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    BASIC ENGINEERING SCIENCES

    REVIEWER(LECTURE)

    Engineering Mechanics, Strength of Materials, Fluid Mechanics,Thermodynamics, and Engineering Economics

    Revision 0

    2011

    Prepared By:

    Agerico U. Llovido PME

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    CONTENTS

    A. ENGINEERING MECHANICS

    B. STRENGTH OF MATERIALS

    C. FLUID MECHANICS

    D. THERMODYNAMICS

    E. ENGINEERING ECONOMICS

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    A E EE EC A C ( EC E)

    1. E E .

    2. B E 2.1

    .2.2 D

    .3. B D

    3.1 .

    3.2 .

    4. D :4.1 F ,

    , . F 4.2 .4.3

    . , . .

    4.4 . . , .

    .4.5 . .

    / .4.6 A .

    / 2.4.7 B .

    5. 5.1 A .5.2 A

    .5.3 A .

    6. 6.1 . (E . , , , , .)6.2 . (E . , , , ).

    7. F ( )7.1 C .7.2 .7.3 C .

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    A E EE EC A C ( EC E)

    7.4 .7.5 C , , .7.6 C .7.7 .7.8 , , .

    8. 8.1 ,

    .

    8.2 C .

    cosF F x = , sinF F y =

    8.3

    ( ) += 180cos2 212221 F F F F R

    cos2 212

    22

    1 F F F F R ++=

    8.4 2

    22

    1 F F R +=

    1

    2tanF

    F =

    8.5

    L++= 2211 coscos F F F x

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    A E EE EC A C ( EC E)

    L++= 2211 sinsin F F F y ( ) ( )22 += y x F F R

    =

    x

    y

    F

    F tan

    9. F

    .cetan Dislar PerpendicuForceForceaof Moment =

    d F M = 10. F B D

    F .11. F E

    = 0 xF = 0 yF = 0 M 12. C

    = 0 A M ( ) 0

    42=

    L Lwd H

    d wL

    H 8

    2

    =

    =

    = = ( / ).2

    2

    2

    += L

    w H T A

    3

    42

    5

    32

    3

    8

    L

    d Ld

    LCableof Length +=

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    A E EE EC A C ( EC E)

    13. C

    wyT T B A ==

    = = 222 cs y +=

    c

    ysc x

    += ln

    x L 2=

    14. FF .

    N f F =

    N F

    f == tan

    := = ( )

    = . .

    .

    C ( ). C ( )

    = =

    = =

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    A E EE EC A C ( EC E)

    15. .

    15.1 vt s =

    :

    = , = , / = ,

    15.2

    vdt ds = dt

    dsv =

    adt dv = dt

    dva =

    adsvdv = 15.3 C

    t

    vva 12

    =

    21

    2

    1at t vs +=

    asvv 22122 +=

    : = , / 2. (+) . ( ) .

    = , / = , = ,

    16. F B

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    A E EE EC A C ( EC E)

    t

    vvg 12

    =

    21

    2

    1gt t vs +=

    gsvv 22122 +=

    : = , / 2. (+) . ( ) .

    17. A

    17.1 t =

    17.2

    t 12

    =

    21

    2

    1t t +=

    22122 +=

    :

    = , / 2 / 2. (+) . ( ) .

    = , / / .

    = , = ,

    18.

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    A E EE EC A C ( EC E)

    18.1 coso x vv =

    sino y vv =

    18.2 ( )t v x

    o cos=

    18.3

    ( ) 22

    1sin gt t v y o =

    18.4 E ( )

    22

    2

    cos2tan

    ov

    gx x y =

    18.5 ( )

    g

    v R o

    2sin2=

    gv

    t y2=

    18.6 ,

    g

    v H o

    2

    sin 22 =

    g

    vt

    y=

    : = , /

    = , = , = , .

    19. A

    r s = r v = r a =

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    A E EE EC A C ( EC E)

    r v

    a n

    2

    =

    r mv

    maF nc

    2

    ==

    22

    t nT aaa +=

    : = , = ,

    = , = , /

    = , / = , / 2

    = , / 2 = , / 2

    = , = ,

    = , /2

    = , /2

    20. F (D )

    ag

    W maF ==

    :F = ,

    = , A = , / 2

    21. D A ( )

    maag

    W = = E F ( )

    A

    = 0 xF = 0 yF

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    A E EE EC A C ( EC E)

    = 0 M

    22. E 21 KE NW PW KE =+

    : = =

    g

    Wv2

    21

    = =

    = =g

    Wv2

    22

    23. , E 23.1 . .

