workshop hall heroult
TRANSCRIPT
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Hall-Heroult Process
Electrochemical Process to Reduce Alumina to Aluminum Alumina is dissolved in a molten fluoride solvent called cryolite
2 Al2O3(cryolite) + 3 C(anode) 4 Al(liquid) + 3 CO2(g)12 e-
T = 960oC
Electrical work is needed:
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= -E 4 V
Electrolyte (cryolitic bath)
Na3AlF6 + (AlF3)excess + CaF2 + Al2O3
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Hall-Heroult Process
Electrochemical Process to Reduce Alumina to Aluminum Alumina is dissolved in a molten fluoride solvent called cryolite
Electrolyte (cryolitic bath)
Na3AlF6 + (AlF3)excess + CaF2 + Al2O3
CR = NaF / AlF3 (molar)
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by CR and %Al2O3
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Hall-Heroult Process
Examples:
1) Create a stream for a standard bath
2) Phase Diagrams (CR = 2.2; 5% CaF2)
3) Phase Diagrams (% Al2O3 vs xs-AlF3; 5%CaF2)
4) Adding reactants to the electrolyte (Al2O3)
5) Adding reactants to the electrolyte (Na2CO3)
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ng reac an s o e e ec ro y e 37) Carbide formation in the cathode blocks
8) Cathode / Collecting Bar / Refractory / Na(g)
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Hall-Heroult Process
Example #1: Create a stream for a standard bath
Create a stream of the following electrolyte
Na3AlF6+ 12.2 wt.% AlF3+ 5.0% CaF2+ 3.0% Al O
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The stream will be constrained in
enthalpy at 960oC.
This stream will be used as reactant
in several following examples.
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Example #1: Create a stream for a standard bath
FThall Database
79.8% Na3AlF6
+ 12.2 wt.% AlF3+ 5.0% CaF2+ 3.0% Al2O3
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Example #1: Create a stream for a standard bath
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Example #1: Create a stream for a standard bath
Hall-Heroult Process
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Example #2: Phase Diagrams
The cryolite (Na3AlF6) liquidus and the alumina (Al2O3) solubilityare very important for the cell operation.
The formation of a side-ledge protects the cell
lining from the corrosive electrolyte.
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Alumina has to be transported in the bathto the reaction site under the anode.
So a high solubility is better.
A mapping of these phase diagram
features will be useful.
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Example #2: Phase Diagrams (CR = 2.2; 5% CaF2)
FThall database
CR = NaF / AlF3
CR = 2.2
(NaF)2.2(AlF3)1.0
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File | Open HALLHEROULT_Isoplethal1
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Example #2: Phase Diagrams (CR = 2.2; 5% CaF2)
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Example #2: Phase Diagrams (CR = 2.2; 5% CaF2)
X-axis
Y-axis T = 800 1050oC
Hall-Heroult Process
( ) ( )100
111
100
3220.132.2
32=
++ OAlCaFAlFNaF
OAl
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Constants P = 1 atm
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( ) ( )0.5
111
100
3220.132.2
2=
++ OAlCaFAlFNaF
CaF
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Example #2: Phase Diagrams (CR = 2.2; 5% CaF2)
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Example #3: Phase Diagrams (% Al2O3 vs xs-AlF3; 5%CaF2)
FThall database
Na3
AlF6
AlF3(excess)
CaF2Al2O3
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T = 960oC
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File | Open HALLHEROULT_Isothermal2
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Example #3: Phase Diagrams (% Al2O3 vs xs-AlF3; 5%CaF2)
X-axis
Y-axis
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5001111
100
322363
3=
+++ OAlCaFAlFAlFNa
AlF
1001111
100
322363
32=
+++ OAlCaFAlFAlFNa
OAl
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Constants T = 960oC
P = 1 atm
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0.51111
100
322363
2=
+++ OAlCaFAlFAlFNaCaF
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Example #3: Phase Diagrams (% Al2O3 vs xs-AlF3; 5%CaF2)
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Example #4: Adding reactants to the electrolyte
The thermal/heat balance on the electrolytic cell is very important
The following additions are frequent:
Al2O3 for the reduction reaction
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Na2CO3 to increase CR3 Na2CO3 + 2 AlF3 6 NaF + Al2O3 + 3 CO2
AlF3 to decrease CR
CR = NaF / AlF3 (molar)
All these reactants are much colder than the cell (10oC 200oC)
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Hall-Heroult Process
Example #4: Adding reactants to the electrolyte (Al2O3)
File | Open HALLHEROULT_Add_Alumina
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Hall-Heroult Process
Example #4: Adding reactants to the electrolyte (Al2O3)
1.0 ton of Bath
(stream @ 960oC)
Alumina @ 125o
C-Al2O3-Al2O3Al2O3(H2O)
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Na2CO3(s) (@ 20oC)
Al(liq.) (@ 960oC)
AlF3(s)
(@ 50oC)
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Hall-Heroult Process
Example #4: Adding reactants to the electrolyte (Al2O3)
1.0 ton of Bath
(stream @ 960oC)
+ 5 kg Alumina-Al2O3-Al2O3Al2O3(H2O)
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Adiabatic Addition
Q = H = 0
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Hall-Heroult Process
Example #4: Adding reactants to the electrolyte (Al2O3)
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Hall-Heroult Process
Example #5: Adding reactants to the electrolyte (Na2CO3)
File | Open HALLHEROULT_Add_Soda
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Example #5: Adding reactants to the electrolyte (Na2CO3)
1.0 ton of Bath
(stream @ 960oC)
Na2CO3(s) (@ 20
o
C)
Al(liq.) (@ 960oC)
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2 3
added manually to thecell.
