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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    The Hamilton operator give2

    2

    pV

    m! "

    ) )

    The p is the operator of moment give

    p i! %h 2

    2

    2H V

    m! & % "

    ) )h

    The Schrdinger equation give by H # =E # , E is the scalar quantity

    corresponding to the energy of the system for ( , )q t# is the system and if apply

    the more ( , )j

    q t# one more subscripts .generally then where

    j j'# ! (#

    1-The Hamilton in one dimensional2 2

    2

    2

    1

    2 2kx

    m x

    )! & "

    )

    h

    A simple harmonic oscillator and we can find by solve the equation

    1

    2E n*

    + ,! "- .

    / 0h

    Where

    1/ 2k

    m*

    + ,

    ! - ./ 0

    Consider the energy states of a particle in the 3-dimensional infinite we

    1 22

    2 2 2

    , , 28x y zn n n x y z

    hn n n

    ma3 ! " "

    , ,x y zn n n Space with coordination give

    1 22

    2 2 2 2

    2

    8x y z

    man n n R

    h

    3" " ! !

    We treat R a continuous variable in the volume of one in sphere of radiuses R3/ 2

    23

    2

    1 4 8( )

    8 3 6

    maR

    h

    4 4 35 3

    + ,! ! - .

    / 0

    The number of sates between 3 and

    ( , ) ( ) ( )* 3 3 5 3 3 5 3 6 ! " 6 & 3/ 2

    21/ 2 2

    2

    8( , ) ( )

    4

    maO

    h

    4* 3 3 3 3 3

    + ,6 ! 6 " 6- .

    / 0

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    For N-particle system2

    2 2 2

    218

    N

    xj yj zj

    j

    hE n n n

    ma !! " "7

    The Hamilton can be written for a system distribution and individual energyaj

    3 where the superscript denotes the particle subscript the state

    Canonical partition function become:-/

    ( , , ) jE KT

    j

    Q N V T e&

    ! 7

    .......a b cj i j kE 3 3 3! " " " ( ....) / // /

    , , ,...

    ( , , ) ........a b c ba ci j k ji k

    KT KTKT KT

    i j k i j i

    Q N V T e e e e3 3 3 3 3 3& " " " && &! !7 7 7 7

    ( , , ) ...........a b cQ N V T q q q! The last equation very important result show that if we can write the N-

    particle Hamilton as a sum of independent terms the useful application of

    separation individual in equation is to the molecular partition function and

    the equation show that molecular Hamilton can be approximation the

    degrees of freedom of the molecule

    .......m ol tran rota vibration electroinq q q q q! /transj kT

    trans

    j

    q e 3&! 7 If N-body energy

    .... .......ijk l i j k l E 3 3 3 3 ! " " " " The Q(N,V,T) give portion function

    ( .......) /( , , ) i j k l

    kT

    ijkl

    Q N V T e3 3 3 3 & " " " "

    ! 7 Fermi-Dirac And Bose Einstein statistics

    There are two cases to consider the evaluation the equation conical

    partion estimation . the resultant distribution function in the case of Fermions

    in called Fermi-Dirac and Bosons is called Bose- Einstein statistics the energy

    ( , )j

    E N V the system containing N-molecules andk

    3 is the molecular quantum

    state when the system itself is in the quantum state with energyjE the set { kn } is

    the entire system total energy

    j k k

    k

    E n 3! 7

    k

    k

    N n! 7

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    We can write Q(V,T,N) as conical ensemble as

    ( , , )k k

    j k

    nE

    j j

    Q V T N e e8 3

    8&

    & 7! !7 7

    This restriction turns but the be mathematics the grand canonical ensemble 9

    give

    0

    ( , , ) ( , , ) k

    N

    V T Q N V T e8:3

    :;

    !

    9 ! 7 We can write the grand conical ensemble

    0

    ( , , )k k k

    k k

    n n

    N

    V T e8 3

    :

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    Grand conical ensemble

    ( , , ) ln(1 )k

    k

    V T e 83< >7

    1

    k

    kk

    e

    e

    83

    83< 7

    So N-particle is given by

    1

    k

    kk

    eN

    e

    83

    83

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    22 2

    2z z z

    an k k n

    a

    4

    4! ? !

    22 2 2 2 2 2 2

    2( )x y z x y zk k k k n n n

    a

    4! " " ! " "

    The moment p is given

    2

    h hkP

    < 4! !

    So the total energy is given by2 2

    2 2 2

    , , 2( )

    2 8x y zn n n x y z

    P hn n n

    m ma3 ! ! " "

    The basic equation associative with the two fundamental distribution laws is

    grand conical ensemble1(1 )k

    k

    e 839 ! >=

    k

    k

    N n! 7

    1

    k

    kk en

    e

    83

    83

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    1-Weakly Degenerate ideal Fermi Dirac gas :

    We are derive series of fermions in a region where

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    By the integration

    1/ 2 1

    3/ 200

    1( 1)y l l ly

    l

    y e e dy<

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    And give that3 2

    2 3/ 2

    ( )

    2a

    B!

    And can find3

    a

    31 2 2

    3 3/ 2 3/ 2

    20

    2 2

    a a aa & " !