    .

    23.2 E . E . .

    23.3 . . (1 = 1/ ).

    velocityForcetime

    cetandisForcePower =

    =

    input Work

    output Work

    input Power

    output Power Efficiency ==

    24. E24.1 E .

    2

    2

    1mvKE =

    24.2 E . , .

    . ( ) .

    mghWhPE ==

    : = , = , /

    = = , = ,

    25. 25.1 .

    t F pulse Im =

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    A E EE EC A C ( EC E)

    25.2 . . / .

    mv Momentum =

    26. C .

    22112211 vmvmvmvm +=+ :

    E .

    .

    C :C .

    21

    21

    =

    : = 1, = 0, .

    27. . A

    , .

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    A E EE EC A C ( EC E)

    ghv 2=

    gv

    h2

    2

    =

    g

    LT 2=

    : = , / = , = ,

    = ,

    28. C

    gr

    W

    F c2

    tan ==

    29. C FC .

    30. C C ,

    .

    r mgr

    Wvr

    mvF c

    222

    ===

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    A E EE EC A C ( EC E)

    : = ,

    = , = 2 = = , /

    = , / /

    31. E B2222

    2

    1

    2

    1

    2

    1 I mk mvKE ===

    , I r F T ==

    : = , = , /

    = , 2 = 2

    = , / /

    = , / 2 / 2

    32. ,

    .

    B = 22 r R /

    A B = x2 / 2

    = = 2

    = = onacceleratint displaceme

    2

    33. B C = C

    . .

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    A E EE EC A C ( EC E)

    34. C , .

    N W =

    c f F F =

    gr v

    f 2

    =

    E

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    B E G H F A E A ( EC E)

    1. E G H F A E A . .

    2. AD .

    F 2.1 D .2.2 .2.3 .2.4 .

    3. E A D A .

    ,

    =

    = F ,

    A = C

    , . , .

    ,

    ,

    = =

    = C ,

    =

    D .

    4. H E A , D F E A C A D D F G D ( HEA D )

    H . .

    F :

    E ,

    =

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    B E G H F A E A ( EC E)

    F :

    ,

    =

    E

    ( ) +=

    12

    5. E A D AG A

    5.1 (A) .

    5.2 E (B) .

    5.3 (C D) .

    5.4 (E) .

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    B E G H F A E A ( EC E)

    :

    =

    :

    =

    8. C E E E A D A

    C :

    =

    C : =

    9. HEA E A D A

    .

    =

    ,

    =

    .

    10. BEA G E

    B .

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    B E G H F A E A ( EC E)

    A : , C , , .

    F :

    B : ( )

    = = D =

    = , =

    :

    B = .

    B :

    =

    = A

    = = ,

    = D

    11. A E A D A G A F

    ( .

    . .

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    B E G H F A E A ( EC E)

    :

    F ,

    ==

    = ,r = ,T = , J = ,G = ,l = , = A l .

    F

    4

    32 =

    316

    =

    F ( od ) ( id ).

    ( ) ( )[ ]4432

    =

    2

    =

    ( )4416

    =

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    B E G H F A E A ( EC E)

    ( )43 116

    =

    =

    =

    =

    ==

    602

    = , = A / .

    E :

    025,63

    = , .

    11.1

    C .

    .

    .

    :

    =22

    2

    11

    121

    +=+

    F , GGG == 21

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    B E G H F A E A ( EC E)

    :

    21 =

    22

    2

    11

    1

    =

    2

    1

    2

    1

    1

    2

    2

    1

    =

    F == 21

    2

    1

    1

    2

    2

    1

    =

    12. BE D G E F E A E

    ==

    = .

    = . = . = ,

    = .

    B :

    ==

    = .

    13. HE A E E A D HE A E A /C AC

    .

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    B E G H F A E A ( EC E)

    E /C =

    =

    =

    ==

    = . = .= C .

    14. EA A D A E A A

    . .

    15. A

    =

    0.25 0.35 .

    16. AC E

    .

