c2_strainanalysis
TRANSCRIPT
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SME 2123
MECHANICS OF SOLIDS IIDr. Zaini AhmadB.Eng (Hons)(Mech), M.Sc (Structures &Crashworthiness), Ph.D (Structural Impact)Department of Applied Mechanics & Design,Faculty of Mechanical Engineering,
Universiti Teknologi Malaysia,
81310 Skudai, Johor, Malaysia.
Tel : (+607) 553 4647(Office)Tel : (+6012) 717 0581 (Mobile)Email: [email protected]
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Mechanics of Solids II
Strain Analysis
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Strain Analysis
(Plane Strain)
General state of strain at a point in a body is represented
by 3 normal strains and 3 shear strains .
The normal and shear strain componentswill vary
according to the orientation of the element
zyx
zyx
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Plane strainone dimension is very large compared to the other
two (z= 0, xz= 0 and yz= 0) (e.g. tunnel, dam, retaining wall, etc)
Strain Analysis
(Plane Strain)
Retaining wall Earth dam
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Strain Analysis
(Plane Strain)
cossinsincos
cossincos
sin
cos
22
'
'
'
'
xyyxx
xyyx dydydxdxdydy
dxdx
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Strain Analysis
(Plane Strain Transformation)
Strain transformation equations:-
2cos2
2sin22
2sin
2
2cos
22
2sin2
2cos22
''
'
'
xyyxyx
xyyxyx
y
xyyxyx
x
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Strain Analysis
(Plane Strain Transformation)
Principal strain:-
Maximum In-Plain Shear Strain - the associated average
normal strain:-
22
2,1222
2tan
xyyxyx
yx
xy
p
2,
222
2tan
22
plane-inmax yx
avg
xyyx
xy
yx
S
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A differential element of material at a point is subjected to a state of plane strain
defined by which tends to distort the
element. Determine:-i) The principal strain at the point and the associated orientation of the element
and show the state of strain on the principal plane
ii) The maximum in-plane shear strain at the point and the associated orientation
of the element and sketch the distorted element.
iii) The equivalent strains acting on an element oriented at the point clockwise
60ofrom the original position
x 350 106 , y 200 106 , xy 80 106
Strain Analysis
(Plane Strain Transformation)
Example 1:-
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Orientation of the element:-
72.1711808.28-and28.82
)10(200350
)10(802tan
6
6
P
yx
xy
P
Strain Analysis
(Plane Strain Transformation)
85.9and14.4P
22
2,1222
xyyxyx
6
226
102
80
2
200350
2
10200350
)10(353
)10(203
6
2
6
1
Substitute = -4.14ointo strain transformation eq.
to determine the deformation of the element
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Orientation of the
element:-
For maximum in-plane shear strain,
311and9.40
80
2003502tan
s
xy
yx
s
6planeinmax
22
planeinmax
10556
222
xyyx
Strain Analysis
(Plane Strain Transformation)
)10(75)10(2
200350
2
66
yx
avg
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Strain Analysis
(Plane Strain Transformation)
86.177
2sin2
2cos22
2sin22cos22
16.258)60(2cos2
80)60(2sin
2
200350
2
2cos2
2sin22
86.27)60(2sin2
80)60(2cos
2
200350
2
200350
2sin2
2cos22
'
'
'
''
''
'
'
y
xyyxyx
y
xyyxyx
y
ooyx
xyyxyx
oo
x
xyyxyx
x
(* if = -60ois used)
(* if = -60o+90o=30ois used)
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Strain Analysis
(Mohrs Circle - Plane Strain)
Solve problems involving the transformation of strain usingMohrs circle
It has a center on the axis at point C(avg, 0) and a radius R
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Example 2:-
The state of plane strain at a point is represented by the components
Determine the maximum in-plane shear strains and the orientation of an
element.
Strain Analysis
(Mohrs Circle - Plane Strain)
666 10120,10150,10250 xyyx
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From the coordinates of point E, we have
To orient the element,we can determine the clockwise
angle,
6planeinmax''
6planeinmax''
10418
108.2082
yx
yx
7.36
35.829050250
60tan902
1
1
1
s
s
Strain Analysis
(Mohrs Circle - Plane Strain)
6622
66
108.208102
120
2
)150(250
1050102
)150(250
R
avg
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666 10750,10760,10520 xyyx
Example 3:-The state of strain at the point on the gear tooth has the components .
Use the strain transformation equations to determine:-
a) The in-plane principal strains
b) The maximum in-plane shear strain and average normal strain
In each case, specify the orientation of the element and show how the strains
deform the element within the x-y plane
Strain Analysis
(Mohrs Circle - Plane Strain)
Ans (1= 622, 2= -862, avg=-120)
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Strain Analysis
(Mohrs Circle - Plane Strain)
Absolute maximum shear strain
Circle with the largest radius
It occurs on the element oriented 45oabout the axis
2
minmax
minmaxmaxabs
avg
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Strain Analysis
(Mohrs Circle - Plane Strain)
For plain strain:-
maxmax''maxabs
zx minmaxmax''maxabs yx
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Example 4:-
The state of plane strain at a point is represented by the strain components,
Determine the maximum in-plane shear strain and the absolute maximum shear
strain.
Strain Analysis
(Mohrs Circle - Plane Strain)
x 400 106 , y 200 106 , xy150 106
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From the strain components, the centre of the circle is on the axis at
Since , the reference point has coordinates
66 10100102
200400
avg
A400 106 ,75 106
Thus the radius of the circle is 9622 103091075100400
R
610752
xy
Strain Analysis
(Mohrs Circle - Plane Strain)
Computing the in-plane principal strains, we have
66
min
66
max
1040910309100
1020910309100
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From the circle, the maximum in-plane shear strain is
66minmaxplaneinmax 1061810409209max abs
10409,0,10209 6minint
6
max
From the above results, we have
Thus the Mohrs circle is as follows,
Strain Analysis
(Mohrs Circle - Plane Strain)
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Strain Analysis
(Strain Rosettes)
Normal strain in a tension-test specimen can bemeasured using an electrical-resistance strain gauge
strain rosettes.
