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1010100 10001111100 1011100101011100 101100011101001 1011110100011010 00001010010110010 1001010101100111 1111010101000101 1101001101010011 001010010101010 1010101000110010 010101001011000 110101100011010 11010100001011 001010100110 1001010010 01.0 172.16.1.0 192.168.10.0 010 10.250.1.0 172.31.15.0 192.168.10.96 192.168.10.126 VLSM Workbook Variable-Length Subnet Mask Version 1.1 Student Name:

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101010010001111100

1011100101011100101100011101001101111010001101000001010010110010100101010110011111110101010001011101001101010011001010010101010101010100011001001010100101100011010110001101011010100001011001010100110100101001001.0172.16.1.0 192.168.10.0

010

10.250.1.0172.31.15.0

192.168.10.96

192.168.10.126

Version 1.0

VLSMWorkbook

Variable-Length Subnet Mask

Version 1.1

Student Name:

IP Address Classes

Class A 1 – 127 (Network 127 is reserved for loopback and internal testing)Leading bit pattern 0 00000000.00000000.00000000.00000000

Class B 128 – 191 Leading bit pattern 10 10000000.00000000.00000000.00000000

Class C 192 – 223 Leading bit pattern 110 11000000.00000000.00000000.00000000

Class D 224 – 239 (Reserved for multicast)

Class E 240 – 255 (Reserved for experimental, used for research)

Private Address Space

Class A 10.0.0.0 to 10.255.255.255

Class B 172.16.0.0 to 172.31.255.255

Class C 192.168.0.0 to 192.168.255.255

Default Subnet Masks

Class A 255.0.0.0

Class B 255.255.0.0

Class C 255.255.255.0

Network . Host . Host . Host

Network . Network . Host . Host

Network . Network . Network . Host

Inside Cover

This workbook assumes you already have a background in subnetting. If you don’t you maywant to consider completing the IP Addressing and Subnetting Workbook.

Produced by: Robb [email protected] and/or [email protected]

Frederick County Career & Technology CenterCisco Networking Academy

Frederick County Public SchoolsFrederick, Maryland, USA

Special Thanks to Melvin Baker and Jim Dorschfor taking the time to check this workbook for errors.

Workbooks included in the series:

IP Addressing and Subnetting WorkbooksACLs - Access Lists Workbooks

VLSM Variable-Length Subnet Mask IWorkbooks

Classful vs. ClasslessSubnetting

When you’re subnetting an IP address for a network you have twooptions: classful and classless. Classful subnetting is the simplest method.It tends to be the most wasteful because it uses more addresses than arenecessary. In classful subnetting you use the same subnet mask for eachsubnet, and all the subnets have the same number of addresses in them.

Classless addressing allows you to use different subnet masks andcreate subnets tailored to the number of users in each group. This techniqueis referred to as VLSM.

What is VLSM

Variable Length Subnet Masks allow you a much tighter control overyour addressing scheme. If you use a class C address with a default subnetmask you end up with one subnet containing 256 addresses. By using VLSMyou can adjust the number of subnets and number of addresses dependingon the specific needs of your network. The same rules apply to a class A orB addresses.

VLSM is supported by the following protocols: RIP version 2, OSPF,EIGRP, Dual IS-IS, and BGP,. You need to configure your router for VariableLength Subnet Masking by setting up one of these protocols. Then configurethe subnet masks of the various interfaces in the IP address interface sub-command.

Benefits of VLSM

Allows efficient use of address spaceAllows the use of multiple subnet mask lengthsBreaks up an address block into smaller custom blocksAllows for route summarizationProvides more flexibility in network designSupports hierarchical enterprise networks

This workbook explores three different methods to figure out sub-subnets:the box method, the circle method, and a VLSM chart.

1

Classful SubnettingExample

When you’re subnetting an IP address for a network you have twooptions: classful and classless. Classful subnetting is the simplest method.It also tends to be the most wasteful because it uses more addresses thanare necessary. In classful subnetting you use the same subnet mask foreach subnet, and all the subnets have the same number of addresses inthem.

In this example you need five subnets, each one containing 30 hosts.The serial connections only require two address each so you are wasting 28usable addresses in each of the serial subnet ranges.

192.168.1.0192.168.1.32192.168.1.64192.168.1.96192.168.1.128192.168.1.160192.168.1.192192.168.1.224

192.168.1.31192.168.1.63192.168.1.95192.168.1.127192.168.1.159192.168.1.191192.168.1.223192.168.1.255

totototototototo

/27255.255.255.224

32 Hosts8 Subnets

Marketing25 Hosts Records

12 Hosts

Research30 Hosts

IP Address: 192.168.1.0

0

255

128

6364 192

191

32

31

95

96159

223

224

160

127

The Box Methodfor visualizing subnets

/27/27/27/27/27/27/27/27

2

Classful Subnet Ranges

Classless SubnettingExample

Classless addressing allows you to use different subnet masksand create subnets tailored to the number of users in each subnetwork.There are fewer wasted IP addresses using smaller subnets.

In this example you need at total of five subnets, two containing 30hosts, one containing 12 hosts, and two serial connections that only requiretwo addresses each.

By adjusting the subnet masks you can cut your address usage byalmost half in this example. This type of subnetting requires a networkprotocol which will support it such as: RIP version 2, EIGRP, OSPF, or BGP.

Marketing25 Hosts Records

12 Hosts

Research30 Hosts

IP Address: 192.168.1.0

0

255

79

128

6364

32

3196

83

87

80

184

12795

88

192.168.1.0192.168.1.32192.168.1.64192.168.1.80192.168.1.84192.168.1.88192.168.1.96192.168.1.128

192.168.1.31192.168.1.63192.168.1.79192.168.1.82192.168.1.87192.168.1.95192.168.1.127192.168.1.255

totototototototo

/27/27/28/30/30/29/27/25

3

The Box Methodfor visualizing subnets

Classless Subnet Ranges

/24255.255.255.0

256 Hosts1 Subnet

Start with a square. The whole squareis a single subnet comprised of 256addresses.

Visualizing Subnets UsingThe Box Method

The box method is a simple way to visualize the breakdown of subnetsand addresses into smaller sizes. By shading or coloring in the boxes youcan easily break up your subnets without overlapping your addresses. Youadjust each subnet to the correct size needed.

/25255.255.255.128

128 Hosts2 Subnets

/26255.255.255.192

64 Hosts4 Subnets

4

Split the box in half and you get twosubnets with 128 addresses.

Divide the box into quarters and youget four subnets with 64 addresses.

5

/27255.255.255.224

32 Hosts8 Subnets

Split each individual square and youget eight subnets with 32 addresses.

/30255.255.255.252

4 Hosts64 Subnets

/29255.255.255.248

8 Hosts32 Subnets

/28255.255.255.240

16 Hosts16 Subnets

Split the boxes in half again and youget sixteen subnets with sixteenaddresses.

The next split gives you thirty twosubnets with eight addresses.

The last split gives sixty four subnetswith four addresses each.

Color in the squares used with differentshades to highlight each subnet.

VLSM AddressingBox Method

(Sample)

Problem 1Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the boxes below, color or shade the sub-subnets used inthe box. This business will be using the class C address 220.10.10.0. Re-member to start with your largest groups first.

MarketingDepartment

60 Hosts

LAN Address:

220.10.10.0/26

ResearchDepartment

28 Hosts

LAN Address:

220.10.10.64/27

0

255127

128

6364

95

96

6

VLSM AddressingBox Method

(Sample)

Problem 2Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the boxes below, color or shade the sub-subnets used inthe box. This company will be using the class C address 192.168.16.0. Re-member to start with your largest groups first.

Washington D.C.120 Hosts

Frederick20 Hosts

Baltimore60 Hosts

0

255127

128

192191

223

LAN Address:

192.168.16.0/25

LAN Address:

192.168.16.192/27LAN Address:

192.168.16.128/26

WAN Address #1:

192.168.16.224/30 WAN Address #2:

192.168.16.228/30

227

239231

224 232

228

240

Color in the squares used with differentshades to highlight each subnet.

7

8

VLSM AddressingBox Method

Problem 3Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the boxes below, color or shade the sub-subnets used inthe box. This company will be using the class C address 190.10.10.0. Re-member to start with your largest groups first.

Dallas60 Hosts

Ft. Worth25 Hosts

LAN Address:

LAN Address:

WAN Address #1:

Color in the squares used with differentshades to highlight each subnet.

0

255

128

6364

95

96

99

103 111

127

104

100

112

VLSM AddressingBox Method

Problem 4Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the boxes below, color or shade the sub-subnets used inthe box. This company will be using the class C address 220.108.38.0. Re-member to start with your largest groups first.

Corpus Christi25 Hosts

Waco50 Hosts

Houston120 Hosts

LAN Address:

LAN Address:LAN Address:

WAN Address #1:WAN Address #2:

Color in the squares used with differentshades to highlight each subnet.

9

0 12832 160

15 4739 175167135 1437

11 4335 171163131 1393

27 5951 187179147 15519

31 6355 191183151 15923

75 10799 235227195 20367

79 111103 239231199 20771

91 123115 251243211 21983

95 127119 255247215 22387

408 136 168

4 13236 1644412 140 172

16 14448 1765624 152 184

20 14852 1806028 156 188

64 19296 22410472 200 232

68 196100 22810876 204 236

80 208112 24012088 216 248

84 212116 24412492 220 252

10

VLSM AddressingBox Method

Problem 5Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the boxes below, color or shade the sub-subnets usedin the box. This company will be using the class C address 192.168.10.0.Remember to start with your largest groups first.

