welcome! the topic for today is…ste sec 4
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Welcome! The Topic For Today Is…STE Sec 4. Your Topic. Topic 1: 200. Question: What is the difference between a toxic and a lethal dose? What year did the Great Depression begin Answer - PowerPoint PPT PresentationTRANSCRIPT
Welcome!The Topic For Today Is…STE Sec 4
Your TopicToxicology Charges Stoicheometry Q=mcT Physics
200 200 200 200 200
400 400 400 400 400
600 600 600 600 600
800 800 800 800 800
1000 1000 1000 1000 1000
Bonus Question: 5000 pts
Topic 1: 200• Question:• What is the difference between a toxic and a lethal dose?
• What year did the Great Depression begin• Answer• A toxic dose is the amount in mg of substance per kg of weight
that causes illness. A lethal dose is the concentration that kills.
Back
Topic 1: 400• Question:• Calculate the LD
50 in each of the following cases. Express in
mg/kg.
• A dose of 1500 mg of salt killed 50% of 5000 g rabbits.
• Answer• 1500 mg/5 kg = 300 mg/kg
Back
Topic 1: 600• Question:• A 75 kg man was killed because in drinking 1000g of booze, he
experienced a LD50
for alcohol. The booze was 53% alcohol.
• Answer• 0.53*1000 000 mg/75kg
• = 7066 mg/kg
Back
Topic 1: 800• Question:• How many 500 mg vitamin tablets would a 100 kg patient have
to swallow in order to experience a lethal dose if the LD50
is
11.9 g/kg?
• Answer• 11.9 g/kg * 100 kg = 1190 g 1190g/ 0.5 g/tablet = 2380 tablets
Back
Topic 1: 1000• Question:• A certain type of green algae have a cadmium concentration of
0.10 parts per million. But an analysis of the algae reveals that the concentration of cadmium contaminant in the water is 0.01 ppm. Calculate the BCF factor.
• Answer• 0.10/0.01 = 10
Back
Topic 2: 200• Question:• What ion formed from an element of the fourth shell (4th period)
is found in seashells?
• Answer• Ca+2
Back
Topic 2: 400• Question:• Describe an experiment that you could do to help you
prove that a hydrogen ion does not have the same chemical properties as a neutral hydrogen molecule
• Answer• Add blue litmus to acid(has hydrogen ion). The
litmus will turn red.• Place blue litmus in hydrogen gas. Nothing will
occur.Back
Topic 2: 600• Question:• Explain why +1 is the common ion for alkali metals.
• Answer• They all have 1 loose valence electron.
Back
Topic 2: 800• Question:• I am an element that likes to form the -1 ion, and I have the
smallest nucleus among the members of my family. What am I?
• Answer• Fluoride
Back
Topic 2: 1000• Question:• Explain why fluorine forms diatomic molecules.
• Answer• By having 9 protons but only two shells, each F nucleus has
enough force to pull in an electron from the other. The result is that the shared electrons act as a bond.
Back
Topic 3: 200• Question:• Convert the following:
• 300 g of Mg = __________moles
• Answer• 300 g (mole/24 g) = 12.5 moles
Back
Topic 3: 400• Question:• Convert the following
• 6 moles of O2
= ________molecules
• Answer• 6 moles (6.02 X 1023 molecules/mole) =
• 3.6 X 1024 molecules
Back
Topic 3: 600• Question:• Monty Mole found a mole of gold. If gold sells for $28 US per
gram in Dec 2008, what is the value of Monty’s mole of gold?
• Answer• 1 mole Au = 197 g
• 197 g($28/g) = $
• 5516 US
Back
Topic 3: 800• Question:• How many moles of water will be produced if 5 moles of
ammonia, NH3(g),
react
• Answer• 5 moles NH
3 (6 H
2O/ 4 NH
3(g)) ) =7.5 molesH
2O
Back
Topic 3: 1000• Question:• How many grams of oxygen react with every 1.0 gram of
NH3(g)?
