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    SME 2123

    MECHANICS OF SOLIDS IIDr. Zaini AhmadB.Eng (Hons)(Mech), M.Sc (Structures &Crashworthiness), Ph.D (Structural Impact)Department of Applied Mechanics & Design,Faculty of Mechanical Engineering,

    Universiti Teknologi Malaysia,

    81310 Skudai, Johor, Malaysia.

    Tel : (+607) 553 4647(Office)Tel : (+6012) 717 0581 (Mobile)Email: [email protected]

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    Mechanics of Solids II

    Strain Analysis

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    Strain Analysis

    (Plane Strain)

    General state of strain at a point in a body is represented

    by 3 normal strains and 3 shear strains .

    The normal and shear strain componentswill vary

    according to the orientation of the element

    zyx

    zyx

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    Plane strainone dimension is very large compared to the other

    two (z= 0, xz= 0 and yz= 0) (e.g. tunnel, dam, retaining wall, etc)

    Strain Analysis

    (Plane Strain)

    Retaining wall Earth dam

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    Strain Analysis

    (Plane Strain)

    cossinsincos

    cossincos

    sin

    cos

    22

    '

    '

    '

    '

    xyyxx

    xyyx dydydxdxdydy

    dxdx

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    Strain Analysis

    (Plane Strain Transformation)

    Strain transformation equations:-

    2cos2

    2sin22

    2sin

    2

    2cos

    22

    2sin2

    2cos22

    ''

    '

    '

    xyyxyx

    xyyxyx

    y

    xyyxyx

    x

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    Strain Analysis

    (Plane Strain Transformation)

    Principal strain:-

    Maximum In-Plain Shear Strain - the associated average

    normal strain:-

    22

    2,1222

    2tan

    xyyxyx

    yx

    xy

    p

    2,

    222

    2tan

    22

    plane-inmax yx

    avg

    xyyx

    xy

    yx

    S

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    A differential element of material at a point is subjected to a state of plane strain

    defined by which tends to distort the

    element. Determine:-i) The principal strain at the point and the associated orientation of the element

    and show the state of strain on the principal plane

    ii) The maximum in-plane shear strain at the point and the associated orientation

    of the element and sketch the distorted element.

    iii) The equivalent strains acting on an element oriented at the point clockwise

    60ofrom the original position

    x 350 106 , y 200 106 , xy 80 106

    Strain Analysis

    (Plane Strain Transformation)

    Example 1:-

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    Orientation of the element:-

    72.1711808.28-and28.82

    )10(200350

    )10(802tan

    6

    6

    P

    yx

    xy

    P

    Strain Analysis

    (Plane Strain Transformation)

    85.9and14.4P

    22

    2,1222

    xyyxyx

    6

    226

    102

    80

    2

    200350

    2

    10200350

    )10(353

    )10(203

    6

    2

    6

    1

    Substitute = -4.14ointo strain transformation eq.

    to determine the deformation of the element

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    Orientation of the

    element:-

    For maximum in-plane shear strain,

    311and9.40

    80

    2003502tan

    s

    xy

    yx

    s

    6planeinmax

    22

    planeinmax

    10556

    222

    xyyx

    Strain Analysis

    (Plane Strain Transformation)

    )10(75)10(2

    200350

    2

    66

    yx

    avg

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    Strain Analysis

    (Plane Strain Transformation)

    86.177

    2sin2

    2cos22

    2sin22cos22

    16.258)60(2cos2

    80)60(2sin

    2

    200350

    2

    2cos2

    2sin22

    86.27)60(2sin2

    80)60(2cos

    2

    200350

    2

    200350

    2sin2

    2cos22

    '

    '

    '

    ''

    ''

    '

    '

    y

    xyyxyx

    y

    xyyxyx

    y

    ooyx

    xyyxyx

    oo

    x

    xyyxyx

    x

    (* if = -60ois used)

    (* if = -60o+90o=30ois used)

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    Strain Analysis

    (Mohrs Circle - Plane Strain)

    Solve problems involving the transformation of strain usingMohrs circle

    It has a center on the axis at point C(avg, 0) and a radius R

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    Example 2:-

    The state of plane strain at a point is represented by the components

    Determine the maximum in-plane shear strains and the orientation of an

    element.

