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AP Calculus Summer
Packet Answer Key
AP Calculus AB students โ Your packet stops at #98.
1
Simplifying Complex Fractions
Simplify each of the following.
1. ๐ฅ3โ9๐ฅ
๐ฅ2โ7๐ฅ+12
๐ฅ(๐ฅ+3)
๐ฅโ4 2.
๐ฅ2โ2๐ฅโ8
๐ฅ3+๐ฅ2โ2๐ฅ
๐ฅโ4
๐ฅ(๐ฅโ1)
3. 1
๐ฅโ
1
51
๐ฅ2โ1
25
5๐ฅ
5+๐ฅ 4.
25
๐โ๐
5+๐
5โ๐
๐
Laws of Exponents
Write each of the following in the form ๐๐๐๐๐ where c, p, and q are constants (numbers).
5. (2๐2)
2
๐ 4๐4๐โ1 6. โ9๐๐33
91/3๐1/3๐
7. ๐๐โ๐
๐2โ๐ ๐๐โ1 8.
๐โ1
(๐โ1)โ๐ ๐โ3/2๐
9. (๐2/3
๐1/2)
2
(๐3/2
๐1/2) ๐5/6๐1/2
2
Laws of Logarithms
Simplify each of the following:
10. log2 5 + log2(๐ฅ2 โ 1) โ log2(๐ฅ โ 1) log2 5(๐ฅ + 1)
11. 32 log3 5 25 12. log101
10๐ฅ โ๐ฅ
Solving Exponential and Logarithmic Equations
Solve for x. (DO NOT USE A CALCULATOR.)
13. 5(๐ฅ+1) = 25 14. 1
3= 32๐ฅ+2 15. log2 ๐ฅ2 = 3 16. log3 ๐ฅ2 = 2 log3 4 โ 4 log3 5
๐ฅ = 1 ๐ฅ = โ3
2 ๐ฅ = 2โ2 ๐ฅ = ยฑ
4
25
Literal Equations
Solve for the indicated variables.
17. ๐ = 2(๐๐ + ๐๐ + ๐๐), ๐๐๐ ๐ 18. ๐ด = ๐ + ๐๐๐, ๐๐๐ ๐
๐ =๐โ2๐๐
2๐+2๐ ๐ =
๐ด
1+๐๐
19. 2๐ฅ
4๐+
1โ๐ฅ
2= 0, ๐๐๐ ๐ฅ
๐ฅ =๐
๐โ1
3
Real Solutions
Find all real solutions.
20. ๐ฅ4 โ 1 = 0 21. ๐ฅ6 โ 16๐ฅ4 = 0
๐ฅ = ยฑ1 ๐ฅ = 0, ยฑ4
22. 4๐ฅ3 โ 8๐ฅ2 โ 25๐ฅ + 50 = 0
๐ฅ = ยฑ5
2, 2
Solving Equations
Solve the equations for x.
23. 4๐ฅ2 + 12๐ฅ + 3 = 0 24. 2๐ฅ + 1 =5
๐ฅ+2
๐ฅ =โ3ยฑโ6
2 ๐ฅ =
1
2, โ3
25. ๐ฅ+1
๐ฅโ
๐ฅ
๐ฅ+1= 0
๐ฅ = โ1
2
Polynomial Division
26. (๐ฅ5 โ 4๐ฅ4 + ๐ฅ3 โ 7๐ฅ + 1) รท (๐ฅ + 2)
๐ฅ4 โ 6๐ฅ3 + 13๐ฅ2 โ 26๐ฅ + 45 โ89
๐ฅ+2
27. (๐ฅ6 + 2๐ฅ4 + 6๐ฅ โ 9) รท (๐ฅ3 + 3)
๐ฅ3 + 2๐ฅ โ 3
28. The equation 12๐ฅ3 โ 23๐ฅ2 โ 3๐ฅ + 2 = 0 has a solution ๐ฅ = 2. Find all other solutions.
๐ฅ =1
4, โ
1
3
4
Interval Notation
29. Complete the table with the appropriate notation or graph.
Solution Interval Notation Graph
โ2 < ๐ฅ โค 4
(โ2, 4]
-2 4
๐ฅ โค 8
(โโ, 8]
8
โ1 โค ๐ฅ < 7
[โ1, 7)
โ1 7
Solving Inequalities
Solve the inequalities. Write the solution in interval notation.
