bba i-bm-u-2- matrix -
TRANSCRIPT
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MATRIX ALGEBRA
Course BBA
Subject: Business Mathematics
Unit-2
1
2
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The notation is used for the algebraic
expression ad – bc.
It is called a determinant of order two.
a, b, c ,d are called the elements of the determinant.
ad – bc is called the expansion or the value of the
determinant.
a b
c d
3.
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a, b is called the first row and c,d is called the
second row of the determinant.
a, c is called first column and b, d is called the
second column of the determinant.
a, d is called the principal diagonal of the
determinant.
a b
c d
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a b c
d e f
g h i
is called a determinant of
order three.
Its expansion is as follows:
:
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= a(ei - fh) - b(di - fg) + c(dh - eg)
4.
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(1) Find the value of
Answer:
= 1 - 2 + (-3)
= 1 [(4*5) – (6*2)] – 2[(5* 5) – (2 * -8)] – 3 [(5 * 6) – (4 *-8)]= 1 [20 - 12] – 2 [25 + 16] – 3 [30 + 32]
= 1[8] – 2 [41] – 3 [62]= 8 – 82 – 186 = -260
1 2 3
5 4 2
8 6 5
4 2
6 5
5 2
8 5
5 4
8 6
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Suppose we are given the following equations.
a1x + b1y + c1 = 0………………. (1)
a2x + b2y + c2 = 0………………..(2)
To solve this equations, multiply equation (1) by b2 and
equation (2) by b1,
a1b2x + b1b2y + c1b2 = 0…………… (3)
a2b1x + b1b2y + c2b1 = 0…………….(4)
Subtracting equation (4) from (3), we get
(a1b2 – a2b1)x + c1b2 – c2b1 = 0
(a1b2 – a2b1)x = c2b1 – c1b2.
If a1b2 – a2b1 ≠ 0 then
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1 2 2 1 1 2 2 1
1x
b c b c a b a b
……(5)
Similarly, eliminating y, we get
2 1 1 2 1 2 2 1
1y
a c a c a b a b
……………. (6)
From (5) and (6), we get the following formula for the value of x and y.
1 2 2 1 2 1 1 2 1 2 2 1
1x y
b c b c a c a c a b a b
Expressing the denominators in the form of determinants, we get
1 1 1 1 1 1
2 2 2 2 2 2
1x y
b c c a a b
b c c a a b
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11 12 13 14
21 22 23 24
31 32 33 34
mn mn mn mn
a a a a
a a a a
a a a a
a a a a
Row 1
Row 2
Row 3
Row m
Column 2Column 1 Column n
5.
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5 3 1
1.) 11
2
2 X 3
3 8 9
2.) 2 5
6 7 1
3 X 3
83.)
7
2 X 1
4.) 2 3
1 X 2
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(1) Row matrix:
A 1 Χ n matrix of the type [ a11, a12, …….a1n] is called
a row matrix.
This matrix has only one row and n columns.
(2) Column matrix:
A m Χ 1 matrix of type is called a column matrix.
This matrix has m rows and only one column.
11
21
1m
a
a
a
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(3) Square matrix:
A matrix of order m Χ m is called a square matrix.
In a square matrix the number of rows equals the number of
columns.
For example, A = B =
2 2
1 2
3 4
3 3
a b c
d e f
g h i
(4) Diagonal matrix:
A square matrix, in which each element except the diagonal
elements is zero, is called a diagonal matrix.
For example, A = is a diagonal matrix. 4 0 0
0 2 0
0 0 5
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(5) Identity matrix:
A square matrix in which all the elements in the principal diagonal are equal to unity (1) and all other elements are 0 is called a unit matrix or an identity matrix.
A unit matrix of order n Χ n is denoted by In. For example.
I2 = I3 =
(6) Scalar matrix:
A diagonal matrix, in which all the elements in the principal diagonal are equal to a scalar k, is called a scalar matrix.
For example,
A =
1 0
0 1
1 0 0
0 1 0
0 0 1
3 0 0
0 3 0
0 0 3
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(7) Null matrix:
A matrix having all its elements as zero is called a zero or a null
matrix.
Null matrix can be square or rectangular.
It is usually denoted by 0mΧn or just 0.
For example 01Χ3 =
(8) Transpose of a matrix:
The matrix obtained from any given matrix A by changing its rows
into corresponding columns is called the transpose of A and it is
denoted by A’ or AT.
For example A = [1 2 3] then AT =
0 0 0
1
2
3
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(9) Symmetric matrix:
If for a square matrix A = [aij], A’ = A, then A is called a
symmetric matrix.
In a symmetric matrix, aij = aji for each pair (i, j).
For example A = B =
(10) Skew symmetric matrix:
If for a square matrix A = [aij], A’ = -A, then A is called
a skew symmetric matrix.
In a skew symmetric matrix, aij = -aji for each pair (i, j).
For example A =
1 3
3 2
3 6 7
6 5 4
7 4 8
0 3 2
3 0 5
2 5 0
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You can add or subtract matrices if they have the
same dimensions (same number of rows and
columns).
