biochem evals 8 set g
TRANSCRIPT
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item
numberanswer explanation
1
a
TAG can be catalyzed to form 3 FFA and glycerol. When glycerol is oxidized it can
form glyceraldehyde or dihydroxyacetone which can be phosphorylated into
glyceraldehyde -3-phosphate or dihydoxyacetonephosphate which then is a
substrate in glycolysis
b
acetaldehyde a product of pyruvate decarboxylation (outside of the
glycolytic pathway) to form ethanol with the enzyme pyruvate
decarboxyalase and cofactor thiamine
cphosphoenolpyruvate is a substrate of glycolysis but cannot be formed
from glycerol
dpyruvate is already the end product of glycolysis; nonetheless, it cannot be
formed form glycerol
2
c the brain is highly dependent on the circulating glucose for its energy generation
a
in the first place, the brain doesnt have the capacity to store fuel (only
liver and muscle stores glycogen). Pwede rin sya kaya lang letter c is a
better answer because this attacks the storage capacity of the brain and not
quite its dependency on glucose (basta better answer ung A)
bthere is no block in the transport of glucose in the brain since, we all know,
that the brain depends greatly on glucose for energy
d
since the brain nga needs glucose, even at a very low concentration as such
in hypoglycemia, the brain can still utilize glucose, so this choice is unlikely
to be considered
3
bUDP glucoronates which is conjugated with bilirubin for excretion and L-ascorbate
(vitamin C) are synthesized in the uronic pathway
a
in citric acid cycle (TCA cycle), glucoronates and L-ascorbates are not
generated (its primary goal is to produce energy in forms of ATP,NADH,FADH etc)
cin Embden-Meyerhoff pathway (glycolysis), the products are pyruvate
(aerobic) or lactate (anaerobic)
d in Cori's cycle, the main product is glucose (gluconeogenesis)
4
c it is the main producer of NADPH+H
a it allowed conversion of different monosaccharides other than triose
b it supplies RIBOSE PHOSPHATES to for nucleic acid synthesis
dit starts with g6p and ends with g6p so we cannot really say there has been
a breakdown but there were conversions along the pathway
5c
ribulose 5 phosphate is the end product of the oxidative reaction in the PPP and the
primary substrate of non-oxidative reaction in PPP
a part of the oxidative reaction
SUBJECT: BIOCHEMISTRYTOPIC: EVALS 8 SET GLECTURER: DR. UYDATE: MARCH 2011
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bproduct of the first reaction in the non-oxidative reaction through the
enzyme isomerase
dproduct of the first reaction in the non-oxidative reaction through the
enzyme epimerase
6
d isomerase is utilized in the reaction of ribulose5phosphate to ribose5phosphate
a3-epimerase in utilized in the reaction of ribulose5phosphate to
xylulose5phosphate
btransaldolase is used in the transfer of 3 carbons to form
fructose6phosphate and erythrose4phosphate
c
transketolase is used in the transfer of 2 carbons to form
sedoheptulose7phosphate and glygeraldehyde3phosphate,
fructiose6phosphate and glyceraldehyde3phosphate
7
d
transketolase and transaldolase are responsible for interconversions of 3-,4-,5-,6-
,7-carbon sugars throug transfer of carbon groups (remember the prefix TRANS for
transfer haha wala lang :) )
abc combinations of enzymes are faulty; other enzymes are not involved in theinterconversions
8b
G6PDH is inhibited by high conc of NADPH though negative feedback; by high GSH
because high GSH (glutathione in sulfhydryl form) means that GSSG (glutathione in
disulfide form) has already been converted to GSH with the help of NADPH--this
signifies that a lot of NADPH has been produced; high palmitoyl CoA signifies that
there was an increase production of NADPH, this NADPH was used for synthesis of
Fatty acid such as palmitoyl coA
acd inappropriate combination
9
a
without G6PDH there is a decreased production of NADPH which is needed to
convert GSSG to GSH; so with the deficiency in G6PDH there is an accumulation ofGSSG
bthere is an increase in H2O2 since glutathione is at its GSSG form which
cannot reduce the H2O2
c
NADPH keeps the Fe at hemoglobin at Fe2+; with its the deficiency in
G6PDH Fe2+ is converted to Fe3+ which cannot bind to oxygen blah blah
blah
d there is a low concentration of GSH in the absence of NADPH
10
c L-xylulose5phosphate are both substrate of uronic acid pathway and HMP shunt
abd these substrates are not common among the 2 pathways
11c
L-gluconolactone oxidase in needed for the production of Vit C. this enzyme is
deficient in humans
abd these enzymes are not involved in the production of vit C
12
bxylulose5phosphate cannot be converted to xylitol(uronic pathway) in the event of
essential pentosuria so it is excreted in the urine
a it is the product of the inhibited reaction in the event of pentosuria
cd
no information was gathered that pointed to an effect of pentosuria on
these molecules
13b
