vectors and scalars quatities
TRANSCRIPT
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SCALAR AND VECTOR
QUANTITIESRAPHAEL V. PEREZ, CpE
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SCALAR AND VECTOR
QUANTITIESDefine Scalar and Vector
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SCALAR QUANTITYhas only magnitde. !"nly the
measre # $antity%
VECTOR QUANTITY
has &oth magnitde and direction.
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SCALAR VECTORdistance
displacement
workpower
acceleration
ol!me
press!re
elocit"
speed
wei#$t
mass
%orce
resistance
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SCALAR AND VECTOR
QUANTITIES'HA( )S RES*L(A+(
VEC("R
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RES*L(A+( VEC("R is the is the-ector that reslts from adding t/o or
more -ectors together.
-1 -0.5 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5
0.5
1
1.5
2
2.5
3
3.5
4
y
V e c t o
r 1 = A
V
e c t o
r 2
= B
R E S U L
T A N T V E C
T O
R = R
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(he goal of this topic is tofind the 0A1+)(*DE "2
(HE RES*L(A+( VEC("R!R%, and the VEC("R
A+1LE !3%
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(HERE ARE (HREE (ECH+)4*ES ("
2)+D (HE RES*L(A+( VEC("R A+D(HE VEC("R A+1LE5
6. 1RAPH)CAL 0E(H"D 7 yo need thetechnical tools li8e sharp pencil, rler,protractor and the paper !graphing or
&ond% to sho/ the -ectors graphically.(he otpt is the connection of -ectorsis li8e a polygon.
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R ɵ
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SA0PLE PR"9LE0
6. A man /al8s at:; meters East
and
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Soltion5 'rite the gi-en
facts1i-en5
A = :; meters East9 =
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graph the -ectors from the origin
!head to tail%
head!arro/head%
VEC("R
tail
0A 1 + ) ( *
D E
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graph the -ectors from the origin
!head to tail%
NOTE: 1 GRID = 10 METERS
B = 3 0
M E T E R S ,
N O R T
A = !0 METERS, EAST
USE RULER TOMEASURE AND
TO DRAW A
LINE
θ = 37° N of E
R = "
0 M E T E
R S
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SA0PLE PR"9LE0
>. 1i-en5
A = ? 8m ,East9 = @ 8m, +EC = 8m,
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graph the -ectors from the origin
!head to tail%
NOTE: 1 GRID = 10 #$
%OSSIBLE GRA%
>. 1i-en5A = ? 8m ,East9 = @ 8m, +EC = 8m,
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ASSI)N*ENT
*se graphical 0ethod to find the magnitde of theresltant displacement and the -ector angle
6. 1i-en5A= 6. 1i-en5
0= ?. cm, +'+= >.? cm, SE"= 6.< cm, +E
R = 3 =
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+, T$e -"t$a#orean T$eorem
(he Pythagorean theorem is a sefl methodfor determining the reslt of adding t/o !andonly t/o% -ectors that ma8e a right angle to
each other. (he method is not applica&le foradding more than t/o -ectors or for adding-ectors that are not at ;degrees to eachother. (he Pythagorean theorem is a
mathematical e$ation that relates the lengthof the sides of a right triangle to the length ofthe hypotense of a right triangle.
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• .orm!la/
Res!ltant ector
• 'here A and 9 are -ectors can form aright angle and are also primarydirections.
