building systems (part one of two) · 19/02/2013 · mechanical and electrical layout the problem...
TRANSCRIPT
BUILDING SYSTEMS
(PART ONE OF TWO)
February 19, 2013
Presented by AIA-Pittsburgh’s Young Architects’ Forum (YAF)
And Allen & Shariff Engineering,LLC
Exam resources are available at AIA-PGH YAF ARE Review
http://yafpghare.wordpress.com/
ARE Blackout Period
Due to migration of record data,
an estimated eight week blackout
period begins July 1, 2013.
During this period:
• No exam appointments may be
scheduled
• There will be no exams administered
• New Authorizations to Test will not be
granted
• State boards will not be able to
establish eligibility or update records
The last day to take an exam before the
blackout will be June 30, 2013.
Alpine Testing Solutions, Inc. will take over content and candidate management
for the ARE beginning July 1, 2013.
Prometric will continue to be NCARB’s site management consultant.
Agenda
� 5:30 Introduction/ Division Overview
� 5:40 Graphic Vignette Review
� 6:00 Multiple Choice Content Review
� 7:00 Break (if desired)
� 8:00 Questions?
Division StatementThe evaluation, selection, and integration of mechanical,
electrical, and specialty systems in building design
and construction.
Exam Structure� 95 Multiple-Choice Questions (2 hours)
� Break (15 minutes)
� 1 Graphic Vignette (1 hour)
� Mechanical and Electrical Layout
Test Day…
� Introductory Tutorial 0:15
� Multiple-Choice Questions 2:00
� Scheduled (Mandatory) Break 0:15
� Introductory Tutorial 0:15
� Graphic Vignette 1:00
� Exit Questionnaire 0:15
� TOTAL APPOINTMENT TIME 4:00
Suggested Sequence
� Construction Documents and Services
� Programming Planning and Practice
� Site Planning and Design
� Structural Systems
� Building Systems
� Building Design and Construction Systems
� Schematic Design
Content Areas� CODES & REGULATIONS (5-8% of scored items)
� “…building codes, specialty codes, zoning, and other regulatory requirements…”
� ENVIRONMENTAL ISSUES (10-15% of scored items)
� “…sustainable design principles…”
� PLUMBING (10-15% of scored items)
� Principles
� Materials and Technology
� HVAC (18-23% of scored items)
� Principles
� Materials and Technology
� ELECTRICAL (10-15% of scored items)
� Principles
� Materials and Technology
� LIGHTING (18-23% of scored items)
� Principles
� Materials and Technology
� SPECIALTIES (14-19% of scored items)
� Principles
� Materials and Technology
By the numbers…� 95 questions…
� 2 hour testing time…
…1 minute, 15 seconds per question
� By content areas…
Codes/ Regulations….…………..……………..…4 - 8 questions
Environmental Issues..……………..……..…..10 - 15 questions
Plumbing……………………………………….....10 - 15 questions
HVAC…………………….…………………….……17 – 22 questions
Electrical ……………………………………….....10 - 15 questions
Lighting..……………….…………………….……17 – 22 questions
Specialties………………………………………...13 – 18 questions
GRAPHIC VIGNETTE
MECHANICAL & ELECTRICAL PLAN
Develop a reflected ceiling plan that
integrates ceiling, lighting, mechanical, and
structural systems and incorporates life safety considerations.
PROGRAMA reflected ceiling plan for an architect’s office is to be prepared. The space is in
a multistory building and is enclosed by leasable office space on one side, a
corridor on another, and two exterior walls. The client wants flexibility for
furniture placement, efficient lighting levels, and a comfortable environment.
GRAPHIC VIGNETTE
The Work Screen
Mechanical and Electrical Layout
The ProblemComplete the partially completed reflected ceiling plan on the work screen
by:
(1) providing a grid for acoustical tile,
(2) locating lighting fixtures to achieve specified light intensity, and
(3) developing a schematic HVAC plan complete with fire dampers and air diffusers, ductwork, and return-air grilles to meet specified air distribution requirements.
It is recommended that the ceiling layout be completed before ducts are added. Your solution must be contained within the perimeter walls of the overall space.
The completed plan should reflect effective coordination and integration of structural, mechanical, and electrical units within the ceiling grid and should provide for maximum flexibility for furniture layouts at the most economical cost.
Program RequirementsComply with the following requirements to develop the reflected ceiling plan:
Suspended Ceiling System
1. Provide a 2 ft X 4 ft grid with lay-in acoustical tiles in all spaces.
2. All ceiling heights are 9 ft above the finished floor.
3. Typical walls terminate 6 inches above the finished ceiling; bearing walls and fire-rated walls extend to
the bottom of the floor deck above.
Lighting System -- should be efficient and should minimize overlighting and underlighting.
1. For all spaces, use only recessed fluorescent fixtures to provide uniform light distribution with a light
level of approximately 50 footcandles measured at desk level (3 ft above the finished
floor).
2. In addition to the fluorescent fixtures required above, provide recessed accent light fixtures.
� Locate the accent light fixtures along the west wall of the Architect’s Office so that the direct light
level on the wall at a height of 5 ft above the floor is 80 footcandles.