New York115 Hosts

Fargo23 Hosts

LAN Address:

LAN Address:

WAN Address #2:

Color in the squares used with differentshades to highlight each subnet.

San Jose

12 Hosts

48 Hosts

LAN Address:

LAN Address:

WAN Address #1:

0 12832 160

15 4739 175167135 1437

11 4335 171163131 1393

27 5951 187179147 15519

31 6355 191183151 15923

75 10799 235227195 20367

79 111103 239231199 20771

91 123115 251243211 21983

95 127119 255247215 22387

408 136 168

4 13236 1644412 140 172

16 14448 1765624 152 184

20 14852 1806028 156 188

64 19296 22410472 200 232

68 196100 22810876 204 236

80 208112 24012088 216 248

84 212116 24412492 220 252

VLSM AddressingBox Method

Problem 6Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the boxes below, color or shade the sub-subnets usedin the box. This company will be using the class C address 222.10.150.0.Remember to start with your largest groups first.

Boston

LAN Address:

WAN Address #1:

Draw the necessary lines and color in the used squareswith different shades to highlight each subnet.

11

London

WAN Address #2:

6 Hosts

12 Hosts

LAN Address:

24 Hosts 37 Hosts

LAN Address:

LAN Address:

0

255

128

6364 192

191

32

31

95

96159

223

224

160

127

Toyko

12

VLSM AddressingBox Method

Problem 7Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and subnet mask in the boxes below, color or shade the sub-subnetsused in the box. This company will be using the class C address 200.150.70.0.Remember to start with your largest groups first.

Draw the necessary lines and color in the used squareswith different shades to highlight each subnet.

Boston 2

LAN Address:

6 Hosts

12 Hosts

LAN Address:

LAN Address:

14 Hosts

LAN Address:

25 Hosts

0

255127

128

6364 192

191

Serial Address:

Boston 1

VLSM AddressingBox Method

Problem 8Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and subnet mask in the boxes below, color or shade the sub-subnetsused in the box. This company will be using the class C address 192.168.24.0.Remember to start with your largest groups first.

LAN Address:

Draw the necessary lines and color in the used squareswith different shades to highlight each subnet.

13

London

WAN Address #2:

18 Hosts

LAN Address:

95 Hosts 12 Hosts

LAN Address:

LAN Address:

0

34 Hosts

255

WAN Address #1:

Paris

New York

/24255.255.255.0

256 Hosts1 Subnet

Start with a circle. The whole circle isa single subnet comprised of 256addresses.

Visualizing Subnets UsingThe Circle Method

The circle method is another method used to visualize the breakdownof subnets and addresses into smaller sizes. By shading or coloring in thedifferent sections of the circle you can easily break up your subnets withoutoverlapping your addresses. You adjust each subnet to the correct sizeneeded.

/25255.255.255.128

128 Hosts2 Subnets

/26255.255.255.192

64 Hosts4 Subnets

Split the circle in half and you get twosubnets with 128 addresses.

Divide the circle into quarters andyou get four subnets with 64addresses.

.0

.127.128

.255

.0

.127.128

.255

.63

.64.191.192

14

/27255.255.255.224

32 Hosts8 Subnets

Split each quarter and you get eightsubnets with 32 addresses.

/30255.255.255.252

4 Hosts64 Subnets

/29255.255.255.248

8 Hosts32 Subnets

/28255.255.255.240

16 Hosts16 Subnets

Split the boxes in half again and youget sixteen subnets with sixteenaddresses.

The next split gives you thirty twosubnets with eight addresses.

The last split gives sixty four subnetswith four addresses each.

.0

.127.128

.255

.63

.64.191.192

.31.32

.95.96.159

.160

.223.224

.0

.31

.15.16

.64

.63

.48.47

.32

.111

.96.95

.80.79

.112.127

.176

.224

.223

.192

.208

.207

.191

.175

.159

.143

.160

.144

.128

.255

.239.240

15

.0 -

.7

.24

- .31.8

- .1

5.1

6 - .

23

.64 - .71

.56 - .63

.48 - .55.40 - .4

7.32 -

.39

.104 - .111.96 - .103

.88 - .95

.80 - .87

.72 - .79

.112 - .119

.120 - .127

.176 - .183

.224

- .23

1

.216 - .223

.192 - .199

.208 - .215

.200 - .207

.184 - .191

.168. - 175

.152 - .159

.136 - .143

.160 - .167 .144 - .151

.128 - .135

.248

- .2

55

.232

- .2

39

.240

- .2

47

.0 -

.3

.24 -

.27

.8 -

.11

.16

- .19

.64 - .67

.56 - .59

.48 - .51

.40 - .43

.32 -

.35

.104 - .107.96 - .99

.88 - .91

.80 - .83

.72 - .75

.112 - .115

.120 - .123.176 - .179

.224

- .22

7

.216 - .219

.192 - .195

.208 - .211

.200 - .203

.184 - .187

.168. - 171

.152 - .155 .136 - .139

.160 - .163

.144 - .147

.128 - .131

.248

- .2

51

.232

- .2

35

.240

- .2

43 .4 -

.7

.12

- .15

.20

- .23

.28 -

.31

.36 - .39

.44 - .47

.52 - .55

.60 - .63

.68 - .71

.76 - .79

.84 - .87.92 - .95

.100 - .103

.108 - .111

.116 - .119

.124 - .127

.132 - .135

.140 - .143

.148 - .151.156 - .159

.164 - .167

.172. - 175

.180 - .183

.188 - .191

.196 - .199

.204 - .207.212 - .2

15.22

0 - .2

23 .228

- .23

1

.236

- .2

39

.244

- .2

47

.252

- .2

55

16

Color in the necessary circle sections used with differentshades to highlight each subnet.

VLSM AddressingCircle Method

(Sample)

Problem 9Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the circle below, color or shade the sub-subnets used.This business will be using the class C address 220.10.10.0.Remember to start with your largest groups first.

MarketingDepartment

60 Hosts

LAN Address:

220.10.10.0/26

ResearchDepartment

28 Hosts

LAN Address:

220.10.10.64/27

.0.255

.127.128

.96

.63

.95

.64

17

VLSM AddressingCircle Method

(Sample)

Problem 10Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the circle below, color or shade the sub-subnets used.This company will be using the class C address 192.168.16.0.Remember to start with your largest groups first.

Washington D.C.120 Hosts

Frederick20 Hosts

Baltimore60 Hosts

LAN Address:

192.168.16.0/25

LAN Address:

192.168.16.192/27LAN Address:

192.168.16.128/26

WAN Address #1:

192.168.16.224/30 WAN Address #2:

192.168.16.228/30

Color in the necessary circle sections used with differentshades to highlight each subnet.

.255.240

.232

- .2

39

.0

.127

.191

.128

.223

.192

.224 -

.227

.228

- .23

1

.0

18

Color in the necessary circle sections used with differentshades to highlight each subnet.

VLSM AddressingCircle Method

Problem 11Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the circle below, color or shade the sub-subnets used.This business will be using the class C address 200.20.20.0.Remember to start with your largest groups first.

MarketingDepartment

50 Hosts

LAN Address:

Department25 Hosts

LAN Address:

MarketingDepartment100 Hosts

LAN Address:

.224

.255

.127

.191

.128

.223

.192

19

VLSM AddressingCircle Method

Problem 12Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the circle below, color or shade the sub-subnets used.This company will be using the class C address 199.55.70.0.Remember to start with your largest groups first.

Color in the necessary circle sections used with differentshades to highlight each subnet.

LAN Address:

New York

21 Hosts

LAN Address:

115 Hosts 8 Hosts

LAN Address:

LAN Address:

12 Hosts

WAN Address #1:

Boston.0

- .3

.24

- .27

.8 -

.11

.16

- .19

.64 - .67

.56 - .59

.48 - .51

.40 - .43.32

- .35

.104 - .107.96 - .99

.88 - .91

.80 - .83

.72 - .75

.112 - .115

.120 - .123

.176 - .179

.224 -

.227

.216 - .219

.192 - .195

.208 - .211

.200 - .203

.184 - .187

.168. - 171

.152 - .155

.136 - .139

.160 - .163 .144 - .147

.128 - .131

.248

- .2

51

.232

- .23

5

.240

- .2

43

.4 -

.7

.12

- .15

.20

- .23

.28 -

.31

.36 - .39

.44 - .47

.52 - .55

.60 - .63

.68 - .71

.76 - .79.84 - .87.92 - .95

.100 - .103

.108 - .111

.116 - .119

.124 - .127

.132 - .135

.140 - .143.148 - .151

.156 - .159

.164 - .167

.172. - 175

.180 - .183

.188 - .191

.196 - .199

.204 - .207.212 - .2

15 .220 -

.223 .2

28 - .

231

.236

- .2

39

.244

- .2

47

.252

- .2

55

20

VLSM AddressingCircle Method

Problem 13Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the circle below, color or shade the sub-subnets used.This company will be using the class C address 200.150.70.0.Remember to start with your largest groups first.

