1-phase transformer construction & working
DESCRIPTION
These ppt's describes the construction & working principle of transformer. phasor diagrams for leading & laginging power factors , equivalent circuits.The efficiency , condition for maximum efficiency,voltage regulation . Dr.Kapp voltage regulation diagram for finding the voltage regulation at any desired power factor.TRANSCRIPT
ELECTRICAL MACHINES – I
ELECTRICAL & ELECTRONICS ENGINEERING
SINGLE-PHASE TRANSFORMERSSINGLE-PHASE TRANSFORMERSSINGLE-PHASE TRANSFORMERSSINGLE-PHASE TRANSFORMERS
REVIEW ONREVIEW ON
MGIT
DEFINATIONTRANSFORMER IS A STATIC DEVICE WHICH TRANSFERS POWER FROM ONE
CIRCUIT TO ANOTHER CIRCUIT WITHOUT CHANGE IN FREQUENCY USUALLY WITH THE CHANGED VALUES OF VOLTAGES & CURRENTS.
PARTS OF TRANSFORMER
BASED ON THE OPERATION….
ABOUT TRANSFORMER…… A TRANSFORMER DOES NOT CHANGE THE FREQUENCY OF THE SYSTEM, IT
CAN BE TREATED AS CONSTANT FREQUENCY DEVICE.
AS TRANSFORMER TRANSFERS SAME AMOUNT OF POWER FROM ONE CIRCUIT TO ANOTHER CIRCUIT , IT CAN BE TREATED AS CONSTANT POWER DEVICE.
T/F IS A ELECTROMAGNETIC ENERGY CONVERSION DEVICE(IF INTERNAL PROCESS IS CONSIDERED).
T/F CAN BE TREATED AS “PHASE SHIFTING DEVICE” SINCE IT OFFERS DISPLACEMENT OF 180 BETWEEN TWO CIRCUITS.
T/F IS A SINGLY EXCITED DEVICE, SINCE IT REQUIRES ONLY ONE EXTERNAL VOLTAGE SOURCE TO ENRGISE ANY NO. OF WINDINGS PLACED ON IT’S CORE.
AS THE AMOUNT OF FLUX IN THE ORE IS CONSTANT IRRESPECTIVE OF POWER TRANSFER , IT CAN BE TREATED AS “CONSTANT FLUX DEVICE”.
WORKING PRINCIPLE OF A TRANSFORMER
A T/F IS WORKS BASED ON “ FARDAY’S LAWS OF ELECTROMAGNETIC INDUCTION” PRINCIPLE.
“WHEN EVER THERE IS A RELATIVE SPACE (OR) RELAITVE TIME VARIATION BETWEEN MAGNETIC FIELD AND CONDUCTOR THE EMF WILL BE INDUCED IN THAT CONDUCTOR”
BASIC REQIUREMENTS TO GENERATE THE EMF:
MAGNETIC FILED
SET OF CONDUCTORS
RELATIVE SPACE VARIATION(OR) RELAIVE TIME VARIATION
METHODS TO GENERATE EMF
RELATIVE SPACE VARIATION(RSV) :
MAGNETIC FIELD ARE STEADY(OR) TIME
INVARIANT.
SET OF CONDUCTORS ARE BEING MOVED
DNAMICALLY (OR) MOTIONALLY INDUCED EMF EX: GENERATORS
THE DIRECTION OF DYNAMICALLY INDUCED EMF AN BE FOUND BY FRHR
RELAIVE TIME VARIATION(RTV):
MAGNETIC FIELD -- TIME VARYNG
SET OF CONDUCTORS-- STATIONARY
STATICALLY INDUCED EMF EX: TRANSFORMERS
THE DIRECTION OF DYNAMICALLY INDUCED EMF AN BE FOUND BY LENZ’S LAW
Laminated
soft iron core
Primary coil Secondary coil
Input voltage
(a.c.)
Output voltage (a.c.)
How Transformer works
EMF EQUATION OF A TRANSFORMERLet
N1 = Number of turns in primary windings. N2 = Number of turns in second windings.
Øm = Maximum flux in the core in Webbers. Øm = Bm.A,
f = Frequency of A.C input in Hz.
As shown in fig- The flux increases from its zero value to maximum value Øm
in one quarter of the cycle i.e. in T/4 seconds.
Average rate of change of flux =
1
4 4
Tdt
f
md d
dt
CONT..Now Rate of change of flux per turn means ,the induced e.m.f per turn In volts. Average e.m.f /per turn = 4f Øm volt.
If flux Øm varies sinusoidally, then r.m.s value of induced .e.m.f is obtained by multiplying the average value with form factor. Form factor =r.m.s value / Average value =1.11
R.m.s value of e.m.f/turn = 1.11 4 f Øm = 4.44f Øm volt
Now R.m.s value of the induced e.m.f in the whole primary winding. =( induced e.m.f/turn) .* number of primary turns
E1 = 4.44fN1 Øm………………………………………(1)
E1 = 4.44fN1BmA. (Øm= BmA)
Semelerly, r.m.s value of the e.m.f. induced in secondry is, E2 = 4.44fN2 Øm
E2 = 4.44fN2BmA. (Øm= BmA)…………..(2)
CONT…It’s seen from (1) and (2) that E1/N1=E2/N2= = 4.44f Øm. It means that e.m.f/ turn is the same in both the primary and secondary windings.
