warm up day 86(4)
Post on 16-Mar-2016
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Warm Up Day 86(4). What is the Force on a electron moving at 200,000 m/s in a magnetic field of .015 T?. What is the radius of the path it follows?. Electron mass=9.11E-31 kg Electron charge=-1.6E-19 C. Solution. F=qvB= F=(1.6E-19)(200,000)(.015) = F=mv^2/r R=mv/qB - PowerPoint PPT Presentation
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Warm Up Day 86(4)
What is the Force on a electron moving at 200,000 m/s in a magnetic field of .015 T?
What is the radius of the path it follows?Electron mass=9.11E-31 kgElectron charge=-1.6E-19 C
Solution
F=qvB=
F=(1.6E-19)(200,000)(.015)=
F=mv^2/r
R=mv/qB
r=(9.11E-31)(200,000)/(1.6E-19)(.015)=
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