New Delhi

LAN Address:

22 Hosts

5 Hosts

LAN Address:

LAN Address:

7 Hosts

LAN Address:

35 Hosts

Serial Address:

Mumbai

12HostsLAN Address:

Color in the necessary circle sections used with differentshades to highlight each subnet.

.0 -

.3

.24

- .27

.8 -

.11

.16

- .19

.64 - .67

.56 - .59

.48 - .51

.40 - .43.32

- .35

.104 - .107.96 - .99

.88 - .91

.80 - .83

.72 - .75

.112 - .115

.120 - .123

.176 - .179

.224 -

.227

.216 - .219

.192 - .195

.208 - .211

.200 - .203

.184 - .187

.168. - 171

.152 - .155

.136 - .139

.160 - .163 .144 - .147

.128 - .131

.248

- .2

51

.232

- .23

5

.240

- .2

43

.4 -

.7

.12

- .15

.20

- .23

.28 -

.31

.36 - .39

.44 - .47

.52 - .55

.60 - .63

.68 - .71

.76 - .79.84 - .87.92 - .95

.100 - .103

.108 - .111

.116 - .119

.124 - .127

.132 - .135

.140 - .143.148 - .151

.156 - .159

.164 - .167

.172. - 175

.180 - .183

.188 - .191

.196 - .199

.204 - .207.212 - .2

15 .220 -

.223 .2

28 - .

231

.236

- .2

39

.244

- .2

47

.252

- .2

55

21

VLSM AddressingCircle Method

Problem 14Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the circle below, color or shade the sub-subnets used.This company will be using the class C address 210.10.10.0.Remember to start with your largest groups first.LAN Address:

Hong Kong

WAN Address #2:

18 Hosts

LAN Address:

95 Hosts 12 Hosts

LAN Address:

LAN Address:

27 Hosts

WAN Address #1:

Shanghai

Beijing

18 Hosts

Draw the necessary lines and color in the used circle sectionswith different shades to highlight each subnet.

.0

.127

.191

.128

.223

.192

.224 .31.32

.63

.64

.95

.96.159

.160

.255

22

VLSM AddressingCircle Method

Problem 15Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the boxes below, color or shade the sub-subnets usedin the circle. This company will be using the class C address 192.168.150.0.Remember to start with your largest groups first.

Vienna15 Hosts

Frankfurt30 Hosts

LAN Address:

LAN Address:

WAN Address #2:

Prague

12 Hosts

48 Hosts

LAN Address:

WAN Address #1:

Draw the necessary lines andcolor in the used circle sectionswith different shades to highlighteach subnet.

Venice 23 Hosts

48 Hosts

LAN Address:

WAN Address #3:LAN Address:

.0

.127

.191

.128

.192 .63.64

.255

23

VLSM AddressingCircle Method

Problem 16Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the boxes below, color or shade the sub-subnets usedin the circle. This company will be using the class C address 195.75.23.0.Remember to start with your largest groups first.

San Juan

LAN Address:

WAN Address #1:

Draw the necessary lines andcolor in the used circle sectionswith different shades to highlighteach subnet.

Kingston

WAN Address #2:

6 Hosts

12 Hosts

LAN Address:

24 Hosts 37 Hosts

LAN Address:

LAN Address:

Guatemala City

San Jose

12 Hosts

LAN Address:

13 Hosts

WAN Address #3

.0

.127.128

.255

Visualizing Subnets Using aVLSM Chart

The VLSM chart is the third method used to visualize the breakdown ofsubnets and addresses into smaller sizes. By shading or coloring in theboxes you can easily break up your subnets without overlapping youraddresses. You can adjust each sub-subnet to the correct size needed.

24

MarketingDepartment

60 Hosts

LAN Address:

220.10.10.0/26

ResearchDepartment

28 Hosts

LAN Address:

220.10.10.64/27

VLSM AddressingVLSM Chart Method

(Sample)

Problem 17Using the network diagram and information given create an addressing

scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the boxes below, color or shade the sub-subnets used inthe chart. This business will be using the class C address 220.10.10.0. Re-member to start with your largest groups first.

0-127

128-255

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

16-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

25

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

26

VLSM AddressingVLSM Chart Method

(Sample)

Problem 18Using the network diagram and information given create an address-

ing scheme which utilizes variable-length subnet masks. Show the subnetaddress and CIDR in the boxes below, color or shade the sub-subnets used inthe chart. This company will be using the class C address 192.168.16.0. Re-member to start with your largest groups first.

Washington D.C.120 Hosts

Frederick20 Hosts

Baltimore60 Hosts

LAN Address:

192.168.16.0/25

LAN Address:

192.168.16.192/27LAN Address:

192.168.16.128/26

WAN Address #1:

192.168.16.224/30 WAN Address #2:

192.168.16.228/30

27

0-127

128-255

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

16-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

28

VLSM AddressingVLSM Chart Method

Problem 19Using the network diagram and information given create an

addressing scheme which utilizes variable-length subnet masks. Show thesubnet address and CIDR in the boxes below, color or shade the sub-subnetsused in the chart. This company will be using the class C address 199.55.78.0.Remember to start with your largest groups first.

LAN Address:

Site 250 Hosts

LAN Address:

Site 130 Hosts

WAN Address #1:

LAN Address:

Site 4100 Hosts

Site 310 Hosts

LAN Address:

29

0-127

128-255

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

16-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

30

VLSM AddressingVLSM Chart Method

Problem 20Using the network diagram and information given create an

addressing scheme which utilizes variable-length subnet masks. Show thesubnet address and CIDR in the boxes below, color or shade the sub-subnetsused in the chart. This company will be using the class C address 223.150.50.0.Remember to start with your largest groups first.

WAN Address #2:

WAN Address #1:

LAN Address:

Bedford12 Hosts

Richland Hills10 Hosts

LAN Address:

LAN Address:Hurst

60 Hosts

Euless50 Hosts

LAN Address:

Arlington15 Hosts

31

0-127

128-255

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

16-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

32

VLSM AddressingVLSM Chart Method

Problem 21Using the network diagram and information given create an

addressing scheme which utilizes variable-length subnet masks. Show thesubnet address and CIDR in the boxes below, color or shade the sub-subnetsused in the chart. This company will be using the class C address 222.22.2.0.Remember to start with your largest groups first.

23 Hosts 15 Hosts

17 Hosts 40 Hosts

35 Hosts 18 Hosts

LAN Address:

12 HostsLAN Address:

WAN Address #2:

WAN Address #1:

WAN Address #1:

WAN Address #1:

33

0-127

128-255

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

16-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

34

VLSM AddressingVLSM Chart Method

Problem 22Using the network diagram and information given create an

addressing scheme which utilizes variable-length subnet masks. Show thesubnet address and CIDR in the boxes below, color or shade the sub-subnetsused in the chart. This company will be using the class C address 200.20.2.0.Remember to start with your largest groups first.

LAN Address:

LAN Address:

LAN Address:

WAN Address #3:

Router A

Hagerstown25 Hosts

Router B

Router C

Router D

FrederickSite A

45 Hosts

Middletown10 Hosts

WAN Address #1:

WAN Address #2:

FrederickSite B

23 Hosts

Boonsburo35 Hosts

LAN Address:

35

0-127

128-255

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

16-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

36

VLSM AddressingVLSM Chart Method

Problem 23Using the network diagram and information given create an

addressing scheme which utilizes variable-length subnet masks. Show thesubnet address and CIDR in the boxes below, color or shade the sub-subnetsused in the chart. This company will be using the class C address 190.150.23.0.Remember to start with your largest groups first.

LAN Address:

Boston25 Hosts

New York22 Hosts

Virgina34 Hosts

West Virginia11 Hosts

Utah36 Hosts

Maryland25 Hosts

WAN Address #1:

Texas10 Hosts

WAN Address #2:

LAN Address:

WAN Address #3:

LAN Address:

LAN Address:

37

0-127

128-255

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

16-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

38

VLSM AddressingVLSM Chart Method

Problem 24Using the network diagram and information given create an

addressing scheme which utilizes variable-length subnet masks. Show thesubnet address and CIDR in the boxes below, color or shade the sub-subnetsused in the chart. This company will be using the class C address 192.168.1.0.Remember to start with your largest groups first.

27 Hosts

12 Hosts

LAN Address:

LAN Address: LAN Address:

WAN Address #1: WAN Address #2:

WAN Address #3:

LAN Address:

8 Hosts5 Hosts 8 Hosts 6 Hosts

18 Hosts

WAN Address #4:

LAN Address:

39

0-127

128-255

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

16-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

40

Practical VLSMProblems

Use the VLSM method of your choice to completethe folowing problems.

.0 -

.3

.24 -

.27

.8 -

.11

.16

- .19

.64 - .67

.56 - .59

.48 - .51

.40 - .43

.32 -

.35

.104 - .107.96 - .99

.88 - .91

.80 - .83

.72 - .75

.112 - .115

.120 - .123

.176 - .179

.224

- .22

7.216 - .2

19

.192 - .195

.208 - .211

.200 - .203

.184 - .187

.168. - 171

.152 - .155 .136 - .139

.160 - .163

.144 - .147

.128 - .131

.248

- .2

51

.232

- .2

35

.240

- .2

43 .4 -

.7

.12

- .15

.20

- .23

.28 -

.31

.36 - .39

.44 - .47

.52 - .55

.60 - .63

.68 - .71

.76 - .79

.84 - .87.92 - .95

.100 - .103

.108 - .111

.116 - .119

.124 - .127

.132 - .135

.140 - .143

.148 - .151.156 - .159

.164 - .167

.172. - 175

.180 - .183

.188 - .191

.196 - .199

.204 - .207.212 - .2

15.22

0 - .2

23 .228

- .23

1

.236

- .2

39

.244

- .2

47

.252

- .2

55

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42

43

VL

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dre

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m 2

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usin

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ork

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ress

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.55.