� Space the accent light fixtures so that the light level between the fixtures at 5 ft above the
floor is 80 footcandles.
� The accent light fixtures should not be considered in determining the uniform light distribution
levels.
� The recessed fluorescent fixtures should not be considered in determining the accent light levels.
Program Requirements, cont.
HVAC System
The space is served by the supply and return risers within the shaft indicated on the floor plan. The HVAC
system should provide for uniform air distribution with an economical duct layout conforming to the
following restrictions:
1. Provide a minimum of one supply diffuser and one return-air grille in each space. An
acceptable air distribution pattern includes one supply diffuser and one return-air grille for every 144
ft of floor area (or portion thereof ) in each space.
2. Connect each supply diffuser to the rigid supply duct system with flexible duct. Do not
exceed 10 ft for flexible duct lengths.
3. Return-air grilles are open to the ceiling space, which serves as a return-air plenum. Connect the plenum to the return riser with rigid duct.
4. Protect duct openings in fire-rated walls with fire dampers.
5. Flexible ducts fit through joist webs.
6. Rigid ducts fit under beams, in spaces between joists, and in a zone that extends 2 ft on either side of
beams and bearing walls in plan view. Rigid ducts do not fit through joists or
between the bottom of joists and the ceiling.
Program Requirements, cont
Mechanical & Electrical Layout
Sample PASSING Solution
Mechanical & Electrical Layout
Sample FAILING Solution
General Tips…
Clear your head.
Remember – it’s not AutoCAD…
… or design studio.
Practice makes perfect…
… but don’t over-practice!!
Take your time.
Follow all of the instructions!!
Don’t second-guess yourself.
MULTIPLE CHOICE
ELECTRICAL SYSTEMS REVIEW
Basic Physics
• The three most common units are:
• Potential (V, measured in volts)
• Current (I, measured in amps)
• Resistance (R, measured in ohms)
Water Analogy for
Voltagefrom the NEED Project www.NEED.org
Water Analogy for
Currentfrom the NEED Project www.NEED.org
Water Analogy for
Resistancefrom the NEED Project www.NEED.org
Ohm’s Law
Ohm’s Law is the formula which relates these
factors to each other. There are several
ways to show the formula:
• V = I x R
• I = V / R
• R = V / I
Ohm’s Law Example
• Given: 120 volt outlet and a hair dryer with
a resistance of 8 ohms. The current (I) flow
through the hair dryer when it is turned on
is ____.
• a. 15 amps
• b. 15 ohms
• c. 15 volts
Ohm’s Law Relationships
• V and I are directly proportional to each
other, i.e. the greater the voltage, the
greater the current.
• I and R are inversely proportional to each
other, i.e. the greater the resistance, the
smaller the current.
Series Resistances
• Resistors may be situated in series (one
path)…
Parallel Resistances
• Resistors may be situated in parallel
(multiple paths)…
Parallel + Series
Resistances
• Or in combinations of series and parallel
paths….
Parallel + Series
Resistances - Effective
Resistance Solution
Parallel + Series
Resistances - Effective
Resistance Solution
Given three parallel paths, two paths with a
resistance of 4 ohms and one with a
resistance of two ohms, find REFF.
1/REFF = 1/4 +1/4 +1/2
1/REFF =1/4 +1/4+2/4 = 4/4
REFF = 1 ohm
Transmitting Electricity
• Two main ways of transmitting
electricity:
1. Direct Current (DC)
2. Alternating Current (AC)
Direct Current (DC)
• Direct current flows in one direction with
constant voltage.
• Batteries are a common example of a DC
source.
DC Power Equation
• P = V x I
• Where:
1. P = Power in watts (W)
2. V = Voltage
3. I = Current in amps
DC Power Example
• Given: 12 volt battery connected to a 4
ohm resistor. Solve for power (P).
• Start with Ohm’s Law
• I = V / R = 12V / 4 ohms = 3A
• P = 12V x 3A = 36 W
DC Power Equation
Variations
• Since we know:
V = I x R, I = V / R, and P = V x I
• Then by substitution, we also know:
P = I x I x R = I2 x R
P = V x V / R = V2 / R
Alternating Current (AC)
• Alternating current (AC) is based on the
concept that electricity has nearly no
inertia, and therefore the direction of flow
can be reversed very rapidly by reversing
the voltage.
• Plotting voltage versus time results in a
sine wave.
Single Phase AC Sine Wave60 Hz or 60 cycles per second
Single Phase AC Power
Equation
• P = V x I x PF
• Where:
1. P = Power in watts (W)
2. V = Voltage
3. I = Current in amps
4. PF = Power Factor in decimal form
Lead and Lag
• The AC current sine wave is not always in
sync with the AC voltage sine wave due to
capacitances and inductances.
• The current sine wave leads when it is
ahead of the voltage sine wave.
• The current sine wave lags when it is
behind the voltage sine wave.
• This is difference is represented as a phase
angle.
Power Factor
• The power factor is the cosine of the phase
angle between the voltage wave and the
current wave.
