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Page 1: 1 Sublinear Algorithms Lecture 1 Sofya Raskhodnikova Penn State University TexPoint fonts used in EMF. Read the TexPoint manual before you delete this

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Sublinear AlgorithmsLecture 1

Sofya RaskhodnikovaPenn State University

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OrganizationalCourse webpage:http://www.cse.psu.edu/~sxr48/sublinear-course/

Office hours:Tuesdays, 2:30PM-3:30PM, IST 343F

Evaluation• class participation• solutions to about 4 homework assignments• taking lecture notes about 2-3 times per person• the final project

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Tentative TopicsIntroduction, examples and general techniques.

Sublinear-time algorithms for• graphs• strings• geometric properties of images• basic properties of functions• algebraic properties and codes• metric spaces• distributions

Tools: probability, Fourier analysis, combinatorics, codes, …

Sublinear-space algorithms: streaming3

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Tentative PlanIntroduction, examples and general techniques.

Lecture 1. Background. Testing properties of images and lists.

Lecture 2. (Next week) Properties of functions and graphs. Sublinear approximation.

Lecture 3-5. Background in probability. Techniques for proving hardness. Other models for sublinear computation.

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Motivation for Sublinear-Time Algorithms

Massive datasets• world-wide web• online social networks• genome project• sales logs• census data• high-resolution images• scientific measurementsLong access time• communication bottleneck (slow connection)• implicit data (an experiment per data point)

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What Can We Hope For?

• What can an algorithm compute if it– reads only a sublinear portion of the data?– runs in sublinear time?

• Some problems have exact deterministic solutions

• For most interesting problems algorithms must be– approximate– randomized

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A Sublinear-Time Algorithm

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B L A - B L A - B L A - B L A - B L A - B L A - B L A - B L A

approximate answer

sublinear-time algorithm

? L? B ? L ? A

Quality of approximation

Resources• number of queries• running time

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Types of Approximation

Classical approximation• need to compute a value

output should be close to the desired value example: average

Property testing• need to answer YES or NO

Intuition: only require correct answers on two sets of instances that are very different from each other

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Classical Approximation

A Simple Example

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Approximate Diameter of a Point Set [Indyk]

Input: points, described by a distance matrix – is the distance between points and – satisfies triangle inequality and symmetry(Note: input size is )

Let be indices that maximize .

Maximum is the diameter.• Output: such that

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Algorithm and Analysis

1. Pick arbitrarily2. Pick to maximize 3. Output

• Approximation guarantee (triangle inequality) (choice of + symmetry of )

• Running time: 𝑖

𝑗

𝑘

A rare example of a deterministic sublinear-time algorithm

Algorithm

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Property Testing

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Property Testing: YES/NO Questions

Does the input satisfy some property? (YES/NO)

“in the ballpark” vs. “out of the ballpark”

Does the input satisfy the property or is it far from satisfying it?

• sometimes it is the right question (probabilistically checkable proofs (PCPs))• as good when the data is constantly changing (WWW)• fast sanity check to rule out inappropriate inputs (airport security questioning)

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Property Tester

Close to YES

Far from YES

YES

Reject with probability 2/3

Don’t care

Accept with probability

Property Tester Definition

Probabilistic Algorithm

YES Accept with probability

Reject with probability 2/3

NO

far = differs in many places - ( fraction of places)

𝜀

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Randomized Sublinear Algorithms

Toy Examples

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Test

Property Testing: a Toy Example

Input: a string Question: Is ?

Requires reading entire input.Approximate version: Is or

does it have 1’s (“errors”)?

1. Sample positions uniformly and independently at random2. If 1 is found, reject; otherwise, accept

Analysis: If , it is always accepted. If is -far, Pr[error] = Pr[no 1’s in the sample]

If a test catches a witness with probability , then iterations of the test catch a witness with probability

Used:

Witness Lemma

0 0 0 1 … 0 1 0 0

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Randomized Approximation: a Toy Example

Input: a string Goal: Estimate the fraction of 1’s in (like in polls)It suffices to sample positions and output the average to get the

fraction of 1’s (i.e., additive error ) with probability ¸ 2/3

= value of sample . Then E[Y] (fraction of 1’s in )

Let be independently distributed random variables in [0,1] and let (sample sum). Then .