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/24.

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C a

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.0/2

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. D

ivid

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rmat

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ired

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w.

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embe

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k fr

omla

rges

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sm

alle

st.

Sub

net

1 2 3 4 5 6 7 8 9 10 11 12 13 14

Sub

net

Add

ress

Sub

net

Mas

k (/

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VL

SM

Ad

dre

ssin

g

Pro

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twor

k ac

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eral

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tions

. T

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aco

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e ne

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ters

. T

he F

argo

offi

ce w

ill n

eed

five

com

pute

rs.

The

WA

Nlin

ks b

etw

een

all t

hree

loca

tions

nee

d to

be

incl

uded

in t

he s

olut

ion.

U

sing

the

IP

add

ress

192

.168

.10.

0/24

divi

de t

he n

etw

ork

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g V

LSM

. C

ompl

ete

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rmat

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ired

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w.

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k fr

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net

1 2 3 4 5 6 7 8 9 10 11 12 13 14

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net

Add

ress

Sub

net

Mas

k (/

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ddre

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46

VL

SM

Ad

dre

ssin

g

Pro

ble

m 2

9A

new

sch

ool i

s be

ing

built

in th

e lo

cal s

choo

l dis

tric

t. It

will

hav

e th

ree

com

pute

r la

bs w

ith 2

8co

mpu

ters

eac

h.

The

re w

ill b

e 58

cla

ssro

oms

with

2 c

ompu

ters

eac

h th

at n

eed

to b

e on

one

sub

-sub

net.

The

offi

ce s

taff

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adm

inis

trat

ors

will

nee

d 7

com

pute

rs.

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gui

danc

e an

d at

tend

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ce w

ill h

ave

5co

mpu

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. T

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choo

l ha

s be

en g

iven

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add

ress

223

.145

.75.

0/24

. C

ompl

ete

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info

rmat

ion

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ired

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w.

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embe

r to

wor

k fr

om la

rges

t to

sm

alle

st.

Sub

net

1 2 3 4 5 6 7 8 9 10 11 12 13 14

Sub

net

Add

ress

Sub

net

Mas

k (/

X)

Firs

t Usa

ble

Hos

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st U

sabl

eH

ost

Bro

adca

stA

ddre

ss

47

VL

SM

Ad

dre

ssin

g

Pro

ble

m 3

0A

loca

l col

lege

is s

ettin

g up

a c

ampu

s w

ide

netw

ork.

T

he te

chno

logy

win

g w

ill b

e on

its

own

netw

ork

addr

ess

of 1

92.1

68.2

50.0

/24.

T

he o

ffice

win

g w

ill in

clud

e 15

com

pute

rs.

The

re a

re 2

labs

of

20 c

ompu

ters

each

, 2

labs

of

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ters

eac

h an

d on

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b of

35

com

pute

rs.

Com

plet

e th

e in

form

atio

n re

quire

d be

low

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ber

to w

ork

from

larg

est

to s

mal

lest

.

Sub

net

1 2 3 4 5 6 7 8 9 10 11 12 13 14

Sub

net

Add

ress

Sub

net

Mas

k (/

X)

Firs

t Usa

ble

Hos

tLa

st U

sabl

eH

ost

Bro

adca

stA

ddre

ss

48

VL

SM

Ad

dre

ssin

g

Pro

ble

m 3

1Yo

u ar

e se

tting

up

a ne

twor

k fo

r a

com

pany

in f

our

loca

tions

. L

ocat

ion

A h

as 8

com

pute

rs.

Loc

atio

n B

has

122

com

pute

rs.

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atio

n C

has

4 c

ompu

ters

. L

ocat

ion

D h

as 5

5 co

mpu

ters

. T

here

is a

WA

N c

onne

c-tio

n be

twee

n al

l fou

r lo

catio

ns.

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plet

e th

e in

form

atio

n re

quire

d be

low

usi

ng t

he c

lass

C a

ddre

ss19

2.16

8.10

.0.

Rem

embe

r to

wor

k fr

om l

arge

st t

o sm

alle

st.

Sub

net

1 2 3 4 5 6 7 8 9 10 11 12 13 14

Sub

net

Add

ress

Sub

net

Mas

k (/

X)

Firs

t Usa

ble

Hos

tLa

st U

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eH

ost

Bro

adca

stA

ddre

ss

49

VL

SM

Ad

dre

ssin

g

Pro

ble

m 3

2A

col

lege

dor

mito

ry is

bei

ng r

emol

ded.

A

new

net

wor

k is

bei

ng in

stal

led.

T

here

are

50

dorm

roo

ms

with

tw

o dr

ops

each

tha

t w

ill b

e on

one

sub

-sub

net.

The

offi

ces

will

hav

e 5

drop

s.

The

rec

eptio

n de

sk w

illha

ve t

hree

dro

ps.

A s

mal

l stu

dy h

all w

ill in

clud

e 30

dro

ps.

Usi

ng t

he I

P a

ddre

ss 1

92.1

68.1

2.0/

24 c

ompl

ete

the

info

rmat

ion

requ

ired

belo

w u

sing

VLS

M.

Wor

k fr

om la

rges

t to

sm

alle

st.

Sub

net

1 2 3 4 5 6 7 8 9 10 11 12 13 14

Sub

net

Add

ress

Sub

net

Mas

k (/

X)

Firs

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ble

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st U

sabl

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ost

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adca

stA

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ss

50

VL

SM

Ad

dre

ssin

g

Pro

ble

m 3

3Yo

u ar

e se

tting

up

a bu

sine

ss n

etw

ork

with

the

cla

ss C

add

ress

219

.75.

160.

0/24

. T

he m

arke

ting

divi

sion

will

nee

d 19

com

pute

rs.

Res

earc

h an

d de

velo

pmen

t ne

eds

40 c

ompu

ters

. T

he r

ecep

tion

area

will

need

fou

r co

mpu

ters

. M

anag

emen

t re

quire

s 12

com

pute

rs.

Div

ide

the

netw

ork

usin

g va

riabl

e le

ngth

sub

net

info

rmat

ion.

O

n th

e op

posi

te p

age

draw

a d

etai

led

map

of

this

net

wor

k.

Incl

ude

the

nam

e an

d su

b-su

bnet

IP

addr

esse

s fo

r ea

ch b

ranc

h of

the

netw

ork

with

the

subn

et m

ask.

O

ne r

oute

r w

ith fo

ur e

ther

net p

orts

will

be

used

for

thi

s ne

twor

k.

Sub

net

1 2 3 4 5 6 7 8 9 10 11 12 13 14

Sub

net

Add

ress

Sub

net

Mas

k (/

X)

Firs

t Usa

ble

Hos

tLa

st U

sabl

eH

ost

Bro

adca

stA

ddre

ss

51

Pro

ble

m 3

3 -

Det

aile

d M

apD

raw

a d

etai

led

map

of

this

net

wor

k.

Incl

ude

the

nam

e an

d su

b-su

bnet

IP

add

ress

esin

form

atio

n fo

r ea

chbr

anch

of t

he n

etw

ork,

and

the

subn

et m

ask.

52

VL

SM

Ad

dre

ssin

g

Pro

ble

m 3

4A

sm

all c

ompa

ny n

eeds

to

set

up it

s ne

twor

k ac

ross

sev

eral

loca

tions

. T

he N

ew Y

ork

bran

ch o

ffice

need

s 15

com

pute

rs.

The

San

Jos

e of

fice

need

s 66

com

pute

rs.

The

Trin

idad

offi

ce w

ill n

eed

18co

mpu

ters

. Y

ou w

ill n

eed

two

WA

N li

nks

betw

een

the

rout

ers.

U

sing

the

IP

add

ress

195

.20.

5.0/

24 d

ivid

e th

ene

twor

k us

ing

VLS

M.

On

the

oppo

site

pag

e dr

aw a

det

aile

d m

ap o

f th

is n

etw

ork.

In

clud

e th

e na

me

and

sub-

subn

et I

P a

ddre

sses

info

rmat

ion

for

each

bra

nch

of t

he n

etw

ork.

La

bel t

he W

AN

link

s w

ith t

he s

ame

info

rma-

tion.

C

ompl

ete

the

info

rmat

ion

requ

ired

belo

w.

Wor

k fr

om la

rges

t to

sm

alle

st.

Sub

net

1 2 3 4 5 6 7 8 9 10 11 12 13 14

Sub

net

Sub

net

Mas

k (/

X)

Firs

t Usa

ble

Hos

tLa

st U

sabl

eH

ost

Bro

adca

stA

ddre

ss

Pro

ble

m 3

4 -

Det

aile

d M

apD

raw

a d

etai

led

map

of

this

net

wor

k.

Incl

ude

the

nam

eand

sub

-sub

net

IP a

ddre

sses

info

rmat

ion

for

each

bran

ch o

f the

net

wor

k.

