a.a.frankel section4
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8/10/2019 A.a.frankel Section4
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L O G I C A L P R O B L E M S O F F I N I T E N E S S A N D I N F I N IT Y
7
Section 4 Logical Problems of Finiteness and Infinity
The Axiom of Choice
So far we have defined the finiteness of a
set
by means of the concept
of finite
number
(integer ; see p. 4). In this sense we shall more specifically
call a finite set, including the null set, an
inductive set
referring to mathe-
matical induction (sometimes called inference from n to n
),
which is characteristic of the theory of positive integers, and hence also
of inductive sets. Bertrand Russell has shown that the explicit reference
to integers can be eliminated
from this definition of finite sets, and Tarski
presented several definitions, seemingly quite different, which can be proved
to be logically equivalent to the definition of an inductive set and to
each other in an elementary sense, namely, without use of the axiom of
choice [see Tarski (1925)].
Yet there are other, fundamentally different definitions of finiteness and
infinity; we shall now examine one to which we have already referred on
p. 15. Surprisingly enough, this will lead us to a novel logico-mathematical
problem which for sixty years caused difficulties and heated discussions in
the world of science and which was finally solved, rather unexpectedly, in
1963.
We start with a theorem which looks quite harmless but which actually
conceals far-reaching depths:
T H E O R E M
1. Every infinite set I includes a denumerable subset.
Proof.
In accordance with the above concept of finiteness we here
consider infinite to mean noninductive. The theorem will be proved
by mathematical induction, as is usual in arithmetic.
1 The p rinciple of m athematical induct ion may be expressed briefly as fol lows : a set
which contains the member 1 and which, together with any element
n,
also contains
n 1,
contains
allpositive
ntegers . By replacing 1 by 0,
we ob tain the non-negative integers.)
2
Viz. by the following definitions a) a set of cardinals is called
hereditary
if the
fact that it contains
n
implies that it contains
n 1;
b) a cardinal is called
inductive
if it
belongs to every hereditary set that contains 1 ; c) a set is called
inductive
if i ts cardinal
is inductive. [Note that
n
1 in a) is taken in the sense of union, i.e ., of adding ele-
ments.]
Cf. the references in footnote 6 on p. 10.
26
W e
start by choosing an arbitrary element i
of the nonempty set I,
and form the subset Si
= {i1
} of / which contains a single element. The
remainder, I = / S1
, is not empty, since otherwise / would contain one
element only and not infinitely many; therefore we may choose an arbi-
trary element i2
of I and form the subset
S2 = {i1 i2}
of I which contains
two elements. We may now inductively assume that after n such steps
(n denoting any positive integer) we have arrived at a subset
S
n
= {i i 2
i}
of / which contains n elements. Since the remainder, I
= /
Sn
,
is still
infinite, we can choose an arbitrary element i
n 4
.1
of /; by adding it to the
elements of S
n
we obtain a subset S
n+
= {i1
, i
2, , in, in 1}
3f
which
contains n 1 elements. Hence, by the induction principle, for
any
positive
integer n there exists a subset
S
of / which contains just n members; these
subsets form an infinite sequence (S
1
, S ,
, S
n, .
Moreover, they have
been chosen so that any
Sn
includes the preceding ones; that is to say,
for m