• It ranges from 0 to 1.0 and is often expressed
as a percentage from 0 to 100%.
• When entered into an AC power equation, it is
changed to decimal form.
• For a purely resistive load, the power factor is
1.0
3-Phase AC Power
• In 3-phase power, there are three voltage
sine waves each 120 degrees apart from
each other.
3-Phase AC Power
Equation
• P = V x I x PF x 1.732
• Where:
1. P = Power in watts
2. V = Voltage
3. I = Current in amps
4. PF = Power Factor in decimal form
Why is line voltage 1.732
times phase voltage?
Answer:
(http://wiki.answers.com/Q/Why_is_line_voltage_1.732_times_phase_voltage)
Line voltage is stated as "phase to phase". Phase voltage is stated as "phase to
ground". In a three phase system, each phase is 120 degrees out of phase with
respect to the other two, one leading, and the other trailing. Draw the vector
diagram for this and you get three triangles inside a larger triangle, the outer
sides being phase to phase and the inner sides being phase to ground. The outer
triangle is equilateral, with angles of 60 degrees, and the inner triangles are
isosceles with angles at the outer triangle's vertices of 30 degrees. Look at one
of the inner triangles and bisect it with a vector from ground perpendicular to
the vector for phase to phase. You see a right triangle. Now you can do
trigonometry...
The base is one half the phase to phase voltage. Lets call that X. In trig,
cosine(theta) = X (one half phase to phase) over hypotenuse (phase to ground).
Cosine 30 is 0.866, so phase to ground is one half phase to phase over 0.866, or
phase to phase over 1.732.
So why times 1.732?
It’s not important for this test!
Just memorize the 3-phase power formula!
P = V x I x PF x 1.732
3-Phase AC Power Example
• Given: A motor draws a current of 7 amps
at 240V-3ph with a power factor of 0.8.
Solve for power (P).
• P = 240V x 7A x 0.8 x 1.732 = 2,325 W
• Large power wattages are expressed in
kilowatts or even megawatts.
• 2,325 W = 2.325 KW
Electrical Equipment
• Motor
– Machine that converts electrical energy into mechanical energy.
– Running a current through a wire loop creates a magnetic field. This is the basic principle behind electric motors and solenoids.
Electrical Equipment
• Generator
– Machine that converts mechanical energy into electrical energy.
– Rotating a wire loop between two magnetic poles will generate a current. This is the basic principle behind generating electricity.
Power Generation
• Single phase alternator is the most basic form of power generation.
• Wire loop rotated between magnetic north and south poles creates a single phase AC current.
• Speed of rotation determines the period (peak to peak) of the AC current sine wave produced.
Single Phase Alternator
• If the speed is 60 rpm, it results in a sine
wave cycle time of 1/60th of a second, or 60
cycles per second, or 60 Hertz (Hz).
• 60 Hz, 120V AC power is typical in the USA.
• 50 Hz, 240V AC power is common in the
rest of the world.
3-Phase Alternator
• Add two more wire loops spaced evenly to
the single phase alternator, and circuit
them separately.
• If the loops are evenly spaced, the resultant
current sine waves produced by each loop
are shifted by 120 degrees from one
another.
Single Phase and 3-Phase
Alternator Diagrams
Transformers
• Transformers can change the voltage to a
higher or lower value.
• They consist of an iron core on which two
separate coils of wire are wound, called the
primary and a secondary “windings”.
• The primary winding is the transformer
input, the secondary winding is the output.
Transformers
• Current enters the primary winding and it induces a current on the secondary winding.
• The number of turns in the windings determines whether the voltage is stepped up or stepped down.
• More turns in the secondary winding yields a higher voltage than the primary.
• Fewer turns in the secondary winding yields a lower voltage than the primary.
Transformers
• Transformer wasted energy is in the form of heat which must be dissipated.
• Transformer sizes are defined in volt-amps (VA), or kilovolt-amps (KVA).
• Transformer windings are insulated to protect them from overheating.
• Common types are dry-type and liquid filled.
Transformers
• Failures can be catastrophic.
• Transformers can be noisy.
• Generally speaking, dry-type transformers
located indoors do not require specially
constructed rooms.
• Liquid filled transformers located indoors
may have more complicated requirements
(liquid containment, vault construction).
Single Phase Transformer
Connections
• Two-wire secondary
– One wire grounded, becomes the neutral.
– One single phase voltage available. (e.g. 120V)
• Three wire secondary
– Center tap is grounded
– Two single phase voltages available. (e.g. 120V-1ph and 240V-1ph).
3-Phase Transformer
Connections
• There are two basic types of connections:
– Delta
– Wye or Star
• When a neutral connection is desired, it
may be taken from the center point of the
Wye or from the midpoint of a Delta leg.
3-Phase Transformer
Connections
Typical Transformer
Voltages• The delta-wye configuration is commonly used in
commercial work.
• Typical commercial system voltages are 480Y/277V-3ph-4w and 208Y/120V-3ph-4w.
• Typical residential system voltage is 120/240V-1ph-3w.