30. ๐ฅ2 + 2๐ฅ โ 3 โค 0 31. 2๐ฅโ1
3๐ฅโ2โค 1 32.
2
2๐ฅ+3>
2
๐ฅโ5
[โ3, 1] (โโ,2
3) ๐[1, โ) (โโ, โ8)๐ (โ
3
2, 5)
Solving Equations with Absolute Value
Solve for x. Give the solution for inequalities in interval notation.
33. |โ๐ฅ + 4| โค 1 34. |5๐ฅ โ 2| = 8 35. |2๐ฅ + 1| > 3
[3, 5] ๐ฅ = โ6
5, 2 (โโ, โ2)๐(1, โ)
5
Functions
Let ๐(๐ฅ) = 2๐ฅ + 1 and ๐(๐ฅ) = 2๐ฅ2 โ 1. Find each of the following.
36. ๐(2) = 5 37. ๐(โ3) = 17 38. ๐(๐ก + 1) = 2๐ก + 3
39. ๐(๐(โ2)) = 15 40. ๐(๐(๐ + 2)) = 8๐2 + 40๐ + 49
Let ๐(๐ฅ) = ๐ฅ2, ๐(๐ฅ) = 2๐ฅ + 5, and โ(๐ฅ) = ๐ฅ2 โ 1. Find each of the following.
41. โ(๐(โ2)) = 15
42. ๐(๐(๐ฅ โ 1)) = 4๐ฅ2 + 12๐ฅ + 9
43. ๐(โ(๐ฅ3)) = 2๐ฅ6 + 3
6
Intercepts and Points of Intersection
Find the ๐ฅ and ๐ฆ intercepts of each.
44. ๐ฆ = 2๐ฅ โ 5 45. ๐ฆ = ๐ฅ2 + ๐ฅ โ 2
x-int.: (5
2, 0) x-int.: (โ2, 0) ๐๐๐ (1, 0)
y-int.: (0, โ5) y-int.: (0, โ2)
46. ๐ฆ = โ16 โ ๐ฅ2
x-int.: (โ4, 0) ๐๐๐ (4, 0)
y-int.: (0, 4)
Domain and Range
Find the domain and range of each function. Write your answer in interval notation.
47. ๐(๐ฅ) = ๐ฅ2 โ 5
Domain: (โโ, โ) Range: [โ5, โ)
48. ๐(๐ฅ) = 3 sin ๐ฅ
Domain: (โโ, โ) Range: [โ3, 3]
49. ๐(๐ฅ) =2
๐ฅโ1
Domain: (โโ, 1)๐(1, โ) Range: (โโ, 0)๐(0, โ)
7
Systems
Find the point(s) of intersection of the graphs for the given equations.
50. {๐ฅ + ๐ฆ = 8
4๐ฅ โ ๐ฆ = 7 51. {
๐ฅ2 + ๐ฆ = 6๐ฅ + ๐ฆ = 4
(3, 5) (โ1, 5) ๐๐๐ (2, 2)
Inverses
8
Find the inverse for each function.
52. ๐(๐ฅ) = 2๐ฅ + 3 53. ๐(๐ฅ) =๐ฅ2
3
๐ฆ =๐ฅโ3
2 ๐ฆ = โ3๐ฅ
Prove ๐ and ๐ are inverses of each other.