0 0 0 1 … 0 1 0 0

Hoeffding Bound

Apply Hoeffding Bound with substitute

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Property Testing

Simple Examples

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Testing Properties of Images

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Pixel Model

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Query: point

Answer: color of

Input: matrix of pixels(0/1 values for black-and-white pictures)

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Testing if an Image is a Half-plane [R03]

A half-plane or -far from a half-plane?

O(1/ time

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Half-plane Instances

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A half-plane -far from a half-plane

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Half-plane Instances

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A half-plane -far from a half-plane

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Half-plane Instances

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A half-plane -far from a half-plane

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Half-plane Instances

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A half-plane -far from a half-plane

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Half-plane Instances

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A half-plane -far from a half-plane

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Half-plane Instances

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A half-plane -far from a half-plane

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Half-plane Instances

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A half-plane -far from a half-plane

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Strategy

“Testing by implicit learning” paradigm

• Learn the outline of the image by querying a few pixels.• Test if the image conforms to the outline by random sampling,

and reject if something is wrong.

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Half-plane Test

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Claim. The number of sides with different corners is 0, 2, or 4.

Algorithm1. Query the corners.

? ?

? ?

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Half-plane Test: 4 Bi-colored Sides

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Claim. The number of sides with different corners is 0, 2, or 4.

Analysis• If it is 4, the image cannot be a half-plane.

Algorithm1. Query the corners.2. If the number of sides with different corners is 4, reject.

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Half-plane Test: 0 Bi-colored Sides

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Claim. The number of sides with different corners is 0, 2, or 4.

Analysis• If all corners have the same color, the image is a

half-plane if and only if it is unicolored.

Algorithm1. Query the corners.2. If all corners have the same color , test if all pixels have color (as in Toy Example 1).

?

?

??

?

?

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Half-plane Test: 2 Bi-colored Sides

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Claim. The number of sides with different corners is 0, 2, or 4.

Algorithm1. Query the corners.2. If # of sides with different corners is 2, on both sides find 2 different

pixels within distance by binary search.3. Query pixels from 4. Accept iff all pixels are white and all pixels are black.

Analysis• The area outside of has pixels. • If the image is a half-plane, W contains only

white pixels and B contains only black pixels.• If the image is -far from half-planes, it has

wrong pixels in • By Witness Lemma, samples suffice to catch a

wrong pixel.

? ?𝜀𝑛 /2

??𝜀𝑛 /2

𝑊

𝐵

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Testing if an Image is a Half-plane [R03]

A half-plane or -far from a half-plane?

O(1/ time

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Other Results on Properties of Images

• Pixel ModelConvexity [Berman Murzabulatov R]Convex or -far from convex?

O(1/ time

Connectedness [Berman Murzabulatov R]Connected or -far from connected?

O(1/ time

Partitioning [Kleiner Keren Newman 10]Can be partitioned according to a template or is -far?

time independent of image size• Properties of sparse images [Ron Tsur 10]

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Testing if a List is Sorted

Input: a list of n numbers x1 , x2 ,..., xn

• Question: Is the list sorted?Requires reading entire list: (n) time

• Approximate version: Is the list sorted or ²-far from sorted? (An ² fraction of xi ’s have to be changed to make it sorted.)

[Ergün Kannan Kumar Rubinfeld Viswanathan 98, Fischer 01]: O((log n)/²) time (log n) queries• Attempts: 1. Test: Pick a random i and reject if xi > xi+1 .

Fails on: 1 1 1 1 1 1 1 0 0 0 0 0 0 0 Ã 1/2-far from sorted

2. Test: Pick random i < j and reject if xi > xj.

Fails on: 1 0 2 1 3 2 4 3 5 4 6 5 7 6 Ã 1/2-far from sorted

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Is a list sorted or ²-far from sorted?