SO in ideal Transformer on no-load, V1=E1 and E2=V2
VOLTAGE TRANSFERMATION RATIO:
2 2 2
1 11
4.44
4.
(2)
(1) 44
fN Øm N
fN Ø
Eequ
eq E mu N
SO in ideal Transformer on no-load, V1=E1 and E2=V2
2 2 2
1 1 1
E V NK
E V N
WHERE “ K ” IS CALLED VOLTAGE TRANSFERMATION RATIO CONSTANT
TRANSFORMER ON –NO LOAD
PRACTICLE T/F ON –NO LOAD
TYPES OF TRANSFORMERS
THERE ARE TWO GENERAL TYPES OF TRANSFORMERS. CORE TYPE TRANSFORMERSHELL TYPE TRANSFORMER THESE TWO DIFFER BY THE MANNERTHE WINDINGS WOUND AROUND THE MAGNETIC CORE. INORDER TO REDUCE THE EDDY CURRENT LOSSES THE CORE IS LAMINATED
INORDER TO REDUCE THE CORE LOSSES THE CORE S MANUFACTURED FROM THE COLD ROLLED GRAIN ORIENTED SHEET STEEL (C.R.G.O)
THERE ARE TWO TYPES OF WINDINGS EMPLOYED FOR TRANSFORMERSCONCENTRICINTERLEAVED
CONCENTRIC COILS ARE USED FOR CORE TYPE TRANSFORMERS
INTERLEAVED WINDINGS ARE USED FOR SHELL TYPE TRANSFORMERS.
T/F TYPES
Shell type T/F is used for LV
Core type T/F is used for HV
Toroid T/F are used for LV preferably in energy conversion systems & for LED.
CONSTRUCTION OF A TRANSFORMER CORE
CORE STAGGERING
SHELL TYPE T/F CORE STAGGERING
CORE TYPE TRANSFORMER
STEPPED CORE
SHELL TYPE TRANSFORMER
ECE 441 22
ΦP = net flux in window of primary ΦS = net flux in window of secondary
Φlp = leakage flux of primary Φls = leakage flux of secondary
ΦM = mutual flux
ΦP = ΦM + Φlp
ΦS = ΦM – Φls
EFFECT OF LEAKAGE FLUXES IN THE TRANSFORMER
PHASOR DIAGRAM OF A T/F WITH LAGGING PF
PHASOR DIAGRAM OF A T/F WITH LEADING PF
PHASOR DIAGRAM OF A T/F WITH UNITY PF
AB AC AD
AB AC AD
GRAINS DIRECTION AT DIFFERENT POINTS
EQUIVALENT RESISTANCE IN A T/F:
2 2 12 2 1 2
21 22 22
1
1 22 2
I R I R
IR R
I
RR
K
IN ORDER TO TRANSFER RESISTNCE FROM ONE SIDE TO ANOTHER SIDE THE POWER LOSS SHOULD BE SAME.
SECONDARY TO PRIMARY:
101 1 2
201 1 2
R R R
RR R
K
PRIMARY TO SECONDARY :
2 2 11 1 2 1
21 11 12
2
1 21 1
I R I R
IR R
I
R K R
102 2 1
202 2 1
R R R
R R K R
LEAKAGE FLUX IN A T/F
EQUIVALENT CIRCUIT OF A TRANSFORMER
EQUIVALENT REACTANCE IN A T/F:
IN ORDER TO TRANSFER REACTANCE FROM ONE SIDE TO ANOTHER SIDE THE PER UNIT DROP SHOULD BE SAME.
12 2 1 2
2
1 2 12 2
1 2
1 22 2
1
I X I X
E E
I EX X
I E
XX
K
101 1 2
201 1 2
X X X
XX X
K
SECONDARY TO PRIMARY:
NOW TOTAL IMPEDANCE REFERRED TO PRIMARY SIDE IS :
2 201 01 01Z R X
PRIMARY TO SECONDARY :
11 1 2 1
1 2
1 1 21 1
2 1
1 21 1
I X I X
E E
I EX X
I E
X K X
102 2 1
202 2 1
X X X
X X K X
NOW TOTAL IMPEDANCE REFERRED TO SECONDARY SIDE IS :
2 202 02 02Z R X
EXACT EQUIVALENT CIRCUIT OF A T/F WITH SECONDARY PARAMETERS REFERRED TO PRYMARY
APPROXIMATE EQUI CKT
EQUIVALENT CIRCUIT OF A T/F WITH PRYMARY PARAMETERS REFERRED TO SECONDARY
EFFECIENCY OF A T/F:The ratio of power output to power input of a T/F is called its efficiency (η).
