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Copyright Hardy K. S. Leung Argonaut Math Olympiad 5.9 Systematic Counting — Part I In the classroom: Lessons with guided exercises ( minutes) Break ( minutes) Lessons with guided exercises ( minutes) Wrap up ( minutes) Homework: All Non-starred questions Homework submission at

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Page 1: Argonaut Math Olympiad - argomath.com · This must be an all-time most diffcult problem in Math Olympiad — only 1% of students answered this correctly. To get this right, you must

Copyright Hardy K. S. Leung

Argonaut Math Olympiad

5.9 Systematic Counting — Part I

In the classroom:

Lessons with guided exercises ( minutes)

Break ( minutes)

Lessons with guided exercises ( minutes)

Wrap up ( minutes)

Homework:

All Non-starred questions

Homework submission at

40

0

30

5

www.argomath.com/homework−−−−−−−−−−−−−−−−−−−−−−−−−−

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P.2Systematic Counting — Part I

Counting problems are tricky. Counting as an the activity may not be hard, buthow do you know you didn't make a mistake, a mental error? You (usually)can't. Your best bet is to use methods that eliminate the possibility of error,and the main technique to do so is to be systematic. Previously, we learned about Fence-Post (linear) counting and circularcounting. In fact, I consider them main techniques of systematic counting:

Fence-Post counting — by always referring to the Fence-Postterminologies, you're unlikely to confuse between posts and panels. How many multiples of between and ? The first post is at , and the last is at . The length of the fence is

, and so there are panels. The number ofposts is . There are multiples of .

Circular Post counting — using transformation, we systematically convertproblems from difficult ones to easy ones without changing the answer. Today is Tuesday. What day of the week is days from today? The answer is the same if we increase or decrease by any multiple of

, for example:

Now ask yourself: what day of the week is days fromTuesday? The answer is Thursday.

5 101 199

105 195195 − 105 = 90 90 ÷ 5 = 18

19 19 5

100

1007

100 →

decrease by 70

30 →

decrease by 28

2

100 − 98 = 2

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P.3Systematic Counting — Part I

Today we'll show other ways to count systematically, and we'll name them,similar to what we did with Geometry:

Gridlines

Negative-Space

Detach-and-Reattach

Snaky-Snake

Naming techniques helps abstract the techniques into well-defined but tinytools — or spells — so you can focus on critical thinking.

Technique — Count by Categories

Instead of arbitrarily counting, we'll first find out all categories of things thatneed to be counted. We only start counting if we are sure that the categoriescover all bases!

#1

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P.4Systematic Counting — Part I

Guided Exercise

Square is drawn at the bottom. Points , and are themidpoints of the sides of the square. What is the total number of squaresof all sizes which can be traced using only the line segments shown?

What are the categories here?

big squares

small squares

big squares

small squares

Hopefully, you are convinced that these categories are exhaustive. Let's countthem:

big squares:

small squares:

big squares:

small squares:

The answer is .

ACEG B, D, F H

45∘

45∘

1

4

45∘ 1

45∘ 4

10

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P.5Systematic Counting — Part I

Guided Exercise

As shown, the "checkerboard" contains one shaded square. In thisdiagram, how many squares of any size do not include the shadedsquares?

This type of problem is error-prone. You can come up with an answer, buthow do you know it is correct? Being systematic is the answer. We'll consider squares of different sizes, andwe know only , , and squares fit.

: of them.

: we'll try to place a square at each position and see which oneworks. There are squares (each number correspondsto the number of that starts in that row).

: only .

The answer is .

Guided Exercise

Suppose Sandy writes every whole number from to withoutskipping any numbers. How many times will Sandy write the digit " "?

5 × 5

1 × 1 2 × 2 3 × 3

1 × 1 24

2 × 2 2 × 24 + 2 + 2 + 4 = 122 × 2

3 × 3 3

24 + 12 + 3 = 39

1 1002

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P.6Systematic Counting — Part I

The categories here are the tens digit and the ones digit. It is good to be ableto conjure up the following table (mentally) on demand:

Be careful what numbers are included or excluded, whether the rows are to, or to !

We'll count the number of in the tens digit separately from the number of

in the unit digit. This is actually one reason why I prefer to , so thateach row has the same tens digit. By inspection, there are s in the tens digit, and s in the ones digit. Theanswer is . Actually we "cheated" a little bit by using a table, chosen because it iseasy to count. It's okay, because neither nor have any twos, soincluding , excluding , and allowing leading zeroes don't matter.However, we should be mindful of the "hacks" that we made. If the questionis asking how many times will Sandy write " ", the answer ( ) would bevery different!

