v1+g level+fybch16 19,+20+nvco08+electricity+and+magnetism+published

8/3/2019 V1+G Level+FyBCh16 19,+20+NVCO08+Electricity+and+Magnetism+Published

http://slidepdf.com/reader/full/v1g-levelfybch16-1920nvco08electricityandmagnetismpublished 1/9

FyBCh16-19-20NVC08 Electricity and Magnetic Field NV-College

Physics B: FyBNVC08G-level test on Electricity and Magnetism Ch 16-19 & Ch 20

Instructions:

The Test Warning! There are more than one version of the test.

At the end of each problem a maximum point which one may get for a correct solution

of the problem is given.

Tools Approved formula sheets, ruler, and graphic calculator. You may use your green

personalized summary-formula-booklet which has your name on it. This should be

submitted along with the test.

Time: 8:00-10:00

The multi-choice problems must be answered on the original test paper.

Limits: This tests gives at maximum 36 points.

Pass (G): minimum 18 points

Qualified For a higher than G: minimum 24 points.

VG/MVG Qualified in this test, and filling the requirements in the

higher level test.

Please answer in this paper and as clear as possible. Do not forget the UNITS!Enjoy it! Behzad

Name:

16-20 E PE C C E, B B C, E C, V C RC C, Q

P 1 2 3 4 5 6 7a 7b 7c 7d 7e Sum

G 2 1 2 2 2 2 1 2 2 2 2 20

G

16-20 B, τ B, I Q, B Q, B Q, B FB FB FB FB Ch 16-20

P 8 9 10 11a 11b 11c 11d 11e 11f Total

G 1 3 2 2 2 2 2 2 2 38

G

Grade:

Teacher’s Comments

Student’s Comments

© [email protected] ☺Free to use for educational purposes. Not for sale. 1/9




4. Doubling the distance between the plates of a parallel plate capacitor of capacitance C

changes its capacitance to

4. Doubling the distance between the plates of a parallel plate capacitor of capacitance C

changes its capacitance to

a) C 4 a) C 4

b) C 2 b) C 2

c)

c)

2

C

d) 4

C

Answer: Alternative:______________ [1/0]

Why? Explain. [1/0]

5. A moving electric charge produces

a) only an electric field.

b) only a magnetic field.

c) both an electric field and a magnetic field.

d) sometimes an electric field and sometimes a magnetic depending the direction of

its velocity.

Answer: Alternative ______________ [1/0]

6. A proton enters a magnetic field parallel to B .

a) The proton’s velocity remains the same, but its direction of motion is changed.

b) Both proton’s velocity and its direction of motion remain the same.

c) The proton’s velocity is changed, but its direction of motion remains the same.d) Both proton’s velocity and its direction of motion are changed.


Why? Explain. [1/0]






7. A parallel plate capacitor, a resistor and a battery are connected as illustrated in the

figure below. The two parallel plates of the capacitor are

7. A parallel plate capacitor, a resistor and a battery are connected as illustrated in the

figure below. The two parallel plates of the capacitor are mm500.0 apart. The plates

are connected through a Ω M .100 resistor to a battery. When the plates are fully

charged, the electric field between the plates is mkV / ..200

a) Draw the electric filed lines as clear as possible on the figure. [1/0]

b) The electric potential difference between the plates is:

i) kV 0.10

ii) kV 00.1

iii) kV 100.0

iv) V 0.10 v) None above it is: ______________


Why? Show your calculations in the space available below. [1/0]

c) If the parallel capacitor has an area of 2

00. and a plate separation of 5 cmmm500.0 . Its capacitance is:

i. pF 85. 8

ii. nF 85. 8

iii. F 85. 8

iv. None. It is: _____________



R





d) The time constant of the circuit isd) The time constant of the circuit is

i) 885 i) 885 ms.0

885

ms.0

ms885

.0

ii) . ii) . ms

iii) s.885 iii) s.885

iv) None. It is: _____________ iv) None. It is: _____________ Answer: Alternative:______________ [1/0]Answer: Alternative:______________ [1/0]

Why? Show your calculations in the space available below. [1/0]Why? Show your calculations in the space available below. [1/0]

e) The total charge on the positive plate of the capacitor, when the capacitor is fullycharged is

e) The total charge on the positive plate of the capacitor, when the capacitor is fullycharged is

i) nC 885 i) nC 885 .0

ii) nC 885 ii) nC 885

iii) C iii) C 5.88

iv) pC 85. 8

v) mC 85. 8

vi) None. It is: _____________



8. The physical reason for the electric motor isa) the torque exerted on a current loop by an electric field.

b) the torque exerted on a current loop by an electromagnetic field.

c) the torque exerted on a current loop by a magnetic field.

d) the torque exerted on a current loop by first an electric field and then a magnetic

field.

e) the torque exerted on a moving charge by a magnetic field.

f) the torque exerted on a moving charge by an electric field.