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    B E G H F A E A ( EC E)

    E =

    ( ) +=21

    ++=

    211

    F :0=

    2=

    17. FF E .

    18. A A E E G E .

    221 2

    ==

    19. C B ED E E

    E A E E = 22 +=

    E A E E =

    ++= 22

    21

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    B E G H F A E A ( EC E)

    19.1 C

    =

    19.2 22

    42

    1

    += 19.3

    22 421

    21

    ++=

    20. HE E F FA E DE A C AD

    20.1 ( ) ( ).A ,

    .

    221 42

    121

    ++==

    = ,

    = ,

    ,

    = . = .

    = F .20.2 ( G ).

    A ,

    22 421

    +=

    =

    , = ,

    = .

    = F .

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    B E G H F A E A ( EC E)

    =

    2

    20.3 ( ) ( ).A ,

    ( ) ( . . ) .

    = 21

    221 42

    121

    ++=

    222 42

    121

    +=

    20.4 ( H ).A ,

    ( ) .

    20.5 ( H ).A ,

    ( ) ( . . )

    .

    ( ) ( )2

    212

    22

    1 2

    =+

    : .

    21. E D A CE / FA G E E F

    .

    ( ) ( )2

    212

    22

    1 2

    =+

    N y

    t t t t

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    B E G H F A E A ( EC E)

    24. E A D DEF EC BEA

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    B E G H F A E A ( EC E)

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    C F ID ECHA IC ( EC E)

    1. F ID ECHA IC1.1 F

    , , .

    , , , ( ), , .

    1.2 F ( ) ( ) ( ) ,

    .

    1.3 F , .

    2. F IDA .A .

    .

    3. I A E IE F F ID .

    .B .

    .

    4. C E IB E A D I C E IB E F IDC

    . G .

    I . .

    5. IDEA A D EA F IDI F , , , . F ,

    .

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    C F ID ECHA IC ( EC E)

    , 2, / ( ), 1/ , , ,

    . = ( ) = = ( ) =

    I .

    , , ( F).

    A (D ) ( .) 1 = 1 / 2, 1 = 1 / 2 = 0.1 . 1 ( ) =

    0.01 .

    ( .) 2/ , 2/ , 1 = 1 2/ . = 0.0001 2/ . 1 ( ) = 0.01 .

    9. E D BE

    . I .

    ===

    : = ,

    = , = , /

    = , 2/ = ,

    10. E F F

    F .

    2000.

    F . 4000. F .

    F 2000 4000.

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    C F ID ECHA IC ( EC E)

    11. FACE E I A D CA I A AC I .

    . .

    C A .

    12. C E IBI I A D B DC ,

    .

    =

    :

    = =

    =

    B , E B . I .

    13. H D A IC E EH .

    :

    1. .

    . .

    2. A .

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    C F ID ECHA IC ( EC E)

    = D H

    ==

    H ,

    ==

    : = ( )

    = ( )

    = D

    14. A E E

    .

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    C F ID ECHA IC ( EC E)

    ( ) ( ) ( ) ( ) +++= 332211 ( ) ( ) ( ) ( ) = 3432321211

    15. B A C

    B .

    A B

    1. A .

    2. A .

    =

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    C F ID ECHA IC ( EC E)

    =

    :

    =

    = =

    =

    16. BA IC CIE IFIC A ED I HE A A I F F ID F

    1. : .

    . .

    2. : . .

    . .

    3. : C . .

    E B .

    4. : .

    17. F A E ( )

    .

    ( ) .

    18. C I I E A I

    C E , , .

    2211 == 222111 =

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    C F ID ECHA IC ( EC E)

    F . 21 == 21 ==

    2211 =

    19. E CI HEAD

    :

    .

    2

    2

    =

    : =

    =

    20. F IC I HEAD I I ED E

    22

    22

    ==

    :

    = , = , / /

    = , = ,

    = , (D ) = 9.81 / 2 32.2 / 2

    21. C EFFICIE F F IC I ,

    1.

    C ( < 2300).64

    =

    2. C C , ( > 2300)

    +=7.3

    51.22 21

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    C F ID ECHA IC ( EC E)

    , =

    A H:

    211.1

    7.39.68.1

    +=

    H. B E (4000 < < 10 5)

    4

    316.0=

    22. H D A IC DIA E E

    F ,

    4=

    = , = , . .

    23. BE I E A IB . I

    , . B : (1) ,(2) , (3) .B , , , .