00 01 02 03 04 05 06 07 08 09

10 11 12 13 14 15 16 17 18 19

20 21 22 23 24 25 26 27 28 29

30 31 32 33 34 35 36 37 38 39

40 41 42 43 44 45 46 47 48 49

50 51 52 53 54 55 56 57 58 59

60 61 62 63 64 65 66 67 68 69

70 71 72 73 74 75 76 77 78 79

80 81 82 83 84 85 86 87 88 89

90 91 92 93 94 95 96 97 98 99

09 1 10

2s

2s 0 9

10 2 10 220

00 − 9900 100

00 100

0 11

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P.7Systematic Counting — Part I

Technique — Count by Casework

This technique is similar to Counting-by-Categories, except that we don'thave distinct categories, but distinct "cases".

Guided Exercise

Fifteen darts have landed on the dartboard shown. Each dart scores , ,or points. In how many different ways can the fifteen darts score a totalof points?

There are too many variations, and it is hard to correctly list all possibilitieswithout making any mistake. Instead, can we go through all variations but ina systematic way? Well, we can exhaustively consider all cases of points:

Case : s

Case : s

Case : s

It is easy to see that this is exhaustive. But how does it help? Well, say youare considering Case , with -point hits. The -point hits already accountfor points, so there are remaining hits and to make aremaining score of points. The solution, if exists, must beunique!

#2

3 5775

7

#0 0 7

#1 1 7

#2 2 7

#4 4 7 74 × 7 = 28 15 − 4 = 11

75 − 28 = 47

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P.8Systematic Counting — Part I

s score from s s/ s score from s/ s Solution?

We can prepare this table in a rather mechanical fashion. We don't have to gotoo far because after a while there are too many s! Now we solve it:

s score from s s/ s score from s/ s ( s, s)

In fact, by being systematic, even the solutions form a pattern! The answer is .

#7 7 # 3 5 3 5

0 0 15 75

1 7 14 68

2 14 13 61

3 21 12 54

4 28 11 47

5 35 10 40

6 42 9 33

7 49 8 26

8 56 7 19

7

#7 7 # 3 5 3 5 #3 #5

0 0 15 75 (0, 15)

1 7 14 68 (1, 13)

2 14 13 61 (2, 11)

3 21 12 54 (3, 9)

4 28 11 47 (4, 7)

5 35 10 40 (5, 5)

6 42 9 33 (6, 3)

7 49 8 26 (7, 1)

8 56 7 19

8

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P.9Systematic Counting — Part I

Technique — Count by Faces ( )

Each cube has faces, say facing North, East, South, West, Up, Down.Sometimes it is helpful to consider the faces individually. also take advantageof "sibling" faces with identical measurement.

Guided Exercise

Eight cubes are glued together to form the figure shown. The length ofan edge of each cube is centimeters. The entire figure is covered inpaint. How many square centimeters are covered in paint?

North and South: squares each. East and West: squares each. Up and Down: squares each. Hole: squares. Total: squarecentimeters. (Note: in this case it is more convenient to count the hole separately, but in someother cases, you can also attribute the hole to each of the six directions)

#3A 3D

6

3

8

3

3

4

(8 + 8 + 3 + 3 + 3 + 3 + 4) × (3 × 3) = 32 × 9 = 288

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P.10Systematic Counting — Part I

Guided Exercise

Twenty unit cubes are glued together to form this figure, with "holes"which you can see through. The total figure measures . If thefigure is fully dipped in a bucket of paint, how many square units ofsurface area would be painted?

You can observe that all faces are identical to each other, so we'll only need tocalculate the area of a single face, say the UP face. Be careful with the squares that are facing UP but hidden inside the interiorof the cube. are in the interior, and are on the surface, for a total of squares. Since the cube, like a die, has faces, the answer is .

3 × 3 × 3

4 8 126 6 × 12 = 72

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P.11Systematic Counting — Part I

Technique — Count by Layers ( )

Guided Exercise

The set of stairs shown at the right is constructed by placing layers ofcubes on top of each other. What is the total number of cubes containedin the staircase?

This is easy to count by layers: , , , and . The answer:

Technique — Count by Columns ( )

Guided Exercise

The tower shown is made of congruent cubes stacked on top of eachother. Some of the cubes are not visible. How many cubes in all are usedto form the tower?

#3B 3D

1 × 3 3 × 3 5 × 3 7 × 3

3(1 + 3 + 5 + 7) = 3 × 16 = 48

#3C 3D

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P.12Systematic Counting — Part I

We can solve this problem counting by layers, or by columns. Either wayworks but in this case it is easier to count the columns:

Technique — Count by Tree

Guided Exercise

Three circular streets intersect at points , and as shown.How many different paths can be walked along the streets from to ,if no intersection is entered more than once when walking each path?

