unit 3: genetics
DESCRIPTION
Unit 3: Genetics. The Cell Cycle + DNA structure/function Mitosis and Meiosis Mendelian Genetics (aka - fun with Punnett squares) DNA replication. Yesterday’s Exit Ticket. g. G. G. G. Gg. gg. g. Gg. Gg. g. Gg. gg. g. Gg. Gg. g. - PowerPoint PPT PresentationTRANSCRIPT
Unit 3: Genetics
• The Cell Cycle + DNA structure/function• Mitosis and Meiosis• Mendelian Genetics (aka - fun with Punnett squares)
• DNA replication
• Create and complete two testcross Punnet squares:
(assume G=green and g=yellow)
gg x Gg gg x GG
½ green all green½ yellow
• Why homozygous recessive for testcross?–Clear and easy determination of unknown’s genotype: 1:1 = heterozygote; all dominant = homozygote
Yesterday’s Exit Ticket
G G
g
g
Gg Gg
Gg Gg
G g
Ggg
g Gg
gg
gg
Today’s Agenda:
• Mendel and multiple characters •Exceptions to Mendel• Sex-linked traits• Gene linkage
https://www.youtube.com/watch?v=Y1PCwxUDTl8
How To Punnet Squares
Fig. 14-8
RESULTS
F1 Generation
Predictions
Hypothesis ofdependentassortment
YyRr
Hypothesis ofindependentassortment
orPredictedoffspring ofF2 generation
Sperm SpermYRYR yryr Yr
YRyR
Yr
yR
yr
YRYYRR
YYRR YyRr
YyRr
YyRr
YyRr
YyRr
YyRr
YYRr
YYRr
YyRR
YyRR
YYrr Yyrr
Yyrr
yyRR yyRr
yyRr yyrr
yyrr
Phenotypic ratio 3:1
EggsEggs
Phenotypic ratio 9:3:3:1
1/21/2
1/2
1/2
1/4
yr
1/41/4
1/41/4
1/4
1/4
1/4
1/43/4
9/163/16
3/161/16
2. Probability and genetic outcomes2. Probability and genetic outcomes
What about multiple characters? Are they inherited together or separately?
For the purposes of example, consider the following two characters:
1. Seed color:• Possible phenotypes = Yellow OR green• Yellow is dominant to green
2. Seed shape:• Possible phenotypes = Round OR wrinkled• Round is dominant to wrinkled
Fig. 14-8
EXPERIMENT
RESULTS
P Generation
F1 Generation
Predictions
Gametes
Hypothesis ofdependentassortment
YYRR yyrr
YR yr
YyRr
Hypothesis ofindependentassortment
orPredictedoffspring ofF2 generation
Sperm SpermYRYR yryr Yr
YRyR
Yr
yR
yr
YRYYRR
YYRR YyRr
YyRr
YyRr
YyRr
YyRr
YyRr
YYRr
YYRr
YyRR
YyRR
YYrr Yyrr
Yyrr
yyRR yyRr
yyRr yyrr
yyrr
Phenotypic ratio 3:1
EggsEggs
Phenotypic ratio 9:3:3:1
1/21/2
1/2
1/2
1/4
yr
1/41/4
1/41/4
1/4
1/4
1/4
1/43/4
9/163/16
3/161/16
2. Probability and genetic outcomes2. Probability and genetic outcomes
What about multiple characters? Are they inherited together or separately?