• Older buildings sometimes had two services, 120/240V-1ph-3w and a 240V-3ph-3w delta for motor loads.
480Y/277V Transformer
Voltage Relationships• 480Y/277V-3ph-4w means:
– Line to line voltages
VL-L = VA-B = VA-C = VB-C = 480V
– Line to neutral voltages
VL-N = VA-N = VB-N = VC-N = 277V
– Or mathematically,
VL-L= VL-N x 1.732
480 = 277 x 1.732
208Y/120V Transformer
Voltage Relationships• 208Y/120V-3ph-4w means:
– Line to line voltages
VL-L = VA-B = VA-C = VB-C = 208V
– Line to neutral voltages
VL-N = VA-N = VB-N = VC-N = 120V
– Or mathematically,
VL-L= VL-N x 1.732
208 = 120 x 1.732
Transformer Calculations
• Transformer capacity is measured in kilovolt-amps (KVA)
• KVA = V x I x 1.732 x 1000
• A 75 KVA 3-phase transformer has a primary voltage of 480V-delta. Find the primary amps:
• (75 KVA x 1000) / (480V x 1.732) = 90A
• Size the breaker: 90A x 1.25 = 112.5A
• Round to the next standard size: 125A
Transformer Calculations
• A 75 KVA 3-phase transformer has a secondary voltage of 208Y/120V. Find the secondary amps:
• (75 KVA x 1000) / (208V x 1.732) = 208A
• Size the breaker: 90A x 1.25 = 260A
• Round to the next standard size: 300A
• Remember, KVA is KVA!
So which voltage do I
choose?• Considerations
– What is available from the power company?
– What is the building square footage?
– Building use? (industrial, office, retail, warehouse,
multi-tenant, high-rise)
– Standard distribution equipment sizes and how they
affect architecture (NEC workspace clearances,
multiple doors to main electrical room, doors with
panic hardware opening outward from the room)
– What makes sense for the major equipment?
Other things to
consider:• Higher voltage = lower current = smaller wire
• Higher voltage = better tolerance for voltage drop
• Higher voltage = more load per circuit = fewer circuits used
These concepts are based on the inverse relationship between voltage and current in the power equation. (Simply P/V = I, and P/I = V)
Electrical Heat
• 100% efficient (electrically speaking) since all electricity is turned into heat.
• Inefficient in the big picture, since heat is used to generate electricity at 30% efficiency, which we are turning around to re-generate heat.
Electric Lighting
• Switching can be done centrally via circuit breakers in a panel, or locally via wall switches.
• Switch types:
– One switch location –need (1) 2-way switch.
– Two switch locations –need (2) 3-way switches, one at
each location.
– More than two switch locations - need (2) 3-way
switches at each “end” location and a 4-way switch at
every “in between” location.
Switching Diagrams
Alternate Switch NamesSPST=2-way, SPDT=3-way, DPDT=4-way
Motors
Four types in general use:
1. DC motor – small scale applications, elevators for
smooth continuous acceleration
2. Single phase AC motors – typically 3/4HP or less
such as exhaust fans, pumps, etc.
3. 3-phase induction motors – larger motors, constant
rpm such as air handlers, power factors from 0.7 to
0.9
4. Universal motors – DC or AC, variable speed, such as
hand drills, mixers, similar appliances
Motor Protection
• Thermal overload protection via thermal
relays which shut the motor off to prevent
permanent damage. (example: the reset
button on a garbage disposal)
Capacitors
• Stores energy for later use.
• Simplest form is two plates separated by a small insulating layer.
• Used for power factor correction, improving efficiency and overall performance. Reduce the utility company KVAR charge.
• Capacitive loads typically “lead”, and can be used to shift the “lagging” current bogged down by inductive motor loads.
Receptacles
• Also called an outlet. (A plug is what you put into the outlet.)
• All 120V outlets should be 3-prong where the third prong is the ground.
• In a large room, provide more than one circuit for the outlets.
• Receptacle placement in commercial buildings:
– show windows
– HVAC equipment outlets
– No “code” for convenience outlets
Receptacle Placement
• NEC 210.52 has very specific rules on the placement of receptacles in dwelling units and hotels.
– 12 feet on center on any wall space greater than 2 feet in width for the following rooms: kitchen, family room, dining room, living room, parlor, library, den, sunroom, bedrooom, or similar.
– At least one receptacle for hallways of 10 feet or more in length.
Receptacle Placement
– One in each basement
– One for laundry
– One for garage
– One for each bathroom basin
– One at the front and back exterior of each dwelling unit
– One at each porch/balcony/deck
– Kitchen countertops and islands
Receptacle Types
• Required types for the above listed locations also are covered in NEC 210
– Ground-fault circuit interrupter
– Weather-resistant
– Arc-fault
– Tamper resistant (pediatric)
Panelboards
• Types: Fuse box, Circuit breaker panelboard, Frankenstein panel (really old)
• Provides a central distribution point for branch circuit wiring.
• Each breaker serves a single circuit.
• Overcurrent protection is designed to protect the wiring to the load.
