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Air Pollution : L 5
01/11/2017
Some Useful Concepts:
• Maximum mixing height/ depth ?
• Ventilation coefficient ?
• Wind-‐rose diagram ?
Atmospheric Stability and Mixing Depth
• The amount of air available to dilute pollutants is related to the wind speed and to the extent to which emissions can rise into the atmosphere.
• An estimate of this (dilution process) can be obtained by determining “maximum mixing depth”
Estimation of Maximum mixing depth and ventilation coefficient
• Following the logic presented earlier, the maximum mixing depth can be estimated by plotting maximum surface temperature and drawing a line parallel to the dry adiabatic lapse rate from the point of maximum surface temperature to the point at which the line intersects the ambient or natural temperature profile (usually of early morning or night)
Ventilation Coefficient (m2/s) = MMD (m) * Avg wind speed within mixing depth (m/s) This parameter is used as an indicator of the atmosphere’s dispersive capability If ventilation coefficient< 6000 m2/s, air pollution potential is considered to be high.
MMD
Ambient temp. profile
Tmax Æ T Æ
Z
Wind-rose diagram
Maximum Ground Level ConcentrationUnder moderately stable to near neutral conditions,
zy k σσ 1=
The ground level concentration at the center line is
( ) ⎥⎦
⎤⎢⎣
⎡−= 2
2
21 2
exp0,0,zz
Huk
QxCσσπ
The maximum occurs at
2 0/ HddC zz =σ⇒=σ
Once σz is determined, x can be known and subsequently C.
( ) [ ]u
Qu
QxCzyzy σσ
=−σπσ
= 1171.01exp0,0,
Discussion….
• 1. In the Holland's formula for finding the plume rise, there is a direct proportionality of Plume rise with the stack diameter. But this is against the intuitive reasoning that we gave in class. If the stack diameter decreases, the exit velocity of the gases increase and hence the Plume rise must increase.
• Why the formula suggest the opposite thing?
• 2. In the case of perfect absorption, which formula should be used. Is it the one where only the (z-‐H)^2 term appears in the exponent.
• Also, should we always consider perfect reflection in case there is nothing specified about the type surface?
Wark & Warner, “Air Pollution: Its Origin & Control”
( ) ( ) ( )⎪⎭
⎪⎬⎫
⎪⎩
⎪⎨⎧
⎥⎦
⎤⎢⎣
⎡
σ
+−+⎥
⎦
⎤⎢⎣
⎡
σ
−−
⎥⎥⎦
⎤
⎢⎢⎣
⎡
σ−
σπσ= 2
2
2
2
2
2
2exp
2exp
2exp
2,,
zzyzy
HzHzyu
QzyxC
Point Source at Elevation H
• Assumes no interference or limitation to dispersion in any directiondispersion in any direction
d l i f li f lx0 and z0 are location of centerline of plumey0 taken as base of the stackz0 is HQ = emission strength of source (mass/time) – g/su = average wind speed thru the plume – m/sC = concentration – g/m3 (Notice this is not ppm)
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Vy and Vz are horizontal and vertical standard deviations in meters
Point Source at Elevation H with Reflection
Notice this is also equation 4-8 in text, it is the second equation 4-8 on theit is the second equation 4 8 on the bottom of page 149
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Point Source at Elevation H without Reflection
• 3 terms– gives concentration on the centerline of the plume– gives concentration as you move in the sideways direction (r y
2direction), direction doesn’t matter because (r y)2 gives a positive value
– gives concentration as you move in the vertical direction (r z direction) direction doesn’t matter because (r (z H))2 gives adirection), direction doesn t matter because (r (z – H))2 gives a positive value
• Concentrations are symmetric about y-axis and z-axis• Same concentration at (z-H) = 10 m as (z-H) =10 m
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• Same concentration at (z-H) 10 m as (z-H) 10 m• Close to ground symmetry is disturbed
Effect of Inversion
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Virtual Source Also Used to Model ReflectionOff of the Top of the Mixed Layer
(added to direct plume concentration)
Eventually well-mixed
Plume Reflection off of the top of the mixed layer
wind
zii
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Virtual Source Also Used to Model ReflectionOff of the Top of the Mixed Layer
(added to direct plume concentration)
Eventually well-mixed
Plume Reflection off of the top of the mixed layer
wind
zii
• 3. Why Gaussian dispersion model is only limited to finding concentration of pollutants beyond X = 50 m?
• 4. In the example that we did in class for the Briggs method, the final condition that whether x > xf is not included. The desired location(x) for concentration measurement is not specified.
• Is the information insufficient in the question?
• 5. Logical explanation of why the stability decreased with the wind in the table that we had in the slides??
Line Sources
• Imagine that a line source, such as a highway, consists of an infinite number of g y,point sources
• The roadway can be broken into finiteThe roadway can be broken into finite elements, each representing a point source, and contributions from each element areand contributions from each element are summed to predict net concentration
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Line SourcesLine Sources• When wind direction is normal to line of emission
G d l l i d i d• Ground level concentration downwind
C( 0) 2 ( 0 5H2)C(x,0) = ___ 2q ___ exp(-0.5H2)(2Π)0.5 Vz u Vz
2
q = source strength per unit distance (g/s * m)
Concentration should be uniform in the y-direction at a given x
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g
Line SourcesLine Sources• For ground level (H = 0), could also use breathing
heightheight
C(x 0) = 2q exp( 0 5H2)
1
C(x,0) = ___ 2q ___ exp(-0.5H )(2Π)0.5 Vz u Vz
2
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Instantaneous Release of a Puff• Pollutant released quickly
E l i• Explosion• Accidental spill• Release time << transport time• Also based on Gaussian distributionAlso based on Gaussian distribution
function
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Instantaneous Release of a PuffInstantaneous Release of a Puff
• Equation 4-41 to predict maximum ground level q p gconcentration
Cmax = _____2Qp____(2Π)3/2 Vx Vy Vz
Receptor downwind would see a gradual increase in t ti til t f ff d d thconcentration until center of puff passed and then
concentration would decreaseAssume V = V
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Assume Vx Vy
Maximum Ground Level Concentration
Puff ExampleA tanker spill on the freeway releases 400 000 grams of chlorineA tanker spill on the freeway releases 400,000 grams of chlorine. What exposure will vehicles directly behind the tanker (downwind) receive if x =100 m? Assume very stable conditions.
From Table 4-7,
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Figure 4-9 and Table 4-7
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Puff ExampleA tanker spill on the freeway releases 400 000 grams of chlorineA tanker spill on the freeway releases 400,000 grams of chlorine. What exposure will vehicles directly behind the tanker (downwind) receive if x =100 m? Assume very stable conditions.
From Table 4-7, Vy = 0.02(100m)0.89 = 1.21
F T bl 4 7 0 05(100 )0 61 0 83From Table 4-7, Vz = 0.05(100m)0.61 = 0.83
Cmax = _____2Qp____ = ____2(400000 g)_____ = 42,181 g/m3
(2Π)3/2 Vx Vy Vz (2Π)3/2(1.21)(1.21)(0.83)
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