block day- april 25, 2012

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Block Day- April 25, 2012 Homework: none Make an entry- Entry 41:Heredity and Genetics2 - 4/25/12 See attached entry

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Block Day- April 25, 2012. Homework: none Make an entry- Entry 41: Heredity and Genetics2 - 4/25/12 See attached entry. Symbols used for alleles. The traditional symbols used for alleles are big and small letters The letter chosen usually refers to the dominant allele - PowerPoint PPT Presentation

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Page 1: Block Day- April 25, 2012

Block Day- April 25, 2012Homework: none

Make an entry- Entry 41:Heredity and Genetics2- 4/25/12 See attached entry

Page 2: Block Day- April 25, 2012

Symbols used for alleles• The traditional symbols used for alleles

are big and small letters• The letter chosen usually refers to the

dominant alleleExample: R = Red allele

r = Blue allele

Page 3: Block Day- April 25, 2012

The combination of alleles determines the observed characteristics

REDalleleChromosome

combination

Allelecombination

Observedcharacteristic

RED allele

REDallele

BLUE allele

BLUEallele

BLUE allele

red, red red, blue(or blue, red)

blue, blue

RED RED BLUE

Page 4: Block Day- April 25, 2012

The combination of alleles determines the observed characteristics

RChromosomecombination

Allelecombination

Observedcharacteristic

RR Rr rr

RED RED BLUE

R R r r r

Page 5: Block Day- April 25, 2012

The combination of alleles determines the observed characteristics

RChromosomecombination

GENOTYPE

PHENOTYPE

RR Rr rr

RED RED BLUE

R R r r r

Page 6: Block Day- April 25, 2012

Homozygous – the two alleles are the same

• RR and rr are homozygous genotypes

Heterozygous – the two alleles are different

• Rr is a heterozygous genotype

Page 7: Block Day- April 25, 2012

Draw the enzymes and pigment molecules present in the cells of each type of flower below.

GENOTYPE for flower type 2:

Allele of chromosome 2A= Y1 (functional enzyme)

PHENOTYPEof flower type 2:

nucleus

Y1

Y2

Yes or no, is any functional enzyme Y in the cell?

Allele of chromosome 2B= Y2 (non-functional enzyme) 2A 2B

1B

1A

YES RED

WHAT DOES Rr ACTUALLY MEAN?

Rr

Page 8: Block Day- April 25, 2012

Possible combinations of inherited chromosomes/genes

R rR r

Dad Mom

R

r

Parents

PossibleOffspring r

r

R

R

r

R

X

Order doesn’t matter, these two are the same (Rr)

What are all possible genotypes produced from the parents?

RR, Rr, rr

Page 9: Block Day- April 25, 2012

Punnett squares organize all possible offspring combinations

R r R rX

R r

R

r

RR

Rr rr

Rr

Dad Mom

Page 10: Block Day- April 25, 2012

1 out of 4 possibilities is rr = What is probability of Rr?• How many out of 4 are red? • What is the probability of red? • What is the probability of blue?

R r

R RR Rr

r Rr rrGenotypic ratio = 1RR: 2Rr:1rr

25 %50 %

3/475 %25 %

R= red flower alleler= blue flower allele

Phenotypic ratio = 3 Red:1 blue

Page 11: Block Day- April 25, 2012

Your turn:• What are all possible genotypes and

phenotypes produced by crossing Rr with rr?

Complete the Punnett Square

r r

R Rr Rr

r rr rr

Page 12: Block Day- April 25, 2012

Punnett squares predict ratios of all genotypes and phenotypes produced

Genotypic ratio = 2 Rr:2 rr or 1Rr : 1 rrPhenotypic ratio = 2 Red:2 Blue or 1 Red : 1 Blue

r r

R Rr Rr

r rr rr

R= red flower alleler= blue flower allele

Page 13: Block Day- April 25, 2012

Punnett square practiceCalculate the predicted genotypic and phenotypic ratios1) Hh X HH H(hairy) is dominant over h(not hairy)

2a) Gg X gg G(green sepals) is dominant over g(yellow sepals)2b) What would the cells of the green and yellow

plants look like? (functional vs non-functional)