To do this, you add (or subtract) the corresponding
numbers (numbers in the same positions).
Example:
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A + B
5 6 0 3
4 2 1 3
1 3
6 4
5 0 6 3;
4 1 2 3A B
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When a zero matrix is added to another matrix of the
same dimension (i.e. number of rows and columns
should be same), that same matrix is obtained.
2 1 3 0 0 02.)
1 0 1 0 0 0
2 1 3
1 0 1
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1 2 1 1
3.) 2 0 1 3
3 1 2 3
1 1 2 ( 1)
2 1 0 3
3 2 1 3
0 3
3 3
5 4
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• If A is an m × n matrix and s is a scalar, then we let kA
denote the matrix obtained by multiplying every
element of A by k.
• This procedure is called scalar multiplication.
310
221A
930
663
331303
2323133A
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To multiply matrices A and B look at their dimensions
pnnm
MUST BE SAME
SIZE OF PRODUCT
If the number of columns of A does not equal the
number of rows of B then the product AB is
undefined.
6.
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•The multiplication of matrices is easier shown than put into
words.
•You multiply the rows of the first matrix with the columns of the
second adding products
140
123A
13
31
42
B
Find AB
First we multiply across the first row and down the first column
adding products. We put the answer in the first row, first column of
the answer.
23 1223 5311223
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140
123A
13
31
42
B
Find AB
We multiplied across first row and down first column so we put the
answer in the first row, first column.
5AB
Now we multiply across the first row and down the second column and we’ll put
the answer in the first row, second column.
43 3243 7113243
75AB
Now we multiply across the second row and down the first column and we’ll put
the answer in the second row, first column.
20 1420 1311420
1
75AB
Now we multiply across the second row and down the second column and we’ll
put the answer in the second row, second column.
40 3440 11113440
111
75AB
Notice the sizes of A and B and the size of the product AB.
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The matrix formed by taking the transpose of the cofactor
matrix of a given original matrix.
The adjoint of matrix A is often written adj A.
Example:
Find the adjoint of the following matrix:
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First find the cofactor of each element.
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As a result the cofactor
matrix of A is
Finally the adjoint of A is the transpose of the
cofactor matrix:
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If for a given square matrix A, there exists a matrix B
such that AB = I = BA, then the matrix B is called an
inverse of A.
It is denoted by A-1
Note: Inverse does not exist if product is not an identity .
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1. Find determinant of matrix. If det. is not equal to 0,
then inverse of matrix exist.
2. Find adjoint of a matrix.
a. find cofactor
b. change sign. (if odd.. –ve sign & if even.. +ve
sign)
c. transpose.
3. Find inverse. i.e. A-1 = (adjoint of A)1
A
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7.
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8.
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1 2 3
0 4 5
1 0 6
A
Find inverse of
Solution:
Step 1
= 1 (24-0) – 2 (0-5) + 3 ( 0 – 4)
= 1 (24) -2 (-5) + 3 (-4)
= 24 + 10 -12 = 22
4 5 0 5 0 41 2 3
0 6 1 6 1 0
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Step-2
Find Cofactor of
matrix
1 2 3
0 4 5
1 0 6
A
The cofactor for each element of matrix A:
11
4 524
0 6A 12
0 55
1 6A 13
0 44
1 0A
21
2 312
0 6A 22
1 33
1 6A 23
1 22
1 0A
31
2 32
4 5A 32
1 35
0 5A 33
1 24
0 4A
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Cofactor matrix of is then given by:
1 2 3
0 4 5
1 0 6
A
24 5 4
12 3 2
2 5 4
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Inverse matrix of is given by:1 2 3
0 4 5
1 0 6
A
1
24 5 4 24 12 21 1
12 3 2 5 3 522
2 5 4 4 2 4
T
AA
12 11 6 11 1 11
5 22 3 22 5 22
2 11 1 11 2 11
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Given AX = B
we can multiply both sides by the inverse of A, provided this exists, to give
A−1AX = A−1B
But A−1A = I, the identity matrix.
Furthermore, IX = X, because multiplying any matrix by an identity matrix of the appropriate size leaves the matrix unaltered.
So X = A−1B
This result gives us a method for solving simultaneous equations
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Example:
Solve x + y + z = 6
2y + 5z = -4
2x + 5y - z = 27
We can call the matrices "A", "X" and "B" and the
equation becomes:
AX = B
9.
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Where
A is the 3x3 matrix of x, y and z coefficients
X is x, y and z, and
B is 6, -4 and 27
Then the solution is this:
X = A-1B
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Multiply A-1 by B
The solution is:
x = 5, y = 3 and z = -2
10
.
11
.
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(A) Online Sources (for images):
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4. http://www.mathsisfun.com/algebra/images/matrix-3x3-det-c.gif
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0
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x%20Algebra.ppt
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%20Matrices.ppt
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1. Business Mathematics by A.G.Patel and G.C.Patel-
Atul Prakashan.