53

54

Class A and B

VLSMProblems

Class A AddressesVLSM Chart 8-15 Bits (2nd octet)

Class B AddressesVLSM Chart 16-23 Bits (3rd octet)

Class C AddressesVLSM Chart 24-30 Bits (4th octet)

10 . 0 . 0 . 0

VLSMwith

Class A and B Addresses

We’ve gone over the practical applications of using VLSM on class C addresses. The sameapproach works with class A and B addresses. For example an ISP may have a class Aaddress which it needs to subnet between its customers. Each customer may need to taketheir addresses and subnet them again in order to use them more effectively. The real trick tothis is to remember which octet of the IP address you are working with.

Sample Problem 35Part 1 of 3

Use the Class A address chart to break down the address for different ISP customers. At this

stage of the problem you are creating subnets using the second octet of the IP address.

ISP Addresses 15.0.0.0

56

CustomerName

Number ofAddresses

Address Range(Include subnet & broadcast addresses)

Customer #1

Customer #2

Customer #3

Customer #4

Customer #5

Customer #6

Customer #7

Customer #8

Customer #9

8 million

2 million

2,000,000

1,000,000

500,000

450,000

200,000

130,000

100,000

15.0.0.0 to 15.127.255.255

15.128.0.0 to 15.159.255.255

15.160.0.0 to 15.191.255.255

15.192.0.0 to 15.207.255.255

15.208.0.0 to 15.215.255.255

15.216.0.0 to 15.223.255.255

15.224.0.0 to 15.227.255.255

15.228.0.0 to 15.229.255.255

15.230.0.0 to 15.231.255.255

/9

/11

/11

/12

/13

/13

/14

/15

/15

CIDR

57

Class A AddressesVLSM Chart 8-15 Bits (2nd octet)

0-127

128-255

/14255.252.0.0

262,144 Hosts

/13255.248.0.0

524,288 Hosts

/12255.240.0.0

1,048,576 Hosts

/11255.224.0.0

2,097,152 Hosts

/10255.192.0.0

4,194,304 Hosts

/9255.128.0.0

8,388.608 Hosts

/8255.0.0.0

16,777,216 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

/15255.254.0.0

131,072 Hosts

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

0 - 12 - 34 - 56 - 78 - 9

10 - 1112 - 1314 - 1516 - 1718 - 1920 - 2122 - 2324 - 2526 - 2728 - 2930 - 3132 - 3334 - 3536 - 3738 - 3940 - 4142 - 4344 - 4546 - 4748 - 4950 - 5152 - 5354 - 5556 - 5758 - 5960 - 6162 - 6364 - 6566 - 6768 - 6970 - 7172 - 7374 - 7576 - 7778 - 7980 - 8182 - 8384 - 8586 - 8788 - 8990 - 9192 - 9394 - 9596 - 9798 - 99

100 - 101102 - 103104 - 105106 - 107108 - 109110 - 111112 - 113114 - 115116 - 117118 - 119120 - 121122 - 123124 - 125126 - 127128 - 129130 - 131132 - 133134 - 135136 - 137138 - 139140 - 141142 - 143144 - 145146 - 147148 - 149150 - 151152 - 153154 - 155156 - 157158 - 159160 - 161162 - 163164 - 165166 - 167168 - 169170 - 171172 - 173174 - 175176 - 177178 - 179180 - 181182 - 183184 - 185186 - 187188 - 189190 - 191192 - 193194 - 195196 - 197198 - 199200 - 201202 - 203204 - 205206 - 207208 - 209210 - 211212 - 213214 - 215216 - 217218 - 219220 - 221222 - 223224 - 225226 - 227228 - 229230 - 231232 - 233234 - 235236 - 237238 - 239240 - 241242 - 243244 - 245246 - 247248 - 249250 - 251252 - 253254 - 255

VLSMwith

Class A and B AddressesSample Problem 35

Part 2 of 3

Customer #5 has a total of 524,288 addresses. Use the Class B address chart to breakdown the sub-subnetwork addresses for their different clients. At this stage of the problem youare creating sub-subnets with the third octet of the IP address.

ISP Addresses 15.208.0.0

CustomerName

Number ofAddresses

Address Range(Include subnet & broadcast addresses)

Client #1

Client #2

Client #3

Client #4

Client #5

Client #6

Client #7

Client #8

Client #9

7,500

5,000

4,500

2,000

1,450

1,150

900

750

450

15.208.0.0 to 15.208.31.255

15.208.32.0 to 15.208.63.255

15.208.64.0 to 15.208.95.255

15.208.96.0 to 15.208.103.255

15.208.104.0 to 15.208.111.255

15.208.112.0 to 15.208.119.255

15.208.120.0 to 15.208.123.255

15.208.124.0 to 15.208.127.255

15.208.128.0 to 15.208.129.255

/19

/19

/19

/21

/21

/21

/22

/22

/23

CIDR

58

0-127

128-255

Class B Addresses

VLSM Chart 16-23 Bits (3rd octet)

/22255.255.252.01,024 Hosts

/21255.255.248.02,048 Hosts

/20255.255.240.04,096 Hosts

/19255.255.224.08,192 Hosts

/18255.255.192.016,384 Hosts

/17255.255.128.032,768 Hosts

/16255.255.0.0

65,536 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

/23255.255.254.0

512 Hosts

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

0 - 12 - 34 - 56 - 78 - 9

10 - 1112 - 1314 - 1516 - 1718 - 1920 - 2122 - 2324 - 2526 - 2728 - 2930 - 3132 - 3334 - 3536 - 3738 - 3940 - 4142 - 4344 - 4546 - 4748 - 4950 - 5152 - 5354 - 5556 - 5758 - 5960 - 6162 - 6364 - 6566 - 6768 - 6970 - 7172 - 7374 - 7576 - 7778 - 7980 - 8182 - 8384 - 8586 - 8788 - 8990 - 9192 - 9394 - 9596 - 9798 - 99

100 - 101102 - 103104 - 105106 - 107108 - 109110 - 111112 - 113114 - 115116 - 117118 - 119120 - 121122 - 123124 - 125126 - 127128 - 129130 - 131132 - 133134 - 135136 - 137138 - 139140 - 141142 - 143144 - 145146 - 147148 - 149150 - 151152 - 153154 - 155156 - 157158 - 159160 - 161162 - 163164 - 165166 - 167168 - 169170 - 171172 - 173174 - 175176 - 177178 - 179180 - 181182 - 183184 - 185186 - 187188 - 189190 - 191192 - 193194 - 195196 - 197198 - 199200 - 201202 - 203204 - 205206 - 207208 - 209210 - 211212 - 213214 - 215216 - 217218 - 219220 - 221222 - 223224 - 225226 - 227228 - 229230 - 231232 - 233234 - 235236 - 237238 - 239240 - 241242 - 243244 - 245246 - 247248 - 249250 - 251252 - 253254 - 255

59

VLSMwith

Class A and B AddressesSample Problem 35

Part 3 of 3

Client #8 has a total of 1,024 addresses. Use the Class C address chart to break down thesub-subnetwork addresses for their different branch offices. At this stage of the problem youare creating sub-subnets with the fourth octet of the IP address.

ISP Addresses 15.208.124.0

CustomerName

Number ofAddresses

Address Range(Include subnet & broadcast addresses)

Branch #1

Branch #2

Branch #3

Branch #4

Branch #5

Branch #6

Branch #7

Branch #8

Branch #9

100

55

25

6

4

2

2

2

2

15.208.124.0 to 15.208.124.127

15.208.124.128 to 15.208.124.191

15.208.124.192 to 15.208.124.223

15.208.124.224 to 15.208.124.231

15.208.124.232 to 15.208.124.239

15.208.124.240 to 15.208.124.243

15.208.124.244 to 15.208.124.247

15.208.124.248 to 15.208.124.251

15.208.124.252 to 15.208.124.255

/25

/26

/27

/29

/29

/30

/30

/30

/30

CIDR

60

0-127

128-255

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

61

VLSMwith

Class A and B AddressesProblem 36Part 1 of 3

The school system you are working for is using the private address of 172.32.0.0 to subnet theentire district. Use the Class B address chart to break down the sub-subnetwork addressesfor the different schools and offices.

At this stage of the problem you are creating sub-subnets with the third octet of the IP address.Remember which octet of the IP address you are working in.

School System Address 172.32.0.0

CustomerName

Number ofAddresses

Address Range(Include subnet & broadcast addresses)

North High

South High

North Middle

South Middle

Central Elem.

Southern Elem.

Eastern Elem.

Central Office

Western Elem.

