trial mate form 5 sgi 2013 (answer)

7/29/2019 Trial Mate Form 5 Sgi 2013 (Answer)

1/7

PEPERIKSAAN PERCUBAAN SPM MATHEMATICS FORM 5 SGI 2013

Kertas 1

Total = Paper 1 + Paper 2

= 40 + 100

= 140

1 C 11 D 21 B 31 B

2 B 12 C 22 A 32 A

3 C 13 D 23 C 33 D

4 D 14 B 24 B 34 A5 C 15 C 25 B 35 D

6 D 16 D 26 D 36 A

7 A 17 B 27 D 37 B

8 A 18 C 28 B 38 C

9 C 19 D 29 C 39 D

10 B 20 B 30 B 40 A

Kertas 2

Q Solution Submarks Full

marks

1 Dotted line y = 3 drawn and Correct shaded region

Note : 1. Solid line y = 2 drawn (1 mark)

2. Give 1 mark if shaded region between 2 inequalities only

3M

3

2 (a) 640

= 240

(b)05

040

or equivalent

= 8 ms1(units not important)

(c)1 1

( 40 5) (240) 40 ( 11)2 2

t

t

t )11(402

1)240()540

2

1(

= 28 or equivalent

t= 15 s (units not important)

1M

1M

1M1M

1M

1M

1M 7

3 3

1 4 22 212 3 7 2

or 5.105.105.10722

34

21 or

222 14

357 2

or 3577

7

22

Volume =1 4 22

10.5 10.5 10.52 3 7

+

227 7 3 5

7

= 7815.5 or2

17815 or

15631

2cm

3(units not important)

1M

1M

1M 3

x + y = 8

y = 82x

y = 2

8

2

x0 84

y


2/7

4 (a)(i) False/Palsu(ii) True/ Benar

(b) k+ 1 is not an odd integer/ k+ 1 bukan satu integer ganjil

(c) 4n3, n = 2, 3, 4, ... or equivalentNote : 4n3 only (Give 1 mark)

1M1M2M

2M 6

5 LNM

tan LNM =8

6 or equivalent

36.87o or 36o 52

1M1M

1M 3

6 3x2 5x 2 = 0(3x + 1) (x 2) = 0

x =3

1 , 2

1M1M

1M,1M 4

7 4mn = 26

4m + 3n = 24n = 24 or

12 ( 6) 13

2m or 4m(-6)= 26 or

or 4m + 3(-6) = 2

m = 5, n = 6

Note :5

6

m

n

only award 1 mark

1M

1M

1M,1M 4

8 (a) MPR

= 2 and c = 4

y = 2x + 4(b) Coordinate T : (2, 0) or x = 2

y = 2(2) + 4 or equivalent

R(2, 8)

1M1M

1M

1M1M 5

9 (a) Sampel space/Ruang sampel = {(S,C), (S,O), (S,R), (S,E),

(C,S), (C,O), (C,R), (C,E),(O,S), (O,C), (O,R), (O,E),

(R,S), (R,C), (R,O), (R,E),(E,S), (E,C), (E,O), (E,R)}

(b)(i) {(C,S), (C,O), (C,R), (C,E)}

4

20 or

1

5

(ii){(S,C), (S,R), (C,S), (C,R), (O,E), (R,S), (R,C), (E,O)}

8

20 or

2

5

Note : Accept correct answer only if list out

1M

1M1M

1M

1M 5

10(a)

60 222 14

360 7 or equivalent

Perimeter =60 22

2 14360 7

+14 + 14 + 7 + 7 or equivalent

= 56.67 or3

256 or

170

3cm (units not important)

1M

1M

1M

1132

22

4 3

11331

21 2

2(3) 4( ) 4 2

25

6

m

n

m

n


3/7

(b) 260 22

14360 7

or 277

22

360

60 or 2

90 227

360 7 or equivalent

Area of the shaded region/Luas kawasan berlorek

= 2 2 260 22 60 22 90 22

14 7 14 7 7360 7 360 7 360 7

or equivalent

= 136.5 or1

1362

or273

2cm2 (units not important)

1M

1M

1M 6

11

(a) Q = )4(3)5(2

1

53

42

=

53

42

2

1 or

1 2

3 52 2

(b)

8

13

23

45

y

x

8

13

53

42

2

1

y

x

2

1

,3 yx

Note :3

12

x

y

only award 1 mark

1M

1M

1M

1M

1M,1M 6

12 (a) x =1, y= 12x = 3, y= 4

(b) GraphAll axis drawn with correct direction and uniform scale

7 points and 2 points* have been plot correctly(7 or 8 points have been plot correctly get 1 mark)