Important Vocab Note:A MONOHYBRID cross deals with one gene
e.g. Aa x Aa
A DIHYBRID cross deals with two genese.g. AaBb x AaBb
Fig. 14-8
EXPERIMENTP Generation
F1 Generation
Gametes
YYRR yyrr
YR yr
Suppose that two F1 individuals are crossed. Consider two mutually exclusive hypotheses about inheritance:
1. Strict dependent assortment = inherited allele combinations are ALWAYS preserved in the gametes an individual produces
2. Independent assortment = all possible combinations of inherited alleles of different genes are equally likely in an individual’s gametes
Fig. 14-8
EXPERIMENT
RESULTS
P Generation
F1 Generation
Gametes
Hypothesis ofdependentassortment
YYRR yyrr
YR yr
YyRr
Hypothesis ofindependentassortment
or
Predictedoffspring ofF2 generation
Sperm
SpermYR
YR
yr
yr
Yr
YR
yR
Yr
yR
yr
YRYYRR
YYRR YyRr
YyRr
YyRr
YyRr
YyRr
YyRr
YYRr
YYRr
YyRR
YyRR
YYrr Yyrr
Yyrr
yyRR yyRr
yyRr yyrr
yyrr
Phenotypic ratio 3:1
EggsEggs
Phenotypic ratio 9:3:3:1
1/21/2
1/2
1/2
1/4
yr
1/41/4
1/41/4
1/4
1/4
1/4
1/43/4
9/163/16
3/161/16
Phenotypic ratio approximately 9:3:3:1315 108 101 32
2. Probability and genetic outcomes2. Probability and genetic outcomes
Fig. 14-8
EXPERIMENT
RESULTS
P Generation
F1 Generation
Gametes
Hypothesis ofdependentassortment
YYRR yyrr
YR yr
YyRr
Hypothesis ofindependentassortment
or
Predictedoffspring ofF2 generation
Sperm
SpermYR
YR
yr
yr
Yr
YR
yR
Yr
yR
yr
YRYYRR
YYRR YyRr
YyRr
YyRr
YyRr
YyRr
YyRr
YYRr
YYRr
YyRR
YyRR
YYrr Yyrr
Yyrr
yyRR yyRr
yyRr yyrr
yyrr
Phenotypic ratio 3:1
EggsEggs
Phenotypic ratio 9:3:3:1
1/21/2
1/2
1/2
1/4
yr
1/41/4
1/41/4
1/4
1/4
1/4
1/43/4
9/163/16
3/161/16
Phenotypic ratio approximately 9:3:3:1315 108 101 32
2. Probability and genetic outcomes2. Probability and genetic outcomes
Fig. 15-2b
0.5 mm
Meiosis
Metaphase I
Anaphase I
Metaphase II
Gametes
1 4yr 1 4
Yr14 YR
3 3
F1 Generation: 2 possiblearrangements ofchromosomes
1 4yR
R
R
R
R
RR
R
R R R R
R
Y
Y
Y Y
Y
YY
Y
YY
YY
yr r
rr
r r
rr
r r r r
y
y
y
y
y
y y
yyyy
All F1 plants produceyellow-round seeds (YyRr)
1
2 2
1
LAW OF INDEPENDENTASSORTMENT Alleles of genes on nonhomologous chromosomes assort independently during gamete formation.
LAW OF SEGREGATIONThe two alleles for each gene separate during gamete formation.
LAW OF SEGREGATIONThe two alleles for each gene separate during gamete formation.
• Mendel’s “law” of independent assortment = alleles for each character segregate independently during gamete formation
• Given what YOU know about the relationship between genes and chromosomes (which Mendel did NOT), when would this “law” be violated?
2. Probability and genetic outcomes2. Probability and genetic outcomes
2. Probability and genetic outcomes2. Probability and genetic outcomes
Y
yr
R
RY
ry
Today’s Agenda:
• Mendel and multiple characters • Exceptions to Mendel• Sex-linked traits• Gene linkage
If only it were all so simple…If only it were all so simple…
The view provided by (my simplified presentation of) Mendel’s pea experiments:
• one gene one character(e.g., flower color gene color of flower)
• one allele one phenotype(e.g., P allele purple flower)
• two alleles of each gene, one completely dominant, the other recessive(e.g., P dominant to p)
• Patterns of inheritance different from those discussed so far can be caused in many ways. Just to name a few:a) Lack of complete dominance by one alleleb) A gene has more than two allelesc) A gene produces multiple phenotypesd) Multiple genes affect a single phenotypee) Environmental circumstances affect the phenotype
3. Extending the Mendelian model3. Extending the Mendelian model
To learn more about all of these, take EBIO 2070!