2,400

2,000

1,200

1,000

550

475

450

400

300

CIDR

62

0-127

128-255

Class B Addresses

VLSM Chart 16-23 Bits (3rd octet)

/22255.255.252.01,024 Hosts

/21255.255.248.02,048 Hosts

/20255.255.240.04,096 Hosts

/19255.255.224.08,192 Hosts

/18255.255.192.016,384 Hosts

/17255.255.128.032,768 Hosts

/16255.255.0.0

65,536 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

/23255.255.254.0

512 Hosts

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

0 - 12 - 34 - 56 - 78 - 9

10 - 1112 - 1314 - 1516 - 1718 - 1920 - 2122 - 2324 - 2526 - 2728 - 2930 - 3132 - 3334 - 3536 - 3738 - 39

48 - 4950 - 5152 - 5354 - 5556 - 5758 - 5960 - 6162 - 6364 - 6566 - 6768 - 6970 - 7172 - 7374 - 7576 - 7778 - 7980 - 8182 - 8384 - 8586 - 8788 - 8990 - 9192 - 9394 - 9596 - 9798 - 99

100 - 101102 - 103104 - 105106 - 107108 - 109110 - 111112 - 113114 - 115116 - 117118 - 119120 - 121122 - 123124 - 125126 - 127128 - 129130 - 131132 - 133134 - 135136 - 137138 - 139140 - 141142 - 143144 - 145146 - 147148 - 149150 - 151152 - 153154 - 155156 - 157158 - 159160 - 161162 - 163164 - 165166 - 167168 - 169170 - 171172 - 173174 - 175176 - 177178 - 179180 - 181182 - 183184 - 185186 - 187188 - 189190 - 191192 - 193194 - 195196 - 197198 - 199200 - 201202 - 203204 - 205206 - 207208 - 209210 - 211212 - 213214 - 215216 - 217218 - 219220 - 221222 - 223224 - 225226 - 227228 - 229230 - 231232 - 233234 - 235236 - 237238 - 239240 - 241242 - 243244 - 245246 - 247248 - 249250 - 251252 - 253254 - 255

63

40 - 4142 - 4344 - 4546 - 47

VLSMwith

Class A and B Addresses

Problem 36Part 2 of 3

Eastern Elementary has been given 512 hosts, with the address range of 172.32.42.0 / 21(255.255.248.0).

Based on the information below supply the required address ranges and subnet masks foreach school area. Use the Class C address chart to break down the sub-subnetworks.

Hint: Another way to look at this problem is to see that with the third octet range of 42 to 43 youhave access to 2 groups of 255 addresses (172.32.42.0 and 172.32.43.0). Think in terms ofhaving two Class C VLSM charts.

Eastern Elementary SchoolAddress Range 172.32.42.0 to 172.32.43.255

CustomerName

Number ofAddresses

Address Range(Include subnet & broadcast addresses)

250

45

40

25

12

CIDR

Students

Printers

Staff

Network Devices

Administrative

64

0-127

128-255

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

65

VLSMwith

Class A and B AddressesProblem 36Part 3 of 3

South High in part 1 of this problem has been given 2,048 hosts, with the address range of172.32.16.0 / 21 (255.255.248.0).

Based on the information below supply the required address ranges and subnet masks foreach school area. Use both the Class B and Class C address charts to break down the sub-subnetwork addresses for the different areas of the network.

Hint:With this problem you are creating sub-subnets with both the third and fourth octets of the IPaddress. You may need to use the Class B VLSM chart for the Students addressinginformation. All the other addresses will be using the Class C VLSM chart. Another way tolook at this problem is to see that with the third octect range of 16 to 23 you have access to 8groups of 255 addresses or eight Class C VLSM charts.

South High SchoolAddress Range 172.32.16.0 to 172.32.23.255

CustomerName

Number ofAddresses

Address Range(Include subnet & broadcast addresses)

1,000

250

200

150

50

CIDR

Students

Network Devices

Printers

Staff

Administrative

66

0-127

128-255

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

67

68

CustomerName

Number ofAddresses

Address Range(Include subnet & broadcast addresses)

Moskva

New York

St. Petersburg

London

Ekaterinoburg

Munchen

Napoli

Birmingham

Rotterdam

3,050,000

1,540,000

1,075,000

975,000

525,000

450,000

150,000

130,000

95,000

CIDR

VLSMwith

Class A and B AddressesProblem 37Part 1 of 3

The company you are working for is using the IP address 110.0.0.0 sub-subneted for multipleoffices around the world. Use the Class A address chart to break down the sub-subnetworkaddresses for the different offices.

At this stage of the problem you are creating sub-subnets with the third octet of the IP address.Remember which octet of the IP address you are working in.

Company Address 110.0.0.0

69

Class A AddressesVLSM Chart 8-15 Bits (2nd octet)

0-127

128-255

/14255.252.0.0

262,144 Hosts

/13255.248.0.0

524,288 Hosts

/12255.240.0.0

1,048,576 Hosts

/11255.224.0.0

2,097,152 Hosts

/10255.192.0.0

4,194,304 Hosts

/9255.128.0.0

8,388.608 Hosts

/8255.0.0.0

16,777,216 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

/15255.254.0.0

131,072 Hosts

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

0 - 12 - 34 - 56 - 78 - 9

10 - 1112 - 1314 - 1516 - 1718 - 1920 - 2122 - 2324 - 2526 - 2728 - 2930 - 3132 - 3334 - 3536 - 3738 - 3940 - 4142 - 4344 - 4546 - 4748 - 4950 - 5152 - 5354 - 5556 - 5758 - 5960 - 6162 - 6364 - 6566 - 6768 - 6970 - 7172 - 7374 - 7576 - 7778 - 7980 - 8182 - 8384 - 8586 - 8788 - 8990 - 9192 - 9394 - 9596 - 9798 - 99

100 - 101102 - 103104 - 105106 - 107108 - 109110 - 111112 - 113114 - 115116 - 117118 - 119120 - 121122 - 123124 - 125126 - 127128 - 129130 - 131132 - 133134 - 135136 - 137138 - 139140 - 141142 - 143144 - 145146 - 147148 - 149150 - 151152 - 153154 - 155156 - 157158 - 159160 - 161162 - 163164 - 165166 - 167168 - 169170 - 171172 - 173174 - 175176 - 177178 - 179180 - 181182 - 183184 - 185186 - 187188 - 189190 - 191192 - 193194 - 195196 - 197198 - 199200 - 201202 - 203204 - 205206 - 207208 - 209210 - 211212 - 213214 - 215216 - 217218 - 219220 - 221222 - 223224 - 225226 - 227228 - 229230 - 231232 - 233234 - 235236 - 237238 - 239240 - 241242 - 243244 - 245246 - 247248 - 249250 - 251252 - 253254 - 255

70

VLSMwith

Class A and B Addresses Problem 37Part 2 of 3

London in part 1 of this problem has been given 1,048,576 hosts, with the address range of110.128.0.0 to 110.143.255.255 /12 (255.240.0.0).

Based on the information below supply the required address ranges and subnet masks foreach office. Use the Class B address chart to break down the sub-subnetwork addresses forthe different areas of the network.

LondonAddress Range 110.128.0.0 to 110.143.255.255

CustomerName

Number ofAddresses

Address Range(Include subnet & broadcast addresses)

Office #1

Office #2

Office #3

Office #4

Office #5

Office #6

Office #7

Office #8

Office #9

6,450

3,780

2,750

2,000

1,000

845

500

450

300

CIDR

71

0-127

128-255

Class B Addresses

VLSM Chart 16-23 Bits (3rd octet)

/22255.255.252.01,024 Hosts

/21255.255.248.02,048 Hosts

/20255.255.240.04,096 Hosts

/19255.255.224.08,192 Hosts

/18255.255.192.016,384 Hosts

/17255.255.128.032,768 Hosts

/16255.255.0.0

65,536 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

/23255.255.254.0

512 Hosts

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

0 - 12 - 34 - 56 - 78 - 9

10 - 1112 - 1314 - 1516 - 1718 - 1920 - 2122 - 2324 - 2526 - 2728 - 2930 - 3132 - 3334 - 3536 - 3738 - 3940 - 4142 - 4344 - 4546 - 4748 - 4950 - 5152 - 5354 - 5556 - 5758 - 5960 - 6162 - 6364 - 6566 - 6768 - 6970 - 7172 - 7374 - 7576 - 7778 - 7980 - 8182 - 8384 - 8586 - 8788 - 8990 - 9192 - 9394 - 9596 - 9798 - 99

100 - 101102 - 103104 - 105106 - 107108 - 109110 - 111112 - 113114 - 115116 - 117118 - 119120 - 121122 - 123124 - 125126 - 127128 - 129130 - 131132 - 133134 - 135136 - 137138 - 139140 - 141142 - 143144 - 145146 - 147148 - 149150 - 151152 - 153154 - 155156 - 157158 - 159160 - 161162 - 163164 - 165166 - 167168 - 169170 - 171172 - 173174 - 175176 - 177178 - 179180 - 181182 - 183184 - 185186 - 187188 - 189190 - 191192 - 193194 - 195196 - 197198 - 199200 - 201202 - 203204 - 205206 - 207208 - 209210 - 211212 - 213214 - 215216 - 217218 - 219220 - 221222 - 223224 - 225226 - 227228 - 229230 - 231232 - 233234 - 235236 - 237238 - 239240 - 241242 - 243244 - 245246 - 247248 - 249250 - 251252 - 253254 - 255

72

VLSMwith

Class A and B Addresses

CustomerName

Number ofAddresses

Address Range

1st Floor

2nd Floor

5th Floor

8th Floor

4th Floor

Basement

7th Floor

3rd Floor

6th Floor

125

75

50

45

30

14

12

6

4

CIDR

Problem 37Part 3 of 3

Office #7 in part 2 of this problem has been given 512 hosts, with the address range of110.128.80.0 / 23 (255.255.254.0).

Based on the information below supply the required address ranges and subnet masks foreach school area. Use the Class C address chart to break down the sub-subnetworkaddresses for the different areas of the network. Hint: Another way to look at this problem isto see that with the third octect range of 80 to 81 you have access to 2 groups of 255addresses or two Class C VLSM charts.