    2

    222

    1

    211

    22

    ++=++

    :

    =

    = 2

    2

    E =

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    D HERMOD NAMICS (LEC RE)

    1. HERMOD NAMICS (1)

    , .

    (2)

    .2. HE ORKING S BS ANCE

    F , , .

    P S . A

    .S S

    .I =R ,

    , , R , , . A

    = RI

    . M .

    3. HE S S EMS (1) , , , ,

    , . I , , .

    S (2) . I .

    S3.1 C S (1)

    . A .C S (2) ,

    ( ) .)

    I S (1) A .

    I S (2) .

    I S (3) . . I , .

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    D HERMOD NAMICS (LEC RE)

    3.2 O S (1) . E . A .

    O S (2) .

    C .

    C S .S E .B ; , .

    4. HERMOD NAMIC PROPER IES P (1)

    ,

    P (2) ; , , ,

    .C P1. I P ; , , , ,

    .S P , .

    2. E P .

    . ,

    . O , . , .

    P F A , ,, , .

    5. MASS AND EIGHM (1)

    . , , . S .M (2) ,

    ( ). (1) ,

    . N. S . F = . =9.81 / 2 32.2 / 2.

    (2) .

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    D HERMOD NAMICS (LEC RE)

    ( : ) 101.325P . 1 , : 760 H( ), 29.92 H , 14.696 .B . B . 1 B = 100P .

    A = 101325(1 2.25577 10 5 ) 5.25588 , = (P ) = ( ).A

    =

    : = , ( )

    = ( ), 0 = = 0 ( ) = 1.0 B (E )

    0 = = 7 (E )O 1,000 , 1 H .

    11. BAROME ERB . I , , .

    12. ABSOL E AND GA GE PRESS RES

    A , . A ( )

    . I .

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    D HERMOD NAMICS (LEC RE)

    G .

    F = + ( )

    .

    F = P

    .13. EMPERA RE

    . I . I

    . S :

    1. F (F) S 180 32 F 212 F.2. C (C) S C S 100 0 C 100 C.R :

    ( ) oo

    +=59

    32

    ( )

    =95

    32 oo

    A .

    .A .A S :1. K (K) S C .2. R (R) S F .

    R :

    460+= oo

    273+= oo

    * 15.273273

    * 67.459460

    C :

    ( ) ( )

    oooo

    =

    ==

    9

    5

    9

    5

    ( ) ( ) oooo

    =

    ==59

    59

    I 1 = 0 C 32 F.S ( ) 1 = 100 C 212F.

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    D HERMOD NAMICS (LEC RE)

    , , . 0.01 C 4.58 .

    14. ENERGE .S E ,

    ; , .P E (1) . S P.E.P E (2)

    =

    = ( , ) = ( , ) = ( / 2, / 2)

    = .

    = 217.32

    = 21

    K E (1) . S K.E.K E (2) ; ,

    .

    2

    2

    =

    = ( , ) = ( / , / )

    = ( / 2, / 2)

    = .

    = 217.32

    = 21

    J C J 778 / B

    I E (1) , ,, .

    I E (2) .

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    D HERMOD NAMICS (LEC RE)

    I E (3) .

    S I E . B / J/ . S .

    P E .S P E P .

    E (1) . I += .

    E (2) . B / J/ . S .

    S E += .

    = =

    =

    C E .N E .

    15. HEA AND ORK E ;

    ; .H (1) .S Q. B , B / , J .H (2)

    .Q (+) Q ( )

    H = =

    . S . , J.

    = = ( , N) = ( , )

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    D HERMOD NAMICS (LEC RE)

    .

    P . .

    =

    16. PES OF ORKN , NF .

    .F , F , . F = =( 2 1)S , SF ; .

    17. SPECIFIC HEAH C ( )

    ( ).S H (1) . B / F B / C.S H (2)

    .S

    .

    =

    =

    =

    S .

    =

    =

    = S

    ==

    18. EN ROPE (1) .

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    D HERMOD NAMICS (LEC RE)

    19.3 SECOND LA OF HERMOD MANICS EN ROP , .

    , , : I .

    S :

    C : I .

    K P : I , .

    A . N

    . C : I 2 ,

    1 2.

    19.4 HIRD LA OF HERMOD NAMICS ABSOL E EMPERA RE

    .A , .

    .20. HERMOD NAMIC EQ ILIBRI M

    E .

