ) s b nhim bnh ( chng 3 / bi 54 / mc 2)

A. Bnh sn l gan . B. Bnh t , l .

C. Bnh st rt . D. Bnh thng hn .p n : A.Cu 255:Thuc bo v thc vt gm cc loi ( chng 3/ bi 54 / mc 1)

A. Thuc tr su , thuc dit c .B. Thuc dit c , thuc dit nm gy hi .C. Thuc tr su , thuc dit nm gy hi .D. Thuc tr su, thuc dit c , thuc dit nm gy hi .

p n : DCu 256: Nguyn nhn dn n bnh t , l : ( chng 3/ bi 54/ mc 1)

A. Thc n khng v sinh , nhim vi khun E. Coli .B. Thc n khng ra sch .

C. Mi trng sng khng v sinh .D. Thc n khng v sinh , nhim vi khun E. Coli, thc n khng ra sch, mi trng sngkhng v sinh .

p n : D.Cu 257: Ngun nhim nhn to gy ra l do ( chng 3 /bi 54/ mc 1)

A. Hot ng cng nghip .B. Hot ng giao thng vn ti .C. t chy nguyn liu trong sinh hot .D. Hot ng cng nghip , giao thng vn ti , t chy nhin liu trong sinh hot .

p n : D.


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32Cu 258: Bin php hn ch nhim do thuc bo v thc vt ( chng 3/ bi 55/ mc 2)

A. Trng rau sch .B. Hn ch phun thuc bo v thc vt .C. Bn phn cho thc vt .D. Trng rau sch , hn ch phun thuc bo v thc vt .

p n : DCu 259: Cc nng lng khng sinh ra kh thi l ( chng 3 / bi 55/ mc 1)

A. Nng lng mt tri . B. Kh t thin nhin .C. Nng lng gi D. Nng lng mt tri v nng lng gi .

p n : D.Cu 260:Xy dng nhiu cng vin , trng cy xanh : ( chng 3 / bi 55/ mc 2)

A. Hn ch bi . B. iu ho kh hu .C. X l cht thi nng nghip . D. Hn ch bi , iu ho kh hu .

p n : D.Cu 261: Bin php hn ch nhim ting n ( chng 3/ bi 55/ mc 1)

A. Hn ch gy ting n ca cc phng tin giao thng ,B. Lp t cc thit b lc kh cho cc nh my .C. Hn ch ting n ca cc phng tin giao thng , xy dng cng vin cy xanh , trng cy .

D. Xy dng cng vin cy xanh, trng cy .p n : C.Cu 262: Bin php hn ch nhim do cht thi rn ( chng 3/ bi 55/ mc 1 )

A. Xy dng nh my ti ch cht thi thnh nguyn liu , dng ..B. To b lng v lc nc thi .C. Trng nhiu cy xanh .D. Sn xut lng thc v thc phm an ton .

p n : A.Cu 263: Bin php hn ch nhim do cht phng x ( chng 3 /bi 55/ mc 1)

A. Xy dng ni qun l tht cht ch cc cht phng x gy nguy him .B. Xy dng nh my ti ch cht thi .

C. Xy dng nh my x l rc .D. Xy dng cc nh my xa khu dn c.p n : ACu 264:To b lng , lc nc thi hn ch ( chng 3 /bi 55/ mc 1)

A. nhim ngun nc . B. nhim khng kh .C. nhim do cht phng x . D. nhim do hot ng thin tai .

p n : A.Cu 265: Lp t cc thit b lc kh cho cc nh my hn ch ( chng 3/ bi 55/ mc 1 )

A. nhim khng kh . B. nhim ngun nc .C. nhim do cht phng x . D. nhim do ting n .

p n : A.

Cu 266: Sn xut lng thc v thc phm an ton hn ch ( chng 3 / bi 55 / mc 1)A. nhim do thuc bo v thc vt , ho cht .B. nhim do cht phng x .C. nhim do khng kh .D. nhim do hot ng thin tai .

p n : A.Cu 267: Trong cc phng tin giao thng sau phng tin no khng gy kh thi ( chng 3 / bi 55 /mc 1)

A. Xe p . B. Xe gn my .C. Xe t . D. t but .

p n : A


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33Cu 268: Nhng hot ng no sau y khng gy nhim mi trng ( chng 3 / bi 55/ mc 1 )

A. Phun thuc tr su . B. Trng cy gy rng .C. Vt rc ba bi ra mi trng . D. Thi nc sinh hot ra mi trng .

p n : BCu 269: Cc dng ti nguyn thin nhin ch yu gm: (Chng IV/Bi 58/Mc 1)

A. t, nc, du mB. t, nc, sinh vt, rng

C. t, nc, khong sn, nng lng, sinh vt, rngD. t, nc, than , sinh vt, rng

p n: CCu 270: Ti nguyn no sau y thuc ti nguyn khng ti sinh: (Chng IV/ Bi 58/Mc 1)