    Strain Analysis

    (Mohrs Circle - Plane Strain)

    666 10120,10150,10250 xyyx

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    From the coordinates of point E, we have

    To orient the element,we can determine the clockwise

    angle,

    6planeinmax''

    6planeinmax''

    10418

    108.2082

    yx

    yx

    7.36

    35.829050250

    60tan902

    1

    1

    1

    s

    s

    Strain Analysis

    (Mohrs Circle - Plane Strain)

    6622

    66

    108.208102

    120

    2

    )150(250

    1050102

    )150(250

    R

    avg

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    666 10750,10760,10520 xyyx

    Example 3:-The state of strain at the point on the gear tooth has the components .

    Use the strain transformation equations to determine:-

    a) The in-plane principal strains

    b) The maximum in-plane shear strain and average normal strain

    In each case, specify the orientation of the element and show how the strains

    deform the element within the x-y plane

    Strain Analysis

    (Mohrs Circle - Plane Strain)

    Ans (1= 622, 2= -862, avg=-120)

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    Strain Analysis

    (Mohrs Circle - Plane Strain)

    Absolute maximum shear strain

    Circle with the largest radius

    It occurs on the element oriented 45oabout the axis

    2

    minmax

    minmaxmaxabs

    avg

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    Strain Analysis

    (Mohrs Circle - Plane Strain)

    For plain strain:-

    maxmax''maxabs

    zx minmaxmax''maxabs yx

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    Example 4:-

    The state of plane strain at a point is represented by the strain components,

    Determine the maximum in-plane shear strain and the absolute maximum shear

    strain.

    Strain Analysis

    (Mohrs Circle - Plane Strain)

    x 400 106 , y 200 106 , xy150 106

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    From the strain components, the centre of the circle is on the axis at

    Since , the reference point has coordinates

    66 10100102

    200400

    avg

    A400 106 ,75 106

    Thus the radius of the circle is 9622 103091075100400

    R

    610752

    xy

    Strain Analysis

    (Mohrs Circle - Plane Strain)

    Computing the in-plane principal strains, we have

    66

    min

    66

    max

    1040910309100

    1020910309100

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    From the circle, the maximum in-plane shear strain is

    66minmaxplaneinmax 1061810409209max abs

    10409,0,10209 6minint

    6

    max

    From the above results, we have

    Thus the Mohrs circle is as follows,

    Strain Analysis

    (Mohrs Circle - Plane Strain)

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    Strain Analysis

    (Strain Rosettes)

    Normal strain in a tension-test specimen can bemeasured using an electrical-resistance strain gauge

    strain rosettes.

    The strain-transformation equation for each gauge:-

    ccxycycxc

    bbxybybxb

    aaxyayaxa

    cossinsincos

    cossinsincos

    cossinsincos

    22

    22

    22

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    Strain Analysis

    (Strain Rosettes)

    Two types of typical strain measurement using strainrosettes45oand 60orosettes

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    Strain Analysis

    (Strain Rosettes)

    Example 5:-

    The state of strain at pointA on the bracket is measure using the strain rosette

    as shown. Due to the loadings, the readings from the gauge give a= 60(10-6),

    b= 135(10-6) and c= 264(10

    -6). Determine the in-plane principal strains at the

    point and the directions in which they act.

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    Measuring the angles counter-clockwise,

    By substituting the values into the 3 strain-transformation equations, we have

    120and60,0 cba

    666 10149,10246,1060 xyyx Using Mohrs circle, we have A(60(10-6), 74.5(10-6)) and center C (153(10-6), 0).

    3.19,108.33,10272

    101.119105.7460153

    p2

    6

    2

    6

    1

    6622

    R

    Strain Analysis

    (Strain Rosettes)

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    Strain Analysis

    (Strain Rosettes)

    Example 6:-

    The 45ostrain rosette is mounted near the tooth of the wrench. The following readings

    are obtained for each gauge give a= 800(10-6), b= 520(10

    -6) and c= -450(10-6).

    Determine (a) the in-plane principal strains and (b) the maximum in-plane shear strain

    and associated average normal strain. In each case, show the deformed element due

    to these strains.