• Power riser diagram includes all of the panelboards and their interconnections (conduit and wire) all of the way to the service entrance.
Panelboard Clearances
(NEC 110.26 simplified)• The panel feeder connects to the panels
main circuit breaker (MCB) or main lugs (MLO).
• Panels require a minimum 3 feet of clearance in front.
• Panels require a 30” wide working space.
• Panels require 6 feet of headroom.• Good link: see http://ecmweb.com/code-
basics/determining-working-clearances
Wiring
• Electrical wiring sizes are standardized
using American Wire Gage (AWG).
• Power wiring is 12 AWG minimum.
• Power wiring is copper.
• Wiring is sized at 125% of a motor load,
and for any load expected to operate for
three hours or more (continuous load).
Aluminum Wiring
• Aluminum wiring has been blamed for
causing fires.
• Questions about oxidation, connection
deterioration, metal fatigue over a long
period of time.
• For feeders 200 amps and above,
aluminum alloy wiring as made by Stabiloy
has been an acceptable substitute for cost
savings.
Conduit
• Wires must be physically protected in
addition to being insulated. Conduit
provides this protection.
• Conduit size is designated by its interior
diameter.
• NEC specifies the number of wires allowed
in a conduit.
Conduit Types
• Rigid – steel, safest, same wall thickness as
Sch 40 PVC, connections are threaded,
galvanized for exterior use.
• Intermediate Metallic Conduit (IMC) –
steel, slightly thinner and less expensive
than rigid.
• Electrical Metallic Tubing (EMT) – thinnest
of the simple metal conduits, compression
fittings, galvanized, called “thin wall”.
More Conduit Types
• Flexible Metallic Conduit – available with or
without a waterproof (liquidtight) jacket,
called “flex” or “Greenfield”, can be used
everywhere except underground.
• Interlocked Armored Cable (BX) – factory
assembled wires encased in an interlocking
spiral metal armor, (cannot add wires to it),
cannot be used underground or embedded
in concrete.
NEC Table 310-16
NEC Ground Sizing Table
NEC Ground Sizing Table
NEC Conduit Fill Table
Sizing a Transformer
Primary Feeder…
• Given: Transformer is 45KVA, 480V delta
• (45KVA x 1000) / (480 x 1.732) = 54A
• 54A x 1.25 = 67.5A
• 70A is next standard size breaker
• Table 310.16: 3#4
• Table 250.66: 1#8(G)
• Table 9: 1-1/4”C.
Sizing the Transformer
Secondary Feeder…
• Given: 45KVA, 208Y/120V
• (45KVA x 1000) / (208 x 1.732) = 125A
• 125A x 1.25 = 156A
• 175A is next standard size breaker
• Table 310.16: 4#2/0
• Table 250.66: 1#4(G)
• Table 9: 2”C.
Calculations
• Load Estimation
– Use watts per square foot load factors based on general experience for various building functions.
– Use watts per square foot allowances as listed in the applicable energy code.
– Use RS Means watts per square foot factors for various building types.
Calculation Tool
Safety Considerations
• Short Circuits
– Short circuits occur when two conductors lose enough insulation to allow current to flow between them (arc).
– Little to no resistance results in a high current which can cause the conductors to get hot enough to start a fire.
– A fire within a wall can go undetected for some time, allowing it to spread.
Short Circuit Protection
• Fuses
– Soft metal link in a glass plug or fiber cartridge
– One and done, can’t be reused.
– Largest glass plug fuse is 30 amps
• Circuit breakers
– Automatically disconnects under fault condition
– Resettable
– More expensive than fuses, but low maintenance cost
Short Circuit Protection
• Ground fault circuit interrupter
– It is a form of protection against short circuits.
– It may actuate even without anything connected to it.
– It can completely disconnect a circuit.
– On a GFCI receptacle it can be reset.
– GFCI receptacles can be daisy chained.
Ground fault circuit
interrupters– Detects continual current lost to ground and
breaks the circuit.
– Required locations are covered by NEC.
– Also required for electrical service equipment that is 480Y/277V-3ph-4w services and 1,000
amps.
– Sample of required locations: EWC, vending machines, commercial kitchens, within 6 feet of water.
Grounding
• Ground wire provides a low resistance path
for current to the ground in the event of a
short circuit.
• Ground wires are usually bare or covered
with green insulation.
• All ground wires are ultimately connected
to a grounding electrode, such as building
steel, a metal water pipe, etc. per NEC
Article 250.
Electrical Service
(Note: These are the “ARE 4.0 book definitions”, not
necessarily NEC definitions.)
• Service drop – consists of the wires from
the main line, a transformer, a meter, and a
disconnect switch.
• The distance from the meter to the
transformer should not exceed 150 feet.
Electrical Service
• The minimum service size for a residence is
100 amps.
• In residences the panel and disconnect are
usually located outside of the building
where they are accessible to firefighters.
• In commercial construction they may be
located inside the building but must be
directly accessible from an exterior door.
Riser Diagram Components
• Service entrance.
• Main service disconnect.
• Main switchboard.