• Answer• 0.074 moles O
2 (32 g/mole) = 2.35 g O
Back
Topic 4: 200• Question:• An average sized banana (118 g) yields 454.300 kJ of heat when burnt to a crisp.
• If you managed to transfer all of the heat to a cup of water ( 250 g) at 20 oC, how warm would the
water get?
• Answer• Specific heat of water = 4190 J (kg C) or 4.19 J (g C)
• Q = mcT
• 454 300 J = 250 g(4.19 J/(g oC)(x – 20)
• x = 454 oC
• (That temperature will never be obtained for water---it’ll boil off first, which means that a cup of
water is too small to absorb all the heat.)
Back
Topic 4: 400• Question:• You want to cool 1000 kg of water at 40o C to a comfortable 32o C with only 258 L of water.
How cold should that 258 L be, assuming that no heat is lost to the surroundings ?
• Answer• Density of water: 1.0 kg/L
• -Qhot = Qcold
• -1 000 000(4.19)(32-40) = 258 000(4.19)(32-x)
• -1000(-8) = 258(32 - x)
• 8000/258 = 32 – x
• x = 32 -8000/258 x= 1
oC
Back
Topic 4: 600• Question:• How much energy in joules is used by the heating element of the
coffee maker during this period?
• Answer• E = VIt
• V=IR, so I =V/R=120/20
• = 120 J/C(120/20)C/s(15*60 s)
• = 648 000 JBack
Topic 4: 800• Question:• A series circuit with three light bulbs has voltage drops of 1.2 V,
1.4 V and 1.4 V. The ammeter measures 0.50 A.
• What is the wattage of the bulb that consumes the least energy?
• Answer• P = VI = 1.2J/C(0.50 C/s) = 0.6 J/s = 0. 6 W.
Back
Topic 4: 1000• Question:• A series circuit with three light bulbs has voltage drops of 1.2 V,
1.4 V and 1.4 V. The ammeter measures 0.50 A.
• How much energy is used by all three bulbs every hour they’re turned on?
• Answer• V
t = 1.2+1.4+1.4= 4.0 V
• E = VIt=4(0.5)(3600 s) = 7200 J
Back
Topic 5: 200• Question:• The effective force is in the direction of the acceleration. If the
35 N force is applied at angle of 27o, calculate the effective force.
• Answer• F
effective/35 = cos 27
• Feffective
= 35 cos 27 = 31.2 N
Back
Topic 5: 400• Question:• The effective force is in the direction of the acceleration. If the
35 N force is applied at angle of 27o, calculate the effective force.
• What is the vertical component of the 35 N force?
• Answer• F
effective/35 = sin 27
• Feffective
= 35 sin 27 = 15.9 NBack
Topic 5: 600• Question:• The effective force is in the direction of the acceleration. If the
35 N force is applied at angle of 27o, calculate the effective force.
• Find the combined weight of the girl and the sled if the combined mass is 30 kg.
• Answer• Weight =F
g= mg
• =(30 kg)(9.8m/s2)= 294 NBack
Topic 5: 800• Question:• The effective force is in the direction of the acceleration. If the
35 N force is applied at angle of 27o, calculate the effective force.
• Why doesn’t the sled lift up?
• Answer• 294 N > 15.9 N(the vertical component)
Back
Topic 5: 1000• Question:• Calculate the skier’s effective force
• as he is pulled downhill.
• Answer
• sin Feffective/Fg 2
• sin 12 = Feffective
/(75 kg*9.8m/s ) Feffective
=75
kg*9.8m/s2)sin12
• =152.8 N
Back
Daily Double
The Winner Of The Last RoundWrite Down How Much Money
You Are Willing To RiskIf You get the Question write you win that money
If you get it wrong you Loss the money!
Daily Double
The Winner Of The Last RoundWrite Down How Much Money
You Are Willing To RiskIf You get the Question write you win that money
If you get it wrong you Loss the money!