9. A straight wire carrying a9. A straight wire carrying a A0.25 current has a

length cm0.10 between the poles of a magnet at

an angle °.30 as illustrated in the figure below.

The magnetic field is fairly uniform at T 00.4 .

The magnitude and direction of the force on thewire.°.30

A0.25

T 00.4

i) N .500 out of the page of the paper towards

the reader.

ii) N 00.5 out of the page of the paper towards the reader.

iii) N 00.5 into the page of the paper away from the reader.

iv) N .500 into the page of the paper away from the reader.

v) None. It is: _____________



10. A charged particle moves in a circular path of radius r in a magnetic field B . The

velocity of the charged particle is doubled. The radius of the circular path of the charged

particle will be

a) r 4

b) r 2

c) r

d) 2

r

e) 4

r

Answer: Alternative:______________ [1/0]Why? Explain. [1/0]





11. An electron is shot into the region between the poles of a magnet. The initial velocity of

the electron is

11. An electron is shot into the region between the poles of a magnet. The initial velocity of

the electron is sm /1000.3 6× perpendicular to

the direction of the magnetic field. The magnetic

field is uniform and its magnitude is

T 400.0 as illustrated in the figure.

Data: C eQ 191060.1 −×−=−= ,

kgme

311011.9 −×=

C eQ19106.1 −

×−=−=

T B 40.0=

smv /100.3 6⋅=

a) The electron will

i) move straight and will not be deflected

by the magnetic field.

ii) will be deflected toward the left.

iii) will be effected toward the right.

iv) will be effected into the page.

v) will be effected out of the page.

vi) None above.


Why? Explain in a sufficient detail. [1/0]

b) The magnitude of the magnetic force on the electron is:

i) N 19 1092.1 −

×

ii) N 14102.1 −×

iii) N 13 1092.1 −

×

iv) J 13

10 92.1 −×

v) None. It is __________


Why? Explain and show your calculations in the space available below. [1/0]






c) The electron in the uniform magnetic field will:c) The electron in the uniform magnetic field will:

i) experience a centripetal acceleration, and as a result it will rotate in a circular

path of radius m.42

i) experience a centripetal acceleration, and as a result it will rotate in a circular

path of radius m.42 7

ii) experience a centripetal acceleration, and as a result it will rotate in a circular

path of radius cm7


path of radius cm7 .42

iii) experience a centripetal acceleration, and as a result it will rotate in a circular

path of radius mm.


path of radius mm. 742

7

.42

742

iv) experience a centripetal acceleration, and as a result it will rotate in a circular

path of radius m


path of radius m7.42

v) None above. See the calculation below.



d) If the polarity of the magnet is reversed, i.e. if the direction of the magnetic field is

changed,

i)

the magnitude and the direction of the force remains the same.ii) the magnitude of the force remains the same, but the direction of the force is

reversed.

iii) the magnitude of the force is reversed, but the direction of the force remains

the same.

iv) the magnitude of the force decreases, and the direction of the force is reversed.

v) the magnitude of the force increases, and the direction of the force is reversed.

vi) None above. It is ____________________________________







e) If the electron is replaced by an alpha-particle, i.e. the nucleus of Helium, with the

charge e2+

e) If the electron is replaced by an alpha-particle, i.e. the nucleus of Helium, with the

charge e2+QQ =α

, and mass kgm 271065.6 −×=

α , keeping everything else the

same, compare the magnitude and the direction of the force on the electron, to the

magnitude and the direction of the force on the on the proton

i) the magnitude and the direction of the force remains the same.

ii) the magnitude of the force is doubled, but the direction of the force remains thesame.

iii) the magnitude of the force is doubled, while the direction of the force is

reversed.

iv) the magnitude of the force is decreased by a factor of two, but the direction of

the force remains the same.

v) the magnitude of the force is decreased by a factor of two, while the direction

of the force is reversed.

vi) None above. It is _________________________________


Why? Explain. [1/0]

f) The α -particle in the uniform magnetic field will:i) experience a centripetal acceleration, and as a result it will rotate in a circular

path of radius m 6.15


path of radius cm6.15


path of radius mm6.15


path of radius m6.15

v) None above. See the calculation below.



v1+g level+fybch16 19,+20+nvco08+electricity+and+magnetism+published

Documents