    21. CONSER A ION OF MASS .

    S S , .

    C E S F

    2

    22

    1

    11222111

    ====

    E : , / 3, 3/ , 2, / .

    22. HEA RESER OIRH

    .

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    D HERMOD NAMICS (LEC RE)

    23. HEA OR HERMAL ENGINE

    H E (1) ( ) ; .H E (2) ( )

    .24. ADIABA IC S RFACE AND PROCESS

    A . I .

    A .

    25. A AILABILIA

    ,

    .A , ,

    ,

    .26. RE ERSIBILI

    R (1) ( ) ,

    , .R (2) " "

    27. IRRE ERSIBILI

    I

    .

    27.1 E .27.2 I .

    28. A AILABLE ENERGA ,

    , , ,

    .29. HELMHOL F NC ION

    H . S . F = .

    30. GIBBS F NC IONG

    . I . S . F = .

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    D HERMOD NAMICS (LEC RE)

    31. EQ ILIBRI M

    E .M , , . A .

    , . . .

    C

    . A . , ,

    . A .

    Q

    32. PERPE AL MO ION MACHINE OF HE SECOND KIND

    P .

    33. BO LE S LAB L (1) ,

    .B L (2)

    .

    2211 =

    34. CHARLES LAC L (1)

    .

    2

    2

    1

    1

    =

    C L (2) .

    2

    2

    1

    1

    =

    35. IDEAL GAS LA

    I G L

    ; , P = R , P , , , R .

    =

    2

    22

    1

    11

    =

    = , = , = , = , = .

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    D HERMOD NAMICS (LEC RE)

    36. BASIC PROPER IES OF IDEAL GAS

    = 3143.8

    =1545

    =

    =

    1=

    1=

    : = =

    =

    = =

    37. PROPER IES OF AIR 97.28=

    4.1= == 287.03.53

    === 0.124.024.0

    === 716.0171.0171.0

    38. A OGADRO S LA AND N MBER

    A L .

    A , N A 6.0225 1023 1 .

    39. JO LE S LAJ L

    .40. DAL ON S LA OF PAR IAL PRESS RE

    D L P P

    .

    =+++=

    L

    [ ] ====== =

    1=

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    D HERMOD NAMICS (LEC RE)

    41. AMAGA S LA OF PAR IAL OL MESA ' L P , .

    =+++=

    L

    [ ] ====== =

    1=

    42. HERMOD NAMIC S S EMS AND PROCESSES P .

    C P C ( ) .

    R P , , , .

    I P . ,

    .A P .

    .I P .

    . A .

    P P , L P ( ) L ( )

    . O nPV = . P

    , 21 hh = ; , 0=W ; , 0=Q .I P ( , )

    .I P (I P ) (

    ), .I P ( , )

    .

    43. EQ A IONS FOR HERMOD NAMIC PROCESSESE = =

    N F E

    +=

    S F E , 0= 0=

    +=

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    D HERMOD NAMICS (LEC RE)

    S F E , 0K 0P

    sf W PK H Q +++=

    : =

    = K = P =

    =

    =

    I E

    =

    E =

    N F =

    S F , 0= 0=

    = S F E , 0 0

    =++

    N :

    =

    44. ISOBARIC PROCESS

    I P ( , ) .

    = C

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    D HERMOD NAMICS (LEC RE)

    1

    2

    1

    2

    =

    ( )12 =

    ( )12 =

    N :

    +=

    ( )12 == =

    E :

    =

    2

    1

    1

    2

    ==

    S F : +=

    0== =

    E : =

    2

    1

    1

    2

    ==

    S H R :

    =

    =

    45. ISOME RIC PROCESS (ISOCHORIC PROCESS)I P (I P ) (

    ), .

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    D HERMOD NAMICS (LEC RE)

    =

    1

    2

    1

    2

    =

    ( )12 =

    ( )12 = N : +=

    0==

    =

    E : =

    1

    2

    1

    2

    ==

    S F : +=

    ( )12 == =

    S H R :

    =

    =

    46. ISO HERMAL PROCESSI P ( , )

    .

