answer for pkp chapter 9-10 sf016
DESCRIPTION
Answer for PKP Chapter 9-10 SF016TRANSCRIPT
PROGRAM KECEMERLANGAN PELAJARUNIT FIZIK
SEM 1 2015/2016
CHAPTER 9 : SIMPLE HARMONIC MOTIONCHAPTER 10: MECHANICAL WAVE
Prepared by: SII/sem1/2015/16
QUESTION 1 (a)
(i) ω = 2πf so, f = ω/2π = 6π/2π = 3Hz
(ii) v = dx/dt= 0.025 cos 6πt (6π)= 0.15π cos 6πt , t = 4s
so, v = 0.15π cos 6π (4) = 0.47 ms-1
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QUESTION 1 (b) (i)
• m = 300g = 0.3 kg A = 4.0cm = 0.04m k = 10Nm-1
KE at x = 3cm = 0.03m :KE = 1/2 k(A2-x2) = 1/2 (10) (0.042 - 0.032) = 3.5 x 10-3 J
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QUESTION 1 (b) (ii)
• a = - ω2A = - (k/m) A = - (10/0.3) (0.04) = -1.33 ms-2
( a +ve is accepted)
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QUESTION 2 (a)
(i) l = 150 cm = 1.5 m T = 2π √(l/g) = 2π √(1.5/9.81) = 2.46 s
(ii) unchanged - because from the equation of T = 2π √(l/g) , period of oscillation is not affected by mass.
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QUESTION 2 (b) (i)
• v = dx/dt = Aω cos ωt = (14) (2π/4) cos (2π/4)t = 7π cos (π/2)tv/cms-1
t/s
7π
-7π
4
1mark - shape1 mark - axis & label
1 mark - label 7π
QUESTION 2 (b) (ii)
• amax = dv/dt = - Aω2 sin ωt = - (14) (2π/4)2 sin (2π/4)t = - 3.5π2 sin (2π/4)t
a/cms-2
t/s
3.5π2
4
-3.5π2
1mark - shape1 mark - axis & label1 mark - label 3.5π2
QUESTION 3 (a)
(i) Mechanical waves are produced by a source of disturbance and the energy transmitted away from the source.
(ii) Energy
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QUESTION 3 (a) (iii)
• Longitudinal Wave Direction of vibration of the particles is
parallel to the direction of the wave propagation.
• Transverse Wave A wave whose direction of vibration of
particles is perpendicular to the direction of the wave propagation.
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QUESTION 3 (b)
(i) to the right
(ii) v=fλ , f= ω/2π = 600/2π = 95.49 Hz λ=2π/k = 2π/5 = 1.26 m
So, v = 95.49 x 1.26 = 120.32 ms-1
(iii) vy = dy/dt = (0.48)(600)cos(600t-5x) = 288 cos (600t-5x)
So, maximum particle vibrational velocity =288 ms-1
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QUESTION 3 (c)
(i) Stationary wave / Standing wave
(ii) Y = y1 + y2
= 2A cos kx sin ωt = 2(20) cos (2x) sin (15t)= 40 cos 2x sin 15t
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