Due to the losses in a transformer, its output power is less than the input power.
∴ Power output = Power input – Total losses ∴ Power input = Power output + Total losses = Power output + Pi + PCu
GENERALLY EFFICIENCY CAN BE EXPRESSED IN %
EFFICIENCY OF A T/F AT ANY LOAD X IS GIVEN BY
WHERE IS CALLED VA RATING OF THE TRANSFORMER 2 2FLV I
CONT…..
CONDITION FOR MAXIMUM EFFICIENCY IN A T/F:
During working of a transformer at constant voltage and frequency, its efficiency varies with the load. Its efficiency increases as the load increases. At a certain load, its efficiency becomes maximum. If the transformer is further loaded, its efficiency starts decreasing.
To determine the condition of maximum efficiency, let us assume that the power factor of the load remains constant and the secondary terminal voltage (V2) is constant. Therefore, efficiency becomes only a function of load current (I2).For maximum efficiency
CONT..
22 02iP I R i cuP P
TO ACHIEVE THE MAXIMUM EFFICIENCY IN A T/F THE COPPER LOSSES(VARIABLE LOSSES) SHOULD BE EQUAL TO IRON LOSSES(CONSTANT LOSSES)
AT THAT CONDITION LOAD CURRENT IS GIVEN BY
202
iPIR
ALL DAY EFFICIENCY The ratio of output in watts to input in watts is called commercial efficiency of a
transformer.
. Distribution transformers are used for supplying lighting and general networks.
In Distribution transformers Core loss occurs through out the day. Copper loss occurs only when they are loaded and hence is less important.
To judge their performance, all-day efficiency (or) operational efficiency is calculated.
The all-day efficiency is defined by
The all-day efficiency is less than the commercial efficiency of a transformer.
CONSTRUCTIONAL & DESIGN DEFFERENCES B/W POWER T/F & D.T/F
POWER TRANSFORMER DISTRIBUTION TRANSFORMER > 33 KV <33KV
Consumers are not directly connected Consumers are directly connected
Load fluctuations are Less Load Fluctuations are More
Fully loaded through out 24 hours Loaded based on load cycle of consumers
Cu losses & core losses takes place Cu losses load cycle of consumer & core losses takes place for 24 hrs
Cu loss are kept min while designing Core losses are kept min while designing
CRGO steel Amorphous steel
Specific weight less Specific weight more
Avg load on PT/F is nearer to full load Avg load on D.T/F is 70-75 % of full load
Max. effi will occur at nearer to full load Max. Effi will occur at 70-75 % of full load
Full load cu loss = core losses Full load cu loss= 2* core loss
Power efficiency All day efficiency
LOSSES IN A T/F
CORE LOSSESCOPPER LOSSES
EFFECT OF VOLTAGE & FREQUENCY ON CORE LOSSES
It is known that for a transformer,
V = 4.44 f Φm N = 4.44 f Bm A N Where A = area... Bm α (V/f) .......... For constant A and N
CONDITIONS
HYSTERISIS LOSS EDDDY CURRENT LOSS
CORE LOSS
‘f’ is Decreased Hysteresis losses increases
Eddy current Losses Constant
As hysteresis losses increases core losses
Increases
‘v’ is DecreasedHysteresis losses
DecreasesEddy current
Losses Decreases Core losses Decreases
maxx
hW B fv 2 2 2maxeW KB f t i h eW W W
tanv
cons tf
h
h
w f
w Af
2
2
e
e
W f
W Bf
2iW Af Bf
tanv
cons tf
1.6
0.6h
vw A
f 2
eW Bv1.6
20.6i
vw A Bv
f
CONT……
VOLTAGE REGULATION OF A T/F
THE CHANGE IN VOLTAGE FROM NO-LOAD TO FULL LOAD IS CALLED VOLTAGE REGULATION
FOR LAGGING PF
VOLTAGE REGULATION CURVE
KAPP VOLTAGE REGULATION DIAGRAM
DRAWING ALGORITHMIn order to create the diagram it is necessary to know the equivalent
reactance X02 and resistance R02 of the transformer as referred to the secondary side.
The following algorithm should be used:
Draw phasor OL representing secondary terminal voltage V2 on load. Draw OX representing the phase of the secondary current at an angle Φ2 to
OL such that cosΦ2 is the power factor of the load. Draw phasor LM (I2 R02 - voltage drop on resistance referred to the secondary
side) parallel to OX, and then MN (I2 X02 - voltage drop on reactance referred to the secondary side).
The resulting NL is the total voltage drop. Transfer the impedance triangle NLM to OO'P which gives O'L = ON = 0V2.
Therefore, for given secondary current the locus of N is a circle with centre O and radius 0V2, while the locus of L has the same radius but with the centre O'
To find the voltage drop on full load at any power factor the radius OQS should be drawn at at angle Φ to OX. If the impedance triangle is drawn in position UQT then OU = OS. The length of QS represents the voltage drop