Smooth curve and continue without straight line and passing through the

correct 8 points for3 x 4.(c) (i) 10 9y

(ii) 0.5 0.4x (d) Identify equationy = 5x5

Straight line y = 5x5 correctly drawn

x =0.4 x 0.5 , x =3.75 x 3.85

1M1M

1M

2M

1M

1M

1M1M1M

1M, 1M 12

13 (a) (i) (4, 9)

(ii) (4, 9) (4, 3)(b)(i)(a) U = Rotation, 900 clockwise, about centre (2, 4)

Note : 1. Rotation, 900 clockwise, get 2 marks

2. Rotation, about centre (2, 4), get 2 marks3. Rotation, get 1 mark

(b) W = Enlargement, with centre (7, 4) , of scale factor 2Note : 1. Enlargement, with centre (7, 4), get 2 marks

2. Enlargement, of scale factor 2 , get 2 marks

3. Enlargement, get 1 mark

(ii)22 A

22 120A A or equivalentA = 40 m

2(units not important)

1M

1M, 1M3M

3M

1M

1M1M 12


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14 (a) (i) 12(ii) I II III

Column I (All Correct)Column II (All Correct)Column III (All Correct)

(iii)(3 112 12 117 26 122 24 127 12 132 8 137 6 142 3 147)

94

= 126.95(b) All axis in correct direction, uniform scale, x-axis label as upper boundry

All 8 points* correctly plot.(6 or 7 points* correctly plot get 1 mark)

Ogive pass through point (109.5, 0)Smooth curve without any straight line and pass all the 8 points correctly

(c) Median = 125.5 0.5

Height(cm)

Tinggi(cm)

Midpoint

TitikTengah

Frequency

Kekerapan

CumulativeFrequency

KekerapanLonggokan

UpperBoundaries

Sempadanatas

105 109 107 0 0 109.5

110114 112 3 3 114.5

115119 117 12 15 119.5

120124 122 26 41 124.5125129 127 24 65 129.5

130134 132 x = 12 77 134.5

135139 137 8 85 139.5

140144 142 6 91 144.5

145 - 149 147 3 94 149.5

1M

1M1M1M1M

1M1M2M

1M1M1M 12

15 (a) Plan

or

The shape must be correct in quadrilateral form. All lines must be drawn in full.JG = NK > GN = KJ > JI = QK

The measurement is accurate to 0.2 cm. (one way ) and the angles at all

verticals of the rectangle are 90 1(b) (i) Viewed from A

The shape must be correct. All lines must be drawn in full.JV > VF > IH > GH > FG, UV > VZ = YU = FGCurve must be smooth

The measurement is accurate to 0.2 cm. (one way ) and the angles at all

verticals of the rectangle are 90 1

1M1M

1M

1M1M1M

1M

IHJE GF

2 cm 4 cm

5 cm

KL NMQP 5 cm

2 cm

4 cm

IH

JE

GF

KL

NM

QP

TCW

JK

Y ZSR

UX VEL

IQ

FM

HP GN

2 cm

5 cm

4 cm

3 cm

4 cm 6 cm


5/7

(i) Viewed from B

The shape must be correct in quadrilateral form. All lines must be drawn in full.

ICGF and QWNM are two parallel straight linesNote: Ignore straight line CW

C and W are joined dotted lines to shape a rectangular CFMWVM = MQ > QI = TV > IC > CT > CG = WNThe measurement is accurate to 0.2 cm. (one way ) and the angles at all

verticals of the rectangle are 90 1

1M

1M

1M1M1M 12

16 (a) R = 70o N

(b) Q(70o

S, 50oW)

(c) 60)9070( = 9600 n.m.(d)(i) 600 2 =1200 n.m.

(ii)70cos60

2600

= 58.48o or 58o 29

58.48o + 50o = 108.48oW or 108o 29W

2M

2M

2M1M

1M

2M

1M

1M 12

3 cm

2 cm

3 cm

3 cm 5 cm

T

IJ

C

ZY

VUFE

QK

MLX

NPR

W

GHS


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Graph For Question 12

-1-2-3 -4

y

x1 2 3

5

10

15

20

25

-5

-10

0

(-2, 16)

(-1, 12)

(0, 2)

(1, -8)

(2, -12)

(3.5, 4.4)

(4, 22)

(3, -4)

(-3, 8)


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Graph For Question 14

Graph for Question 14

(-3, -29)

50

10

60

40

20

30

70

80

90

100

0

UpperBoundar

124.5 129.5 139.5 144.5134.5119.5114.5109.5 149.5

Cumulative

Frequency

trial mate form 5 sgi 2013 (answer)

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