• Feeders
• Distribution boards
• Feeders
• Branch panelboards
• Branch circuits
Meters
• Residential meters measure total
consumption (kwh). Cost per kwh range
from 8 to 18 cents.
• Commercial meters often measure
consumption and peak demand.
• Think of load as the energy being used at
any given time.
Peak Demand
• Think of “peak demand” as the time when
demand for energy is at its highest.
• Utility companies must be capable of
providing enough power to meet the peak
demand. This power sits there, idle, during
non-peak times.
• The charge associated with the peak
demand is called a demand surcharge.
Emergency Power Sources
• Emergency power is required for
emergency egress lighting and exit signs.
• IBC Section 1006 covers Means of Egress
lighting levels and power sources.
• Hospitals have special emergency power
requirements.
• Stand-by power may be required for
elevators.
Emergency Power Sources
• Lighting backup power is often provided
through emergency battery ballasts that
are continuously recharged while power is
on, and operate one or more lamps when
normal power is lost.
• Emergency lighting may be provided
through individual emergency lighting
units that contain a rechargeable battery.
These operate only when normal power is
lost.
Generators
• Generator fuel supply should be enough for
two hours of runtime under load.
• Common fuel supplies are diesel, natural
gas, and propane.
• Separate automatic transfer switches are
provided for life safety, stand-by, and
optional equipment loads.
Building Automation
• Lighting can be controlled by:
– Photocells
– Time clocks
– Smart breakers or smart relays
– Occupancy or vacancy sensors
– Daylighting controls
• Lighting controls are mandated by the
energy code.
3 Second
Break
LIGHTING REVIEW
What is Light?
• Light is defined as that part of the
electromagnetic radiation spectrum that
can be perceived by the human eye.
• It ranges from:
– Blue light (450 to 475 nanometers)
– Through green and yellow light (at 525nm and 575nm)
– To red light (at 650nm)
• White light is the combination of all
wavelengths.
The Eye
• Lens focuses
• Iris controls the amount of light entering
• Retina senses light
– Rods sense black and white – low light level
– Cones sense color – require more light
• Can adjust from levels below 1fc to over
10,000fc in moments.
• Extreme contrasts are know as glare.
Perception and the Mind
• Eyes sense 2-D info, brain processes a 3-D
image interpreting color, shadows.
• Misinterpretations are common in optical
illusions.
Lighting Terms
• Transmission
– Transmitted light passes through a material.
– Transparent means the image is transmitted.
– Refraction changes the transmitted image.
– Translucent means light is transmitted with no image.
– Opaque means no light passes through.
More Lighting Terms
• Reflective materials bounce light.
– Specular means the image is maintained.
– Diffusing means the image is not maintained.
• Diffuse or Ambient Light
– No sharp shadows like on a cloudy day.
– Light from all directions.
– Referred to area lighting.
More Lighting Terms
• Direct Light
– Very sharp shadows.
– Distinct reflections from shiny objects.
– Examples: sunlight, projector, desk lamp.
– Most useful when aimed at a task.
Color Rendition Index
(CRI)
• CRI is the measure of how well light shows
true color.
• Highest rating is 100, meaning there are no
colors missing.
• CRI is calculated by comparing the color
rendering of a test source to a perfect
source.
More CRI
• The perfect source is an incandescent lamp
for lower CCTs and daylight for higher
CCTs.
• Typical CRIs
– Incandescent: 100; T8 linear fluorescent: 75-85; Cool white linear fluorescent: 62; Compact fluorescent: 82; Standard metal halide: 65; Standard high pressure sodium: 22; Daylight: 100.
So What Is CCT?
• CCT, or correlated color temperature, is a
specification of the color appearance of the
light emitted by a lamp, relating its color to
the color of a light from a reference source
when heated to a particular temperature….
• …which happens to be an incandescent
source.
More CCT
• The color temperature is actually the
temperature of the filament of the
incandescent lamp in degrees Kelvin,
ranging from 3000 K to 3200 K.
• For other sources, the color temperature is
correlated based on appearance.
• Remember, CCTs below 3200 K are warm,
and CCTs above 4000 K are cool.
Basic Lighting Physics
• Power or Intensity
– Represented by the letter “I” for Intensity
– Measured in candlepower (cp) (archaic)
– New unit of measurement is candela (cd)
– Definition: Light emitted in a particular direction.
Basic Lighting Physics
• Flux
– Represented by the letter “F”
– Measured in lumens (l) or (lm)
– Definition: Time rate flow of light.
• Luminance
– Represented by the letter “L”
– Measured in foot-Lamberts (fL)
– Definition: Perception of brightness.
– Proportional to Illumination
Basic Lighting Physics
• Illumination
– Represented by the letter “E”
– Measured in foot-candles (fc)
– Measured in lux (lx)
– Definition: Lumens per unit area, where:
• Foot-candles (fc) = lm / ft2
• Lux (lx) = lm / m2
• 1 fc = 10.76 lx
– E (fc) = F (lm) / Area
Inverse Square Law
• If the light source may be approximated as
a point source, then the flux (F), and
resultant illumination (E), is inversely
proportional to the square of the distance
from the surface.
