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  • 8/10/2019 A.a.frankel Section4

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    L O G I C A L P R O B L E M S O F F I N I T E N E S S A N D I N F I N IT Y

    7

    Section 4 Logical Problems of Finiteness and Infinity

    The Axiom of Choice

    So far we have defined the finiteness of a

    set

    by means of the concept

    of finite

    number

    (integer ; see p. 4). In this sense we shall more specifically

    call a finite set, including the null set, an

    inductive set

    referring to mathe-

    matical induction (sometimes called inference from n to n

    ),

    which is characteristic of the theory of positive integers, and hence also

    of inductive sets. Bertrand Russell has shown that the explicit reference

    to integers can be eliminated

    from this definition of finite sets, and Tarski

    presented several definitions, seemingly quite different, which can be proved

    to be logically equivalent to the definition of an inductive set and to

    each other in an elementary sense, namely, without use of the axiom of

    choice [see Tarski (1925)].

    Yet there are other, fundamentally different definitions of finiteness and

    infinity; we shall now examine one to which we have already referred on

    p. 15. Surprisingly enough, this will lead us to a novel logico-mathematical

    problem which for sixty years caused difficulties and heated discussions in

    the world of science and which was finally solved, rather unexpectedly, in

    1963.

    We start with a theorem which looks quite harmless but which actually

    conceals far-reaching depths:

    T H E O R E M

    1. Every infinite set I includes a denumerable subset.

    Proof.

    In accordance with the above concept of finiteness we here

    consider infinite to mean noninductive. The theorem will be proved

    by mathematical induction, as is usual in arithmetic.

    1 The p rinciple of m athematical induct ion may be expressed briefly as fol lows : a set

    which contains the member 1 and which, together with any element

    n,

    also contains

    n 1,

    contains

    allpositive

    ntegers . By replacing 1 by 0,

    we ob tain the non-negative integers.)

    2

    Viz. by the following definitions a) a set of cardinals is called

    hereditary

    if the

    fact that it contains

    n

    implies that it contains

    n 1;

    b) a cardinal is called

    inductive

    if it

    belongs to every hereditary set that contains 1 ; c) a set is called

    inductive

    if i ts cardinal

    is inductive. [Note that

    n

    1 in a) is taken in the sense of union, i.e ., of adding ele-

    ments.]

    Cf. the references in footnote 6 on p. 10.

    26

    W e

    start by choosing an arbitrary element i

    of the nonempty set I,

    and form the subset Si

    = {i1

    } of / which contains a single element. The

    remainder, I = / S1

    , is not empty, since otherwise / would contain one

    element only and not infinitely many; therefore we may choose an arbi-

    trary element i2

    of I and form the subset

    S2 = {i1 i2}

    of I which contains

    two elements. We may now inductively assume that after n such steps

    (n denoting any positive integer) we have arrived at a subset

    S

    n

    = {i i 2

    i}

    of / which contains n elements. Since the remainder, I

    = /

    Sn

    ,

    is still

    infinite, we can choose an arbitrary element i

    n 4

    .1

    of /; by adding it to the

    elements of S

    n

    we obtain a subset S

    n+

    = {i1

    , i

    2, , in, in 1}

    3f

    which

    contains n 1 elements. Hence, by the induction principle, for

    any

    positive

    integer n there exists a subset

    S

    of / which contains just n members; these

    subsets form an infinite sequence (S

    1

    , S ,

    , S

    n, .

    Moreover, they have

    been chosen so that any

    Sn

    includes the preceding ones; that is to say,

    for m