Page 14: Block Day- April 25, 2012

Genotypic ratio = 2 HH:2 Hh or 1HH : 1HhPhenotypic ratio = 4 Hairy: 0 Non-hairy

H H

H HH HH

h Hh Hh

Page 15: Block Day- April 25, 2012

Genotypic ratio = 2 Gg:2 gg or 1Gg : 1ggPhenotypic ratio = 2 Green: 2 Yellow or 1 Green : 1 Yellow

g g

G Gg Gg

g gg gg

Page 16: Block Day- April 25, 2012

GENOTYPE for Green Flower (Gg) :

Allele of chromosome A= C1 (functional enzyme)

PHENOTYPEof flower type 2:

nucleus

Yes or no, is any functional enzyme C in the cell?

Allele of chromosome B= C2 (non-functional enzyme)

Y1

Y2

A

B

1B1A

GENOTYPE for yellow flower (gg):

Allele of chromosome A= C2 (non-functional enzyme)

PHENOTYPEof flower type 3:

nucleus

Y2

Y2

Yes or no, is any functional enzyme Y in the cell?

Allele of chromosome B= C2 (non-functional enzyme)

A

B1B

1A

YES

Green

NO

Yellow

Page 17: Block Day- April 25, 2012

Make an entry- Entry 42: Punnett Square Worksheet- 4/25/12

See attached entry

Page 18: Block Day- April 25, 2012

• #1 In rabbits, black fur is dominant over white fur. Show the cross of a heterozygous black male with a homozygous white female.

• Parents: Bb x bb b b • Genotypic Ratio: B  1 Bb : 1bb • Phenotypic Ratio: b 1 black: 1 white

Bb Bb

bb bb

Page 19: Block Day- April 25, 2012

• #2 Tall is dominant over short in pea plants. Show the cross of a homozygous short plant is crossed with a homozygous tall plant.

• Parents: tt x TT  • Genotypic Ratio:   4 Tt (or 100% Tt) • Phenotypic Ratio: All or 100% Tall

Tt Tt

Tt Tt

T T

t

t

Page 20: Block Day- April 25, 2012

• # 3 In humans, free-ear lobes are dominant to attached ear lobes. Two parents that are both heterozygous free are expecting a child. What are the chances that the child will have free ear lobes of attached?

• Parents: Ff x Ff   F f • Genotypic Ratio: F  1 FF:2Ff: 1ff • Phenotypic Ratio: f 3 Free: 1 attached

FF Ff

Ff ff

Page 21: Block Day- April 25, 2012

#4

S=smooths= wrinkledParents: ss x SsGenotypic ratio: 2 Ss:2 ssPhenotypic ratio: 2 smooth: 2 wrinkled

Page 22: Block Day- April 25, 2012

#5

S=smooths= wrinkledParents: Ss x SsGenotypic ratio: 1 SS: 2Ss: 1ssPhenotypic ratio: 3 smooth: 1 wrinkled

Page 23: Block Day- April 25, 2012

#6

B=blue eyesb=red eyesParents: Bb x bbGenotypic ratio: 2 Bb: 2 bbPhenotypic ratio: 2 blue eyes: 2 red eyes

Page 24: Block Day- April 25, 2012

#7

R= red eyesr= white eyesParents: rr x rrGenotypic Ratio: 4 rr or all rrPhenotypic: 4 white eyes or all white eyes

Page 25: Block Day- April 25, 2012

• #8 A homozygous dominant brown mouse is crossed with a heterozygous brown mouse (tan is the recessive color).

• Parents: BB x Bb B b • Genotypic Ratio: B  1 BB : 1Bb • Phenotypic Ratio: B All Brown or 4 Brown: 0 Tan

BB Bb

BB Bb

Page 26: Block Day- April 25, 2012

• #9 Two heterozygous white (brown fur is recessive) rabbits are crossed.

• Parents: Ww x Ww Genotypic Ratio: 1WW:2Ww:1ww • Phenotypic Ratio: 3 WHITE: 1 BROWN W w

W

w

WW Ww

Ww ww