54. ๐(๐ฅ) =๐ฅ3
2 ๐(๐ฅ) = โ2๐ฅ
3
Simplify: ( โ2๐ฅ
3)
2
2 and โ2 (
๐ฅ3
2)
3
55. ๐(๐ฅ) = 9 โ ๐ฅ2 ๐(๐ฅ) = โ9 โ ๐ฅ
Simplify: 9 โ (โ9 โ ๐ฅ)2 and โ9 โ (9 โ ๐ฅ2)
9
Vertical Asymptotes
Determine the vertical asymptotes for each function. Set the denominator equal to zero to find
the x-value for which the function is defined. This will be the vertical asymptote.
56. ๐(๐ฅ) =1
๐ฅ2 57. ๐(๐ฅ) =
๐ฅ2
๐ฅ2โ4. 58. ๐(๐ฅ) =
2+๐ฅ
๐ฅ2(1โ๐ฅ)
๐ฅ = 0 ๐ฅ = 2, โ2 ๐ฅ = 0, 1
Horizontal Asymptotes
Determine the horizontal asymptotes using the three cases below.
Case I: Degree of the numerator is less than the degree of the denominator. The asymptote is
๐ฆ = 0.
Case II: Degree of the numerator is the same as the degree of the denominator. The asymptote
is the ratio of the lead coefficients.
Case III: Degree of the numerator is greater than the degree of the denominator. There is no
horizontal asymptote. The function increases without bound. (If the degree of the numerator is
exactly 1 more than the degree of the denominator, then there exists a slant asymptote, which
is determined by long division.)
Determine all horizontal asymptotes.
59. ๐(๐ฅ) =๐ฅ2โ2๐ฅ+1
๐ฅ3+๐ฅโ7 ๐ฆ = 0
60. ๐(๐ฅ) =5๐ฅ3โ2๐ฅ2+8
4๐ฅโ3๐ฅ3+5 ๐ฆ = โ
5
3
61. ๐(๐ฅ) =4๐ฅ5
๐ฅ2โ7 ๐๐ โ๐๐๐๐ง๐๐๐ก๐๐ ๐๐ ๐ฆ๐๐๐ก๐๐ก๐
10
Equation of a Line
Slope Intercept Form: ๐ฆ = ๐๐ฅ + ๐ Vertical Line: ๐ฅ = ๐ (slope is undefined)
Point-slope Form: ๐ฆ โ ๐ฆ1 = ๐(๐ฅ โ ๐ฅ1) Horizontal Line: ๐ฆ = ๐ (slope is 0)
62. Use slope-intercept form to find the equation of the line having slope of 3 and a y-intercept
of 5.
๐ฆ = 3๐ฅ + 5
63. Determine the equation of a line passing through the point (5, โ3) with an undefined
slope.
๐ฅ = 5
64. Determine the equation of a line passing through the point (โ4, 2) with a slope of 0.
๐ฆ = 2
65. Use point-slope form to find the equation of a line passing through the point (0, 5) with a
slope of 2/3.
๐ฆ โ 5 =2
3๐ฅ
66. Find the equation of a line passing through the point (6, 8) and parallel to the line
๐ฆ =5
6๐ฅ โ 1.
๐ฆ =5
6๐ฅ + 3
67. Find the equation of a line passing through points (โ3, 6) and (1, 2).
๐ฆ โ 2 = โ1(๐ฅ โ 1)
๐๐ ๐ฆ โ 6 = โ1(๐ฅ + 3) ๐๐ ๐ฆ = โ1๐ฅ + 3
68. Find the equation of a line with an x-intercept of (2, 0) and a y-intercept (0, 3).
๐ฆ = โ3
2๐ฅ + 3
11
Parent Functions
For 69 โ 78, identify the parent function associated with each graph.
69. 70.
๐ฆ = ๐ฅ ๐ฆ = ๐ฅ2
71. 72.
๐ฆ = โ๐ฅ ๐ฆ = ๐ฅ3
73. 74.
