15 solving equations - bainbridge island school district · 1.5 notes alg1.notebook september 10,...
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![Page 1: 15 Solving Equations - Bainbridge Island School District · 1.5 Notes Alg1.notebook September 10, 2012 4) 4 – 6a + 4a = –1 – 5(7 – 2a) II. Solving Harder "Both Sides" 5. 6](https://reader034.vdocuments.net/reader034/viewer/2022051607/602b9b76f63ad5040444f9e0/html5/thumbnails/1.jpg)
1.5 Notes Alg1.notebook September 10, 2012
Simplify.1. 4x 10x 2. –7(x – 3)
3. 4. 15 – (x – 2)
Solve.
5. 3x + 2 = 8 6.
15 Solving Equations with Variables on Both Sides
![Page 2: 15 Solving Equations - Bainbridge Island School District · 1.5 Notes Alg1.notebook September 10, 2012 4) 4 – 6a + 4a = –1 – 5(7 – 2a) II. Solving Harder "Both Sides" 5. 6](https://reader034.vdocuments.net/reader034/viewer/2022051607/602b9b76f63ad5040444f9e0/html5/thumbnails/2.jpg)
1.5 Notes Alg1.notebook September 10, 2012
1.5 Solving Equations with Variables on Both Sides
Solving equations in one variable that contain variable terms on both sides.
For Example...
1) 7n – 2 = 5n + 6. 2) 4b + 2 = 3b.
3) 0.5 + 0.3y = 0.7y – 0.3
I. Solving Both Sides
![Page 3: 15 Solving Equations - Bainbridge Island School District · 1.5 Notes Alg1.notebook September 10, 2012 4) 4 – 6a + 4a = –1 – 5(7 – 2a) II. Solving Harder "Both Sides" 5. 6](https://reader034.vdocuments.net/reader034/viewer/2022051607/602b9b76f63ad5040444f9e0/html5/thumbnails/3.jpg)
1.5 Notes Alg1.notebook September 10, 2012
4) 4 – 6a + 4a = –1 – 5(7 – 2 a)
II. Solving Harder "Both Sides"
5. 6. 3x + 15 – 9 = 2(x + 2)
Solve
![Page 4: 15 Solving Equations - Bainbridge Island School District · 1.5 Notes Alg1.notebook September 10, 2012 4) 4 – 6a + 4a = –1 – 5(7 – 2a) II. Solving Harder "Both Sides" 5. 6](https://reader034.vdocuments.net/reader034/viewer/2022051607/602b9b76f63ad5040444f9e0/html5/thumbnails/4.jpg)
1.5 Notes Alg1.notebook September 10, 2012
Move variables first to avoid confusion!
3x + 7 = 3x + 7
versus 3x + 7 = 3x + 7
![Page 5: 15 Solving Equations - Bainbridge Island School District · 1.5 Notes Alg1.notebook September 10, 2012 4) 4 – 6a + 4a = –1 – 5(7 – 2a) II. Solving Harder "Both Sides" 5. 6](https://reader034.vdocuments.net/reader034/viewer/2022051607/602b9b76f63ad5040444f9e0/html5/thumbnails/5.jpg)
1.5 Notes Alg1.notebook September 10, 2012
7) Solve 10 – 5x + 1 = 7x + 11 – 12x.
III. Solving Infinite and No Solutions
8) Solve 60 + 3x = 10 + 3(x 1)
![Page 6: 15 Solving Equations - Bainbridge Island School District · 1.5 Notes Alg1.notebook September 10, 2012 4) 4 – 6a + 4a = –1 – 5(7 – 2a) II. Solving Harder "Both Sides" 5. 6](https://reader034.vdocuments.net/reader034/viewer/2022051607/602b9b76f63ad5040444f9e0/html5/thumbnails/6.jpg)
1.5 Notes Alg1.notebook September 10, 2012
8) Solve 12x – 3 + x = 5x – 4 + 8x.
9) Solve 4y + 7 – y = 10 + 3y.
10) Solve 2c + 7 + c = –14 + 3c + 21.
Jon and Sara are planting tulip bulbs. Jon has planted 60 bulbs and is planting at a rate of 44 bulbs per hour. Sara has planted 96 bulbs and is planting at a rate of 32 bulbs per hour. In how many hours will Jon and Sara have planted the same number of bulbs? How many bulbs will that be?
Expression for Jon:
Expression for Sara:
SET EQUAL
IV. Application
![Page 7: 15 Solving Equations - Bainbridge Island School District · 1.5 Notes Alg1.notebook September 10, 2012 4) 4 – 6a + 4a = –1 – 5(7 – 2a) II. Solving Harder "Both Sides" 5. 6](https://reader034.vdocuments.net/reader034/viewer/2022051607/602b9b76f63ad5040444f9e0/html5/thumbnails/7.jpg)
1.5 Notes Alg1.notebook September 10, 2012
Check!
Four times Greg's age, decreased by 3 is equal to 3 times Greg's age increased by 7. How old is Greg?
11.
Let g represent Greg's age, and write expressions for his age.
![Page 8: 15 Solving Equations - Bainbridge Island School District · 1.5 Notes Alg1.notebook September 10, 2012 4) 4 – 6a + 4a = –1 – 5(7 – 2a) II. Solving Harder "Both Sides" 5. 6](https://reader034.vdocuments.net/reader034/viewer/2022051607/602b9b76f63ad5040444f9e0/html5/thumbnails/8.jpg)
1.5 Notes Alg1.notebook September 10, 2012
1.5 Lesson Quiz
1. 7x + 2 = 5x + 8 Solve each equation.
2. 4(2x – 5) = 5x + 4
3. 6 – 7(a + 1) = –3(2 – a)
4. 4(3x + 1) – 7x = 6 + 5x – 2
5.
A painting company charges $250 base plus $16 per hour. Another painting company charges $210 base plus $18 per hour. How long is a job for which the two companies costs are the same?
6.
![Page 9: 15 Solving Equations - Bainbridge Island School District · 1.5 Notes Alg1.notebook September 10, 2012 4) 4 – 6a + 4a = –1 – 5(7 – 2a) II. Solving Harder "Both Sides" 5. 6](https://reader034.vdocuments.net/reader034/viewer/2022051607/602b9b76f63ad5040444f9e0/html5/thumbnails/9.jpg)
1.5 Notes Alg1.notebook September 10, 2012
1.5 Page 43, #1535, 3751 odd, 5263, 6669