transfer kinetic energy (the energy of motion) reduce the effort needed to move a load

47
• Transfer kinetic energy (the energy of motion) • Reduce the effort needed to move a load • Change the direction or amount of motion • Change the type of motion (rotary to straight line)

Upload: dudley

Post on 18-Jan-2016

17 views

Category:

Documents


1 download

DESCRIPTION

Simple Machines are used to:. Transfer kinetic energy (the energy of motion) Reduce the effort needed to move a load Change the direction or amount of motion Change the type of motion (rotary to straight line). Key Terms:. Effort (E) = the input force - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• Transfer kinetic energy (the energy of motion)

• Reduce the effort needed to move a load

• Change the direction or amount of motion

• Change the type of motion (rotary to straight line)

Page 2: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• Effort (E) = the input force• Either the user or some type of engine

supplies this force.

• Load (R) = the output force. • Also known as the force resisting the

motion.

Page 3: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• Mechanical Advantage (MA) = a measure of how much effort is decreased by the simple machine.

Mechanical Advantage = Load Effort

MA = R

E

Page 4: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• Work : The force applied on an object times the distance traveled by the object.

Work = (Force)Distance = (F)dStarting Position

Force

Finishing Position

Distance

Page 5: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• Friction results from two bodies moving against each other in different directions. – Friction always opposes motion and makes doing work harder. – Lubricants (graphite, oil, grease, silicone) and bearings are used to

combat friction.– Sometimes, friction is a good thing!

• Efficiency is the ratio of the work that results to the amount of work put into the machine.

Page 6: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Power is the rate at which work is performed.

Energy describes the amount of work that can be performed by a force.

P=W

tE=W

P = power

W = work

t = time

E = energy

Page 7: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

•A lever is a stiff bar which rotates around a point called the fulcrum. •The forces on the lever are the Effort (E) and the load (R).

Page 8: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

E = EffortR = LoadLE = Length (distance) from fulcrum to EffortLR = Length (distance) from fulcrum to Load (R)

Page 9: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Moment = Force x distance to fulcrum

CW (-) CCW (+)

The Effort is positive because it is rotating in a counter clock wise rotation around the fulcrum.

The Load is negative because it is rotating in a clock wise rotation around the fulcrum.

Page 10: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Moment 1 = Moment 2

Force 1 x distance 1 = Force 2 x distance 2

300 lb x 4 ft = 1200 lb x 1 ft

1200 ft-lb = 1200 ft-lb

Page 11: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Mechanical Advantage =Load Effort

MA = LE

LR

=1200 lb

300 lb= 4

=4 ft

1 ft= 4

RE

LE

LR= or LE(E) = LR(R)

R E=

Page 12: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• You are given a board that is 8 feet long and a rock to use as a fulcrum and you need to lift a heavy object. Where would you place the rock? Why?

LE becomes very large.

LR becomes very small.Place the rock as close as

possible to the load

Page 13: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

If LE greater than LR, then MA greater than 1

If LE less than LR, then MA less than 1

Page 14: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Since LE greater than LR, then MA greater than 1

Page 15: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Since the LE less than LR, then MA less than 1

Page 16: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Given: LE = 6 ft, LR = 3 ft, E = 1 lb Find R.

Solution:LE R

LR E= =6 ft

3 ft= 2 So.. 2 =

R

1lb = 2 lb

Page 17: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Given: R = 8 lb , LE = 4 ft , E = 4 lb Find LR.

Solution:

LE R

LR E= =4 ft

LR =8 lb

4 lb= LR= 2 ft

Page 18: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load
Page 19: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load
Page 20: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load
Page 21: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Mechanical Advantage =Load Effort

MA = Radius to Effort

Radius to Load =LE

LR

Page 22: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• A wheel with a 12 inch radius is used to turn an axle with a radius .5 inches. What is the mechanical advantage?

