voltage supply inverter using ic 555

27
Voltage Supply Inverter Using IC 555 SUMAN HOSMANE SURAJ DONTHI

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Page 1: Voltage  supply     inverter using ic 555

Voltage Supply Inverter Using IC 555

SUMAN HOSMANE

SURAJ DONTHI

Page 2: Voltage  supply     inverter using ic 555

Intro

Whats a power sopply???

Page 3: Voltage  supply     inverter using ic 555

A power supply is used to convert an input electrical energy to the required

electrical specifications of a loadIn our mini project we have used a

variable power supply….

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Classification

AC Power Supply

DC Power Supply

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AC Power Supply

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DC Power Supply

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Common Sources Batteries, Thermocouples, solar cells,

dynamo…..

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Voltage Invertors

•Extensively used in the analog domain

•Most circuits incorporate voltage invertors

•Generally as dual power supply

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Few Commonly used Inverters

◊ICL 7660

◊Op-amp sign changer/inverter

◊IC555 timer in astable multivibrator mode.

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IC 555 Timer

Extensively used in pulse generation,

PWM, oscillators, time delays

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Pin Layout

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Internal Structure

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Modes

Astable mode

Bistable mode

Monostable mode

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The Astable Mode

DC to AC

Produces square waves at Vo

Produces square waves at Vc

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Circuit Diagram

Page 16: Voltage  supply     inverter using ic 555

Time Calculation

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Avoid low values of R1 so that o/p is saturated0V-2/3 Vcc in 1st cycle1/3-2/3 Vcc in subsequent cycles

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Page 19: Voltage  supply     inverter using ic 555

Astable Multi Vibrator as Voltage Inverter

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During +ve half cycle:◦The diode eliminates the -ve DC component

◦Fed to the –ve potential line to convert to –ve

During –ve half cycle:The –ve voltage is let out through the diode D2 as it is.

Working

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Overall O/P

Finally the th o/p is got across the 100uF Capacitor at V0

The o/p is slightly smaller.

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Calculation The output frequency of the circuit constructed is given by the   f = 1.449 / [(4.8+66)* 10^3 * 22 * 10^-6] f = 1.449 / 1.5576 f = 0.93 Hz

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Duty Cycle

T on = 0.693(Ra + Rb) C = 0.693 (4.8 + 33) * 10^3 * 22 * 10^-6 = 0.57629s   T off = 0.693(Rb) C = 0.693 (33 * 10^3) (22 * 10^ -6) = 0.593s

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Advantages

Used to run op amp which requires Vcc and –Vcc for its working. Circuits that require both negative and positive voltages for their working can incorporate such circuits. Eg:

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Reference

CicuitsToday

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Thank U