glucagon decreases the production of fructose2,6bisphosphate which is a potent
inhibitor of fructose1,6bisphosphatase; therefore it cannot inhibit the action of
f16bp thus promote gluconeogenesis
acd these enzymes are not affected by F26BP
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14a
gluconeogenesis is an energy requiring pathway and in the action of PEPCK it
utilizes GTP as a source of phosphate to be transferred to OXAA to produce
Phosphoenolpyruvate
bcd not used by the enzyme (ayaw nya eh, bakit ba?!? Haha joke lang :| )
15
ain glycogenesis, UDP-glc is added to the NON-REDUCING end of a small glycogen
molecule this is applicable in both elongation (linear) and branching of the chain
b glycogenesis doesnt involve synthesis of a protein primer though it is aused to start the process
c
though this can be an answer, letter A choice discussed how the elongation
happens; in addition amylopectin chains are linear and glycogenesis
involves both elongation in a linear pattern and branching pattern
dthis can also be an answer however this only describes the branching
mechanism of the pathway
16
c fructose must first be phosphorylated before its metabolism
abdenzymes are found in the middle of the pathway so they are not really in
the INITIAL REACTION of fructose metabolism
17
cglycogenolysis is the removal of glucose residues in glycogen and in order to do this
the enzyme glycogen phosphorylase is used.
a glycogen synthase is used in glycogenesis
b hexokinase is used in phosphorylation of glucose
dg6pase is used in the cleavage of phosphate in G6P at the end of
glycogenolysis
18
c
the formation of NADH in glycolysis is a source of energy. In the event of low
oxygen concentration such as in exercise, NADH is utilized by lactated
dehydrogenase to form lactate from pyruvate. This decreases the source of energyof muscles since NADH is equivalent to 3ATPs; thus, less energy generated, more
prone to fatigue (disclaimer: not sure if this is really the explanation but
nonetheless it makes sense so...you could look it up if you want. sorry :( )
a
in exercise, energy is utilized and exhausted but then, ATP is produced in a
normal rate. ATP can be exhausted but this may not be primarily the cause
of muscle fatigue, it contributes though (hindi kasi ito ung answer sa
answer key eh :) hahaha joke :)
b
sodium-potassium imbalance doesnt contribute to the energy production
pathways so there might not be a connection with these ions and fatigue
(not sure)
d
accumulation of ADP is not directly correlated to energy utilization (haha
not sure.sorry ulit. Nevermind this na lang, di naman ito ang sagot eh :)
haha)
19
dthe reaction that links glycolysis to TCA cycle is: pyruvate (glycolysis) to Acetyl CoA
(TCA cycle) through the enzyme pyruvate dehydrogenase
a enzyme in TCA cycle
b link between TCA and gluconeogenesis
c enzyme in TCA cycle
20
d
there are 3 irreversible steps in glycolysis. They are catalyzed by (1) glucose kinase,
(2) phosphofructokinase (3)pyruvate kinase. The committed step is the reaction
catalyzed by PFK1 which produces fructose 1,6 bisphosphate
abcall of which are products of non-reversible reactions which cannot be
considered as a committed step
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21
d
phosphofructokinase2 is a bifuctional enzyme(PFK2-FBP2 complex) which alter the
concentration of F26BP (an increase in F26BP promotes PFK1, increase rate of
glycolysis; a decrease in F26BP lifts the inhibition on F16BPase, increase rate of
gluconeogenesis
abcall of which are not bifunctional and only regulates either of the pathways
not both
22d
1 mole of glyceraldehyde3phosphate yeilds to 1 mole of pyruvate and in the
process produces 2 moles of ATP; however in RBCs there is an absence ofmitochondria thus it the metabolism of glucose ends in glycolysis. Since glycolysis
alone is an anaerobic pathway, pyruvate is converted to lactate. so, all in all the
products are 2 ATP and 1 lactate
abc basta hindi ito :)
23c glucose is first phosphorylated before metabolized
abd all of which happens after phosphorylation of glucose
24
d
pyruvic acid is the end product of glycolysis in an aerobic condition because the
conversion of pyruvate into the substrate of TCA cycle inhibits its conversion to
lactated
a lactic acid is produced in an anaerobic environment
bc not products of glycolysis
25c
pyruvate carboxylase is a enzyme for gluconeogenesis which is activated in
starvation state not in a high glucose environment
abd these enzymes are anabolic in nature. These are activated in fed state
26d
muscle glycogen doesnt have g6pase so it cannot release glucose in blood, so
glucose reserves in muscle can only be ulitized by the muscle itself (SELFISH!!)
abc not true. Haha
27
d all reactions are involved in glycolysis
a no enolization
b no mutarotation
c no tautomerization
28 b
since the question asks for which requires ATP, first thing to consider is KINASE.