A. Ti nguyn rngB. Ti nguyn tC. Ti nguyn khong snD. Ti nguyn sinh vt

p n: C

Cu 271: Ti nguyn no sau y thuc ti nguyn ti sinh: (Chng IV/Bi 58/ Mc 1)A. Kh t v ti nguyn sinh vtB. Ti nguyn sinh vt v ti nguyn tC. Du m v ti nguyn ncD. Bc x mt tri v ti nguyn sinh vt

p n: BCu 272: Gi v nng lng nhit t trong lng t c xp vo ngun ti nguyn no sau y: (ChngIV/Bi 58/ Mc 1)

A. Ti nguyn khng ti sinhB. Ti nguyn nng lng vnh cu

C. Ti nguyn ti sinh v ti nguyn khng ti sinhD. Ti nguyn ti sinh

p n: BCu 273: Ti nguyn di y c gi tr v tn l: (Chng IV /Bi 58/ Mc 1)

A. Du m, than v kh tB. Ti nguyn khong sn v ti nguyn sinh vtC. Nng lng mt triD. Cy rng v th rng

p n: C

Cu 274:Ngun nng lng di y nu c khai thc s dng s khng gy nhim mi trng l:(Chng IV /Bi 58/ Mc 1)A. Kh t thin nhinB. Than C. Du mD. Bc x mt tri

p n: DCu 275 : Ti nguyn no sau y c xem l ngun nng lng sch? (Chng IV /Bi 58/ Mc 1)

A. Bc x mt tri, gi, nhit trong lng tB. Du m, kh t


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34C. Than v ngun khong sn kim loiD. Du m, thy triu, kh t

p n: ACu 276:Ngun nng lng vnh cu l: (Chng IV /Bi 58/ Mc 1)

A. Nng lng kh tB. Nng lng t du m

C. Nng lng nhit t mt triD. Nng lng t than ci

p n: CCu 277 : Da vo yu t no sau y xp t vo ngun ti nguyn ti sinh: (Chng IV /Bi 58/Mc 2)

A. Trong t cha nhiu khong sn kim loiB. t thng xuyn c bi p bi ph sa, c tng mn t xc ng thc vtC. Trong t c nhiu than D. Nhiu qung du m, kh t trong lng t

p n: BCu 278: Hy cho bit nhm ti nguyn no sau y l cng mt dng (ti nguyn ti sinh, khng ti sinhhoc nng lng vnh cu) : (Chng IV /Bi 58/ Mc 3 )

A. Rng, ti nguyn t, ti nguyn ncB. Du m, kh t, ti nguyn sinh vtC. Bc x mt tri, rng, ncD. t, ti nguyn sinh vt, kh t

p n: ACu 279 :Nhng bin php bo v ngun ti nguyn t l: (Chng IV /Bi 58/ Mc 2)

A. Trng cy gy rng chng xi mnB. Tng cao ph cho t

C. Bo v ng vt hoang dD. Chng xi mn, chng nhim mn, nng cao ph cho t

p n: DCu 280: bo v rng v ti nguyn rng, bin php cn lm l: (Chng IV /Bi 58/ Mc 3)

A. Khng khai thc s dng ngun li t rng naA. Tng cng khai thc nhiu hn ngun th rngB. Thnh lp cc khu bo tn thin nhin v cc vn quc giaC. Cht ph cc khu rng gi trng li rng mi

p n: CCu 281:Ngoi vic cung cp g qu, rng cn c tc dng g cho mi trng sng ca con ngi?

(Chng IV /Bi 58/ Mc 3)A. Cung cp ng vt qu himB. Thi kh CO2, gip cy trng khc quang hpC. iu ha kh hu, chng xi mn, ngn chn l ltD. L ni tr n ca nhiu loi ng vt

p n: CCu 282: Gn gi thin nhin hoang d l : (Chng IV /Bi 59/ Mc 1)

A. Bo v cc loi sinh vtB. Bo v rng u ngunC. Bo v mi trng sng ca sinh vt


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35D. Bo v cc loi sinh vt v mi trng sng ca chng

p n: DCu 283: bo v thin nhin hoang d, cn ngn chn hot ng no di y? (Chng IV /Bi 59/Mc 1)

A. Trng cy gy rng to mi trng sng cho ng vt hoang d.B. Sn bn th hoang d, qu him

C. Xy dng cc khu bo tn, cc vn quc giaD. Bo v rng gi, rng u ngun

p n: BCu 284: i vi nhng vng t trng, i ni trc th bin php ch yu v cn thit nht l:(Chng IV /Bi 59/ Mc 1)