This must be an all-time most diffcult problem in Math Olympiad — only 1%of students answered this correctly. To get this right, you must be verydiscipline and systematic. We will use a tree which is helpful in enumeratingoptions.

10

4 + (3 + 3) + (2 + 2 + 2) + (1 + 1 + 1 + 1) = 4 + 6 + 6 + 4 = 20

#4

A, B, C, D, E F

A F

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P.13Systematic Counting — Part I

Starting from , we repeatedly branch out to all possibilities.

We'll continue to expand each node while keeping track of the constraint weneed to satisfy (no repeated visit).

By being systematic, the solution is more robust because you may findpatterns in the system:

Finally,

A

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P.14Systematic Counting — Part I

To be careful, we'll circle the ones that are real endpoints:

There are paths.28

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P.15Systematic Counting — Part I

Guided Exercise

Numbers such as or have their digits in decreasing order becauseeach digit is less than the digit to its left. The digits in are not indecreasing order. How many whole numbers between and havetheir digits in decreasing order?

Let's use a tree:

Careful, some of the intermediate paths lead to nowhere, and we must becareful not to consider them (this is a common mistake). I prefer to circle thecorrect ones (the answer is ):

543 531322100 599

20

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P.16Systematic Counting — Part I

Technique — Count by Scratch Table

Guided Exercise

Assume that a post office issues only ¢ and ¢ stamps and all postage isin whole numbers of cents. What is the greatest amount of postage incents which cannot be made using only ¢ and ¢ stamps?

You can use trial-and-error to find out what postage can be made. But whatabout those that cannot be made? There is no obvious method to count all possibilities using some kind offormula. Yet, we still do this systematically. Sometimes a tree works better;sometimes a table does. In this case, we use a table of numbers, and we circle, or "scratch-off",numbers that satisfy our criteria. I call this a Scratch Table. It is the most usefulwhen you can only find the result by looking at the big picture after the fact,e.g. if you need to count the unique number of ways to do something, or tofind the largest unscratched number. An ancient technique used to findprime numbers, called the Sieve of Eratosthenes, is based on Scratch Table.

We start by circling (or boxing) and because we know they are "reachable"(can be made with ¢ and ¢ stamps):

#5

3 8

3 8

3 83 8

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P.17Systematic Counting — Part I

Next, we'll go down the numbers one by one, and ask, is this numberreachable by adding a ¢ stamp or a ¢ stamp to a previously-reachablepostage? If the answer is no, we'll leave it alone. If the answer is yes, we'llcircle (or box) the number to mark it as "reachable".

¢: —

¢: —

¢: Reachable (original)

¢: —

¢: —

¢: Reachable (from )

¢: —

¢: Reachable (original)

¢: Reachable (from )

¢: —

¢: Reachable (from )

¢: Reachable (from )

¢: —

¢: Reachable (from )

¢: Reachable (from )

¢: Reachable (from )

¢: Reachable (from )

¢: Reachable (from )

¢: Reachable (from )

¢: Reachable (from )

¢: Reachable (from )

¢: Reachable (from )

At this point, the table looks like this:

1 2 4 5 7 10

13

1 2 3 4 5 6 7 8 9 10

11 12 13 14 15 16 17 18 19 20

21 22 23 24 25 26 27 28 29 30

3 8

1

2

3

4

5

6 3

7

8

9 6

10

11 8

12 9

13

14 11

15 12

16 8

17 14

18 15

19 16

20 17

21 18

22 19

3 6 8 9

11 12 14 15 16 17 18 19 20

21 22 …

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P.18Systematic Counting — Part I

Now observe that there is a long sequence of reachable numbers startingfrom . It is not hard to reason that anything afterwards is reachable:

Therefore, we have seen the last of the uncircled, which is ¢!

14

14, 15, 16⟶ 17, 18, 19

17, 18, 19⟶ 20, 21, 22

20, 21, 22⟶ 23, 24, 25

23, 24, 25⟶ …

13

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P.19Systematic Counting — Part I

Guided Exercise

Consider all pairs of counting numbers whose sum is less than . Thetwo members of a pair could be either the same as each other ordifferent. How many different products are possible if the two numbersare multiplied?

Do you realize that the multiplications that we want are just the upper-leftcorner of the multiplication table? We can further cut it roughly byhalf because of duplicates (e.g. ):

dup —

3 dup dup — —

4 dup dup dup — — —

5 dup dup dup dup — — — —

6 dup dup dup dup — — — — —

7 dup

We need to eliminate duplicates (e.g. ), either using an actualScratch Table, or just keep track of unique numbers in-place (more error-prone).

