vectors and scalars quatities

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    SCALAR AND VECTOR

    QUANTITIESRAPHAEL V. PEREZ, CpE

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    SCALAR AND VECTOR

    QUANTITIESDefine Scalar and Vector

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    SCALAR QUANTITYhas only magnitde. !"nly the

    measre # $antity%

    VECTOR QUANTITY

    has &oth magnitde and direction.

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    SCALAR VECTORdistance

    displacement

    workpower

    acceleration

    ol!me

    press!re

    elocit"

    speed

    wei#$t

    mass

    %orce

    resistance

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    SCALAR AND VECTOR

    QUANTITIES'HA( )S RES*L(A+(

    VEC("R

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    RES*L(A+( VEC("R is the is the-ector that reslts from adding t/o or

    more -ectors together.

    -1 -0.5 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5

    0.5

    1

    1.5

    2

    2.5

    3

    3.5

    4

    y

     V e c t o

     r  1  = A

             V

          e      c        t      o

          r          2

          =          B

       R    E   S   U   L

       T  A   N   T    V   E  C

       T  O

       R    =    R 

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    (he goal of this topic is tofind the 0A1+)(*DE "2

    (HE RES*L(A+( VEC("R!R%, and the VEC("R

    A+1LE !3%

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    (HERE ARE (HREE (ECH+)4*ES ("

    2)+D (HE RES*L(A+( VEC("R A+D(HE VEC("R A+1LE5

    6. 1RAPH)CAL 0E(H"D 7 yo need thetechnical tools li8e sharp pencil, rler,protractor and the paper !graphing or

    &ond% to sho/ the -ectors graphically.(he otpt is the connection of -ectorsis li8e a polygon.

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    R ɵ

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    SA0PLE PR"9LE0

    6. A man /al8s at:; meters East

    and

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    Soltion5 'rite the gi-en

    facts1i-en5

    A = :; meters East9 =

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    graph the -ectors from the origin

    !head to tail%

    head!arro/head%

    VEC("R

    tail

     0A 1  +  )  (  *

     D  E

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    graph the -ectors from the origin

    !head to tail%

    NOTE: 1 GRID = 10 METERS

       B  =   3   0

       M   E   T   E   R   S ,

       N   O   R   T   

    A = !0 METERS, EAST

    USE RULER TOMEASURE AND

     TO DRAW A

    LINE

    θ = 37° N of E 

       R    =   "

      0    M   E  T   E

       R   S

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    SA0PLE PR"9LE0

    >. 1i-en5

    A = ? 8m ,East9 = @ 8m, +EC = 8m,

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    graph the -ectors from the origin

    !head to tail%

    NOTE: 1 GRID = 10 #$

    %OSSIBLE GRA%

    >. 1i-en5A = ? 8m ,East9 = @ 8m, +EC = 8m,

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    ASSI)N*ENT 

    *se graphical 0ethod to find the magnitde of theresltant displacement and the -ector angle

    6. 1i-en5A= 6. 1i-en5

    0= ?. cm, +'+= >.? cm, SE"= 6.< cm, +E

    R = 3 =

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    +, T$e -"t$a#orean T$eorem

    (he Pythagorean theorem is a sefl methodfor determining the reslt of adding t/o !andonly t/o% -ectors that ma8e a right angle to

    each other. (he method is not applica&le foradding more than t/o -ectors or for adding-ectors that are not at ;degrees to eachother. (he Pythagorean theorem is a

    mathematical e$ation that relates the lengthof the sides of a right triangle to the length ofthe hypotense of a right triangle.

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    • .orm!la/

    Res!ltant ector

    • 'here A and 9 are -ectors can form aright angle and are also primarydirections.

    Vector Angle

    the ans/er is 50t$e R12 0(1 0opposite1 o% 0ad3acent1

    •  

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    SA0PLE PR"9LE0

    6. A man /al8s at :; meters East

    and

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       B  =   3   0   M   E

       T   E   R   S ,   N   O   R   T   

    A = !0 METERS, EAST

    sketchyourpro!e"

    θ

    θ =

    θ =use calculator

     

       R    =   "

      0    M   E  T   E

       R   S

    = "0 $

     

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    • 1. ____ is an example of a scalar quantity #$ %e!oc&ty $ 'orce c$ %o!u"e ($ #cce!er#t&o)

    • 2. ___ is an example of a vector quantity #$ "#ss $ 'orce

     c$ %o!u"e ($ (e)s&ty

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    • 3. A scalar quantity: #$ #!*#ys h#s "#ss $ &s # +u#)t&ty th#t &s co"p!ete!y spec&,e( y&ts "#-)&tu(e c$ sho*s (&rect&o)

     ($ (oes )ot h#%e u)&ts

    • 4. A vector quantity #$ c#) e # (&"e)s&o)!ess +u#)t&ty $ spec&,es o)!y "#-)&tu(e c$ spec&,es o)!y (&rect&o) ($ spec&,es oth # "#-)&tu(e #)( # (&rect&o)