Office #7Address Range 110.128.80.0 to 110.128.81.255

73

0-127

128-255

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

74

VLSMwith

Class A and B Addresses

Problem 38Part 1 of 4

Use the Class A address chart to break down the address for different business customers bycountry. At this stage of this problem you are creating subnets in the second octet of the IPaddress.

Addresses 75.0.0.0

CustomerName

Number ofAddresses

Address Range

United States

China

Japan

Germany

Russia

Australia

Brazil

Canda

Denmark

6.5 million

4 million

1 million

500,000

455,000

450,000

125,000

90,000

88,000

CIDR

75

Class A AddressesVLSM Chart 8-15 Bits (2nd octet)

0-127

128-255

/14255.252.0.0

262,144 Hosts

/13255.248.0.0

524,288 Hosts

/12255.240.0.0

1,048,576 Hosts

/11255.224.0.0

2,097,152 Hosts

/10255.192.0.0

4,194,304 Hosts

/9255.128.0.0

8,388.608 Hosts

/8255.0.0.0

16,777,216 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

/15255.254.0.0

131,072 Hosts

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

0 - 12 - 34 - 56 - 78 - 9

10 - 1112 - 1314 - 1516 - 1718 - 1920 - 2122 - 2324 - 2526 - 2728 - 2930 - 3132 - 3334 - 3536 - 3738 - 3940 - 4142 - 4344 - 4546 - 4748 - 4950 - 5152 - 5354 - 5556 - 5758 - 5960 - 6162 - 6364 - 6566 - 6768 - 6970 - 7172 - 7374 - 7576 - 7778 - 7980 - 8182 - 8384 - 8586 - 8788 - 8990 - 9192 - 9394 - 9596 - 9798 - 99

100 - 101102 - 103104 - 105106 - 107108 - 109110 - 111112 - 113114 - 115116 - 117118 - 119120 - 121122 - 123124 - 125126 - 127128 - 129130 - 131132 - 133134 - 135136 - 137138 - 139140 - 141142 - 143144 - 145146 - 147148 - 149150 - 151152 - 153154 - 155156 - 157158 - 159160 - 161162 - 163164 - 165166 - 167168 - 169170 - 171172 - 173174 - 175176 - 177178 - 179180 - 181182 - 183184 - 185186 - 187188 - 189190 - 191192 - 193194 - 195196 - 197198 - 199200 - 201202 - 203204 - 205206 - 207208 - 209210 - 211212 - 213214 - 215216 - 217218 - 219220 - 221222 - 223224 - 225226 - 227228 - 229230 - 231232 - 233234 - 235236 - 237238 - 239240 - 241242 - 243244 - 245246 - 247248 - 249250 - 251252 - 253254 - 255

76

VLSMwith

Class A and B AddressesSample Problem 38

Part 2 of 4

The United States customers have a total of 8,388,608 addresses. Use the Class A addresschart to break down the sub-subnetwork addresses for their different areas. At this stage ofthis problem you are creating sub-subnets in the second octet of the IP address.

Addresses Range: 75.0.0.0 to 75.127.255.255

CustomerName

Number ofAddresses

Address Range

Client #1

Client #2

Client #3

Client #4

Client #5

Client #6

Client #7

1,950,000

1,000,000

950,000

700,000

550,000

500,000

450,000

CIDR

Class A AddressesVLSM Chart 8-15 Bits (2nd octet)

0-127

128-255

/14255.252.0.0

262,144 Hosts

/13255.248.0.0

524,288 Hosts

/12255.240.0.0

1,048,576 Hosts

/11255.224.0.0

2,097,152 Hosts

/10255.192.0.0

4,194,304 Hosts

/9255.128.0.0

8,388.608 Hosts

/8255.0.0.0

16,777,216 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

/15255.254.0.0

131,072 Hosts

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

0 - 12 - 34 - 56 - 78 - 9

10 - 1112 - 1314 - 1516 - 1718 - 1920 - 2122 - 2324 - 2526 - 2728 - 2930 - 3132 - 3334 - 3536 - 3738 - 3940 - 4142 - 4344 - 4546 - 4748 - 4950 - 5152 - 5354 - 5556 - 5758 - 5960 - 6162 - 6364 - 6566 - 6768 - 6970 - 7172 - 7374 - 7576 - 7778 - 7980 - 8182 - 8384 - 8586 - 8788 - 8990 - 9192 - 9394 - 9596 - 9798 - 99

100 - 101102 - 103104 - 105106 - 107108 - 109110 - 111112 - 113114 - 115116 - 117118 - 119120 - 121122 - 123124 - 125126 - 127128 - 129130 - 131132 - 133134 - 135136 - 137138 - 139140 - 141142 - 143144 - 145146 - 147148 - 149150 - 151152 - 153154 - 155156 - 157158 - 159160 - 161162 - 163164 - 165166 - 167168 - 169170 - 171172 - 173174 - 175176 - 177178 - 179180 - 181182 - 183184 - 185186 - 187188 - 189190 - 191192 - 193194 - 195196 - 197198 - 199200 - 201202 - 203204 - 205206 - 207208 - 209210 - 211212 - 213214 - 215216 - 217218 - 219220 - 221222 - 223224 - 225226 - 227228 - 229230 - 231232 - 233234 - 235236 - 237238 - 239240 - 241242 - 243244 - 245246 - 247248 - 249250 - 251252 - 253254 - 255

77

78

VLSMwith

Class A and B AddressesSample Problem 38

Part 3 of 4

Client #7 has a total of 524,288 addresses. Use the Class B address chart to break down thesub-subnetwork addresses for their different clients. At this stage of this problem you arecreating sub-subnets in the third or forth octet of the IP address.

Hint: Another way to look at this problem is to see that with the second octect range of 104 to111 you have access to 8 groups of 65,536 addresses or 8 Class B VLSM charts.

ISP Addresses 75.104.0.0 to 75.111.255.255

CustomerName

Number ofAddresses

Address Range

Office #1

Office #2

Office #3

Office #4

Office #5

Office #6

Office #7

Office #8

Office #9

60,000

45,000

30,000

24,000

15,000

10,000

8,000

2,000

1,000

CIDR

79

0-127

128-255

Class B Addresses

VLSM Chart 16-23 Bits (3rd octet)

/22255.255.252.01,024 Hosts

/21255.255.248.02,048 Hosts

/20255.255.240.04,096 Hosts

/19255.255.224.08,192 Hosts

/18255.255.192.016,384 Hosts

/17255.255.128.032,768 Hosts

/16255.255.0.0

65,536 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

/23255.255.254.0

512 Hosts

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

0 - 12 - 34 - 56 - 78 - 9

10 - 1112 - 1314 - 1516 - 1718 - 1920 - 2122 - 2324 - 2526 - 2728 - 2930 - 3132 - 3334 - 3536 - 3738 - 3940 - 4142 - 4344 - 4546 - 4748 - 4950 - 5152 - 5354 - 5556 - 5758 - 5960 - 6162 - 6364 - 6566 - 6768 - 6970 - 7172 - 7374 - 7576 - 7778 - 7980 - 8182 - 8384 - 8586 - 8788 - 8990 - 9192 - 9394 - 9596 - 9798 - 99

100 - 101102 - 103104 - 105106 - 107108 - 109110 - 111112 - 113114 - 115116 - 117118 - 119120 - 121122 - 123124 - 125126 - 127128 - 129130 - 131132 - 133134 - 135136 - 137138 - 139140 - 141142 - 143144 - 145146 - 147148 - 149150 - 151152 - 153154 - 155156 - 157158 - 159160 - 161162 - 163164 - 165166 - 167168 - 169170 - 171172 - 173174 - 175176 - 177178 - 179180 - 181182 - 183184 - 185186 - 187188 - 189190 - 191192 - 193194 - 195196 - 197198 - 199200 - 201202 - 203204 - 205206 - 207208 - 209210 - 211212 - 213214 - 215216 - 217218 - 219220 - 221222 - 223224 - 225226 - 227228 - 229230 - 231232 - 233234 - 235236 - 237238 - 239240 - 241242 - 243244 - 245246 - 247248 - 249250 - 251252 - 253254 - 255

80

VLSMwith

Class A and B AddressesSample Problem 38

Part 4 of 4

Office #7 from part 3 of 4 has a total of 8,192 addresses. Use the Class B address chart tobreak down the sub-subnetwork addresses for the different branch offices. At this stage of thisproblem you are creating sub-subnets in the third octet of the IP address.

Hint: Remember that the range of this problem is between 128 and 159 in the third octect.

Your subnetting will start in the middle of the chart not at the top for this range.