Idea: Associate positions in the list with vertices of the directed line.

Construct a graph (2-spanner)• by adding a few “shortcut” edges (i, j) for i < j• where each pair of vertices is connected by a path of length at most 2

……

≤ n log n edges

1 2 3 … n-1 n

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Is a list sorted or ²-far from sorted?

Pick a random edge (xi ,xj) from the 2-spanner and reject if xi > xj.

1 2 5 4 3 6 7Analysis:• Call an edge (xi ,xj) violated if xi > xj , and good otherwise.• If xi is an endpoint of a violated edge, call it bad. Otherwise, call it good.

Proof: Consider any two good numbers, xi and xj.

They are connected by a path of (at most) two good edges (xi ,xk), (xk ,xj).

) xi ≤ xk and xk ≤ xj

) xi ≤ xj

12

12

5 4 3xi xj

xk

Claim 1. All good numbers xi are sorted.

Test [Dodis Goldreich Lehman Raskhodnikova Ron Samorodnitsky 99]

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Test [Dodis Goldreich Lehman Raskhodnikova Ron Samorodnitsky 99]

Is a list sorted or ²-far from sorted?

Pick a random edge (xi ,xj) from the 2-spanner and reject if xi > xj.

1 2 5 4 3 6 7Analysis:• Call an edge (xi ,xj) violated if xi > xj , and good otherwise.• If xi is an endpoint of a bad edge, call it bad. Otherwise, call it good.

Proof: If a list is ²-far from sorted, it has ¸ ² n bad numbers. (Claim 1)• Each violated edge contributes 2 bad numbers. • 2-spanner has ¸ ² n/2 violated edges out of · n log n.

12

12

5 4 3xi xj

xk

Claim 1. All good numbers xi are sorted. Claim 2. An ²-far list violates ¸ ² /(2 log n) fraction of edges in 2-spanner.

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Is a list sorted or ²-far from sorted?

Pick a random edge (xi ,xj) from the 2-spanner and reject if xi > xj.

1 2 5 4 3 6 7Analysis:• Call an edge (xi ,xj) violated if xi > xj , and good otherwise.

By Witness Lemma, it suffices to sample (4 log n )/² edges from 2-spanner.

Sample (4 log n)/ ² edges (xi ,xj) from the 2-spanner and reject if xi > xj.

Guarantee: All sorted lists are accepted.All lists that are ²-far from sorted are rejected with probability ¸2/3.Time: O((log n)/²)

12

12

5 4 3xi xj

xk

Test [Dodis Goldreich Lehman Raskhodnikova Ron Samorodnitsky 99]

Algorithm

Claim 2. An ²-far list violates ¸ ² /(2 log n) fraction of edges in 2-spanner.

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Generalization

Observation: The same test/analysis apply to any edge-transitive property of a list of

numbers that allows extension.

• A property is edge-transitive if1) it can be expressed in terms conditions on ordered pairs of numbers

2) it is transitive: whenever and satisfy (1), so does

• A property allows extension if3) any function that satisfies (1) on a subset of the numbers can be

extended to a function with the property

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12

x y z

12

x y

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Testing if a Function is Lipschitz [Jha R]

A function f : D R is Lipschitz if it has Lipschitz constant c:that is, if for all x,y in D,

distanceR(f(x),f(y)) ≤ distanceD(x,y).• can rescale by to get a Lipschitz function from a function with Lipschitz

constant

Consider f : {1,…,n} R:

The Lipschitz property is edge-transitive:

1. a pair (x,y) is good if |f(y)-f(x)| ≤ |y-x|2. (x,y) and (y,z) are good ) (x,z) is good It also allows extension for the range R.Testing if a function f : {1,…,n} R is Lipschitz takes O((log n )/²) time.

Does the spanner-based test apply if the range is with Euclidean distances? with Euclidean distances?

nodes = points in the domain; edges = points at distance 1node labels = values of the function

2 3 3 5421

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Properties of a List of n Numbers

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• Sorted or -far from sorted?