MA = Radius to Effort

Radius to Load =LE

LR

MA = Radius of Wheel

Radius of Axel =12 in

.5 in = 24

Page 23: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• Consider an axle used to drive the wheels of a car. The wheel radius is 12 inches, while the axle radius is 1 inch. What is the mechanical advantage?

MA = Radius to Effort

Radius to Load =LE

LR

MA = Radius of Axle

Radius of Wheel =1in

12 in = 0.083

Page 24: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

You need to know the Circumference of Wheel

S

S = Distance traveled in one revolution

C = (Π)Wheel Diameter = (3.14)D

Page 25: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• If your car has tires with a diameter of 24 inches how many times will the tires rotate if the car travels 100 feet?

C = (Π)Wheel Diameter = (3.14)2 ft = 6.28 ft.

24 inches = 2 feet

100 ft

6.28 ft

S = Distance traveled in one revolution = 6.28 ft

Number of Revolutions = = 15.9 revolutions

Page 26: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load
Page 27: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Work at Effort end = Work at Load end

(Effort) Dist. traveled by rope = (Load) Dist. moved by Load

MA = The number of strands supporting the load. (The end strand ONLY counts when the effort is pointing upward.)

Page 28: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Fixed Pulley Movable

Pulley

Block & Tackle

MA = 1MA = 2 MA = 4

Page 29: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

The pulley system shown is used to lift a load of 60 lbs a distance of 2’. How much effort must be applied, and how much rope do you need to pull?

Page 30: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

MA = # of strands = 6

6 = R

E =60 lb

E

Effort = 10 lb

Distance traveled = 2 ft * 6Distance traveled = 12 ft

Page 31: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load
Page 32: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

R or Load E or Effort

MA = R

E

The Effort is parallel to the Inclined Plane.

The Load is 900 to the ground. Or in the direction of gravity.

Page 33: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

H or Height of Inclined PlaneL or Length of In

clined Plane

MA = L

H

The Length is how long the Inclined Plane is.

The Height is vertical distance between the starting point and ending point.

Page 34: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• In the diagram below, L = 24 inches, H = 6 inches and the Effort = 60 lb

• Find the mechanical advantage and the maximum load that can be moved.

• What is the tradeoff for reducing the effort?

A

B

H

L

R

E

Page 35: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

A

B

H

L

R

E

MA = L 24 in

H 6 in= = 4

Mechanical Advantage =Load Effort

4 =Load

30 lb

Load = 120 lb

In order to move the 120 lb 6 inches off the ground, we need to travel a distance of 24 inches along the incline.

Page 36: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load
Page 37: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Effort

Inclined Plane

Effort

Wedge

Page 38: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Single

LH

Double

L

H

Mechanical Advantage =Load Effort

MA = L

H

Page 39: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• Find the mechanical advantage and the maximum separation load for a wedge with an incline length of 10 inches, an overall height of 4 inches, and which is exerting an effort of 100 pounds.

Page 40: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Effor

t

MA = L

H =10 in

4 in = 2.5

Mechanical Advantage =Load Effort

2.5 =Load

100 lb = Load = 250 lb

Page 41: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load
Page 42: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• 1/4 - 20 UNC

1/4 = the outer diameter of the threads.

20 = the number of threads per inch of screw length.

UNC refers to Unified National Coarse thread.

Page 43: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

OD

1in.

Number of Threads per Inch

View A

View APitch

Page 44: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Pitch =

Number of Threads per Inch

1in.

Page 45: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Mechanical Advantage =Load Effort

MA =Circumference

Pitch=

C

P

Page 46: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

• A screw with 18 threads per inch is turned by a screwdriver having a handle diameter of 1 inch. What is the mechanical advantage of the screw?

MA =Circumference

Pitch=

C

P

Page 47: Transfer  kinetic energy  (the energy of motion)  Reduce the  effort  needed to move a load

Pitch =

Circumference = (3.14) 1 in = 3.14 in

1 in

18= 0.055 in

MA =Circumference

Pitch=

C

P=

3.14 in

0.055 in= 57.09