For now, the simplest exceptions:
1. Genes on sex chromosomes2. Gene linkage
Y
X
REMINDER:
A complete single set of human chromosomes
includes:
• 22 autosomes (non-sex chromosomes)
• 1 sex chromosome
(diploid cells have 44 autosomes and
2 sex chromosomes)
Fig. 15-5
X
Y
Humans and many other species have chromosomal sex determination
In the human system,females have two “X” chromosomes, males have one “X” and one “Y”
Fig. 15-6c
The Z-W system
76 + ZW
76 + ZZ
Other forms of chromosomal sex determination in the animal kingdom…
What consequences might sex chromosomes have for patterns of inheritance and gene expression?
22 pairs of chromosomes
+
X Y
22 pairs of chromosomes
+
X X
Who determines the sex of our offspring?
XXDiploid
Parent Cell
Gametes X X
XY
X
Dad determines a child’s sex!
Y
from female parent from male parent
allele on X chromosome(“X-linked”)
passed on to either sons or daughters with
probability ½
passed on ONLY to daughters with
probability 1
Patterns of inheritance in mammals (and other XY systems)
XAXaDiploid
Parent Cell
Gametes XA Xa
XAY
XA Y
from female parent from male parent
allele on Y chromosome(“Y-linked”)
typically not possessed by females
passed on ONLY to sons with probability 1
Patterns of inheritance in mammals (and other XY systems)
XXDiploid
Parent Cell
Gametes X X
XYA
X YA
Dad is who determines a child’s sex
expression in females expression in males
dominant X-linked allele yes yes
recessive X-linked allele
ONLY if present with other recessive allele yes
Y-linked allele never present(never expressed) yes
Patterns of gene expression in mammals (and other XY systems)
Male-pattern baldnessSRY gene:
Testes formation
Santhi’s Story
http://www.ibnlive.com/videos/28851/how-are-athletes-gender-tested.html
Santhi Soundarajan won the silver medal in the 800-meter race at the 2006 Asian Games in Doha, Qatar.
Following her silver medal performance, she was stripped of her medal.
Santhi has female genitalia but her genotype is XY.
Speakequal.com
expression in females expression in males
dominant X-linked allele yes yes
recessive X-linked allele
ONLY if present with other recessive allele yes
Y-linked allele never present(never expressed) yes
Patterns of gene expression in mammals (and other XY systems)
• Breeding fruit flies (Drosophila melanogaster)
– Rapid breeders
– Males = XY; Females = XX
– For Drosphila:recessive alleles = “mutant” (b)dominant alleles = “wild type” (b+)
Genes on chromosomesGenes on chromosomesb) Sex-linked traitsb) Sex-linked traits
News.wisc.edu
Fig. 15-3
One of Morgan’s experiments (think back to Mendel’s peas):• Character: eye color• Phenotypes: red or white
Is the allele for white eyes dominant or recessive?
P Generation(true breeding)
F1 Generation All offspring had red eyes
Then, cross the F1 offspring with each other, and what does the F2 generation look like?
3:1 ratio of red : white
2:1:1 ratio of red female : red male : white male
3:1 ratio of red : white
2:1:1 ratio of red female : red male : white male
The best explanation for the pattern of inheritance seen in the F2 generation is:
a)The eye color gene is on an autosomeb)The eye color gene is sex-linked, on the X chromosomec)The eye color gene is sex-linked, on the Y chromosomed)There is not enough information to discriminate between hypotheses (a) through (c)
Fig. 15-4c
EggsF1
CONCLUSION
Generation
Generation
P XX
r
Sperm
XY
EggsSperm
GenerationF2
R
r
r
RR
r
R
R
RR
r
R
R
rr
Genes on chrom
osomes
Genes on chrom
osomes
b) Original discoveries
b) Original discoveries
r
All females XRXr All males XRY
Fig. 15-4c
EggsF1
CONCLUSION
Generation
Generation
P XX
r
Sperm
XY
EggsSperm
GenerationF2
R
r
r
RR
r
R
R
RR
r
R
R
rr
Genes on chrom
osomes
Genes on chrom
osomes
b) Original discoveries
b) Original discoveries
r
All females XRXr All males XRY
Females all red: ½ XRXr
½ XRXR
Males half red (XRY) and half white (XrY)
For now, the simplest exceptions:
1. Genes on sex chromosomes2. Gene linkage
Y
X
https://www.youtube.com/watch?v=-_UcDhzjOio
Gene Linkage and Fruit Flies
Fig. 15-2b
Meiosis
Metaphase I
Anaphase I
Metaphase II
1 4Yr
3
1 4yR
R
R
R
R R
R
Y
Y
YY
Y
Y
yr
r
r
r
r r
y
y
y
yy
All F1 plants produceyellow-round seeds (YyRr)
2
1
LAW OF INDEPENDENTASSORTMENT Alleles of genes on nonhomologous chromosomes assort independently during gamete formation.
