evaluating algebraic expressions 1-7 solving equations by adding or subtracting warm up warm up...
Post on 19-Jan-2016
221 Views
Preview:
TRANSCRIPT
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Warm UpWarm Up
California StandardsCalifornia Standards
Lesson PresentationLesson Presentation
PreviewPreview
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Warm UpAdd, subtract, multiply, or divide.
41 4
–4236
–8
1. 24 + 17 2. 23 – 19
3. 12 3 4. 6(–7)
5. 6. –250 + (–85)–64 8
–335
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Preparation for AF4.0 Students solve simple linear equations and inequalities over the rational numbers.
AF1.4 Use algebraic terminology (e.g., variable, equation, term, coefficient, inequality, expression, constant) correctly.
California Standards
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Vocabularyequationinverse operation
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
An equation is a mathematical sentence that uses an equal sign to show that two expressions have the same value. All of these are equations.
3 + 8 = 11 r + 6 = 14 –24 = x – 7 –1002
= 50
To solve an equation that contains a variable, find the value of the variable that makes the equation true. This value of the variable is called the solution of the equation.
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Determine which value of x is a solution of the equation.
x + 8 = 15; x = 5, 7, or 23
Additional Example 1: Determining Whether a Number is a Solution of an Equation
Substitute each value for x in the equation.
Substitute 5 for x.13= 15 ?
So 5 is not solution.
x + 8 = 15?
5 + 8 = 15?
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Determine which value of x is a solution of the equation.x + 8 = 15; x = 5, 7, or 23
Additional Example 1 Continued
Substitute each value for x in the equation.
Substitute 7 for x.15= 15 ?
So 7 is a solution.
x + 8 = 15?
7 + 8 = 15?
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Determine which value of x is a solution of the equation.x + 8 = 15; x = 5, 7, or 23
Additional Example 1 Continued
Substitute each value for x in the equation.
Substitute 23 for x.31= 15 ?
So 23 is not a solution.
x + 8 = 15?
23 + 8 = 15 ?
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Adding and subtracting by the same number are inverse operations. Inverse operations “undo” each other. To solve an equation, use inverse operations to isolate the variable. In other words, get the variable alone on one side of the equal sign.
The properties of equality allow you to perform inverse operations. These properties show that you can perform the same operation on both sides of an equation.
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
You can use the properties of equality along with the Identity Property of Addition to solve addition and subtraction equations.
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Solve.
Additional Example 2A: Solving Equations Using Addition and Subtraction Properties
Since 10 is added to n, subtract 10 from both sides to undo the addition.
10 + n = 1810 + n = 18
–10 –10
0 + n = 8 n = 8 Identity Property of Addition: 0 + n = n.
Check
10 + n = 18?
10 + 8 = 18
18 = 18?
To check your solution, substitute 8 for n in the original equation.
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Solve.
Additional Example 2B: Solving Equations Using Addition and Subtraction Properties
Since 8 is subtracted from p, add 8 to both sides to undo the subtraction.
p – 8 = 9p – 8 = 9
+ 8 + 8
p + 0 = 17 p = 17 Identity Property of Addition: p + 0 = p.
Checkp – 8 = 9
? 17 – 8 = 9
9 = 9?
To check your solution, substitute 17 for p in the original equation.
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Solve.
Additional Example 2C: Solving Equations Using Addition and Subtraction Properties
Since 11 is subtracted from y, add 11 to both sides to undo the subtraction.
22 = y – 1122 = y – 11
+ 11 + 11
33 = y + 0 33 = y Identity Property of Addition: y + 0 = y.
Check22 = y – 11
? 22 = 33 – 11
22 = 22?
To check your solution, substitute 33 for y in the original equation.
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Jan and Alex are arguing over who gets to play a board game. If Jan, on the right, pulls with a force of 14 N, what force is Alex exerting on the game if the net force is 3 N?
Additional Example 3: Problem Solving Application
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Force is measured in newtons (N). The number ofnewtons tells the size of the force and the sign tells its direction. Positive is to the right and up, and negative is to the left and down.
Helpful Hint!
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Net force Alex’s forceJan’s force= +
The answer is the force that Alex, on the left,
is exerting on the board game.
List the important information:• Jan, on the right pulls with a force of 14 N. • The net force is 3 N.
11 Understand the Problem
Show the relationship or the information:
Additional Example 3 Continued
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Write an equation and solve it. Let f represent Alex’s force on the board game, and use the equation model. 3 = f + 14
3 = f + 14Subtract 14 from both sides.
–11 = fAlex was exerting a force of –11 N on the board game.
22 Make a Plan
Solve33
– 14 – 14
Additional Example 3 Continued
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Look Back44
The problem states that the net force is 3 N, which means that the person on the right, Jan, must be pulling with more force. The absolute value of Alex's force is less than the absolute value of Jan's force, |–11| < |14|, so the answer is reasonable.
Additional Example 3 Continued
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Frankie and Carol are playing tug of war using a rope. If Frankie, on the right, pulls with a force of 7 N, what force is Carol exerting on the game if the net force is 4 N?
Check It Out! Example 3
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Net force Carol’s forceFrankie’s force= +
The answer is the force that Carol, on the left is
exerting on the rope.
List the important information:• Frankie, on the right pulls with a force of 7 N. • The net force is 4 N.
11 Understand the Problem
Show the relationship or the information:
Check It Out! Example 3 Continued
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Write an equation and solve it. Let f represent Carol’s force on the rope, and use the equation model. 4 = f + 7
4 = f + 7Subtract 7 from both sides.
–3 = f
Carol was exerting a force of –3 N on the rope.
22 Make a Plan
Solve33
– 7 – 7
Check It Out! Example 3 Continued
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Look Back44
The problem states that the net force is 4 N, which means that the person on the right, Frankie, must be pulling with more force. The absolute value of Carol's force is less than the absolute value of Frankie's force |–3| < |7|, so the answer is reasonable.
Check It Out! Example 3 Continued
Evaluating Algebraic Expressions
1-7 Solving Equations by Adding or Subtracting
Lesson Quiz
Determine which value of x is a solution of each equation.
1. x + 9 = 17; x = 6, 8, or 26
2. x – 3 = 18; x = 15, 18, or 21
Solve.
3. a + 4 = 22
4. n – 6 = 39
5. The price of your favorite cereal is now $4.25. In prior weeks the price was $3.69. Write and solve an equation to find n, the increase in the price of the cereal.
821
a = 18
n = 45
3.69 + n = 4.25; $0.56
top related