Then since 2 lang naman yung kinase pili na lang kayo haha joke lang. pyruvate
kinase is in glycolysis so it is not the answer. It should be phosphoglycerate kinase
which is an enzyme of gluconeogenesis which is the one asked for in the question :)
29
bglucokinase is used to phosphorylate glucose in the liver. With its high km, at low
conventration of glucose such as in hypoglycemia, glucose cannot be utilized
a glucokinase has a high km
cd PFK1 is not regulated by allosterically
30
b all of which are precursors of gluconeogenesis
a leucine is ketogenic
cdfatty acid when oxidized (unless it is odd numbered--in form of proprionyl
CoA) cannot produce glucose
31 b
in the absence of G6Pase, G6P cannot be converted to glucose to be released in
blood so G6P will find another way for it to be metabolized and one pathway which
utilizes G6P is HMP. Increased levels of G6P will induce HMP
32 c transketolase perform optimally with the help of vitamin B1 (thiamine)
33 d pyruvate kinase is inactivated when phosphorylated
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a active when phosphorylated
b not allosterically regulated, just activated by cAMP
c active when phosphorylated
34
cinsulin (produced in fed state) promotes anabolism. So glycogen synthase activity is
promoted in increased levels of insulin
ab these are produced in starved states
d glycogen synthase in inhibited in starved state
35
d
when pyruvate kinase is deficient, substrate before the reaction tends to
accumulate and look for other pathways to go to. One of which is
1,3bisphosphoglycerate which is converted to 2,3BPG. This product competes with
oxygen in binding to hemoglobin
aacetyl coa is produced form pyruvate but pyruvate production is inhibited
in the set up. So there is no accumulation of acetyl coa
b since pyruvate kinase is inhibited there is no production of pyruvate
c glucose should have entered the pathway because it needs to bemetabolized and there are available enzymes which can utilize it so its
accumulation is least likely
36 b FRUCTOSE..YUM! I couldnt elaborate more :) Joke lang :)
37
c fructose 1,6 bisphosphatase is inhibited by F26BP
a synthesis is induced by cAMP
b synthesis is inhibited during starvation
d synthesis is induced by fasting
38-41NOT INCLUDED IN THE COVERAGE OF BIOCHEM COMPREHENSIVE EXAM :) *ENDOCRINE
PART*
42 d
galactose is phosphorylated by galactokinase to produce galactose1phosphate.
Then, it is converted to glucose1phosphate by coupling with UDPglc which then
produces UDPgal. G1P is the converted to G6P then it enters glycolysis
43-44NOT INCLUDED IN THE COVERAGE OF BIOCHEM COMPREHENSIVE EXAM :) *ENDOCRINE
PART*
45 a amylopectin is a linear chain composed of glucose residues linked by a1->4 linkage
46
d fructose 1,6 bisphosphatase has no effect in pyruvate kinase
alosing the allosteric site for ATP in phosphofuctokinase renders it immuneto ATP meaning ATP cannot inhibit its activity therefore rate of glycolysis
increases
b
losing the allosteric site for citrate in phosphofuctokinase renders it
immune to citrate meaning citrate cannot inhibit its activity therefore rate
of glycolysis increases
c
losing the phosphatase domain of phosphofructokinase-2 increases the
production of F26BP which increases PFK1 activity which increases rate of
glycolysis
47 c
PPP is the only source of carbon dioxide in the cytoplasm. So liberation of carbon
dioxided is seen when there is much NADPH is required meaning there is a drive
for PPP
48 creactions from ribose5phosphate generates a lot of products however only F6P and
G3P can enter glycolysis
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49d
fructose26bisphosphate is synthesized in fed state meaning increased
glucagon:insulin ratio (increased insulin, decreased FBP2 activity, increased PFK2
activity). This is observed just after the consumption of a large bowl of ice cream
abc seen in starved state; lowers levels of F26BP
50 a
during exercise there is an increased rate of glycolysis therefore increasing
NADH/NAD ratio. NADH is utilized by lactate dehydrogenase to form lactate to
pyruvate
51
b aldose reductase converts glucose to sorbitol
a sorbitol dehydrogenase converts sorbitol to fructiose
cd not mentioned at all
52
c
fasting for 12 hours would promote glycogenolysis. When glycogen phosphorylase