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    • 5. A oy pus!es a"ainst t!e #all #it! 5$ poun%s

    of force. &!e #all %oes not move. &!e resultantforce is: #$ ./0 pou)(s $ 100 pou)(s c$ 0 pou)(s

     ($ .7/ pou)(s

    • '. A man #al(s 3 miles nort! t!en turns ri"!t an%#al(s 4 miles east. &!e resultant %isplacement is: #$ 1 "&!e SW

     $ 7 "&!es NE c$ / "&!es NE ($ / "&!es E

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    • ). A man #al(s at 1$ m *ast+ ut !e returns ac(

    at 1$ m at #est. &!e resultant %isplacement is: #$ 0 k" $ 20 k" c$ 10 k" ($ .10 k"

    • ,. &!e %i-erence et#een spee% an% velocity is: #$ spee( h#s )o u)&ts $ spee( sho*s o)!y "#-)&tu(e *h&!e %e!oc&tyreprese)ts oth "#-)&tu(e 4stre)-th$ #)( (&rect&o)

     c$ they use (&5ere)t u)&ts to represe)t the&r "#-)&tu(e ($ %e!oc&ty h#s # h&-her "#-)&tu(e

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    • ). A plane yin" 5$$ /0!r %ue nort! !as a tail

    #in% of 45 /0!r t!e resultant velocity is: #$ /6/ "&!eshour (ue south8 $ 6// "&!eshour )orth8 c$ /6/ "&!eshr (ue )orth8 ($ 6// MIhr (ue south

    • ,. &!e %i-erence et#een spee% an% velocity is: #$ spee( h#s )o u)&ts $ spee( sho*s o)!y "#-)&tu(e *h&!e %e!oc&tyreprese)ts oth "#-)&tu(e 4stre)-th$ #)( (&rect&o)

     c$ they use (&5ere)t u)&ts to represe)t the&r "#-)&tu(e ($ %e!oc&ty h#s # h&-her "#-)&tu(e

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    • . &!e resultant ma"nitu%e of t#o vectors

     #$ Is #!*#ys pos&t&%e $ 9#) )e%er e :ero c$ 9#) )e%er e )e-#t&%e ($ Is usu#!!y :ero

    • 1$. !ic! of t!e follo#in" is not true. #$ %e!oc&ty c#) e )e-#t&%e $ %e!oc&ty &s # %ector

     $ spee( &s # sc#!#r ($ spee( c#) e )e-#t&%e

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    4, ANALYTICAL 0CO*-ONENT1 *ET5OD

    Each -ector has t/o components 5

    the Fcomponent and the ycomponent)f the -ectors are in secondary directions 5

    !+', +E, S' or SE directions%

    AF = A cos 3FA y = A sin 3F

    /here5A = the gi-en -ector -ale3F = the gi-en angle from F aFis

    AF = the F 7 component of -ector A

    A y = y 7 component of -ector A

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    Component formla for F and y5

     A x = A cos θ  x

     A y = A sin θ  x

    Sm of F and y Components5 

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    2)+AL A+S'ER )S5

    0agnitde of the Resltant Vector5

    (he -ector Angle5

    •  

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    Consider t$e si#n conentions for the Sm of F and yComponents

     

    4adrant of 0agnitde

    6 6 I

    7 6 II

    7 7 III

    6 7 IV

    8  Y7a9is 0Nort$ or So!t$1

    8 :7 a9is 0;est or East1

    4adrant of 0agnitde6 6 I

    7 6 II

    7 7 III

    6 7 IV

    8  Y7a9is 0Nort$ or So!t$1

    8 :7 a9is 0;est or East1

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    A

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    Recall the SA0PLE PR"9LE0

    1i-en5A = ? 8m ,East9 = @ 8m, +EC = 8m,

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    S l ti n/ D t

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    Sol!tion/ Draw a ta

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    Sol!tion/ Comp!te %or t$e ma#nit!de and

    ector an#le

    T$e ma#nit!de

    = ,.3) (m

      (he -ector Angle5

     + of E

    &ecase of the sign con-entionof the components and theangle /hich is !G,G% at G3!positi-e angle%

     

    W>I9> IS NEAR IN OUR ?RE@IOUS DRAWIN IN RA?>I9AL MET>OD

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    Actal happen on -ectors

    !not needed to ra h%

    NOTE: 1 GRID = 10 #$

    %OSSIBLE GRA%

    A = ? 8m ,East9 = @ 8m, +EC = 8m,

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    graph the -ectors from the origin

    !head to tail%

     

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          R 

        &      >

     ,     4      A

           k 

        m  ,

     

    θ =').')°

    & R Ʃ x, R Ʃ y' = &3(1)0!*, +(+!2*!'

    -./r.t I

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    .INAL ANS;ER

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    4 N

    ectors6

    component

     76compone

    nt

    A

    <

    9

     Tot#!

    A =

    B =

    C =

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    A =

    B =

    C =

    D = 7 N

    ectors

    6component

     76component

    A

    <

    9

    D