11 13 17 19

22 23

The answer is .

11

10 × 103 × 4 = 4 × 3

× 1 2 3 4 5 6 7 8 9

1 1 2 3 4 5 6 7 8 9

2 4 6 8 10 12 14 16

9 12 15 18 21

16 20 24

25

2 × 6 = 3 × 4

1 2 3 4 5 6 7 8 9 10

12 14 15 16 18 20

21 24 25 …

19

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P.29Systematic Counting — Part I (HW5)

Problem

For how many different counting numbers between and is thesum of the digits equal to , if zero is not a digit of any of the numbers?

Problem

How many numbers between and have digits that differ by ?

Problem

Abracadabra has four different coins with values as shown at thebottom. Suppose you had just one of each of the four different coins.How many different amounts can be made using one or more of the fourdifferent coins?

01

10 2006

02

10 99 3

03

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P.30Systematic Counting — Part I (HW5)

Problem

I have four ¢-stamps and three ¢-stamps. Using one or more of thesestamps, how many different amounts of postage can I make?

Problem

A boy has the following seven coins in his pocket: pennies, nickels, dimes, and quarter. He takes out two coins, records the sum of theirvalues, and then puts them back with the other coins. He continues totake out two coins, record the sum of their values, and put them back.How many different sums can he record at most?

Problem

The six faces of a three-inch wooden cube are each painted red. The cubeis then cut into one-inch cubes along the lines shown in the diagram.How many of the one-inch cubes have red paint on at least two faces?

04

3 5

05

2 2 21

06

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P.31Systematic Counting — Part I (HW5)

Problem

The tower shown at the bottom is made of horizontal layers of unitcubes, not all being visible in the diagram. How many unit cubes arecontained in the tower?

Problem

The structure at the bottom is made of unit cubes piled on top of eachother. Some cubs are not visible. What is the number of cubes in thestructure?

07

08

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P.32Systematic Counting — Part I (HW5)

Problem

Five disks, numbered , , , , and , are placed in a bag. Three disksare withdrawn from the bag, the sum of their numbers is recorded, andthe three disks are then returned to the bag. Suppose this process isrepeated indefinitely. What is the largest number of different sums thatcan be recorded?

Problem

A set of coins may contain any combination of pennies, nickels,dimes, quarters, or half-dollars. In how many different ways can the setof coins have a total value of ¢?

09

1 2 4 8 16

10

10

10 59

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P.33Systematic Counting — Part I (HW5)

Problem

The tower shown at the bottom is made by placing congruent cubes ontop of each other. Not all cubes of the tower are visible. How many cubesdoes the tower contain?

Problem

At the bottom is a cubic block of wood. Suppose all six faces ofthe cube are painted red and the cube is then cut into cubesalong the lines shown. How many cubes will have red painton just two faces?

11

12

4 × 4 × 41 × 1 × 1

1 × 1 × 1

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P.34Systematic Counting — Part I (HW5)

Problem

A person has four special coins whose values in cents are shown at thebottom. How many different amounts can the person make using one ormore of the coins?

Problem

The tower shown at the right is made by placing congruent cubes on topof each other with no gaps. Not all cubes are visible. How many cubesdoes the tower contain?

13

14

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P.35Systematic Counting — Part I (HW5)

Problem

In the number , the last two zeroes are called terminal zeroes.The zero after the digit is not a terminal zero. How many terminalzeroes does the product of the first counting numbers (

) have?

Problem

Takeru has four -cent stamps, three -cent stamps, and three -centstamps. How many different postage amounts of at least cent canTakeru make?

Problem

In each turn of a certain game, only the following point-scores arepossible: . Eight turns are taken. In how many ways can the totalpoint score be ?

15⋆

203, 5002

301 × 2 × 3 × ⋯ × 30

16⋆

1 5 251

17⋆

5, 3, 2, 025

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P.36Systematic Counting — Part I (HW5)

Problem

The tower at the bottom has no gaps. Suppose it is painted red on allexterior sides including the bottom, and then cut into cubes along theindicated lines. How many cubes will each have red paint on just threefaces?

Problem

Let all the odd numbers from through inclusive be written. Howmany times will the digit appear?

Problem

is a triple of counting numbers whose sum is . We consider and to be the same triple as because each triple

has the same three numbers. How many other triples of countingnumbers have a sum of ?

18⋆

19⋆

1 3013

20⋆

(1, 1, 9) 11(1, 9, 1) (9, 1, 1) (1, 1, 9)

11