Fig. 14-8
F1 Generation
Hypothesis ofdependentassortment
YyRr
Hypothesis ofindependentassortment
or
Predictedoffspring ofF2 generation
Sperm
SpermYR
YR
yr
yr
Yr
YR
yR
Yr
yR
yr
YRYYRR
YYRR YyRr
YyRr
YyRr
YyRr
YyRr
YyRr
YYRr
YYRr
YyRR
YyRR
YYrr Yyrr
Yyrr
yyRR yyRr
yyRr yyrr
yyrr
Phenotypic ratio 3:1
EggsEggs
Phenotypic ratio 9:3:3:1
1/21/2
1/2
1/2
1/4
yr
1/41/4
1/41/4
1/4
1/4
1/4
1/43/4
9/163/16
3/161/16
In crosses involving two characters, sometimes you get outcomes that were intermediate between
these two hypotheses.
• Morgan crossed flies to study the characters of body color and wing size Genes for both are located on autosomes
Example
Fig. 15-9-1
EXPERIMENT P Generation (homozygous)
Wild type(gray body,normal wings)
Double mutant(black body,vestigial wings)
b b vg vg b+ b+ vg+ vg+
F1 generation
?
Fig. 14-8
F1 dihybrid(wild type phenotype)
b+ b vg+ vg
Hypothesis ofdependentassortment
Hypothesis ofindependentassortment
xF1 dihybrid
(wild type phenotype)
b+ b vg+ vg
3 : 1 9 : 3 : 3 : 1
Observed (approx.): 8 : 2 : 2 : 4
b+b?v+v? bbvv b+b?v+v? b+b?vv bbv+v? bbvv
• Each chromosome has hundreds or thousands of genes• Genes located on the same chromosome that tend to be inherited
together are called linked genes
• Occasional crossing over leads to occasional, but not common, recombinant chromosomes
Why would some genes be inherited neither completely together nor completely independently?
Gene linkage
Prophase Iof meiosis
Pair ofhomologs
Nonsisterchromatidsheld togetherduring synapsis
Chiasma
Centromere
Anaphase I
crossing over Sources of genetic variation
Recombination of Linked Genes: Crossing Over
Crossing over during Prophase I of meiosis is the mechanism for recombining alleles Crossing over during Prophase I of meiosis is the mechanism for recombining alleles
Fig. 15-UN1
b+ vg+
Parents in testcross
Most offspring
b+ vg+
b vg
b vg
b vg
b vg
b vg
b vg
or
Gene linkage
Fig. 15-10b
Testcrossoffspring
965Wild type
(gray-normal)
944Black-
vestigial
206Gray-
vestigial
185Black-normal
b+ vg+
b vg b vg
b vg b+ vg
b vg
b vg
b+ vg+
Spermb vg
Parental-type offspring Recombinant offspring
b vg
b+ vg b vg+
b vg+
Eggs
Recombinantchromosomes
3. Gene linkage
5 : 5 : 1 : 1
An x-linked recessive allele b produces red-green color blindness in humans. A normal-sighted woman whose father was color-blind marries a color-blind man.
1.What genotypes are possible for the mother of the colorblind man?
1.What are the chances that the first child from this marriage will be a color-blind boy?
1.Of the girls produced by these parents, what proportion can be expected to be color-blind?
1.Of all the children (sex unspecified) of these parents, what proportion can be expected to have normal color vision?
Today’s Exit Ticket