    = , =

    ( )12 =

    ( )12 =

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    D HERMOD NAMICS (LEC RE)

    N F E : +=

    ==== 2211

    2

    1

    1

    2

    ==

    2

    1

    1

    2

    ==

    =

    S F : +=

    2

    1

    1

    2

    ==

    2

    1

    1

    2

    ==

    =

    E :

    1

    2

    =

    2

    1

    =

    2

    1

    1

    2

    ==

    47. ISEN ROPIC PROCESSI P .

    = , 0= , = , 0=Q

    =

    2

    1

    1

    2

    ,

    1

    2

    1

    1

    2

    =

    ,O

    k k

    p

    p

    T

    T 1

    1

    2

    1

    2

    =

    ( )12 =

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    D HERMOD NAMICS (LEC RE)

    ( )12 = N : +=

    =

    =

    11

    11

    1

    2

    1111

    1

    211

    =

    =

    =

    11

    11

    11

    1

    1

    211

    2

    111

    1

    21

    ( )

    =

    =

    =11

    11

    112212

    1

    21

    B ,

    1=

    ( ) == 12 S F : +=

    =

    =

    =

    =

    11

    11

    11

    11 1

    211

    2

    11

    1

    1

    21

    1

    1

    211

    ( )

    =1

    12

    B

    1=

    ( ) == 12 N :

    =

    =

    ==

    48. POL ROPIC PROCESSP P = C .

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    D HERMOD NAMICS (LEC RE)

    = , =

    1

    21

    12

    =

    ,

    1

    12

    12

    =

    ( )12 =

    ( )12 = N : +=

    =

    =

    11

    11

    1

    2

    1111

    1

    211

    =

    =

    =

    111111

    1

    121

    1

    211

    1

    121

    ( )

    =

    =

    =11

    11

    112212

    1

    21

    B ,

    1=

    ( )11

    112212

    =

    =

    ( ) ( ) ( )( )( )( )111

    11

    11

    11

    1 112211221122

    =

    =

    +

    =

    S F : +=

    =

    =

    =

    =

    11

    11

    11

    11 1

    211

    2

    11

    1

    1

    21

    1

    1

    211

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    D HERMOD NAMICS (LEC RE)

    ( )

    =1

    12

    B

    1=

    ( ) ( ) ( )11

    11221212

    =

    ==

    ( ) ( )11221122 1111

    11

    =

    +

    =

    ( )( )( )( )11

    1122

    =

    E :

    1

    2

    1

    =

    O

    ( )

    =

    2

    1

    =

    =

    1

    2

    1

    1

    2

    1

    N :S :

    =++

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    D HERMOD NAMICS (LEC RE)

    54. PHASES OF P RE S BS ANCE

    P (1) . I .

    P (2) .

    P (3) .54.1 S .54.2 L .

    S L

    .C L

    . I , .

    S L

    .54.3 G .

    .

    S .

    S .

    55. PHASE RANSI IONSP C .

    55.1 M .55.2 F .

    55.3 S .55.4 D .

    55.5 C .55.6 .

    56. SA RA ED EMPERA RES ,

    .57. SA RA ED PRESS RE

    S P , , '

    .58. DEGREES S PERHEA AND DEGREES S BCOOLING

    D S .D S .

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    D HERMOD NAMICS (LEC RE)

    59. SENSIBLE HEAS H

    60. LA EN HEAL H .60.1 L ,

    .60.2 L ,

    . I .61. CRI ICAL POIN

    C P .

    62. MOLLIER DIAGRAMM D ( ) .

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    D HERMOD NAMICS (LEC RE)

    63. EMPERA RE EN ROP DIAGRAM

    64. C

    66. PROPER IESS , .I E ,

    .E , : = + .

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    D HERMOD NAMICS (LEC RE)

    E , ; .

    67. MI RESM .=

    = 1 = P

    +=

    +=

    +=

    +=

    68. PROCESSES IN OL ING P RE S BS ANCES. I : 1 = 2 . I : 1 = 2 E .. I : 1 = 2

    F : 1 = 2 I : 1 = ( + )2 . I : 1 = 2 I ( ) ( , ,

    ).. ( ) : 1 = 2 I : 1 = ( + )2

    I , :( + )1 = 2 69. ESSEN IAL ELEMEN S OF A HERMOD NAMIC HEA ENGINE

    69.1 , , .69.2 S (H , H , S )

    .69.3 H (R , C , S ) .69.4 E .