A bag can partially
touch the metal pad
below the bath and
react with it.
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Example #5: Adding reactants to the electrolyte (Na2CO3)
1.0 ton of Bath
(stream @ 960oC)
Na2CO3(s) (@ 20
o
C)
Al(liq.) (@ 960oC)
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2 3
added manually to thecell = 10 kg
A bag can partially
touch the metal pad
below the bath and
react with it
= 0 or 2 kg
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Example #5: Adding reactants to the electrolyte (Na2CO3)
Bags of Na2CO3 = 10 kg
metal pad
= 0 kg
Result
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T < 960oC
4.2 kg gas
(9.5 m3 gas)
986.7 kg bath
19.1 kg Na3AlF6
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Example #5: Adding reactants to the electrolyte (Na2CO3)
Bags of Na2CO3 = 10 kg
metal pad
= 2 kg
Result
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T > 960oC
2.2 kg gas
(7.8 m3 gas)
1009.6 kg bath
0.2 kg C
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Hall-Heroult Process
Example #6: Adding reactants to the electrolyte (AlF3)
File | Open HALLHEROULT_Add_AlF3
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H ll H l P
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Hall-Heroult Process
Example #6: Adding reactants to the electrolyte (AlF3)
1.0 ton of Bath
(stream @ 960oC)
AlF3(s)
(@ 50oC)
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H ll H lt P
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Hall-Heroult Process
Example #6: Adding reactants to the electrolyte (AlF3)
1.0 ton of Bath
(stream @ 960oC)
+ 5 kg AlF3(s)
(@ 50oC)
Adiabatic Addition
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H ll H lt P
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Hall-Heroult Process
Example #6: Adding reactants to the electrolyte (AlF3)
1.0 ton of Bath
(stream @ 960oC)
+ 5 kg AlF3(s)
(@ 50oC)
T = 956.00oC
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.
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Example #7: Carbide formation in the cathode blocks
The lifetime of the cell is very dependent on the cathode block(graphite) lifetime.
The cathode blocks can be degraded by mechanical erosion, but alsoby chemical reactions with the penetrating sodium vapors andliquid electrolyte.
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Sodium is generated at the metal
bath interface with
3 NaF + Al AlF3 + 3 Na
Residual N2 and CO can be
present in the carbon pores init.
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Na
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Example #7: Carbide formation in the cathode blocks
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Example #7: Carbide formation in the cathode blocks
Hall-Heroult Process
Bath; CR=2.2
C with smallamounts of N & O
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File | Open HALLHEROULT_Cathode1
Penetrating Na
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Example #7: Carbide formation in the cathode blocks
FACT53 Gas species
NaCN(liq.)
C
Fthall
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Metal
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Example #7: Carbide formation in the cathode blocks
X-axis
Y-axis
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10..0100
32=
OAl
( ) ( )01.0..0
111
1
3220.132.2
=
++ OAlCaFAlFNaF
Na
00.01 kg Na / kg of bath
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Constants T = 960oC & P = 1 atm
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( ) ( )5
111
100
3220.132.2
2=
++ OAlCaFAlFNaF
CaF
1113220.132.2
++ OACaFA FNaF
( ) ( )5
111
1
3220.132.2
=
++ OAlCaFAlFNaF
C
CaF2 is 5% of the mass of the bath
The carbon to bath mass ratio is fixed at 5.0(arbitrary)
0 10% Al2O3 in the bath
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Example #7: Carbide formation in the cathode blocks
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Hall Heroult Process
Example #8: Cathode / Collecting Bar / Refractory / Na(g)
The current collecting bar (steel) entrapped inside the cathode block(C-graphite);
a SiO2/Al2O3 layer is beneath it;
Na(vapors) percolated through the
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Cathode block from the metal pad;
Unwanted reaction products can
increase the electrical resistivity
$$
T 900-960oC
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Hall Heroult Process
Example #8: Cathode / Collecting Bar / Refractory / Na(g)
FACT53
Gas species FToxid
Refractory Mat.
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Steel
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File | Open HALLHEROULT_Cathode_CollectingBar
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Example #8: Cathode / Collecting Bar / Refractory / Na(g)
PNa is variedfrom 10-10 atm to10-1 atm
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Example #8: Cathode / Collecting Bar / Refractory / Na(g)
Extract & Plot
Results
Na(g)
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Example #8: Cathode / Collecting Bar / Refractory / Na(g)
X-axis : log10(PNa)
Na(g) is species #13
Y-axis : log10(grams)
Select all s ecies with
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Mole (max) > 0
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Example #8: Cathode / Collecting Bar / Refractory / Na(g)
At low log10(PNa)
C+ Austenite(fcc)
+ Refractory (SiO2 + mullite)
At intermediate log10(PNa)
C
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+ Austenite(fcc)
+ Albite (NaAlSi3O8) + SiO2
Higher:+ Slag+ Nepheline (NaAlSiO4)
At high log10(PNa)
C+ Ferrite(bcc)+ Slag (Na2SiO3 + NaAlO2-NaAlSiO4(s.s.))