• Lipschitz (does not change too drastically) or -far from satisfying the Lipschitz property?

O(log n/ time

This bound is tight [Chakrabarty Dixit Jha Seshadhri 15]

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Basic Properties of Functions

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f(000)

f(111) f(011)

f(100)

f(101)

f(110)f(010)

f(001)

Boolean Functions

Graph representation:-dimensional hypercube

• vertices: bit strings of length • edges: is an edge if can be obtained from by increasing one

bit from 0 to 1

• each vertex is labeled with

001001 011001

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Monotonicity of Functions

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[Goldreich Goldwasser Lehman Ron Samorodnitsky, Dodis Goldreich Lehman Raskhodnikova Ron Samorodnitsky Fischer Lehman Newman Raskhodnikova Rubinfeld Samorodnitsky]

• A function is monotone if increasing a bit of does not decrease .

• Is monotone or -far from monotone ( has to change on many points to become monontone)?

– Edge is violated by if .

Time: – , logarithmic in the size of the input, – for restricted class of tests– Recent: for nonadaptive tests

[Khot Minzer Safra 15, Chen De Servidio Tang 15]

0

0 0

01

1

1

1

1

1 0

00

0

1

1

monotone

-far from monotone

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Monotonicity Test [GGLRS, DGLRRS]

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Idea: Show that functions that are far from monotone violate many edges.

Analysis• If is monotone, EdgeTest always accepts. • If is -far from monotone, by Witness Lemma, it suffices to show that

fraction of edges (i.e., edges) are violated by .– Let denote the number of edges violated by .

Contrapositive: If , can be made monotone by changing values.

EdgeTest (, ε)1. Pick 2 edges uniformly at random from the hypercube.2. Reject if some is violated (i.e. . Otherwise, accept.

Repair Lemma can be made monotone by changing values.

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Repair Lemma: Proof Idea

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Proof idea: Transform f into a monotone function by repairing edges in one dimension at a time.

Repair Lemma can be made monotone by changing values.

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Repairing Violated Edges in One Dimension

0 0 0 0

1

1

1

0

0

0

0

0

1

1

0

1

Swapping horizontal dimension

Swap violated edges 10 in one dimension to 01.

Let = # of violated edges in dimension

Enough to prove the claim for squares

i

j

Claim. Swapping in dimension does not increase for all dimensions

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Proof of The Claim for Squares

• If no horizontal edges are violated, no action is taken.

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Swapping horizontal dimension

i

j

Claim. Swapping in dimension does not increase for all dimensions

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Proof of The Claim for Squares

• If both horizontal edges are violated, both are swapped, so the number of vertical violated edges does not change.

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Swapping horizontal dimension

i

j

01 10

1 0 0 1

Claim. Swapping in dimension does not increase for all dimensions

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Proof of The Claim for Squares

• Suppose one (say, top) horizontal edge is violated.• If both bottom vertices have the same label, the vertical edges

get swapped.

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i

j

Swapping horizontal dimension

1 0 0 1

𝒗𝒗 𝒗𝒗

Claim. Swapping in dimension does not increase for all dimensions

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Proof of The Claim for Squares

• Suppose one (say, top) horizontal edge is violated.• If both bottom vertices have the same label, the vertical edges

get swapped. • Otherwise, the bottom vertices are labeled 01, and the

vertical violation is repaired.55

i

j

Swapping horizontal dimension

1 0 0 1

10 10

Claim. Swapping in dimension does not increase for all dimensions

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Proof of The Claim for Squares

After we perform swaps in all dimensions:• becomes monotone• # of values changed:

• Improve the bound by a factor of 2.56

Claim. Swapping in dimension does not increase for all dimensions

Repair Lemma can be made monotone by changing values.

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Testing if a Functions is monotone

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Monotone or -far from monotone?

O(n/ time (logarithmic in the size

of the input)

0

0 0

01

1

1

1

1

1 0

00

0

1

1

monotone

-far from monotone