A. Trng cy gy rngB. Tin hnh chn th gia scC. Cy xi lm nng, ry sn xut lng thcD. Lm nh

p n: ACu 285:Nhng hnh ng no sau y lm suy thoi mi trng: (Chng IV /Bi 59/ Mc 1)

A. Trng cy trn i trcB. Sn bt ng vt qu himC. Khng cht ph rng ba biD. Sn bt ng vt qu him phun thuc tr su

p n: DCu 286:Vai tr ca vic trng cy gy rng trn vng t trc, t trng l: (Chng IV /Bi 59/ Mc 2)

A. Hn ch xi mn, l lt, ci to kh huB. Cho ta nhiu g

C. Ph xanh vng t trngD. Bo v cc loi ng vt

p n: ACu 287: lm cho t khng b cn kit ngun dinh dng, tn dng c hiu sut s dng t tngnng sut cy trng, ta cn phi: (Chng IV /Bi 59/ Mc 2)

A. Trng mt loi cy nht nh trn vng t B. Thay i cc loi cy trng hp l (trng lun canh, trng xen k)C. Trng cy kt hp bn phnD. Trng cc loi ging mi

p n: BCu 288:Xy dng cc khu bo tn thin nhin, vn quc gia nhm mc ch g? (Chng IV /Bi 59/Mc 2)

A. Bo v ngun gen sinh vtB. To khu du lchC. Bo v h sinh thi v bo v ngun gen sinh vtD. Hn ch din tch rng b khai ph

p n: CCu 289 : Nhng bin php ch yu bo v thin nhin hoang d l : (Chng IV /Bi 59/ Mc 3)

A Bo v ti nguyn sinh vt - bo v cc khu rng gi.


36/38

36B. Trng thm cy v gy rng to mi trng sng cho nhiu sinh vt.C. Bo v ti nguyn sinh vt v ci to cc h sinh thi b thoi haD. Bo v cc ng vt qu him, xy dng cc vn quc gia

p n: CCu 290: Cng ngh sinh hc ng vai tr quan trng nh th no trong vic bo v ti nguyn sinh vt:(Chng IV /Bi 59/ Mc 3)

A. Bo tn ngun gen qu him

B. To ra nhiu ging miC. Lu gi v nhn nhanh nhiu ging qu him.D. p ng c nhu cu ngy cng cao ca con ngi

p n: CCu 291: Em hy cho bit cng vic ca chng ta lm bo v ngun ti nguyn sinh vt: (ChngIV /Bi 59/ Mc 3)

A. Xy dng cc khu rng quc gia ,bo v sinh vt c tn trong sch B. Cht ph rng lm ci, ly gC. S dng ng mc thuc tr su v ha chtD. Khai thc ngun ti nguyn thin nhin.

p n: ACu 292:Cc h sinh thi ch yu trn tri t: (Chng IV /Bi 60/ Mc 2)

A. H sinh thi trn cn, h sinh thi vng ven bB. H sinh thi trn cn, h sinh thi vng bin khiC. H sinh thi nc mn, h sinh thi ao hD. H sinh thi trn cn, h sinh thi nc mn, h sinh thi nc ngt

p n: DCu 293: H sinh thi di y khng phi l h sinh thi trn cn? (Chng IV /Bi 60/ Mc 1)

A. Rng l rng rng l theo ma vng n i

B. Rng ngp mnC. Vng tho nguyn hoang mcD. Rng ma nhit i

p n: BCu 294: H sinh thi ln nht trn qu t l: (Chng IV /Bi 60/ Mc 2)

A. Rng ma nhit iB. Cc h sinh thi nng nghip vng ng bngC. Cc h sinh thi hoang mcD. Bin

p n: DCu 295 : Mc tiu ca bo v cc h sinh thi nng nghip l : (Chng IV /Bi 60/ Mc 1)A. Tng nng sut v hiu qu cc h sinh thi pht trin kinh t trong thi gian hin ti.B. Pht trin n nh kinh t - mi trng, duy tr v ci to cc h sinh thi ch yu t nng sut

v hiu qu cao.C. Thay i tp qun canh tc lc hu thiu hiu qu v nng sut thpD. Bo m cung cp lng thc, thc phm trong chn nui.

p n: BCu 296: va khai thc ngun ti nguyn bin, va bo v mi trng bin v phc hi ti nguynbin, cn phi: (Chng IV /Bi 60/ Mc 2)


37/38

37A. Khai thc hp l kt hp ci to, phc hi v nui b sung .B. nh bt hi sn bng cht nC. Tng cng nh bt ven bD. Dng ha cht hoc xung in nh bt hi sn

p n: ACu 297: Bo v a dng cc h sinh thi c ngha g? (Chng IV /Bi 60/ Mc 3)

A. Bo v c ngun khong snB. Bo v c cc loi ng vt hoang dC. Bo v vn gen, gi vng cn bng sinh thi trn ton cu.D. Bo v sc khe cho mi ngi.