is phosphorylated, the enzyme is rendered active thus, glycogenolysis occur. When
pyruvate kinase and glycogen synthase are phosphorylated they are rendered to be
inactive this inhibiting glycolysis and glycogenesis and promoting glycogenolysis
a gluconeogenesis is not activated until 24 hours of fasting
b adenylate cyclase is activated by the presence of glucagon which promotesgluconeogenesis and this doesnt happen until 24 hrs of fasting
d glycogen synthas is activated in fed state which is not the case in the given
53 apyruvate carboxylase utilizes the cofactor biotin in a key step in synthesizing
glucose from pyruvate
54
athe km of glucokinase is high and it is above the fasting concentration of glucose in
blood; thus in fasting, glucose cannot be efficiently phosphorylated in the liver
b glucokinase is found only in the liver
c its activity is inhibited by F26BP since it favors the binding of GK to GKRPd it is less sensitive to inhibition of g6p
55-70NOT INCLUDED IN THE COVERAGE OF BIOCHEM COMPREHENSIVE EXAM :) *ENDOCRINE
PART*
71 asince the conversion of pyruvate to OXAA is catalyzed by pyruvate carboxylase it
consumes carbon dioxide (it's in the name ;))
72 balso the enzyme pyruvate carboxylase requires biotin as its cofactor for optimal
activity
73 bremember the malate-aspartate shuttle? Oxaloacetate takes up NADH and forms
malate to be able to cross the mitochondrial membrane
74 c once inside the mitochondroa, malate gives off NADH and forms OXAA
75 dconversion of OXAA to phosphoenolpyruvate also releases carbon dioxide as a by
product
76 b
increased ATP means, there is no more need for generation of ATP therefore
inhibition of glycolysis. On the other hand, gluconeogenesis requires high levels of
ATP to produce glucose so increased ATP promotes gluconeogenesis
77 a
increased F26BP increases the activity if PFK1 thus increases rate of glycolysis. On
the other hand, high levels of F26BP inhibits the activity of F1,6BPase this
inhibiting gluconeogenesis
78 ain fed state, there is increased insulin:glucagon ration therefore increasing
glycolytic activity
79-88NOT INCLUDED IN THE COVERAGE OF BIOCHEM COMPREHENSIVE EXAM :) *ENDOCRINE
PART*
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89 cin using G6P as substrate, 1 ATP is utilized by PFK; 4 ATPs are produced by (2
from) phosphoglycerate kinase and (2 from) pyruvate kinase. So -1 +4 =3
90 bin using DHAP as substrate, no ATP is utilized, 1 ATP is generated from
Phosphoglycerate kinase and another from pyruvate kinase. So, +1 +1 = 2
91 bin using G3P as substrate, no ATP is utilized, 1 ATP is generated from
Phosphoglycerate kinase and another from pyruvate kinase. So, +1 +1 = 2
92 b in using fructose as substrate, 1 ATP is used by hexokinase; 1ATP is used by PFK;4ATPs are produced: 2 from phosphoglycerate kinase and 2 fro) pyruvate kinase.
So -2 +4 =2
93 din using sucrose, you can metabolize 2 sugars: fructose + glucose. Fructose yields to
2 ATP and Glucose yields to 2ATP. So 2+2=4 :)
94 ahemolysis indicates a defect in the PPP since NADPH is not utilized to protect RBCs
from lysis. So we can conclude that this is a deficiency in G6PDH
95 ccataract formation can be associated with accumulation of galactose (galactosemia)
due to deficiency in galactokinase
96 b galactose1phosphate uridyltransferase deficiency leads to severe liver disease
97 d
deficiency in fructokinase means there is no formation of F1P and instead, fructose
will be enter the glycolytic pathway though F6P via hexokinase activity. F6P is can
be used both in glycolysis and gluconeogenesis. If glyconeogenesis is favored then
there can be increased glucose level which can manifest in increased glucose levels
in urine
98 dCori's disease is caused by a defect in the debranching enzyme (glucosyl 4:6
transferase) Thus, glycogen accumulates. This manifests as liver disease.
99 b
Anderson's disease on the other hand is a deficiency in the branching enzyme
resulting to accumulation of glycogen with long outer chains but the branches
contains only few glucose molecules
100 c
McAdle's disease is caused by the deficiency of skeletal muscle glycogen
phosphorylase; thus, there is an accumulation of glycogen in skeletal muscle but not
in liver. This results to muscle cramps and weakness
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