The strain-transformation equation for each gauge:-
ccxycycxc
bbxybybxb
aaxyayaxa
cossinsincos
cossinsincos
cossinsincos
22
22
22
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Strain Analysis
(Strain Rosettes)
Two types of typical strain measurement using strainrosettes45oand 60orosettes
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Strain Analysis
(Strain Rosettes)
Example 5:-
The state of strain at pointA on the bracket is measure using the strain rosette
as shown. Due to the loadings, the readings from the gauge give a= 60(10-6),
b= 135(10-6) and c= 264(10
-6). Determine the in-plane principal strains at the
point and the directions in which they act.
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Measuring the angles counter-clockwise,
By substituting the values into the 3 strain-transformation equations, we have
120and60,0 cba
666 10149,10246,1060 xyyx Using Mohrs circle, we have A(60(10-6), 74.5(10-6)) and center C (153(10-6), 0).
3.19,108.33,10272
101.119105.7460153
p2
6
2
6
1
6622
R
Strain Analysis
(Strain Rosettes)
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Strain Analysis
(Strain Rosettes)
Example 6:-
The 45ostrain rosette is mounted near the tooth of the wrench. The following readings
are obtained for each gauge give a= 800(10-6), b= 520(10
-6) and c= -450(10-6).
Determine (a) the in-plane principal strains and (b) the maximum in-plane shear strain
and associated average normal strain. In each case, show the deformed element due
to these strains.
Ans (1= 889, 2= -539, max/2 =1428, avg=175)
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Strain Analysis
(Material Property Relationship)
Generalized Hookes Law:-
For a tri-axial state of stress, the general form for
Hookes law is as follow:
Valid only for a linearelasticmaterials
Hookes law for shear stress and shear strain is
written as
xzxzyzyzxyxyGGG
1
1
1
yxzzzxyyzyxx vEvEvE 1
,1
,1
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Strain Analysis
(Material Property Relationship)
Relationship involving E, vand G:-
Bulk modulus - a measure of the stiffness of a volumeof material
vE
G
12
v
Ek
213
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Strain Analysis
(Material Property Relationship)
Example 7:-
The copper bar is subjected to a uniform loading along its edges. If
it has a = 300 mm, b = 50 mm, and t = 20 mm before load is applied,
find its new length, width and thickness after application of the load.
Take 34.0,GPa120 cucu
vE
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Strain Analysis
(Material Property Relationship)
From the loading we have
The associated normal strains are determined from the generalized Hookes law,
0,MPa500,MPa800 zyx
000850.0,00643.0,00808.0 yxzzzxyyzyxx Ev
EE
v
EE
v
E
The new bar length, width, and thickness are therefore
mm98.1920000850.020'
mm68.495000643.050'
mm4.30230000808.0300'
t
b
a
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Strain Analysis
(Material Property Relationship)
Example 7: Final exam question
A cantilevered T-structure made from 40
mm-diameter bars, supports forces 1 kN and
3 kN. The material is mild steel which the
elastic modulus is 200 GPa, the shear
modulus is 75 GPa and Poissons ratio is 0.3.Point E which is on the side of the bar AB, is
to be analyzed.
i) Find the principal stresses at point E and
sketch the orientation and deformation
of the element in this condition
ii) Find the in-plane maximum shear stress
at point E and sketch the orientation anddeformation of the element in this
condition.
iii) At point E, calculate the normal strain in
the direction 30oto the axial direction as
shown in this figure
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Three strain gauges were fixed onto a surface of a automotive frame.
Under loading, the readings of the gauges were:-
a) By sketching Mohrs circle and using trigonometry method,
determine the value of the principal strains and maximum shearstrain, and draw the orientation and the element under these
conditions. Verify your answers using the strain transformation
equations.
b) Calculate x, y and xyusing material properties relation. By
plotting Mohrs circle on graph paper, determine the values of
the principle stresses and maximum shear stress, and draw the
orientation and the element under this condition. Also, verify your
answers using the stress transformation equations (E = 200
GPa, G = 75 GPa, v= 0.35)
c) Determine the values of the normal stress, shear stress, normal
strain and shear strain at direction P4o(clockwise) from the x-
axis and draw the orientation of element for each condition
Strain Analysis
Assignment 1:-
P1a
P2b
P3c
P5o
25o
a
bc
x
y
Due date for submission: 11 Oct 2013
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Strain Analysis
Group 1P1= 220
P2= -130
P3= 100
P4= 25o
P5= 65o
Group 2P1= -220
P2= 130
P3= 150
P4= 20o
P5= 45o
Group 3P1= 150
P2= -180
P3= -110
P4= 38o
P5= 60o
Group 4P1= 190
P2= -100
P3= -95
P4= 30o
P5= 53o
Group 5P1= 150
P2= -130
P3= -100
P4= 32o
P5= 50o
Group 6
P1= -300
P2= -180
P3= 110
P4= 30o
P5= 75o
Group 7
P1= 280
P2= 100
P3= -150
P4= 40o
P5= 55o
Group 8
P1= -190
P2= 130
P3= -120
P4= 55o
P5= 70o
Group 9
P1= -300
P2= -200
P3= -95
P4= 35o
P5= 80o
Group 10
P1= 320
P2= -230
P3= -130
P4= 15o
P5= 77o