• Formula: E (fc) = I (cp) / d2
Sample Illumination
Calculation
• Given a lamp with an intensity of 1,600 cp
and a perpendicular surface 10 feet away,
calculate E.
• E1 (fc) = I (cp) / d12
• E1 = 1,600 cp / (10 x 10) ft2
• E1 = 16 fc
Sample Illumination
Calculation
• Given a lamp with an intensity of 1,600 cp
and a perpendicular surface 20 feet away,
calculate E.
• E2 (fc) = I (cp) / d22
• E2 = 1,600 cp / (20 x 20) ft2
• E2 = 4 fc
Relationship between
Illumination and Distance
• In both examples, the intensity “I” was the same, 1,600 fc. So there is a relationship between the illuminations “E’s” and distances “d’s”.
• E1 x d12 = I = E2 x d2
2
• This equation can be rearranged as follows:
• E1 x (d1 / d2)2 = E2
• 16 fc x (10 / 20)2 = E2 = 4 fc
Luminance Calculation #1
• Given the same lamp with an intensity of
1,600 cp placed 10 feet from a white wall
with surface reflectance of 75%, calculate
the luminance “L”.
• L (fL) = E (fc) x % reflectance
• We previously solved for E at 10 feet which
was 16 fc.
• L = 16 fc x 0.75 = 12 fL
Luminance Calculation #2
• Given the same lamp with an intensity of
1,600 cp placed 10 feet from a piece of
frosted glass with a transmittance of 65%,
calculate the luminance “L”.
• L (fL) = E (fc) x % reflectance
• From previously, E at 10 feet was 16 fc.
• L = 16 fc x 0.65 = 10.4 fL
Lighting Systems
• Incandescent
– Contains a tungsten alloy filament
– Filament is heated by a current flowing through
– Filament glows and produces light and heat
– Lamp is filled with an inert gas (nitrogen or argon)
– Typically warmer than sunlight/daylight, rich in yellows and reds, weak in greens and blues.
Incandescent
• Least efficient type of artificial light
• Output of 15 to 18 lumens per watt
• Lifetime of 2,000 hours
• Dimming increases life span of the lamp
• Various shapes, sized in terms of wattage,
and in multiples of 1/8”. (Ex. A-19 lamp is
19 x 1/8” or 2.375” in diameter)
Incandescent
• R lamps and PAR lamps include an internal
reflector so that all of the light comes out
of the front of the lamp.
• There are low voltage lamps that operate
at 12 or 24 volts, which allows a smaller
filament and results in better focus of the
beam. Example MR16 lamps.
Tungsten Halogen
• Lamp is housed in an inner quartz envelope.
• Lamps contain halogen gas which prevents
evaporated metal from the filament from
depositing on the inner surface of the quartz,
allowing the filament to run at much higher
temperatures.
• Lamps produce more light with better color.
• Lamp life extended slightly by redeposition of
the metal back onto the filament.
Fluorescent
• Fluorescent lighting is based on passing a
current through gases inside a glass tube.
• Energy is released in the form of gas ions
and free electrons.
• The glass tube is lined with phosphors
which are excited by the ions, and in turn
glow in characteristic colors.
Fluorescent
• Good color rendition is achieved by
combining the phosphors correctly.
• Ballasts are required to get the current to
arc through the lamp.
• Ballasts are sometimes noisy, and are
assigned Sound Ratings from A to E, A
being the quietest.
Fluorescent
• Linear fluorescent lamp technology has
evolved from the use of T12, to T8, to T5
lamps.
• Cool white produces the most lumens per
watt, but the color is unflattering.
• Warm white looks better.
• The deluxe series and SP series lamps
provide better CRI at a higher cost.
Fluorescent
• Output of 60 to 80 lumens per watt
• Average lifetime of 10,000 hours, based on
a three hour burning period each time the
lamp is turned on.
• Switching decreases the life span of the
lamp.
High Intensity Discharge
(HID)
• HID lamps consist of a lamp within a lamp
which is run at very high voltage.
• General types:
– Mercury vapor – very bright bluish light
– Mercury vapor deluxe – phosphors added for better color.
– Mercury vapor lifetime is 24,000 hours and its
output is 50 lumens per watt.
HID Types
• Metal halide
– Typically iodine gas in the inner envelope.
– Better color than mercury vapor.
– Improved output to 80 lumens per watt.
– Lifetime dropped to 10,000 hours.
HID Types
• High Pressure Sodium
– Most efficient with an output of 110 lumens per watt, but color rendering is not so good.
– Lifetime expectancy of 24,000 hours.
• Low Pressure Sodium
– Highest ratings in lifetime and lumens per watt.
– Worst CRI. Good for security lighting only.
Lamp Output Rankings
• Normal incandescent is the least efficient.
• Tungsten halogen is a slight improvement.
• Mercury vapor
• Fluorescent and metal halide
• High pressure sodium is the most efficient.
• Low pressure sodium (security lighting
only)
Lighting Calculations
• Point Grid Method
– Works best for a single or small quantity of fixtures.