๐ฆ = โ๐ฅ3
๐ฆ = ln ๐ฅ
12
75. 76.
๐ฆ = ๐๐ฅ ๐ฆ = |๐ฅ|
77. 78.
๐ฆ =1
๐ฅ ๐ฆ =
1
๐ฅ2
13
Unit Circle
79. Identify all parts of the unit circle, including degree, radian, and coordinates of each point.
Without using a calculator, evaluate the following.
80. a) sin 180ยฐ b) cos 270ยฐ c) sin ๐ d) cos(โ๐)
0 0 0 โ1
e) sin5๐
4 f) cos
9๐
4 g) tan
7๐
6
โโ2
2
โ2
2 โ
1
โ3
14
Inverse Trigonometric Functions
For each of the following, find the value in radians.
81. ๐ฆ = sinโ1 โโ3
2 โ
๐
3
82. ๐ฆ = arccos(โ1) ๐
83. ๐ฆ = tanโ1(โ1) โ๐
4
84. ๐ฆ = cosโ1 (sin (โ๐
4))
3๐
4
15
For each of the following give the value without a calculator.
85. tan (arccos2
3)
โ5
2 86. sec (sinโ1 12
13)
13
5
87. sin (arcsin7
8)
7
8
Trigonometric Equations
Solve each of the equations for 0 โค ๐ฅ < 2๐. Isolate the variable and find all the solutions within
the given domain. Remember to double the domain when solving for a double angle. Use trig
identities, or rewrite the trig functions using substitution, if needed.
88. sin ๐ฅ = โ1
2 89. 2 cos ๐ฅ = โ3
๐ฅ =7๐
6,
11๐
6 ๐ฅ =
๐
6,
11๐
6
16
90. sin2 ๐ฅ =1
2 91. sin 2๐ฅ = โ
โ3
2
๐ฅ =๐
4,
3๐
4 ๐ฅ =
2๐
3,
5๐
6
92. 2 cos2 ๐ฅ โ 1 โ cos ๐ฅ = 0 93. 4 cos2 ๐ฅ โ 3 = 0
๐ฅ = 0,2๐
3,
4๐
3 ๐ฅ =
๐
6,
11๐
6
94. Find the ratio of the area inside the square but outside the circle to the area of the square in
the picture below.
1 โ๐
4
95. Find the formula for the perimeter of the window of the shape in the picture below.
4๐ + ๐๐
17
96. A water tank has the shape of a cone (where ๐ =๐
3๐2โ). The tank is 10 ๐ high and has a
radius of 3 ๐ at the top. When the water is 5 ๐ deep (in the middle of the tank) what is the
surface area of the top of the water?
9๐
4
97. Two cars start moving from the same point. One travels south at 100 ๐๐/โ๐, the other
west at 50 ๐๐/โ๐. How far apart are they two hours later?
100โ5 ๐๐
98. A kite is 100 ๐ above ground. If there is 200 ๐ of string connecting the kite to the
horizontal, what is the angle between the string and the horizontal? (Assume that the string is
perfectly straight.)
๐
6 ๐๐ 30ยฐ
Limits
Using the graphs, find the following limits.
99. lim๐ฅโ3+ ๐(๐ฅ) = โ 100. lim๐ฅโโ ๐(๐ฅ) = 2 101. lim๐ฅโ3 ๐(๐ฅ) = ๐ท๐๐ธ
18
102. lim๐ฅโ2 ๐(๐ฅ) = โ3 103. ๐(2) = 0
Find ๐(๐ฅ+โ)โ๐(๐ฅ)
โ for the given function ๐.
104. ๐(๐ฅ) = 2๐ฅ + 3
2
105. ๐(๐ฅ) = 3๐ฅ2 โ ๐ฅ + 5
3โ + 6๐ฅ โ 1
106. ๐(๐ฅ) = 5 โ 2๐ฅ
โ2