Vector Angle
the ans/er is 50t$e R12 0(1 0opposite1 o% 0ad3acent1
•
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SA0PLE PR"9LE0
6. A man /al8s at :; meters East
and
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B = 3 0 M E
T E R S , N O R T
A = !0 METERS, EAST
sketchyourpro!e"
θ
θ =
θ =use calculator
R = "
0 M E T E
R S
= "0 $
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• 1. ____ is an example of a scalar quantity #$ %e!oc&ty $ 'orce c$ %o!u"e ($ #cce!er#t&o)
• 2. ___ is an example of a vector quantity #$ "#ss $ 'orce
c$ %o!u"e ($ (e)s&ty
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• 3. A scalar quantity: #$ #!*#ys h#s "#ss $ &s # +u#)t&ty th#t &s co"p!ete!y spec&,e( y&ts "#-)&tu(e c$ sho*s (&rect&o)
($ (oes )ot h#%e u)&ts
• 4. A vector quantity #$ c#) e # (&"e)s&o)!ess +u#)t&ty $ spec&,es o)!y "#-)&tu(e c$ spec&,es o)!y (&rect&o) ($ spec&,es oth # "#-)&tu(e #)( # (&rect&o)
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• 5. A oy pus!es a"ainst t!e #all #it! 5$ poun%s
of force. &!e #all %oes not move. &!e resultantforce is: #$ ./0 pou)(s $ 100 pou)(s c$ 0 pou)(s
($ .7/ pou)(s
• '. A man #al(s 3 miles nort! t!en turns ri"!t an%#al(s 4 miles east. &!e resultant %isplacement is: #$ 1 "&!e SW
$ 7 "&!es NE c$ / "&!es NE ($ / "&!es E
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• ). A man #al(s at 1$ m *ast+ ut !e returns ac(
at 1$ m at #est. &!e resultant %isplacement is: #$ 0 k" $ 20 k" c$ 10 k" ($ .10 k"
• ,. &!e %i-erence et#een spee% an% velocity is: #$ spee( h#s )o u)&ts $ spee( sho*s o)!y "#-)&tu(e *h&!e %e!oc&tyreprese)ts oth "#-)&tu(e 4stre)-th$ #)( (&rect&o)
c$ they use (&5ere)t u)&ts to represe)t the&r "#-)&tu(e ($ %e!oc&ty h#s # h&-her "#-)&tu(e
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• ). A plane yin" 5$$ /0!r %ue nort! !as a tail
#in% of 45 /0!r t!e resultant velocity is: #$ /6/ "&!eshour (ue south8 $ 6// "&!eshour )orth8 c$ /6/ "&!eshr (ue )orth8 ($ 6// MIhr (ue south
• ,. &!e %i-erence et#een spee% an% velocity is: #$ spee( h#s )o u)&ts $ spee( sho*s o)!y "#-)&tu(e *h&!e %e!oc&tyreprese)ts oth "#-)&tu(e 4stre)-th$ #)( (&rect&o)
c$ they use (&5ere)t u)&ts to represe)t the&r "#-)&tu(e ($ %e!oc&ty h#s # h&-her "#-)&tu(e
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• . &!e resultant ma"nitu%e of t#o vectors
#$ Is #!*#ys pos&t&%e $ 9#) )e%er e :ero c$ 9#) )e%er e )e-#t&%e ($ Is usu#!!y :ero
• 1$. !ic! of t!e follo#in" is not true. #$ %e!oc&ty c#) e )e-#t&%e $ %e!oc&ty &s # %ector
$ spee( &s # sc#!#r ($ spee( c#) e )e-#t&%e
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4, ANALYTICAL 0CO*-ONENT1 *ET5OD
Each -ector has t/o components 5
the Fcomponent and the ycomponent)f the -ectors are in secondary directions 5
!+', +E, S' or SE directions%
AF = A cos 3FA y = A sin 3F
/here5A = the gi-en -ector -ale3F = the gi-en angle from F aFis
AF = the F 7 component of -ector A
A y = y 7 component of -ector A
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Component formla for F and y5
A x = A cos θ x
A y = A sin θ x
Sm of F and y Components5
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2)+AL A+S'ER )S5
0agnitde of the Resltant Vector5
(he -ector Angle5
•
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Consider t$e si#n conentions for the Sm of F and yComponents
4adrant of 0agnitde
6 6 I
7 6 II
7 7 III
6 7 IV
8 Y7a9is 0Nort$ or So!t$1
8 :7 a9is 0;est or East1
4adrant of 0agnitde6 6 I
7 6 II
7 7 III
6 7 IV
8 Y7a9is 0Nort$ or So!t$1
8 :7 a9is 0;est or East1
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A
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Recall the SA0PLE PR"9LE0
1i-en5A = ? 8m ,East9 = @ 8m, +EC = 8m,
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S l ti n/ D t
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Sol!tion/ Draw a ta
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Sol!tion/ Comp!te %or t$e ma#nit!de and
ector an#le
T$e ma#nit!de
= ,.3) (m
(he -ector Angle5
+ of E
&ecase of the sign con-entionof the components and theangle /hich is !G,G% at G3!positi-e angle%
W>I9> IS NEAR IN OUR ?RE@IOUS DRAWIN IN RA?>I9AL MET>OD
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Actal happen on -ectors
!not needed to ra h%
NOTE: 1 GRID = 10 #$
%OSSIBLE GRA%
A = ? 8m ,East9 = @ 8m, +EC = 8m,
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graph the -ectors from the origin
!head to tail%
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R
& >
, 4 A
k
m ,
θ =').')°
& R Ʃ x, R Ʃ y' = &3(1)0!*, +(+!2*!'
-./r.t I
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.INAL ANS;ER
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4 N
ectors6
component
76compone
nt
A
<
9
Tot#!
A =
B =
C =
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A =
B =
C =
D = 7 N
ectors
6component
76component
A
<
9
D