– Ignores surrounding reflection
• Zonal Cavity Method
– Based on a uniform distribution of a large number of fixtures.
– Accounts for reflectivity and volume of space.
Point Grid Method
• Based on the formula:
E = I cos G / d2
• Where:
– E = illumination (fc)
– I = intensity (cp) at the source at a given angle
– G = the angle between perpendicular to the receiving surface and a line from the source to the service
– D = the distance from the source to the surface
Abney’s Law
• States that the light arriving at a surface is
the sum of the light arriving from all of the
sources, and can be expressed by repeating
the point grid formula for each source:
E = I1 cos G1/ d12 + I2 cos G2/ d2
2 + …
…+ In cos Gn/ dn2
Candlepower Distribution
Curves
Zonal Cavity Method
• Most commonly used for office,
commercial, factory space calculations.
• Based on a coefficient of utilization (CU)
for each fixture type.
• Accounts for fixture performance, room
shape, reflectances, maintenance factors,
and dirt.
Zonal Cavity Method
EquationE (fc) = (N x n x LL x LLD x DDF x CU) / A
• Where:
– E = illumination in fc
– N = number of fixtures
– n = number of lamps
– LL = lumens per lamp
– LLD = lamp lumen depreciation factor
– DDF = dirt depreciation factor
– CU = coefficient of utilization
– A = area of the work plane
Zonal Cavity Method
Equation
• Rearrange the equation to solve for the
number of fixtures (N), given a desired
foot-candle level:
N = (E x A) / (n x LL x LLD x DDF x CU)
Recommended Illumination
• The optimum lighting is called the
equivalent spherical illumination (ESI).
• It is based on a theoretical sphere
surrounding the object being illuminated
with the light cast evenly from all
directions, eliminating any shadows and
any reflected bright spots.
Daylighting
• Turning off lights reduces the electrical
load and the heat generated within the
space.
• Daylight itself is a diffuse light source with
perfect CRI.
• Direct sunlight should be shielded, diffused
by diffusing glass, or bounced off diffusing
surfaces.
Daylighting
• Provide artificial lighting in daylit areas.
• Zone lighting for daylight sensor control
via switching fixtures off or dimming them.
• Dimming can be accomplished using
continuous dimming ballasts or stepped
diming ballasts.
• The daylight zone extends 15 feet from the
window, skylight, etc. into the room.
Daylighting Strategies
• Light shelf is an overhang with glass above
which reflects light into the room and up
on the ceiling.
• Glass transoms le light pass from one room
to another.
• A sawtooth roof facing north to let in
diffuse light.
Lighting and Sustainable
Design
• Goal is to balance the use of natural and
artificial lighting sources.
– Incorporate daylighting in the architecture.
– Use efficient lighting sources that reduce energy cost and increase visual comfort.
– Install lighting controls (code mandated).
– Computer modeling for an optimum design.
Daylight Calculating
Methods
• Lumen Method
– Developed in the USA.
– Amount of daylight is calculated in three places: 5 feet from the window, the middle of the room, and 5 feet from the back of the room.
– Can be used to calculate the amount of daylight from one window wall, or two opposing window walls, but not from a corner window.
– Works for clear and cloudy skies.
Daylight Calculating
Methods
• Daylight Factor Method
– Developed in Europe.
– Assumes overcast or diffuse sky conditions.
– Can be used to calculate the amount of daylight anywhere in a room, including the effect of corner windows.
Daylight Factor
Calculation Results
• The calculation result is a number that
expresses the amount of light at a
particular location inside as a percentage of
the light available on the exterior surface.
• A daylight factor of 3 means that 3% of the
available light outside would arrive on the
workplane in that area.
• For 2,000 fc outside, 3% would yield 60 fc
inside.
Emergency and Exit
Lighting
• IBC Section 1006 covers emergency egress
lighting requirements.
• IBC Section 1016 covers exit sign
requirements.
• Emergency lighting may be powered by
generators, battery packs, or emergency
ballasts.
• NiCad rechargeable batteries are common.
Emergency and Exit
Lighting
• Exit signs are typically LED due to energy
code constraints.
• Exit signs should be visible even with the
lights out.
General Tips…
� Study comprehensively…
� Save practice tests until the end.
� Don’t get stuck.
� Answer every question!
Suggested Resources� “References Available During the Test” document
� Mechanical and Electrical Equipment for Buildings
� Heating, Cooling, Lighting (Lechner)
� Dustin Goffron’s “Helpful Links for the ARE 4.0”� http://www.dustingoffron.com/ARE/
� Alkikat’s Study Guide
� Jenny’s Notes (AREndurance)� www.arendurance.files.wordpress.com
� YouTube’s “WikiEngineering” channel
� MEEB’s Student Companion Site� http://bcs.wiley.com/he-
bcs/Books?action=contents&itemId=0471465917&bcsId=2879
� CED Engineering.com’s “Design Options for HVAC Distribution Systems”� http://www.cedengineering.com/upload/Design%20Options%20for%20HVA
C%20Distribution%20Systems.pdf
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