ISP Addresses 75.107.128.0 to 75.107.159.255

CustomerName

Number ofAddresses

Address Range

Branch #1

Branch #2

Branch #3

Branch #4

Branch #5

4,000

2,000

1,000

500

450

CIDR

81

0-127

128-255

Class B Addresses

VLSM Chart 16-23 Bits (3rd octet)

/22255.255.252.01,024 Hosts

/21255.255.248.02,048 Hosts

/20255.255.240.04,096 Hosts

/19255.255.224.08,192 Hosts

/18255.255.192.016,384 Hosts

/17255.255.128.032,768 Hosts

/16255.255.0.0

65,536 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

/23255.255.254.0

512 Hosts

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

0 - 12 - 34 - 56 - 78 - 9

10 - 1112 - 1314 - 1516 - 1718 - 1920 - 2122 - 2324 - 2526 - 2728 - 2930 - 3132 - 3334 - 3536 - 3738 - 3940 - 4142 - 4344 - 4546 - 4748 - 4950 - 5152 - 5354 - 5556 - 5758 - 5960 - 6162 - 6364 - 6566 - 6768 - 6970 - 7172 - 7374 - 7576 - 7778 - 7980 - 8182 - 8384 - 8586 - 8788 - 8990 - 9192 - 9394 - 9596 - 9798 - 99

100 - 101102 - 103104 - 105106 - 107108 - 109110 - 111112 - 113114 - 115116 - 117118 - 119120 - 121122 - 123124 - 125126 - 127128 - 129130 - 131132 - 133134 - 135136 - 137138 - 139140 - 141142 - 143144 - 145146 - 147148 - 149150 - 151152 - 153154 - 155156 - 157158 - 159160 - 161162 - 163164 - 165166 - 167168 - 169170 - 171172 - 173174 - 175176 - 177178 - 179180 - 181182 - 183184 - 185186 - 187188 - 189190 - 191192 - 193194 - 195196 - 197198 - 199200 - 201202 - 203204 - 205206 - 207208 - 209210 - 211212 - 213214 - 215216 - 217218 - 219220 - 221222 - 223224 - 225226 - 227228 - 229230 - 231232 - 233234 - 235236 - 237238 - 239240 - 241242 - 243244 - 245246 - 247248 - 249250 - 251252 - 253254 - 255

See Hint

82

Reference Chartsand Support Materials

Class A AddressesVLSM Chart 8-15 Bits (2nd octet)

Class B AddressesVLSM Chart 16-23 Bits (3rd octet)

Class C AddressesVLSM Chart 24-30 Bits (4th octet)

Class A AddressesVLSM Chart 8-15 Bits (2nd octet)

0-127

128-255

/14255.252.0.0

262,144 Hosts

/13255.248.0.0

524,288 Hosts

/12255.240.0.0

1,048,576 Hosts

/11255.224.0.0

2,097,152 Hosts

/10255.192.0.0

4,194,304 Hosts

/9255.128.0.0

8,388.608 Hosts

/8255.0.0.0

16,777,216 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

/15255.254.0.0

131,072 Hosts

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

0 - 12 - 34 - 56 - 78 - 9

10 - 1112 - 1314 - 1516 - 1718 - 1920 - 2122 - 2324 - 2526 - 2728 - 2930 - 3132 - 3334 - 3536 - 3738 - 3940 - 4142 - 4344 - 4546 - 4748 - 4950 - 5152 - 5354 - 5556 - 5758 - 5960 - 6162 - 6364 - 6566 - 6768 - 6970 - 7172 - 7374 - 7576 - 7778 - 7980 - 8182 - 8384 - 8586 - 8788 - 8990 - 9192 - 9394 - 9596 - 9798 - 99

100 - 101102 - 103104 - 105106 - 107108 - 109110 - 111112 - 113114 - 115116 - 117118 - 119120 - 121122 - 123124 - 125126 - 127128 - 129130 - 131132 - 133134 - 135136 - 137138 - 139140 - 141142 - 143144 - 145146 - 147148 - 149150 - 151152 - 153154 - 155156 - 157158 - 159160 - 161162 - 163164 - 165166 - 167168 - 169170 - 171172 - 173174 - 175176 - 177178 - 179180 - 181182 - 183184 - 185186 - 187188 - 189190 - 191192 - 193194 - 195196 - 197198 - 199200 - 201202 - 203204 - 205206 - 207208 - 209210 - 211212 - 213214 - 215216 - 217218 - 219220 - 221222 - 223224 - 225226 - 227228 - 229230 - 231232 - 233234 - 235236 - 237238 - 239240 - 241242 - 243244 - 245246 - 247248 - 249250 - 251252 - 253254 - 255

84

0-127

128-255

Class B Addresses

VLSM Chart 16-23 Bits (3rd octet)

/22255.255.252.01,024 Hosts

/21255.255.248.02,048 Hosts

/20255.255.240.04,096 Hosts

/19255.255.224.08,192 Hosts

/18255.255.192.016,384 Hosts

/17255.255.128.032,768 Hosts

/16255.255.0.0

65,536 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

/23255.255.254.0

512 Hosts

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

0 - 12 - 34 - 56 - 78 - 9

10 - 1112 - 1314 - 1516 - 1718 - 1920 - 2122 - 2324 - 2526 - 2728 - 2930 - 3132 - 3334 - 3536 - 3738 - 3940 - 4142 - 4344 - 4546 - 4748 - 4950 - 5152 - 5354 - 5556 - 5758 - 5960 - 6162 - 6364 - 6566 - 6768 - 6970 - 7172 - 7374 - 7576 - 7778 - 7980 - 8182 - 8384 - 8586 - 8788 - 8990 - 9192 - 9394 - 9596 - 9798 - 99

100 - 101102 - 103104 - 105106 - 107108 - 109110 - 111112 - 113114 - 115116 - 117118 - 119120 - 121122 - 123124 - 125126 - 127128 - 129130 - 131132 - 133134 - 135136 - 137138 - 139140 - 141142 - 143144 - 145146 - 147148 - 149150 - 151152 - 153154 - 155156 - 157158 - 159160 - 161162 - 163164 - 165166 - 167168 - 169170 - 171172 - 173174 - 175176 - 177178 - 179180 - 181182 - 183184 - 185186 - 187188 - 189190 - 191192 - 193194 - 195196 - 197198 - 199200 - 201202 - 203204 - 205206 - 207208 - 209210 - 211212 - 213214 - 215216 - 217218 - 219220 - 221222 - 223224 - 225226 - 227228 - 229230 - 231232 - 233234 - 235236 - 237238 - 239240 - 241242 - 243244 - 245246 - 247248 - 249250 - 251252 - 253254 - 255

85

86

0-127

128-255

Class C Addresses

VLSM Chart 24-30 Bits (4th octet)

0-34-78-11

12-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99

100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255

/30255.255.255.252

4 Hosts

/29255.255.255.248

8 Hosts

/28255.255.255.240

16 Hosts

/27255.255.255.224

32 Hosts

/26255.255.255.192

64 Hosts

/25255.255.255.128

128 Hosts

/24255.255.255.0

256 Hosts

0-7

8-15

16-23

24-31

32-39

40-47

48-55

56-63

64-71

72-79

80-87

88-95

96-103

104-111

112-119

120-127

128-135

136-143

144-151

152-159

160-167

168-175

176-183

184-191

192-199

200-207

208-215

216-223

224-231

232-239

240-247

248-255

0-15

16-31

32-47

48-63

64-79

80-95

96-111

112-127

128-143

144-159

160-175

176-191

192-207

208-223

224-239

240-255

0-63

64-127

128-191

192-255

0 - 255

0-31

32-63

64-95

96-127

128-159

160-191

192-223

224-255

Inside Cover

# of BitsBorrowed

012345678910111213141516171819202122

SubnetMask

255.0.0.0255.128.0.0255.192.0.0255.224.0.0255.240.0.0255.248.0.0255.252.0.0255.254.0.0255.255.0.0

255.255.128.0255.255.192.0255.255.224.0255.255.240.0255.255.248.0255.255.252.0255.255.254.0255.255.255.0

255.255.255.128255.255.255.192255.255.255.224255.255.255.240255.255.255.248255.255.255.252

Total # ofSubnets

1248163264128256512

1,0242,0484,0968,19216,38432,76865,536131,072262,144524,288

1,048,5762,097,1524,194,304

Total # ofHosts

16,777,2168,388,6084,194,3042,097,1521,048,576524,288262,144131,07265,53632,76816,3848,1924,0962,0481,02451225612864321684

Usable # ofHosts

16,777,2148,388,6064,194,3022,097,1501,048,574524,286262,142131,07065,53432,76616,3828,1904,0942,0461,02251025412662301462

# of BitsBorrowed

01234567891011121314

SubnetMask

255.255.0.0255.255.128.0255.255.192.0255.255.224.0255.255.240.0255.255.248.0255.255.252.0255.255.254.0255.255.255.0

255.255.255.128255.255.255.192255.255.255.224255.255.255.240255.255.255.248255.255.255.252

Total # ofSubnets

1248163264128256512

1,0242,0484,0968,19216,384

Total # ofHosts65,53632,76816,3848,1924,0962,0481,02451225612864321684

Usable # ofHosts65,53432,76616,3828,1904,0942,0461,02251025412662301462

Class C Addressing Guide# of Bits

Borrowed0123456

SubnetMask

255.255.255.0255.255.255.128255.255.255.192255.255.255.224255.255.255.240255.255.255.248255.255.255.252

Total # ofSubnets

1248163264

Total # ofHosts

25612864321684

Usable # ofHosts

25412662301462

CIDR/8/9/10/11/12/13/14/15/16/17/18/19/20/21/22/23/24/25/26/27/28/29/30

CIDR/16/17/18/19/20/21/22/23/24/25/26/27/28/29/30

CIDR/24/25/26/27/28/29/30

Class B Addressing Guide

Class A Addressing Guide

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________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________

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