    70. HE CARNO C CLE

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    D HERMOD NAMICS (LEC RE)

    3421 = 3241 =

    ( )411 = ( ) ( )412322 ==

    ( ) ( )412411 == ( ) ( )( )411

    412411

    =

    ==

    =

    =

    1

    21

    =

    = C

    1 = H =

    2 = L = 71. S IRLING AND ERICSSON C CLE

    I S C , .

    I E C , .

    72. BASIC ORKING C CLES FOR ARIO S APPLICA IONS

    A B CS P P R CG E (S I ) O CD E (C I ) D CG B CR S R C

    E

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    E E GI EE I G EC IC ( EC E)

    5. C IC

    .

    ( ) += 1 = ( ) ( )niniPF += 1%,,

    ( )niPF PF %,,= = ( ) ( ) += 1,,

    ( )niF PF P %,,= :

    = = =

    = 6. C F D

    C .

    7. DD .D , PF D =

    ,F

    PF d

    =

    8. E I

    .E

    . E .

    ni = =

    E = 11

    +=

    mn

    m

    ii

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    E E GI EE I G EC IC ( EC E)

    := 2 = 4 = 12 = 6

    = 360

    9. C C I rt PeF =

    : = =

    = =

    10. A

    A .

    A .

    10.1 A 10.1.1 I .10.1.2 A .10.1.3 D10.1.4 .

    10.2

    10.2.1 A .10.2.2 A D .10.2.3 D A .10.2.4 .

    11. A

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    E E GI EE I G EC IC ( EC E)

    = ( ) ( )i

    ini AF

    n 11%,,

    +=

    ( )ni AF AF %,,=

    = ( )( ) 11

    %,,+

    =

    ni

    iniF A

    ( )niF AF A %,,=

    C = ( ) ( )( ) 11

    1%,,

    +

    +=

    n

    n

    i

    iiniP A

    ( )niP AP A %,,=

    = ( ) ( )( )n

    n

    ii

    ini AP

    +

    +=

    1

    11%,,

    ( )ni AP AP %,,=

    : = . =

    = A =

    =

    12. A D

    ( )4%,, i AP A AP += ( )5%,, iPF PF = ( )51 iPF +=

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    E E GI EE I G EC IC ( EC E)

    13. D A

    ( )( )3%,,5%,, iF Pi AP AP = ( )8%,, iPF PF = ( )81 iPF +=

    14.

    i

    AP =

    :

    = = A

    =

    15. A G

    A = ( ) ( )( ) ( )nn

    n

    ii

    n

    ii

    iniGP

    +

    +

    +=

    11

    11%,,

    2

    A = ( ) ( )in

    i

    iniGF

    n

    +=

    2

    11%,,

    A = ( ) ( ) 111%,,

    +=

    nin

    iniG A

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    E E GI EE I G EC IC ( EC E)

    ( )niGPGPG %,,= ( )niG AG AG %,,= ( ) ( )niGF GniPF PF GG %,,%,, ==

    : = E .

    16. G G

    =+

    +

    +

    =

    igi

    n A

    iggi

    ig

    A

    P

    n

    g

    1

    1

    11

    1

    1

    ( )niPF PF gg %,,=

    17. D

    D . D .

    17.1 D17.1.1

    , , .

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    E E GI EE I G EC IC ( EC E)

    17.1.2 F ,

    .17.2 D

    17.2.1 .17.2.2

    .17.3 D

    F C ( ) .

    E ( ) . (A )

    .

    .

    17.4 C .

    B ( ) .

    ( ) ; .

    ( ) .F

    . .

    F ( ) .

    18. C D18.1

    .

    A D =n

    SV FC d

    =

    B .

    =

    n

    SV FC mFC BV

    D ( ) .

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    E E GI EE I G EC IC ( EC E)

    D =Cost First

    on Depreciati Annual

    18.2 F

    .

    A D =( ) ( )

    ii

    SV FC ni AF

    SV FC d n 11%,, +

    =

    =

    : =

    B .

    ( ) +=

    ii

    d FC BV n 11

    18.3 D ( D) D 1 .

    ( )2

    1+==

    nnSOYDT

    ( )SV FC T k n

    d k

    +

    =1

    ( )SV FC T

    nd

    =1

    ( )SV FC T

    nd

    =1

    2

    ( )SV FC T

    nd

    =2

    3

    E .B .

    ( )md d d d FC BV L+++= 321 18.4 D B

    (A D B , , C C ).