    Ans (1= 889, 2= -539, max/2 =1428, avg=175)

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    Strain Analysis

    (Material Property Relationship)

    Generalized Hookes Law:-

    For a tri-axial state of stress, the general form for

    Hookes law is as follow:

    Valid only for a linearelasticmaterials

    Hookes law for shear stress and shear strain is

    written as

    xzxzyzyzxyxyGGG

    1

    1

    1

    yxzzzxyyzyxx vEvEvE 1

    ,1

    ,1

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    Strain Analysis

    (Material Property Relationship)

    Relationship involving E, vand G:-

    Bulk modulus - a measure of the stiffness of a volumeof material

    vE

    G

    12

    v

    Ek

    213

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    Strain Analysis

    (Material Property Relationship)

    Example 7:-

    The copper bar is subjected to a uniform loading along its edges. If

    it has a = 300 mm, b = 50 mm, and t = 20 mm before load is applied,

    find its new length, width and thickness after application of the load.

    Take 34.0,GPa120 cucu

    vE

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    Strain Analysis

    (Material Property Relationship)

    From the loading we have

    The associated normal strains are determined from the generalized Hookes law,

    0,MPa500,MPa800 zyx

    000850.0,00643.0,00808.0 yxzzzxyyzyxx Ev

    EE

    v

    EE

    v

    E

    The new bar length, width, and thickness are therefore

    mm98.1920000850.020'

    mm68.495000643.050'

    mm4.30230000808.0300'

    t

    b

    a

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    Strain Analysis

    (Material Property Relationship)

    Example 7: Final exam question

    A cantilevered T-structure made from 40

    mm-diameter bars, supports forces 1 kN and

    3 kN. The material is mild steel which the

    elastic modulus is 200 GPa, the shear

    modulus is 75 GPa and Poissons ratio is 0.3.Point E which is on the side of the bar AB, is

    to be analyzed.

    i) Find the principal stresses at point E and

    sketch the orientation and deformation

    of the element in this condition

    ii) Find the in-plane maximum shear stress

    at point E and sketch the orientation anddeformation of the element in this

    condition.

    iii) At point E, calculate the normal strain in

    the direction 30oto the axial direction as

    shown in this figure

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    Three strain gauges were fixed onto a surface of a automotive frame.

    Under loading, the readings of the gauges were:-

    a) By sketching Mohrs circle and using trigonometry method,

    determine the value of the principal strains and maximum shearstrain, and draw the orientation and the element under these

    conditions. Verify your answers using the strain transformation

    equations.

    b) Calculate x, y and xyusing material properties relation. By

    plotting Mohrs circle on graph paper, determine the values of

    the principle stresses and maximum shear stress, and draw the

    orientation and the element under this condition. Also, verify your

    answers using the stress transformation equations (E = 200

    GPa, G = 75 GPa, v= 0.35)

    c) Determine the values of the normal stress, shear stress, normal

    strain and shear strain at direction P4o(clockwise) from the x-

    axis and draw the orientation of element for each condition

    Strain Analysis

    Assignment 1:-

    P1a

    P2b

    P3c

    P5o

    25o

    a

    bc

    x

    y

    Due date for submission: 11 Oct 2013

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    Strain Analysis

    Group 1P1= 220

    P2= -130

    P3= 100

    P4= 25o

    P5= 65o

    Group 2P1= -220

    P2= 130

    P3= 150

    P4= 20o

    P5= 45o

    Group 3P1= 150

    P2= -180

    P3= -110

    P4= 38o

    P5= 60o

    Group 4P1= 190

    P2= -100

    P3= -95

    P4= 30o

    P5= 53o

    Group 5P1= 150

    P2= -130

    P3= -100

    P4= 32o

    P5= 50o

    Group 6

    P1= -300

    P2= -180

    P3= 110

    P4= 30o

    P5= 75o

    Group 7

    P1= 280

    P2= 100

    P3= -150

    P4= 40o

    P5= 55o

    Group 8

    P1= -190

    P2= 130

    P3= -120

    P4= 55o

    P5= 70o

    Group 9

    P1= -300

    P2= -200

    P3= -95

    P4= 35o

    P5= 80o

    Group 10

    P1= 320

    P2= -230

    P3= -130

    P4= 15o

    P5= 77o