bell work: solve for x: 5y + x – 2y – 4 + 3x = 0

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Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

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Page 1: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Bell Work:

Solve for x:

5y + x – 2y – 4 + 3x = 0

Page 2: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Answer:

x = -3/4 y + 1

Page 3: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Lesson 43:Least Common Multiple, Least

Common Multiples of Algebraic

Expressions

Page 4: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

If we are given the numbers

4, 5, and 8

And are asked to find the smallest number that is evenly divisible by each of the numbers, a reasonable guess would be the product of the numbers, which is 160, because we know that each of the numbers will divide 160 evenly

160/4 = 40 160/5 = 32 160/8 = 20

Page 5: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

But 160 is not the smallest number that is evenly divisible by the three numbers. The number 40 is.

40/4 = 10 40/5 = 8 40/8 = 5

Page 6: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

We call the smallest number that can be divided evenly by each of a group of specified numbers the least common multiple (LCM) of the specified numbers.

Page 7: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

We can find the LCM of some numbers by making mental calculations, but it is nice to have a special procedure to use if some of the numbers are large numbers. The procedure is as follows:

Page 8: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

1. Write each number as a product of prime factors.

2. Compute the LCM by using every factor of the given numbers as a factor of the LCM. Use each factor the greatest number of times it is a factor in any of the numbers.

Page 9: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

To demonstrate this procedure we will find the LCM of

18, 81, and 500

First we write each number as a product of prime factors:

18 = 2 x 3 x 3

81 = 3 x 3 x 3 x 3

500 = 2 x 2 x 5 x 5 x 5

Page 10: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Now we find the LCM by using the procedure in Step 2. The number 2 is a factor of both 18 and 500. it appears twice in 500, so it will appear twice in the LCM.

2 x 2

Page 11: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

The number 3 is a factor of both 18 and 81. it appears four times in 81, so it will appear four times in the LCM.

2 x 2 x 3 x 3 x 3 x 3

Page 12: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Therefore, 40,500 is the smallest number that is evenly divisible by each of the three numbers 18, 81, and 500.

Page 13: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Example:

Find the LCM of 8, 15, and 100.

Page 14: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Answer:

8 = 2 x 2 x 2

15 = 3 x 5

100 = 2 x 2 x 5 x 5

2 x 2 x 2 x 3 x 5 x 5

= 600

Page 15: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Example:

Find the Least Common Multiple of 30, 75, and 80.

Page 16: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Answer:

30 = 2 x 3 x 5

75 = 3 x 5 x 5

80 = 2 x 2 x 2 x 2 x 5

2 x 2 x 2 x 2 x 3 x 5 x 5

= 1200

Page 17: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Practice:

Find the LCM of 560, 588, and 1250.

Page 18: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Answer:

560 = 2 x 2 x 2 x 2 x 5 x 7

588 = 2 x 2 x 3 x 7 x 7

1250 = 2 x 5 x 5 x 5 x 5

2 x 2 x 2 x 2 x 3 x 5 x 5 x 5 x 5 x 7 x 7

= 1, 470, 000

Page 19: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

The least common multiple is most often encountered when it is used as the least common denominator. If we are asked to add the fractions

¼ + 5/8 + 7/12

We rewrite each of these fractions as a fraction whose denominator is 24, which is the least common multiple of 4, 8 and 12.

6/24 + 15/24 + 14/24 = 35/24

Page 20: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

In lesson 44 we will discuss the method of adding algebraic fractions. To prepare for that, we will practice finding the least common multiple of algebraic expressions.

Page 21: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Example:

Find the least common multiple of 15a b and 10ab .2 3

Page 22: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Answer:

15a b = 3 x 5 x a x a x b

10ab = 2 x 5 x a x b x b x b

LCM = 2 x 3 x 5 x a x a x b x b x b

= 30a b

2

3

2 3

Page 23: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Practice:

Find the LCM of 4x m and 6x m.

2 3

Page 24: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Answer:

4x m = 2 2 x x m

6x m = 2 3 x x x m

LCM = 2 2 3 x x x m

= 12x m

2

3

3

Page 25: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Practice:

Find the LCM of 12x am and 14x am .

2 2

3 4

Page 26: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

Answer:

84x am3 4

Page 27: Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

HW: Lesson 43 #1-30