    ( )nr FC SV = 1

    ( )( ) 11 = k k r FC r d ( )FC r d =1

    ( )( )r FC r d = 12 ( )( )23 1 r FC r d =

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    E E GI EE I G EC IC ( EC E)

    E .B .

    ( )mr FC BV = 1

    18.5 D D B D

    . D .

    L

    LFC SV

    =2

    1

    ( )1

    21

    2

    =

    k

    LFC

    Ld k

    ( )FC L

    d 2

    1 =

    ( )

    = L

    FC L

    d 2

    12

    2

    ( )2

    32

    12

    = L

    FC L

    d

    E .B .

    m

    LFC BV

    =2

    1

    18.6

    .

    D ,capacityunitsof No

    SV FC d

    .

    =

    18.7 H H

    D ,capacityhoursof No

    SV FC d

    .

    =

    19. D , , , .

    D19.1 C D , , . I

    .C

    .

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    E E GI EE I G EC IC ( EC E)

    capacityresource

    t cos first pt =

    . . I

    , .

    19.2 D . A ,

    50% . F , 100% .

    =

    , .

    20. C (F A C )20.1 F

    C = A D + I C

    A D =( )

    ii

    SV FC n 11 +

    I C = ( )FC i 20.2

    C = A D + A I

    A D =n

    SV FC

    I C = ( ) ( )SV iSV FC n

    ni+

    + 1

    2

    21. C CC C , ,

    .

    C C C21.1 F .

    C C =i

    OM FC +

    21.2 F .

    C C =( ) 11 +

    ++

    ni

    SV FC i

    OM FC

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    E E GI EE I G EC IC ( EC E)

    23.3 C , , ,

    . I 15, . . .

    . ,

    . , .

    F C C C23.3.1 C .23.3.2 I (5 15)

    .23.3.3 .23.3.4 .

    . C ..

    .

    24. CC .24.1 F B C

    24.1.1 , .24.1.2 .24.1.3 .24.1.4 B .

    24.2 B .24.3 , ,

    , .24.4

    , , .25. B

    B 10 .

    25.1 25.1.1

    .

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    E E GI EE I G EC IC ( EC E)

    25.1.2 C .

    25.1.3 D .

    25.2 B

    ( ) ( ) %,,%,, += :

    = =

    = = = ( )=

    26. B I 26.1 .

    Investment Total

    rofit P Net turn Reof Rate =

    26.2 .

    FlowCash Annual Net

    ValueSalvage Investment TotalPeriod Payout

    =

    27. A

    27.1

    E .

    , , .27.2

    . .

    27.3

    .27.4 A C

    A C = D + I C + + E

    .27.5

    .

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    E E GI EE I G EC IC ( EC E)

    27.6 F F

    .

    28.

    .28.1

    quired ReCapital Additional

    placement Re By Incurred Savingsturn Reof Rate =

    28.2 A CA C = D + I C + +

    E

    I , .

    29. B C B C

    .

    : =

    = =

    = = = , , .

    = ( ) ( )niF ASV niP AFC C %,,%,, =

    B C

    C OM B

    C B

    =

    B/C 1 .

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    E E GI EE I G EC IC ( EC E)

    30. E E (E ) .A (E ) : .

    h

    ak QO E

    2=

    : = ( )

    = , = ( )

    31. A31.1 B

    B . A . A

    , .31.2 B

    B :

    A = + E

    D . A .

    F , .31.3 C

    C .

    31.4 F F .F ,

    .31.4.1 F

    31.4.1.1 B .31.4.1.2

    . . E , , . , , , .

    31.4.2 B 31.4.2.1 C

    .

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    E E GI EE I G EC IC ( EC E)

    31.4.2.2 F , , , .

    31.4.2.3 C , .

    31.4.2.4 .

    31.4.3 F 31.4.3.1 C .

    s LiabilitieCurrent

    AssetsCurrent RatioCurrent =

    31.4.3.2 A .

    s LiabilitieCurrent

    AssetsQuick RatioTest Acid =

    31.4.3.3 .

    ceivables Re Average

    Credit onSales Net Turnover ceivable Re =

    31.4.3.4 G .

    Sales Net

    ofit Pr Grossinarg M Gross =

    31.4.3.5 .

    Sales Net

    Tax Before Income Net Ratioinarg M ofit Pr =

    31.4.3.6 .

    EquitysOwner

    Income Net Investment onturn Re

    '=