p n: CCu 298: Hin trng rng nc ta nh th no? (Chng IV /Bi 60/ Mc 3)

A.T l t c che ph ca rng trn 50%B. Rng ang dn b thu hp, c bit rng nguyn sinh ang b ph hoiC. Rng u ngun t nhin ang pht trin tt, gp phn lm gim l lt.D. Rng c bo v tt, cc loi chim di c ang xut hin tr li.

p n: BCu 299:Vai tr ca h sinh thi bin i vi i sng con ngi? (Chng IV /Bi 60/ Mc 3)A. Cc loi ng - thc vt bin l ngun thc n ca con ngiB. Bin gip con ngi vn chuyn hng haC. Bin cho con ngi mui nD. Bin cung cp thc n , pht trin kinh t , giao lu vn chuyn, iu ha nhit trn tri t

p n: DCu 300: C cn phi bo v h sinh thi bin khng? Ti sao? (Chng IV /Bi 60/ Mc 3)

A. Hin nay cha cn quan tm n s nhim ca bin v bin v cng rng ln, hot ng conngi khng nh hng n h sinh thi bin

B. Cn v : bin ang b nhim do cc hot ng giao thng trn binC. Cn v : nhiu vng bin b nhim do hot ng ca con ngi .D. Khng cn v : hng nm trn th gii c ngy lm sch bi bin

p n: CCu 301:Hsinhthi vng rng ngp mn ven bin nc ta c ngha g? (Chng IV /Bi 60/ Mc 1)

A. Gp phn iu ha khng kh, chn sngB. Cho mt khi lng g ng kC. L bi v ni sinh sng nhiu loi hi snD. L ni c tr ca nhiu loi ng vt, thc vt gp phn iu ha kh hu, chn sng, ni t chc

du lch sinh thi, nui cc loi hi sn qu, cho ta mt lng g ln.

p n: DCu 302: Cc loi ra bin ang b sn lng ly mai lm m ngh, s lng ra cn li rt t, chng tacn bo v loi ra bin nh th no? (Chng IV /Bi 60/ Mc 1)

A. Bo v cc bi ct l bi ca ra bin v vn ng ngi dn khng nh bt ra binB. T chc cho nhn dn nui raC. Khng ly trng raD. Ch khai thc ra ngoi thi gian sinh sn

p n: ACu 303: Lut Bo v mi trng quy nh vic bo v mi trng nhm (Chng IV /Bi 61/ Mc 1)

A. Bo v s a dng cc h sinh thi


38/38

38B. Bo v sc khe ca nhn dn, phc v s pht trin lu bn ca t nc v gp phn bo v mi

trng trong khu vc ton cuC. Bo v mi trng khng khD. Bo v cc ti nguyn thin nhin

p n: BCu 304: Cho bit ni dung chng II ca Lut Bo v mi trng Vit Nam? (Chng IV /Bi 61/

Mc 2)A. Phng chng suy thoi mi trngB. Cm nhp khu cht thi vo Vit NamC. Cc t chc v c nhn phi c trch nhim x l cht thi bng cng ngh thch hpD. Phng chng suy thoi, nhim v s c mi trng

p n: DCu 305: i vi vic s dng t sn xut, Lut Bo v mi trng quy nh cho ngi c s dng l:(Chng IV /Bi 61/ Mc 1)

A. c t do thay i thc trng ca tB. c t do thay i mc ch s dng

C. C quy hoch s dng t hp l v c k hoch ci to tD. T do sang nhng t

p n: CCu 306:Trch nhim ca c nhn khi gy ra s c mi trng l :(Chng IV /Bi 61/ Mc 2)

A. Phi np pht cho chnh quyn s ti hoc t chc qun l mi trng ca a phng.B. Phi thay i cng ngh sn xut khng gy nhim mi trngC. Phi c trch nhim bi thng, khc phc hu qu v mt mi trngD. Phi di di c s sn xut ra khi ni c dn c

p n: C

Cu 307: i vi cht thi cng nghip v sinh hot, Lut Bo v mi trng quy nh: (Chng IV /Bi61/ Mc 2)A. C th a trc tip ra mi trngB. C th t do chuyn ch cht thi t ni ny n ni khcC. Cc t chc, c nhn phi c trch nhim x l cht thi bng cng ngh thch hp.D. Chn vo t

p n: CCu 308:Chng ta cn phi lm g thc hin Lut Bo v mi trng: (Chng IV /Bi 61/ Mc 2)

A. Thnh lp i cnh st mi trngB. Mi ngi dn phi tm hiu lut v t gic thc hin

C. Xy dng mi trng Xanh, sch, pD. Quy hoch v s dng k hoch c hiu qu t aip n: B

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