    3 3

    3 3/ 2

    1 1( )

    4 2a

    C D! & BE FG H

    3 3 2 3 3

    3 / 2 3 / 2

    1 1 1( ) ( )

    2 4 2

    < @ @ @ C D

    ! B " B " & BE FG H

    Now we want get the ratioP

    KTby integration

    (ln(1 )k

    k

    PV KT e83

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    3/ 2 1

    2 5/ 21

    2 ( 1)l l

    l

    P m KT

    KT h l

    4

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    0

    3/ 2 1/ 2

    2

    1 22

    1 1

    k

    k

    m ed

    V h e

    83

    833 3

    <

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    All other thermodynamic function for a weakly degenerate ideal gas of Bosons

    following in similar way in thermodynamics function useful only for small

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    At room temperature the quantity0

    /K: is called Fermi temperature and id

    denote by FT . Fermi temperature are typically of the order of thus and degrees

    Kelvin

    0

    3/ 2

    3/ 2

    02 0

    24

    mE V d

    h

    :

    4 3 3+ ,

    ! - ./ 0 $

    0

    3/ 2

    3/ 2

    0 02

    2 24 |

    5

    mE V

    h

    :4 3 3

    + ,! - .

    / 0

    0 0

    2

    5E N!

    Where we have written0

    E to emphasize that this T=0K result the equation give

    in zero temperature distribution but not difficult to calculate correction to be

    theses zero temperature and we are expansion in power of parameter

    0/KTN :)!! . now we can write all thermodynamic quantities N,E, P,.. can be

    written by

    0( ) ( )I f h d3 3 3

    ;

    ! $

    Where I=N give h by3/ 2

    3/ 2

    22( ) 4 mh Vh

    3 4 3+ ,! - ./ 0

    And we derive the E and N by the I by integral by part give

    00

    ( ) ( ) | ( ) ( )I f H f h d3 3 3 3 3 ;

    ; O! &$ Now we can fin the I give

    0( ) ( )I f h d3 3 3

    ;O! &$

    Where

    0( ) ( )h d

    3

    3 3 3! $ We using the fact ( ) 0f 3 ! and ( )f 3O is nonzero only for some small region

    around 3 :! and we can find ( )H 3 by Taylor around 3 :!

    22

    2

    1( ) ( ) ( ) ( ) .............

    2

    dH d H H H

    d d3 :

    3 :

    3 : 3 : 3 : 3 3

    !!

    + ,+ ,! " & " & "- .- .

    / 0 / 0

    2

    0 12

    1( ) ( ) .......2

    dH d H I H H L Ld d

    3 :3 :

    3 :3 3

    !!

    + ,+ ,! ! " " "- .- ./ 0 / 0

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    Where

    0( ) ( )jj f d3 : 3 3

    ;O! & &$

    The first integral1

    1L !

    And we can find1 2, ,....L L we may replace the lower limited &; so we can writhe

    the probability function like

    ( )

    ( ) 2( )

    (1 )

    e

    e

    8 3 :

    8 3 :

    83

    8

    &

    &O !

    " But ( )8 3 :& ! and /d dx3 8!

    20

    1, 0,1, 2,......

    (1 )

    j x

    j j x

    x eL dx j

    e8

    ;

    ! & !"$

    Now we can find 1 0L ! 2 2

    2 2 2 20

    1

    (1 ) 3

    x

    x

    x eL dx

    e

    4

    8 8

    ;

    ! & !"$

    Now we can write the I by2 2

    2

    2( ) ( )

    6

    d HI H KT

    d3 :

    4:

    3!

    + ,! " - .

    / 0

    Now we can defined 0( ) ( )H h d

    3

    3 3 3!

    $ and we calculate N in this case3/ 21/ 2

    2

    2( ) 4

    mh V

    h3 4 3

    + ,! - .

    / 0

    3/ 2

    3/ 2

    2

    3/ 221/ 2

    2 2

    8 2( )

    3

    2| 2

    mH V

    h

    d H mV

    d h3 :

    4: :

    4 :

    3

    &!

    + ,! - .

    / 0

    + ,! - .

    / 0

    By replace I by N and give N now3/ 2 2

    3/ 2 2

    2

    8 21 ( )

    3 8

    mN V

    h

    4 4: 8: &

    C D+ ,! "- . E F

    / 0 G H

    By equation

    2/3 3/ 22

    0

    3

    2 8

    h N

    m V:

    4

    + , + ,! - . - .

    / 0 / 0

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    2 /32

    2

    0

    2 /32

    20

    22

    0

    1 ( )8

    1 ( )8

    1 ( )12

    4: : 8:

    4: : 8:

    4: : 8:

    &

    &

    &

    &

    C D! "E F

    G H

    C D! "E FG H

    C D! &E F

    G H

    This equation show that : change slowly with temperature and is

    approximately0

    : throughout the entire solid state range of a metal

    Now we can calculate E by the I looks like3/ 2

    3/ 2

    2

    2( ) 4

    mh V

    h3 4 3

    + ,! - .

    / 0

    so we can write3/ 2

    5/ 2

    2

    3/ 22 1/ 2

    2 2

    4 2( )

    5

    26

    mH V

    h

    d H m Vd h

    43 3

    4 33

    + ,! - .

    / 0

    + ,! - ./ 0

    In the finally we get on E by series3/ 2 2

    5/ 2 2

    2

    5/ 22

    2

    00

    8 2 51 ( )

    5 8

    5

    1 ( )8

    mE V

    h

    E E

    4 4: 8:

    : 4

    8::

    &

    &

    C D+ ,! "- . E F

    / 0 G H

    + , C D

    ! "- . E FG H/ 0

    By the ratio we fin E

    22

    0

    51 ( )

    12E E

    48: &

    C D! "E F

    G H

    The last equation give the energy in power series

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    * Bc.S, Faculty of science Egypt south valley university, Application Mathematics

    4-A strongly Degenerate ideal Bose-Einstein :we consider the situation when

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    * Bc S Faculty of science Egypt south valley university Application Mathematics

    In this equation where V M ; give 1